Answer:
(i) 3.438159 kg
(ii) 5.336803297 cm
Step-by-step explanation:
the external diameter = 12 cm, => the radius = 6 cm.
the internal diameter = 12 - 2×2 = 8 cm, radius = 4 cm.
I assume the mass of 1 cm³ (not cm) is 5.4 g (very, very light metal).
the material is in the volume of external sphere minus internal (empty) sphere.
the volume of a sphere is
4/3 × pi×r³
V-e = 4/3 × pi×6³ = 4/3 × pi×216 = 4×pi×72 = 904.7786842 cm³
V-i = 4/3 × pi×4³ = 4/3 × pi×64 = 268.0825731 cm³
V-e - V-i = 4/3 × pi×(216-64) = 4/3 × pi×152 = 636.6961111 cm³
1cm³ = 5.4g
636.6961111 cm³ = 5.4×636.6961111 = 3438.159g = 3.438159 kg
for (ii) we need to work with the volume of the material and calculate backwards to find the radius of the sphere with the full volume of that size.
636.6961111 = 4/3 × pi×r³ = 4/3 × pi×152
152 = r³
r = 5.336803297
Deion is saving up to buy a new phone. He already has $95 and can save an additional $7 per week using money from his after school job. How much total money would Deion have after 6 weeks of saving? Also, write an expression that represents the amount of money Deion would have saved in w weeks.
The expression that represents the amount of money Deion would have saved in w weeks is 95 + 7w and the total savings after 6 weeks will be $137.
What is an expression?A statement expressing the equality of two mathematical expressions is known as an equation.
A mixture of variables, numbers, addition, subtraction, multiplication, and division are called expressions.
An expression is a mathematical proof of the equality of two mathematical expressions.
As per the given,
Initial fixed money = $95
Per week saving $7/week
Total money = fixed money + money in w weeks.
⇒ 95 + 7w
For 6 weeks, w = 6
⇒ 95 + 7× 6 = $137.
Hence "The expression that represents the amount of money Deion would have saved in w weeks is 95 + 7w and the total savings after 6 weeks will be $137".
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richu and Deepu two students of a Vidyalaya contribute to charity the contribution of richu is 3/5 of the contribution of Deepu write a linear equation according to the above statement and draw the graph
please help, will give brainliest!!!
Answer:
Find the domain by finding where the equation is defined.
Interval Notation:
(−∞,−4)∪(−4,7)∪(7,∞)
Set-Builder Notation:
{x|x≠−4,7}
Step-by-step explanation:
Answer:
all real numbers except x=-4 or x = 7
Step-by-step explanation:
The domain is the numbers that x can take
We have restrictions for this problem
the denominator cannot be zero
x^2 -3x-28 cannot be zero
(x-7)(x+4) ≠ 0
x-7≠0 x+4≠0
x≠7 x≠-4
Otherwise all real numbers are valid
there are 10 marbels in a bag, 4 are multi colored and 6 are solid. what is the probability of picking a solid marble and then another solid marble without replacing the first marble?
Answer:
(2/5) * (3/4) = 3/10 = 0.3
PLEASE ANSWER FAST
The solution set x s2 or x> 4 is consistent with an equation of the form
Answer:
yes
Step-by-step explanation:
it is not correct I think
Sitting on a park bench, you see a swing that is 100 feet away and a slide that
is 60 feet away. The angle between them is 30°.
distance between the swing and the slide?
What is the approximate
Answer:
50
Step-by-step explanation:
Answer:
The approximate between the swing and slide is 56.21 feet.
Step-by-step explanation:
It's estimated that 330 billion photographs are taken each year. If there are 6.9
billion people in the world, how many photos on average is that per person?
Calculus!
The volume of a substance, A, measured in cubic centimeters increases according to the exponential growth model dA/dt = 0.3A, where t is measured in hours. The volume of another substance, B, also measured in cubic centimeters increases at a constant rate of 1 cm^3 per hour according to the linear model dB/dt = 1. At t = 0, substance A has a volume A(0) = 3 and substance B has size B(0) = 5. At what time will both substances have the same volume?
