A pool has some initial amount of water in it. Then it starts being filled so the water level rises at a rate of 666 centimeters per minute. After 202020 minutes, the water level is 220220220 centimeters.
Graph the relationship between the pool's water level (in centimeters) and time (in minutes).

Answer:

14 and 21 and 28

Step-by-step explanation:

2:3:4.

The shortest side is 14

14/2 = 7

Multiply each side by 7

2*7:3*7:4*7

14 : 21 : 28

Answer:

f⁻¹(x) = -4 + √x

Step-by-step explanation:

Switch the positions of x and y then solve for x.

[tex]f(x)=(x+4)^2\\x=(y+4)^2\\\sqrt{x} =y+4\\\sqrt{x} -4=y[/tex]

Answer:

Step-by-step explanation:

there are function that "invert" each other..

subtraction inverts addition...

3+2 = 5 ... 5-2 = 3

division inverts multiplication

5*2 = 10 ... 10/2 = 5

Using that concept, "factoring" is basically the inverse of multiplication

3x^2 + 9x can be factored to 3x(x+3)

if you multiply that out it reverts back to the original equation

so  x^2 + 5x + 6 factors to (x+3)(x+2)

if you multiply that out (foil it)

you get x^2 + 5x + 6

Answer:

at 15.39% that should not be sufficient to reject the Null

= "Fail to reject the Null hypothesis"

Step-by-step explanation:

z = -1.02 (L)0.15386 (R)0.84614

84.61% / 15.39%

Answer:

(6C1)(5C1)/20C2

Step-by-step explanation:

Was right on egde

[tex] \Large \mathbb{SOLUTION:} [/tex]

[tex] \begin{array}{l} \text{Let }r\text{ be the rate of the boat in still water and} \\ c\text{ be the rate of the current.} \\ \\ \text{So } \\ \begin{aligned} \quad&\bullet\:\text{Rate Upstream}= r - c \\ &\bullet\:\text{Rate Downstream}= r - c\end{aligned} \\ \\ \text{We know that }\text{Rate} = \dfrac{\text{Distance}}{\text{Time}}. \end{array} [/tex]

[tex] \begin{array}{l} \bold{Equations:} \\ \\ \begin{aligned} &\quad\quad \quad r - c = \dfrac{104}{4} = 26\quad (1) \\ \\ & \quad \quad \quad r + c = \dfrac{200}{4} = 50\quad (2)\\ \\ & \text{Adding (1) and (2), we get} \\ \\ &\quad\quad 2r = 76 \implies \boxed{r = 38\ \text{kph}} \\ \\ &\text{Using (2), it follows that} \\ \\ & \quad \quad c = 50 - r \implies \boxed{c = 12\ \text{kph}} \end{aligned} \end{array} [/tex]

a=2,5937

b=2,7048

c=2,7181

d=2,7183

e=2,7183

Answer:

Step-by-step explanation:

The way to do this so as to streamline both the vertex and finding the zeros is to complete the square. That method will provide us with the vertex, and then we can continue on to factor from that form to find the zeros. Completing the square requires us to set the quadratic equal to 0 then move over the constant, giving us

[tex]-x^2+18x=72[/tex] The leading coefficient HAS to be a positive 1; ours is negative 1 so we factor out the negative to get:

[tex]-(x^2-18x)=72[/tex] Now we're ready to complete the square.

Take half the linear term, square it, and add it to both sides. Our linear term is 18 (from -18x; don't worry about the negative because squaring it makes it positive anyway). Half of 18 is 9, and 9 squared is 81.

BUT on the left we have that -1 sitting out front that refuses to be ignored. What we actually added on to the left side, inside the parenthesis, is -1(81) which is -81.   -81 is what we add to the right since that turns out to be what we added to the left:

[tex]-(x^2-18x+81)=72-81[/tex] and we clean that up.

The reason we complete the square is because when we simplify the left side, we end up with a perfect square binomial found from taking the square root of x-squared, the first sign we come to, then the square root of 81:

[tex]-(x-9)^2=-9[/tex].  Move the constant back over to get

[tex]-(x-9)^2+9=y[/tex] telling us that the vertex is (9, 9). In the context of the problem that means that the gym sells on average 9 memberships a day and the profit it makes on average per day is $9.

