A phone company charges each customer a monthly fee of $11.25. In addition, it charges $0.03 per minute for in-state calls and $0.11 per minute for out-of-state calls. What is the total monthly charge for a customer who made 340 minutes of in-state calls and 84 minutes of out-of-state calls?

Answers

Answer 1

340 x 0.03 = 10.2 (in state)

84 x 0.11 = 9.24 (out of state)

10.2 + 9.24 + 11.25

= $30.69 monthly charge

hope it helps :)

Answer 2

The total monthly charge for a customer is given as $30.69.

What is simplification?

Simplifying allows us to test each process and strategy to determine which is the most efficient and best suited for its specific goal.

here,

A phone provider costs each customer $11.25 per month. Furthermore, it charges $0.03 per minute for in-state calls and $0.11 for out-of-state calls.

Charge within the boundary  of state for 340 minutes = 340 x 0.03 = 10.2

Charge beyond the boundary  of state for 84 minutes  = 84 x 0.11 = 9.24

Total monthly charge = 10.2 + 9.24 + 11.25

                                = $30.69 monthly charge

Thus, A customer's total monthly price is shown as $30.69.

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Related Questions

What statement describes the graph?

Answers

Answer:

D.

Step-by-step explanation:

The gragh crosses the y-axis at (0,-5), decreasing from x=-10 to x=-2 and remaining constant from x=-2 to x=10

For which of the following equations is x = 7 not a solution?
4= -x + 11
-3x = x - 28
-5 = 2x – 9
5x = 2x + 21

Answers

Answer: For following equation x = 7 not a solution:

-5 = 2x-9

Answer:

Step-by-step explanation:

Put x to the equation.

4=-7+11 => 4=4 ✓

-3•7=7-28 =>-21=-21 ✓

-5•7= 2•7-9 =>-35=5 is incorrect.

5•7=2•7+21 =>35=35 ✓

Hence,for the third equation x is not a solution.

If n(A)=36, n(B)=10, n(AU B) = 40 and n(A) = 27 find n(U) and n(AB​

Answers

Answer:

n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)

Given n(A)=7

n(B)=9

n(A∪B)=14

Substituting in 1

14=7+9−n(A∩B)

⇒n(A∩B)=16−14=2

Step-by-step explanation:

ok

Answer:

The question is incomplete.

It should be:

If n(A)=36, n(B)=10, n(A∪B)=40, and n(A')=27. Find n(∪) and n(A∩B)

Find n(U)

n(A') = n(∪) - n(A)27 = n(∪) - 36n(∪) = 27 + 36n(∪) = 63

Find n(A∩B):

n(A∪B) = n(A) + n(B) - n(A∩B)40 = 36 + 10 - n(A∩B)n(A∩B) = 46 - 40n(A∩B) = 6

Help ME PLS IM FAILING PYTHAGOREAN THEOREM I NEED HELP NOW

Answers

Answer:

3.9

Step-by-step explanation:

We can use the Pythagorean theorem

a^2 +b^2 =c^2 where a and b are the legs and c is the hypotenuse

7^2 + h^2 = 8^2

49 + h^2 = 64

h^2 = 64-49

h^2 = 15

Taking the square root of each side

sqrt(h^2) = sqrt(15)

h = 3.87298

To the nearest tenth

h = 3.9

I will mark as the brillianest plzzzzzzzzzzzzzzzzzzzz be helpful to me ......
c) If C.P. = Rs 750, loss percent = 8% find S.P.​

Answers

Answer: SP is Rs 690

Step-by-step explanation:

CP= Rs 750

loss percent = 8%

so

loss = 8% of CP

= 8/100 * 750

= Rs 60

Loss = Rs 60

so

SP = Rs 750-60

= Rs 690

Answer:

here,

CP=750

loss%=8%

now,

SP= (100-L)×cp/100

= (100-8)×750/100

= (92×750)/100

= 69000/100

= 690

hence the SP of the article is Rs 690

any problem then comment it

hope this helped you ☺️

If two natural numbers are n and (n+3) prove that the differences of their square is an even numbers

Answers

Answer and explanation:

Given two natural numbers n and n+3, we prove that the difference or their squares is even thus:

(n+3)²-(n)²= (n+3)(n+3)-(n)²

=n²+3n+3n+9-n²

=6n+9

Since the value of the difference of square of the natural numbers n and n+3 is in the form 6n+9, the difference is not an even number.

