Answer:
percentage yield = 63%
Explanation:
The yield efficiency or percentage yield measure the amount of products that are formed from a given amount of reactant. For a percentage yield of 100, all the reactants are completely converted to product. Mathematically, the percentage yield is given by:
[tex]percentage\ yield = \frac{Actual\ yield}{expected\ yield} \times 100\\Actual\ yield = 10.08kg\\Expected\ yield= 16.00kg\\\\\therefore percentage\ yield = \frac{10.08}{16.00} \times 100 = 63 \%[/tex]
Air is saturated with water vapor at 35.0 oC and a total pressure of 1.50 atmospheres. If the molar flow rate of the dry air in this stream is 300 mols per minute, what is the molar flow rate of water vapor in the stream?
Answer:
11.541 mol/min
Explanation:
temperature = 35°C
Total pressure = 1.5 * 1.013 * 10^5 = 151.95 kPa
note : partial pressure of water in mixture = saturation pressure of water at T = 35°c )
from steam table it is = 5.6291 Kpa
calculate the mole fraction of H[tex]_{2}o[/tex] ( YH[tex]_{2}o[/tex] )
= 5.6291 / 151.95
= 0.03704
calculate the mole fraction of air ( Yair )
= 1 - mole fraction of water
= 1 - 0.03704 = 0.9629
Now to determine the molar flow rate of water vapor in the stream
lets assume N = Total molar flow rate
NH[tex]_{2}o[/tex] = molar flow rate of water
Nair = molar flow rate of air = 300 moles /min
note : Yair * n = Nair
therefore n = 300 / 0.9629 = 311.541 moles /min
Molar flowrate of water
= n - Nair
= 311.541 - 300 = 11.541 mol/min
An engineer designing a vibration isolation system for an instrument console models the consoleand isolation system as a 1 degree-of-freedom spring-mass-damper system. The modeled mass is 2kg, the spring constant is 8 N/m, and the damping constant is 1 Ns/m. The system is exposed to atime-varying force acting on the mass. This force measured is approximated by:F(t) = 20 sin(4t) [N]. Determine the steady-state response of the system to this input.
Solution :
Given :
m = 2 kg
k = 8 N/m
C= 1 N-s/m
F(t) = 20 sin (4t)
[tex]$F_0= 20 \ N$[/tex]
ω = 4 rad/s
[tex]$\omega_n = \sqrt{\frac{k}{m}}$[/tex]
[tex]$\omega_n = \sqrt{\frac{8}{2}}$[/tex]
= 2 rad/s
Therefore,
[tex]$\epsilon = \frac{C}{2 m \omega_n}$[/tex]
[tex]$\epsilon = \frac{1}{2 \times 2 \times 2}$[/tex]
= [tex]$\frac{1}{8}$[/tex]
= 0.125
So, r = [tex]$\frac{\omega}{\omega_n}$[/tex]
= [tex]$\frac{4}{2}$[/tex]
= 2
Steady state response is given by
[tex]$(A)=\frac{F_0 / k}{\sqrt{(1-r^r)^2+(2 \epsilon r)^r}}$[/tex]
[tex]$(A)=\frac{20 / 8}{\sqrt{(1-2^r)^2+(2 \times 0.125 \times 2)^r}}$[/tex]
A = 0.82 m
Anything you want to do in Hootsuite can be found in the ________, with the main workspace in the _________?
Settings; Streams
Sidebar; center
Header; Sidebar
Nav-panel; dashboard
Answer:
Anything you want to do in Hootsuite can be found in the ___ Sidebar_____, with the main workspace in the ___center______
Sidebar; center
Explanation:
The main workspace of the Hootsuite is located in the center. The sidebar is where the core access to the Hootsuite functionality, like Streams, Inbox, Planner, Analytics, Publisher, and the App Directory, is obtained. Hootsuite is a media management platform for curating content, scheduling posts, managing team members, and measuring performances.
Waterjet cutting uses a _____. a) Very-small-diameter jet of water that exits the cutting nozzle at approximately the speed of sound. b) Diamond cutting wire cooled by a waterjet which also carries away the composite material as a slurry. c) Very-small-focused-stream of water that oscillates at 20,000 cycles per second.
Answer:
a
Explanation:
Waterjet cutting uses a very-small-diameter jet of water that exits the cutting nozzle at approximately the speed of sound. A water jet cutter, is oftentimes simply called a water jet is an industrial tool, like its name suggests, with the capabilities of cutting a different types of materials. Like its name suggests again, it uses water, although an extremely high-pressure jet of water to do the cutting. Other times, it uses a mixture of water and an abrasive substance to facilitate the cutting.
Una barca intenta cruzar un río. La barca lleva una velocidad de 3 m/s con dirección perpendicular a la de la velocidad del agua que es de 4 m/s. Si el ancho del río es de 120 m. El tiempo en llegar a la otra orilla es de:
Answer:
El tiempo que tarda la barca en llegar a la orilla es 40 s.