Would it be correct to write the growth model of substance B as x + 5? And how could I write the growth model of substance A? Thank you in advance, and sorry for the poor formatting.
Answer:
The two substances will have the same volume after approximately 3.453 hours.
Step-by-step explanation:
The volume of substance A (measured in cubic centimeters) increases at a rate represented by the equation:
[tex]\displaystyle \frac{dA}{dt} = 0.3 A[/tex]
Where t is measured in hours.
And substance B is represented by the equation:
[tex]\displaystyle \frac{dB}{dt} = 1[/tex]
We are also given that at t = 0, A(0) = 3 and B(0) = 5.
And we want to find the time(s) t for which both A and B will have the same volume.
You are correct in that B(t) is indeed t + 5. The trick here is to multiply both sides by dt. This yields:
[tex]\displaystyle dB = 1 dt[/tex]
Now, we can take the integral of both sides:
[tex]\displaystyle \int 1 \, dB = \int 1 \, dt[/tex]
Integrate. Remember the constant of integration!
[tex]\displaystyle B(t) = t + C[/tex]
Since B(0) = 5:
[tex]\displaystyle B(0) = 5 = (0) + C \Rightarrow C = 5[/tex]
Hence:
[tex]B(t) = t + 5[/tex]
We can apply the same method to substance A. This yields:
[tex]\displaystyle dA = 0.3A \, dt[/tex]
We will have to divide both sides by A:
[tex]\displaystyle \frac{1}{A}\, dA = 0.3\, dt[/tex]
Now, we can take the integral of both sides:
[tex]\displaystyle \int \frac{1}{A} \, dA = \int 0.3\, dt[/tex]
Integrate:
[tex]\displaystyle \ln|A| = 0.3 t + C[/tex]
Raise both sides to e:
[tex]\displaystyle e^{\ln |A|} = e^{0.3t + C}[/tex]
Simplify:
[tex]\displaystyle |A| = e^{0.3t} \cdot e^C = Ce^{0.3t}[/tex]
Note that since C is an arbitrary constant, e raised to C will also be an arbitrary constant.
By definition:
[tex]\displaystyle A(t) = \pm C e^{0.3t} = Ce^{0.3t}[/tex]
Since A(0) = 3:
[tex]\displaystyle A(0) = 3 = Ce^{0.3(0)} \Rightarrow C = 3[/tex]
Therefore, the growth model of substance A is:
[tex]A(t) = 3e^{0.3t}[/tex]
To find the time(s) for which both substances will have the same volume, we can set the two functions equal to each other:
[tex]\displaystyle A(t) = B(t)[/tex]
Substitute:
[tex]\displaystyle 3e^{0.3t} = t + 5[/tex]
Using a graphing calculator, we can see that the intersect twice: at t ≈ -4.131 and again at t ≈ 3.453.
Since time cannot be negative, we can ignore the first solution.
In conclusion, the two substances will have the same volume after approximately 3.453 hours.
Tameeka tells Marcus, "When you add 16 to my mystery number then subtract 20, you get the same result as when you add my mystery number to itself, then add 20 and subtract 16.” What is Tameeka’s mystery number?
Write and solve an equation to represent this situation.
Answer:
-8.
Step-by-step explanation:
x + 16 - 20 = 2x + 20 - 16
x - 4 = 2x + 4
x - 2x = 4 + 4
-x = 8
x = -8.
The mystery number 'm' that satisfies the stated conditions is - 8.
What is a numerical expression?A numerical expression is a mathematical statement written in the form of numbers and unknown variables. We can form numerical expressions from statements.
Let, The mystery number be 'm'.
So, When you add 16 to my mystery number then subtract 20,
m + 16 - 20,
you get the same result as when you add my mystery number to itself, then add 20 and subtract 16,
m + m + 20 - 16.
Therefore,
m + 16 - 20 = m + m + 20 - 16
m - 4 = 2m + 4.
- m = 8.
m = - 8.