Does this graph show a function? Explain how you know.

Answers

Answer is (a.)
No it is not a function fails the vertical line test .

A function is only a function if it passes the vertical line test, meaning every x-value has only one y-value. In the case of this graph, it does not pass the vertical line tests and has multiple y-values for each x-value.

Correct Answer: A. No; the graph fails the vertical line test.

B is incorrect because y-values can have more than 1 x-value, such as a function like y = 2. The opposite is the correct statement; x-values can have no more than 1 y-value. For example, x = 2 would not pass the vertical line test.

Hope this helps!

Parametric equation of the line d: 4x-3y+17=0

Answers

Answer:

x = t/4 and y = (t+17)/3

Step-by-step explanation:

4x-3y+17=0

or, 4x=3y-17

let, 4x = t

so, x = t/4

and 3y-17 = t

or, 3y = t+17

or, y = (t+17)/3

Answered by GAUTHMATH

Please help solve for x

Answers

Answer:

8.49

Step-by-step explanation:

there is a little formula related to the famous formula of Pythagoras.

it says that the height of a triangle is the square root of the product of both segments of the baseline (the segments the height splits the baseline into).

so, x is actuality the height of the triangle.

x = sqrt(3×24) = sqrt(72) = 8.49

In an experiment, a student is to flip a quarter 10 times and record the number of times heads appears. A group of students performs the experiment 21 times, with these results.

6 4 5 6 5 6 4 6 2 4 3 4 5 7 5 8 7 5 3 5 5

Construct a dotplot with these data and then identify the dotplot you created.

Answers

Answer:

The average, mode, and median of the results are 5, meaning that half of the time the quarter will land on heads.

Step-by-step explanation:

The required dot plot shows the result of the experiment performed by flipping a quarter 21 times.


In an experiment, a student is to flip a quarter 10 times and record the number of times heads appears. A group of students performs the experiment 21 times, with these results. 6 4 5 6 5 6 4 6 2 4 3 4 5 7 5 8 7 5 3 5 5.


What is arithmetic?

In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication, and division,

What is Statistic?

Statistics is the study of mathematics that deals with relations between comprehensive data.

Here,
The dot plot has been made, for the number of outcomes and their frequencies. The dot plot gives the info about the mean mode and median.

Thus, the required a dot plot showing the result of the experiment performed by flipping a quarter 21 times.

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3(t-3)=5(2t+1) solve the following linear equations

Answers

Step-by-step explanation:

3(t-3)=5(2t-1)

= 3t-9=10t-5

= 3t-10t = -5+9

= -7t = 4

= -t = 4/7

= - 4/7 Answer

hope it helps

Answer 3(t-3) = 5(2t+1): t = -2
T= -2


Plz mark brainliest if it helps

I need help to Find the value of x. Round to
the nearest tenth.

Answers

Answer:

4.5

Step-by-step explanation:

We are given opposite and adjacent, so use tangent

tan(37)=x/6

6tan(37)=4.521324301

Match each equation to its graph. Use the drop-
down menus to describe the equations.

Answers

Answer:

D.  y=x+1                   Linear

A.   y=x^2                 Quadratic

B.   y=(3/2)^x             Exponential

C.   y=x^2+2/x^2-2    Rational

Step-by-step explanation:

got it right :)

The correct option for the equations are:

y=x+1 : Option Dy=x²: Option Ay=(3/2)ˣ: Option By=(x²+2)/(x²-2) : Option C

What is a linear equation?

The linear equation is an equation whose highest degree of the variable is 1 which represents the graph of the straight line.

For example y=2x+3

What is a quadratic equation?

The quadratic equation is an equation whose highest degree of the variable is 2 and it has at most 2 solutions.

For example, y=3x²

Here given that the functions are given in the figure and we have to identify the appropriate graph.