Explanation:
Debido a que el río se mueve en dirección perpendicular a la barca, ésta se va a mover de manera diagonal, cuya velocidad ([tex]v_{b_{d}}[/tex]) viene dada por:
[tex]|v_{b_{d}}| = \sqrt{v_{r}^{2} + v_{b}^{2}} = \sqrt{(4)^{2} + (3)^{2}} = 5 m/s[/tex]
Por lo tanto, el módulo del vector velocidad diagonal es 5 m/s, y su dirección es:
[tex]tan(\alpha) = \frac{v_{r}}{v_{b}} = \frac{4}{3}[/tex]
Entonces, α es:
[tex] \alpha = arctan(\frac{4}{3}) = 53.13 ^{\circ} [/tex]
Ahora, debemos encontrar la distancia de la longitud diagonal que recorre la barca:
[tex] cos(\alpha) = \frac{a}{d_{d}} [/tex]
[tex] d_{d} = \frac{a}{cos(\alpha)} = \frac{120 m}{cos(53.13)} = 200.0 m [/tex]
Finalmente, el tiempo que le tomaría a la barca recorrer 200 m sería:
[tex]v_{b_{d}} = \frac{d_{d}}{t}[/tex]
[tex] t = \frac{200 m}{5 m/s} = 40 s [/tex]
Por lo tanto, el tiempo que tarda la barca en llegar a la orilla es 40 s.
Espero que te sea de utilidad!
A resistor and a capacitor are connected in series across a 150 Vac supply. When
the frequency is 40 Hz the current is 5 A, and when the frequency is 50 Hz the
current is 6 A. Find the resistance and capacitance for the of the resistor and
capacitor respectively.
Explanation:
for 40hz
since they are in series they will have the same amper
so R=30ohm
C=30F
for 50Hz
R=25
C=25
brainiest and 35 points for the RIGHT ANSWER
Which of the following devices is used to determine if an item is horizontal?
a level
a lever
a shank
a clamp
Which of the following is NOT a peripheral?
Input devices
Output devices
CPU devices
Input/Output devices
Answer:
I believe that cpu devices are not considered peripherals
Explanation:
From google: A peripheral or peripheral device is an ancillary device used to put information into and get information out of the computer.
What are the two tools used to create an HTML code? Name one example of each tool.
Answer:
please mark me as BRAINLIEST
Explanation:
There are so many software packages available to develop HTML. The software packages can be grouped into two main categories: text-based (or code-based) editors.
...
WYSIWYG editors
Macromedia Dreamweaver.
Microsoft FrontPage.
Adobe GoLive.
Example 5 10, P 236 9th edition Refrigerant 134 a at 700 kPa , 70 deg C and 8 kg/min is cooled by water in a condenser until it exists as a saturated liquid at the same pressure. The cooling water enters the condenser at 300 kPa and 15 deg C and leaves at 25 deg C at the same pressure. Determine the mass flow rate of the cooling water required to cool the refrigerant.
Solution :
The mass flow rate of the cooling water is determined from the energy balance equation. The enthalpies of the refrigerant at the initial and the final states were obtained from A-13 and A-12 for the given parameters.
Therefore by energy balance equation,
[tex]$\dot m_r h_{r1}=\dot m_w \Delta h_w +\dot m_r h_{r2} $[/tex]
[tex]$\dot m_w = \frac{\dot m(h_1-h_2)_r}{c \Delta T}$[/tex]
[tex]$\dot m_w = \frac{8(308.34-88.82)}{4.18 \times 10}$[/tex]
= 42 kg / min
An electronic device, such as a power transistor mounted on a finned heat sink, can be modeled as a spatially isothermal object with internal heat generation and an external convection resistance. (a) Consider such system of mas M, specific heat c, and surface area As, which is initially in equilibrium with the environment at To. Suddenly, the electronic device is energized such that a constant heat generation Eg(W) occurs. Show that the temperature response of the device is: θ = exp RC where θ Ξ T-T(w): T(oo) is the steady-state temperature corresponding to t → oo; 0Ti T(; T: initial temperature of the device; R: thermal resistance 1/hAs; and C: thermal capacitance Mc. (b) An electronic device, which generates 60W of heat, is mounted on an aluminum heat sink weighing 0.31 kg and reaches a temperature of 100°C in ambient air at 20°C under steady- after the power is switched on?
Answer:
hello your question is incomplete attached below is the complete question
answer :
a) attached below
b) 63.71°c
Explanation:
A) Given data
The system has ; mass ( M ) , specific heat capacity , and surface area
attached below is a detailed solution
B) Given data
power generated = 60w
weight of heat sink = 0.31 kg
temperature given = 100°c
temp in ambient air = 20°c
lets take
specific heat capacity = 918.18 J /kg-k
density = 2702 kg/m^2
attached below is the detailed solution
The entropy of the working fluid of the ideal Carnot cycle (increases, decreases, remains the same) during the isothermal heat rejection process. (Explain the reasoning behind your answer selection!)
Answer:
Decreases
Explanation:
The Entropy change for a reversible process is;
ΔS = nRIn(V_b/V_a)
Now, applying this formula to an isothermal expansion in an irreversible process, it will have same initial and final states as we got for the reversible expansion process. Now, due to the fact that entropy is a state function, the change in entropy of the system will be the same as we got for the equation in reversible process and is given by the same formula.
In both the reversible and irreversible process, the surroundings of which they differ by the entropy there are usually at a constant temperature, T in a way that we have the change jn entropy relationship as;
ΔS_sur = −Q/T
Where;
- the negative sign is used since the heat transferred to the surroundings is equal in magnitude and opposite in sign to the heat, Q, transferred to the system.
Thus, it is clear that the change in the entropy decreases due to the negative sign.