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The figure below is a square. Find the length of side x in simplest radical form with a rational denominator.
9514 1404 393
Answer:
x = (√2)/2
Step-by-step explanation:
The diagonal is √2 times the side length (x), so ...
1 = x√2
√2 = 2x . . . . . multiply by √2
(√2)/2 = x . . . . divide by 2
The side length x is (√2)/2.
EFGH is an isosceles trapezoid and EFGI is a parallelogram. If m∠IEF = 36°, then m∠HGI = ° (Blank 1).
The base angles of an isosceles trapezoid are equal; For EFGI to be a parallelogram, the measure of [tex]\angle HGI[/tex] is: 108 degrees
Given that:
[tex]\angle IEF = 36^o[/tex]
IEF and GHI are the base angles of the trapezoid.
So:
[tex]\angle GHI = \angle IEF = 36^o[/tex]
Also:
[tex]\triangle GHI[/tex] is an isosceles triangle.
This means that:
[tex]\angle GHI = \angle HIG = 36^o[/tex] --- base angles of an isosceles triangle
So:
[tex]\angle GHI + \angle HIG + \angle HGI = 180[/tex] --- sum of angles in a triangle
Substitute known values
[tex]36 + 36+ \angle HGI = 180[/tex]
[tex]72 + \angle HGI = 180[/tex]
Collect like terms
[tex]\angle HGI = 180-72[/tex]
[tex]\angle HGI = 108[/tex]
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I can't figure this out, please help! I'll give a brainliest
Answer:
u can use pythagoras or sine rule
Step-by-step explanation:
cos-1(9/11)
Find the length of the third side. If necessary, round to the nearest tenth.
16
12
Answer:
Submit Answer
PLS HELP ASAP
Answer:
I think 16.
Step-by-step explanation:
because 12 is impossible and last answer is 16.
Answer:
the third side will be √500
Step-by-step explanation:
[tex]\sf{}[/tex]
using PGT
(16)²+(12)²=H²
=> 256+144 = H²
=> 500 = H ²
=> √500 = H
Review the graph of function g(x).
Which point is on the graph of the inverse function g^-1(x)?
O (-3,0)
O (0,-3)
O (2,3)
O (3,4)
Answer:
A
Step-by-step explanation:
I did the wrong thing. I inverted the graph. That's not the question. The question is which one of the following is on the inverse of the graph. That means that x and y are interchanged. The answer you gave was the second best answer. The answer is (-3,0) which is A.
Find the error in the student's work. Which of the following steps is where the first error occurred?
f(x) = -3x^2 - 2x
Step 1: f(-2) = -3(2)^2 - 2(-2)
Step 2: f(-2) = -3(4) + 4
Step 3: f(-2) = -12 + 4
Step 4: f(-2) = -8
Step 3 should be 12 + 4.
Step 2 should be -3(-4).
O Step 1 should have a -2 substituted for both values.
Answer:
Step 1 should have a -2 substituted for both values.
The slope of the line below is -0.25. Write the equation of the line in point-
slope form, using the coordinates of the labeled point. Do not use parenthesis
on the y side.
Consider the function ƒ(x) = x2. Which of the following functions shifts ƒ(x) downward 5 units and to the right 3 units?
A)
ƒ(x) = (x – 5)2 – 3
B)
ƒ(x) = (x – 3)2 – 5
C)
ƒ(x) = (x + 3)2 – 5
D)
ƒ(x) = (x – 5)2 + 3
Answer:
B
Step-by-step explanation:
f(x)=(x+3)2 3 units to the left
f(x)=(x-3)2 3 units to the right
f(x)=(x)2+5 upward 5 units
f(x)=(x)2-5 downward 5 units
The length of a rectangular field is 6 metres longer than its width. If the area of the field is 72 square metres, What are the width and the length of the field?
Answer:
Let's call the length of the field "l", and the width of the field "w".
If the area of the field is 72 square meters, then we have:
l x w = 72
And if the length is 6 meters longer than the width, we have:
l = w+6
So looking at the first equation (l x w = 72), we can substitute the l for a w+6.