Checking all the equations individually

y=x+1 the correct option for this equation is Option D as it is a linear equation that represents a straight line.y=x² the correct option for this equation is Option A as it is a quadratic equation that represents a parabola.y=(3/2)ˣ the correct option for this equation is Option B as it is an exponential equation that represents an exponential graph such as the graph of y=aˣ.y=(x²+2)/(x²-2) the correct option for this equation is Option C as from the equation it is clear that it is symmetrical about the y-axis and it is negative for the value x²<2⇒ -√2<x<√2 which matches with the graph in Option D.

Therefore the correct option for the equations are:

y=x+1 : Option Dy=x²: Option Ay=(3/2)ˣ: Option By=(x²+2)/(x²-2) : Option C

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Patients in a hospital are classified as surgical or medical. A record is kept of the number of times patients require nursing service during the night and whether or not these patients are on Medicare. The data are presented here: Patient Category Medicare Surgical Medical Yes 46 52 No 36 43 Test the hypothesis (using ) that calls by surgical-medical patients are independent of whether the patients are receiving Medicare. Find to 2 decimal places the P-value for this test. The evidence Choose the answer from the menu in accordance to the question statement sufficient to claim that surgical-medical patients and Medicare status are dependent.

Answers

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Given:

[tex]N= 177\\\\a=46\\\\b=52\\\\c=36\\\\d=43[/tex]

[tex]\to \chi _{1}^{2}=\frac{N(ad-bc)^{2}}{(a+c)(b+d)(a+b)(c+d)}[/tex]

         [tex]=\frac{177((46\times 43)-(52 \times 36))^{2}}{(98)(79)(82)(95)}\\\\=\frac{177((1978)-(1872))^{2}}{60310180}\\\\=\frac{177(106)^{2}}{60310180}\\\\=\frac{177(11236)}{60310180}\\\\=\frac{1988772}{60310180}\\\\= 0.032976[/tex]

P-value= [tex]CHIDIST(0.032976,1) = 0.86.[/tex]

thus, the surgical-medical patients and Medicare are dependent.

8x(x-2017)-2x+4034=0

Answers

Answer:

¼ và 2017

Step-by-step explanation:

if 2/5 of the sweets in a bag is 60, how
many sweets would represent 1/3

Answers

Answer:

50 Candy

Step-by-step explanation:

We know that 2/5 of the bag is 60 candy. By taking this information we can conclude that 1/5 of the bag is 30 candy. We know that 1/5 of the bag is 30, so 30 times 5 is 150 candy.

Now that we have found out that there is 150 candy total we can know divde 150 by 3 to find out how much candy is in 1/3 of the bag.

150/3 = 50 Candy

1/3 of the bag represent 50 candy.

Instructions: Find the missing side of the triangle.
24 and 7

Answers

We can use the Pythagorean theorem to solve this. The Pythagorean theorem is a^2 + b^2 = c^2. We already have a and b, we need to find c. 24^2 + 7^2 is 625. Then, we need to find the square root of 625 to find c. The answer is 25. x = 25.

If 24 and 7 are the lengths of the legs of the right triangle, the missing side, which is the hypotenuse, has a length of 25.

To find the missing side of the triangle, we need more information about the triangle. Specifically, we need to know which side is missing: the hypotenuse (longest side) or one of the legs.

If 24 and 7 are the lengths of the legs of a right triangle, we can use the Pythagorean theorem to find the length of the hypotenuse.

The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs.

Let's label the hypotenuse as 'c' and the legs as 'a' and 'b'.

Using the Pythagorean theorem:

[tex]c^2 = a^2 + b^2[/tex]

Substituting the given values:

[tex]c^2 = 24^2 + 7^2\\c^2 = 576 + 49\\c^2 = 625[/tex]

Taking the square root of both sides:

c = √625

c = 25

Therefore, if 24 and 7 are the lengths of the legs of the right triangle, the missing side, which is the hypotenuse, has a length of 25.