To factor, we will go back one step to

[tex]-(x-9)^2=-9[/tex] and begin by dividing both sides by -1 to get

[tex](x-9)^2=9[/tex] and undo the squaring by taking the square root of both sides to get

x - 9 = ±3 so

x = 9 + 3 and

x = 9 - 3 so

x = 6 and 12

Those are the zeros. This means that if they sell either 6 or 12 memberships they have a 0 profit. That may sound strange, but in business it does often work like that...selling too many of something makes your company lose money (this is often due to the cost required by you to produce or manufacture the product).

Answer:

y = -1

Step-by-step explanation:

Answer:

14

Step-by-step explanation:

3 1/2 multiply by 4 equals 14

Answer:

Cannot be determined

Step-by-step explanation:

We only know one angle and we could only compare one set of sides.

We do not have enough information to determine if the triangles are similar

Answer:

$6.60

Step-by-step explanation:

12% = 0.12

12% of $55 = 0.12 x 55

=6.6

So, $6.60

Answer:

84°

Step-by-step explanation:

the total angle in a straight line sum up to 180°

Answer:

30

Step-by-step explanation:

5 x 3 = 15

15 - 5 = 10

20 + 10 = 30

Asnwer: C

-------------------------------------

Answer:

Hence the answer is TRUE.

Step-by-step explanation:

If event A is taking 15 or more minutes to urge to figure tomorrow and event B is taking but a quarter-hour to urge to figure tomorrow, then events A and B must be complimentary events. this is often because the occurring of 1 is going to be precisely the opposite of the occurring of the opposite event and that they cannot occur simultaneously. In other words, events A and B are mutually exclusive and exhaustive.  

Mathematically,  

P(A) + P(B) = 1.

Answer:

a. Yes

b. VT

c. Segment RQ

Step-by-step explanation:

a. Find the slope of RS and UV

Slope = rise/run

Slope of RS = rise/run = RQ/QS

Slope of RS = 6/6

Slope of RS = 1

Slope of UV = rise/run = UT/TV

Slope of UV = 3/3

Slope of UV = 1

Thus, TS and UV have equivalent slopes

b. Slope of VT:

VT is an horizontal line.

It has no rise. But only run.

Therefore, it's rise = 0, while run = VT = 3

Slope of VT = rise/run = 0/3

Slope of VT = 0

c. Vertical lines have undefined slope.

Segment RQ is vertical line and therefore has an undefined slope.

RQ has rise but no run.

Thus:

Rise = 6

Run = 0

Slope of Segment RQ = 6/0 (this can't divide)

Therefore, slope of Segment RQ is undefined.

Answer:

997.5 is the answer to your question..

Answer:

a=1, b=-2,c=-1

Step-by-step explanation:

1*(x)+(-2)*y+(-1)*1. a=1, b=-2,c=-1

Answer:

((c)).g(x) = 3 × 2^x +2..

Answer:

2[tex]\sqrt{2}[/tex]

Step-by-step explanation:

See the photo for the steps. :)

Answer:

2x-3x+1

Step-by-step explanation:

f'(x,y)=2x-3x+1

Answer:

your answer should be six I hope this help

Answer:

the should be 6

Step-by-step explanation:

(2-3)(-6)

-12+18

=6

Answer:

b/a

Step-by-step explanation:

ax+by=c

To find the slope solve for y

by = -ax+c

Divide by b

y = -a/b x + c/b

The slope intercept form is y = mx+b where m is the slope

The slope is -a/b

A perpendicular line has a slope that is the negative reciprocal

-1/ (-a/b)

-1 * -b/a

b/a

Answer:

D. ( f + g)(x) = 2x^3 + 3x^2 - 5x - 3

Answer:

Step-by-step explanation:

(D+R) = 80:2 = 40

D = 40-R

(D+8) * R = 72X

Thay D=40-R

(40-R+8)*R = 72X

R=1.55, D=38.45

Hey there! Is there more text to this? I would love to help, but there is no question.

Answer:

D.

Step-by-step explanation:

.

The number of planes that can be drawn that pass through point A is 1.

A perpendicular line creates an angle of 90° with a line or a plane. If a line exists to be drawn from a point to a line or a plane it can only be one. In this case, a line exists to be drawn through a point A to a plane P. If the line stands to be perpendicular, then it exists only one.

Therefore, the correct answer is option D. 1.

To learn more about points on a plane refer to:

https://brainly.com/question/10680920

#SPJ2