And we obtain:
(w+6) x (w) = 72
Which simplifies to w^2 + 6w = 72.
This quadratic equation is pretty easy to solve, you just need to factor it.
w^2 + 6w - 72 = 0
(w-6)(w+12)
This leaves the roots of the quadratic equation to be 6 and -12, but in this case, a width of -12 wouldn't make sense.
So, the width of the rectangular field is 6, and the length of the field is 12.
Let me know if this helps!
Answer:
we assume one side is x and other side must be x+6 and when we multiple it together we can find x²+6x =72
Step-by-step explanation:
one side is 6 and. other is 12 so the lenght= 12 the width=6
Does 8in to 1ft reduce it or enlarge it
Answer:
enlarge it
Step-by-step explanation:
I ft = 12 inches
Thus 8 in → 12 in makes the transformation larger.
Thus going from 8 in to 12 in is an enlargement
please help me Find DE.
Answer:
DE = 11
Step-by-step explanation:
DF = DF +EF
4x+2 = x+7 + 7
Combine like terms
4x+2 = x+14
Subtract x from each side
4x+2-x = x+14-x
3x+2 = 14
Subtract 2 from each side
3x+2-2 =14-2
3x=12
Divide by 3
3x/3 = 12/3
x = 4
DE = x+7 = 4+7 =11
Answer:
DE is 11
Step-by-step explanation:
[tex]DE = DF - EF \\ DE = (4x + 2) - 7 \\DE = 4x - 5 [/tex]
But for x:
[tex]4x + 2 = (x + 7) + 7 \\ 4x + 2 = x + 14 \\ 3x = 12 \\ x = 4[/tex]
Therefore:
[tex]DE = (4 \times 4) - 5 \\ = 16 - 5 \\ = 11[/tex]
Using the Factor Theorem, which of the polynomial functions has the zeros 2, radical 3 , and negative radical 3 ?
f(x)= x3 - 2x2 - 3x + 6
f(x)= x3 - 2x2 + 3x + 6
f(x)= x3 + 2x2 - 3x + 6
f(x)= x3 + 2x2 - 3x - 6
Using the factor theorem, it is found that the polynomial is:
[tex]f(x) = x^3 - 2x^2 - 3x + 6[/tex]
Given by the first option
---------------------------
Given a polynomial f(x), this polynomial has roots [tex]x_{1}, x_{2}, x_{n}[/tex] using the factor theorem it can be written as: [tex]a(x - x_{1})*(x - x_{2})*...*(x-x_n)[/tex], in which a is the leading coefficient.
---------------------------
In this question:
[tex]x_1 = 2[/tex][tex]x_2 = \sqrt{3}[/tex][tex]x_3 = -\sqrt{3}[/tex]By the options, leading coefficient [tex]a = 1[/tex]Thus:
[tex]f(x) = (x - 2)(x - \sqrt{3})(x + \sqrt{3})[/tex]
[tex]f(x) = (x - 2)(x^2 - 3)[/tex]
[tex]f(x) = x^3 -2x^2 - 3x + 6[/tex]
Which is the polynomial.
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What is a negative rational number times a positive integer?
A) A negative integer
B) A positive rational number
C) A negative rational number
D) An irrational number
Answer:
C
Step-by-step explanation:
The product of a negative rational number and a positive integer is a negative rational number
Answer: C (A Negative Rational Number)
Step-by-step explanation
A Negative number mutiplied by a positive number is a negative number.
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95°
6rº + 47°
r_ degrees
Answer:
r = 8°
Step-by-step explanation:
95° = 6r° + 47° ( vertically opposite angles are equal)
6r° = 95° - 47°
6r = 48°
r = 48°/6
r = 8°
Answer: r = 8
Step-by-step explanation:
The angles a VOA vertically opposite angles which means they are congurent and equal
6r + 47 = 95
6r = 95 - 47
6r = 48
r = 48/6
r = 8
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find the product using formula (a+b) (a-b) = a square + b square a.61×59. Note: Solve by using formula.