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Can someone please help me with my maths question​

Answers

Answer:

[tex]a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]

[tex]b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

[tex]\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}[/tex]

By expanding the expression, we get;

[tex]\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}[/tex]

Collecting like terms gives;

[tex]\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]

[tex]\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]

(b) The given expression is presented as follows;

[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4[/tex]

Therefore, we get;

[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}[/tex]

Collecting like terms gives;

[tex]x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )[/tex]

[tex]x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]

[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]

Find the midpoint given the endpoints (4,-10) (22,-4) Please do not use space when
typing in your answer

Answers

Answer: (13,-7)

Step-by-step explanation:

By using the formula [tex](x_{m},y_{m}) =(\frac{x_{1}+x_{2} }{2},\frac{y_{1}+y_{2} }{2} )[/tex]

[tex](x_{m},y_{m})\\[/tex] is the coordinates of the midpoint.

For finding the midpoint X variable do:

[tex](\frac{4+22}{2})=13[/tex]

For finding the midpoint Y variable do:

[tex]\frac{-10+(-4)}{2} = -7[/tex] (you can either keep the parenthesis or take them out. Either way, the answer is the same.

Considering coordinate numbers follow the format: (x,y), you'll simply just substitute the numbers found above into their respective places.

x: 13

y: -7

(13,-7).

Hey I’m having trouble finding out how to divide fractions

Answers

The first step to dividing fractions is to find the reciprocal (reverse the numerator and denominator) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators. Finally, simplify the fractions if needed.

Find the third term of (x^2 + 2)^4.

Answers

Answer:

Step-by-step explanation:

[tex]in~the~expansion~of~(x+a)^n\\T_{r+1}=ncr x^{n-r}a^r\\r+1=3\\r=3-1=2\\n=4\\4c2=\frac{4 \times 3}{2 \times 1} =6\\T_{2}=4(x^2)^{4-2}(2)^2\\=16(x^2)^2\\=16x^4[/tex]

the third term is: 24*x^4

We want to find the third term of the equation:

(x^2 + 2)^4

So we need to expand that.

Remember the rule:

(a + b)^2 = a^2 + 2*a*b + b^2

(a + b + c)^2 = a^2 + b^2 + c^2 + 2*a*b + 2*b*c + 2*c*a

Then we can write:

(x^2 + 2)^4 = (x^2 + 2)^2*(x^2 + 2)^2

and we have:

(x^2 + 2)^2 = (x^4 + 2*2*x^2 + 2^2) = (x^4 + 4*x^2 + 4)

Then we have:

(x^2 + 2)^4 = (x^2 + 2)^2*(x^2 + 2)^2

(x^2 + 2)^4 = (x^4 + 4*x^2 + 4)^2

And we can expand this as:

(x^4)^2 + (4*x^2)^2 + 4^2 + 2*(x^4)*(4*x^2) + 2*(4*x^2)*(4) + 2*(x^4)*(4)

now we have this expanded, so we need to simplify this:

x^8 + 16*x^4 + 16 + 8*x^6 + 32*x^2 + 8*x^4

Putting the terms in order (larger degrees go in the left) we get:

x^8 + 8*x^6 + 16*x^4 + 8*x^4 + 32*x^2 + 16

x^8 + 8*x^6 + (16 + 8)*x^4 + 32*x^2 + 16

x^8 + 8*x^6 + 24*x^4 + 32*x^2 + 16

So the third term would be the third counting from the left, which is:

24*x^4

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You start at (1, 6). You move up 1 unit and right 7 units. Where do you end?

Answers

Answer:

(8,7)

Step-by-step explanation:

Because our x-value for this ordered pair is 1, and it says to move to the right 7 units, 1+7 = 8. Therefore, our x-value for the ordered pair would be 8.

Because our y-value for this ordered pair is 6, and it says to move up 1 unit, 6+1=7. Therefore, our y-value for the ordered pair would be 7.

Once we have our x- and y-value, we can set up the ordered pair:

(8,7)

Answer:

(7, 8)

Step-by-step explanation:

In the picture below, when the point is moved up, it only changes the y part of the point, and the x part is kept the same. When the point is moved right by 7 units, the x part is changed while the y part is kept the same.

Hope this helps.

Solve 4 sinx + 9 cosx=0 for 0° ​

Answers

4 sin(x) + 9 cos(x) = 0

4 sin(x) = -9 cos(x)

tan(x) = -9/4

x = arctan(-9/4) + … … … (in radians)

or

x = arctan(-9/4) + 180n ° … … … (in degrees)

where n is any integer.

I'm guessing you're solving for x over some domain, probably 0° ≤ x < 360°. In that case, you would have two solutions for n = 1 and n = 2 of

x ≈ 113.96°   and   x ≈ 293.96°

what is the total cost

Answers

Answer:

Step-by-step explanation:

We need to first find the perimeter of this oddly-shaped rink. We have a rectangle for which we are enclosing 3 of its sides, and the fourth "side" is a half-circle. Let's find the perimeter (or circumference) of the circle, divide it in half because we have half a circle, then add in the remaining 3 sides from the rectangle, shall we?

C = πd. The diameter of the circle is the same as the shorter length in the rectangle, 26. Therefore,

C = (3.14)(26) so

C = 81.64 m for a whole circle, and for half of that circle, the circumference is

C = 40.82 m

Now we can find the perimeter of the rink:

40.82 + 61 + 26 + 61 = p so

p = 188.82 m

If the fencing costs $6.20 per meter and we have 188.82 m, then the total cost is

[tex]cost=\frac{6.20dollars}{meter}*188.82meters[/tex]. The label "meter" cancels out, leaving us with

cost = $1170.82

I need help to find W =

Answers

Answer:

120

Step-by-step explanation:

Since the figures are similar the angles are the same

<A = <F

<B = <E

<C = <C

<D = <G

We know <G = 120 so angle D = 120

W = <D = 120

Answer:

w = 120 degrees

Step-by-step explanation:

ABCD and FECG are the same shapes, which means they also have the same angles.

∠A = ∠F

∠B = ∠E

∠C = ∠C

∠D = ∠G

∠G = 120°, so D = 120°

So, w = 120°

16 + 28 = ___ ´ (4 + 7).

Answers

Answer:

Solution given:

16+28=44

(4+7)=11

Answer:

The solution is 4

Step-by-step explanation:

Step 1:  Find the correct answer

I'm not really sure what you are asking but I will give it a shot.

16 + 28 = ___ (4 + 7)

44 = ___ (11)

44 / 11 = ___ (11) / 11

4 = ___

Answer:  The solution is 4

f(x) = 5x + 2x^2-7x+4
g(x) =3x-7
find (f+g)(x)

Answers

Answer:

(f+g)(x)=5x+2x²-7x+4+3x-7 = 2x²+x-3

Step-by-step explanation:

Answer:

=6x^3-20x^2+26x-28

Step-by-step explanation:

the width of a rectangle is twice as long as the length. if the length is increased by 50% and the width is decreased by 20%, the perimeter becomes 248. find the width and length of the original rectangle.
will give brainliest to correct answer

Answers

Answer:

Step-by-step explanation:

I answered your question in #24317186. Apparently you asked it twice and no one helped you yesterday.

The sum of three numbers is 78. The second number is 10 more than the first, and the third number is two times the second number.

1. Write an equation that will help you determine the 3 numbers.
2. Solve the equation showing all your steps.
3. Tell what the 3 numbers are.

Answers

Step-by-step explanation:

a+b+c=78

b=10+a

c=2b

then, we back the first

a+10+a+2b=78

2a+2b=78- 10

2a+2(10+a)=68

2a+2a=48

4a=48

a=12

b=22

c=44

If (3x2 + 22x + 7) ÷(x + 7) = 3x + 1, then (x + 7)( ) = . The check of the polynomial division problem shows that the product of two polynomials is a polynomial. This supports the fact that the property is satisfied for polynomial multiplication.

Answers

Answer:

[tex](x + 7) * (3x + 1) = (3x^2 + 22x + 7)[/tex]

Step-by-step explanation:

Given

[tex](3x^2 + 22x + 7) \div (x + 7) = 3x + 1[/tex]

[tex](x + 7) * (\ ) = [\ ][/tex]

Required

Complete the blanks

We have:

[tex](3x^2 + 22x + 7) \div (x + 7) = 3x + 1[/tex]

Rewrite as:

[tex]\frac{(3x^2 + 22x + 7) }{ (x + 7)} = 3x + 1[/tex]

Cross multiply

[tex](x + 7) * (3x + 1) = (3x^2 + 22x + 7)[/tex]

Answer:

Answer B, C, C

Other Questions
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