Answer:
[tex]\huge\boxed{\sf 3599}[/tex]
Step-by-step explanation:
= 61 × 59
You can write 61 = 60 + 1 and 59 = 60 - 1
Hence,
= ( 60 + 1 ) ( 60 - 1 )
According to the formula:
[tex](a+b)(a-b) = a^2-b^2[/tex]
= (60)² - (1)²
= 3600 - 1
= 3599
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807Peace!PLEASE HELP!!!
What is the overlap of Data Set 1 and Data Set 2?
A.) high
B.) moderate
C.) low
D.) none
Step-by-step explanation:
Step by step explanation, The answer is C
[tex]Evaluate \: the \: following \\ (1) \: log1000 \: \\ (2) ( \frac{128}{625} ) \\ (3) log {x}^{2} {y}^{3} {z}^{4} \\ (4) log \frac{ {p}^{2} {q}^{3} }{r} \\ (5) log \sqrt{ \frac{ {x}^{3} }{ {y}^{2} } } [/tex]
[tex]If \: {x}^{2} + {y}^{2} = 25xy. \\ Then \: prove \: that \: \\ 2 log(x + y) = \\ 3 log3 + logx + logy. \: [/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \: \:I \: need \: the \: answer \\ \: \: \: \: \: \: \: \: \: \: \: \: Plz \: fastly \: [/tex]
I need ans !!!!!
Step-by-step explanation:
log1000= log 10³= 3 log10 =3log(128/625)= 7 log 2+ 4 log 5log x²y³z⁴= 2 logx + 3 log y + 4 log zlog p²q³/r= 2 log p +3 log q - log rlog√(x³/y²)=3/2[ log (x)] - log yx²+y²=25xy
(x+y)²-2xy=25xy
(x+y)²= 2xy +25 xy
=27xy
Take log on both sides
2 log(x+y) =log 27 + log x + log y
=log 3³+ log x + log y
2 log(x+y)=3 log 3 + log x + log y
Answer:
(1)
log 1000 = log 10³ = 3 log 10 = 3(2) It should be with log? If yes ignore log x and consider the right side
(128/625) = xlog x = log (128/625)log x = log 128 - log 625log x = 7 log 2 - 4 log 5(3)
log (x²y³z⁴) = log x² + log y³ + log z⁴ = 2 log x + 3 log y + 4 log z(4)
log (p²q³/r) = log p² + log q³ - log r = 2 log p + 3 log q - log r(5)
log [tex]\sqrt{\frac{x^3}{y2} }[/tex] = 1/2 log [tex]x^3y^{-2}[/tex] = 3/2 log x - log y(6)
x² + y² = 25xyx² + 2xy + y² = 27xy(x + y)² = 27xylog (x + y)² = log (27xy)2 log (x + y) = log 3³+ log x + log y2 log (x + y) = 3 log 3 + log x + log yProvedWhat would your position on the circle (cos q, sin q) be after rotating 72degrees from the point (1,0)?
A=(.97, .25)
B=(.31, .95)
C=(.95, .31)
D=(.25, .97)
Answer:
B=(.31, .95)
Step-by-step explanation:
When your at the point (1,0) you are at 0 degrees (cos 0, sen 0) = (1,0).
So at 72 degrees you moved 72 degrees (cos 72, sin 72) = (.31, .95)
URGENT!!!!
The value of a12 is:
2
0
1
can't be done
it's 1 beacuse the exponent has no power so its 1
The correct answer from the given matrix shows that the value of a12 is 1
What is a Matrix?This refers to a rectangular array of numbers that is arranged in rows and columns to indicate a mathematical property.
Hence, we can see that from the matrix given, we can see that there are different values for each one and to find a12, we can see that because there is no power in the exponent, the answer is 1.
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1. Write an algebraic expression for the following word phrase: the quotient of r and 12. (1 point)
Or. 12
Or+12
Or-12
Or- 12
The answer is Or + 12
please help you can answer it by saying something like option 3 or option 2 that would be ok
Answer:
maby option 5
Step-by-step explanation:
