(−98)+(−97)+(−96) + ⋯ +(−1)+0+1+2+ ⋯ +98+99+100

Answer:

[tex]2p=348 cm\: S=6726 cm^{2}[/tex]

Step-by-step explanation:

Ciao, come stai?

1) Per prima cosa, dobbiamo trovare la misura della base più grande. Scomponendo la figura possiamo visualizzare un triangolo e un quadrato. Ci sono somiglianze con gli angoli. Quindi è un triangolo rettangolo. Applichiamo il teorema di Pitagora:

[tex]a^2=b^2+c^2\\95^2=b^2+76^2\\57=b[/tex]

2) Perimetro:

[tex]2p=60+57+76+60+95\\2p=348 cm[/tex]

3) L' area

[tex]\frac{(B+b)h}{2} =\frac{(117+60)76}{2} =6726 \:cm^{2}[/tex]

Answer:

1/6

Question: Scott made a casserole for dinner he gave equal portions of 1/2 the casserole to 3 friends what diagram could scott use to find the fraction of the whole casserole that each friend got?

Step-by-step explanation:

Find attached the diagram Scott used to find the portion each friend got.

The shaded part indicate the portion of the casserole.

When Scott prepared the dinner = 1 portion of casserole

He shared 1/2 the portion to 3 of his friends:

Divide the diagram of the full portion into 2 to get ½ of the casserole

1/2 of the casserole = ½ × 1 portion = ½ portion

Each of his 3 friends would have equal portions = ⅓ of the ½ portion

The diagram of the ½ portion would be divided into 3 equal part

In terms of calculation = ½ × ⅓

= 1/6

Each of his friends would have 1/6 portion of the casserole.

Hello! I provided the answer to your problem in a picture.

Ex. (3/6)

Answer:

The 95​% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

For this problem, we have that:

[tex]n = 185, \pi = \frac{100}{185} = 0.5405[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5405 - 1.96\sqrt{\frac{0.5405*0.4595}{185}} = 0.4687[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5405 + 1.96\sqrt{\frac{0.5405*0.4595}{185}} = 0.6123[/tex]

The 95​% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).

Answer:

c. 0.80

Step-by-step explanation:

Probability from relative frequency:

The probability is the number of desired outcomes divided by the number of total outcomes.

What is the probability that the next bus sold will be yellow or green?

250+150+100 = 500 buses sold

Of those, 250+150 = 400 are yellow or green.

400/500 = 0.8

So the correct answer is:

c. 0.80

Answer:

Answers are below in bold.

Step-by-step explanation:

The first answer is correct. 1 m² = 10,000cm²

A=2(wl+hl+hw)        To find the surface area of the package, use this equation

A=2(18*50+20*50+20*18)      Multiply in the parentheses

A=2(900+1000+360)             Add in the parentheses

A=2(2260)                              Multiply

A=4520

The package has a surface area of 4520 cm²

The area of the package is less than the area of the wrapping paper.

So, Dayson can completely cover the package with the wrapping paper.

Answer:

1/3

Step-by-step explanation:

The slope of a perpendicular line is always the negative reciprocal of the slope of the original line.

-1/-3 = 1/3

Answer:

x=4 and y = 12

Step-by-step explanation:

A diagonal of a parallelogram cuts the other diagonal in exactly 2 equal parts. So, we can say that x+12 = 16. That would give us x=4. And, we can say that 3y-14 = 22. If we solve for y, we get y = 12.

Answer:

[tex]x^{4} -11x^{2} +28[/tex]

Step-by-step explanation:

[tex](x^{2} -7)(x^{2} -4)[/tex]

[tex]x^{4} -4x^{2} -7x^{2} +28[/tex]

[tex]x^{4} -11x^{2} +28[/tex]

Answer:

y = -x + 3

Step-by-step explanation:

I graphed the equation on the graph below to show you that it goes through (-1,4) and is perpendicular to y = x.

Answer:

- Only Drawing D has KL being a symmetrical segment.

- Drawings A, B and C have no axis of symmetry.

- Tylko rysunek D ma KL będący segmentem symetrycznym.

- Rysunki A, B i C nie mają osi symetrii.

Step-by-step explanation:

English Translation

In which drawing was the symmetrical segment of KL drawn? Which of these letters has no axis of symmetry?

Solution

The attached image to the question is presented in the attached image to this Solution.

Symmetry is a concept where a figure/shape has half of its part being a mirror image of the other part.

About the line or axis of symmetry, the structure or figure can be rotated at right angles or whole number multiples of right angles and the resulting structure is still the same as the one we started with.

Of the 4 drawings, only drawing D satisfies this conditions/criteria. And Hence, it is the only drawing amongst the four with an axis of symmetry.

In Polish/Po polsku

Załączony obraz do pytania jest przedstawiony na załączonym obrazku do tego rozwiązania.

Symetria to koncepcja, w której figura / kształt ma połowę swojej części stanowiącą odbicie lustrzane drugiej części.

W odniesieniu do linii lub osi symetrii, strukturę lub figurę można obracać pod kątem prostym lub wielokrotności liczby całkowitej pod kątem prostym, a wynikowa struktura jest nadal taka sama jak ta, od której zaczęliśmy.

Z 4 rysunków tylko rysunek D spełnia te warunki / kryteria. I dlatego jest to jedyny rysunek wśród czterech z osią symetrii.

Hope this Helps!!!

Mam nadzieję że to pomoże!!!

Answer:

17000

Step-by-step explanation:

we can use the equation I=PRT

I=10,000(10)(0.07)

I=100,000(0.07)

i=7000

7000+ the initial 10,000=17000

Answer:

a) 0.6628 = 66.28% probability that at least 85 visitors had a recorded entry through the Beaver Meadows park entrance

b) 0.5141 = 51.41% probability that at least 80 but less than 90 visitors had a recorded entry through the Beaver Meadows park entrance

c) 0.5596 = 55.96% probability that fewer than 12 visitors had a recorded entry through the Grand Lake park entrance.

d) 0.9978 = 99.78% probability that more than 55 visitors have no recorded point of entry

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].

In this problem, we have that:

[tex]n = 175[/tex]

(a) What is the probability that at least 85 visitors had a recorded entry through the Beaver Meadows park entrance?

46.7% of visitors to Rocky Mountain National Park in 2018 entered through the Beaver Meadows. This means that [tex]p = 0.467[/tex]. So

[tex]\mu = E(X) = np = 175*0.467 = 81.725[/tex]

[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{175*0.467*0.533} = 6.6[/tex]

This probability, using continuity correction, is [tex]P(X \geq 85 - 0.5) = P(X \geq 84.5)[/tex], which is 1 subtracted by the pvalue of Z when X = 84.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{84.5 - 81.725}{6.6}[/tex]

[tex]Z = 0.42[/tex]

[tex]Z = 0.42[/tex] has a pvalue of 0.6628.

66.28% probability that at least 85 visitors had a recorded entry through the Beaver Meadows park entrance.

(b) What is the probability that at least 80 but less than 90 visitors had a recorded entry through the Beaver Meadows park entrance?

Using continuity correction, this is [tex]P(80 - 0.5 \leq X <  90 - 0.5) = P(79.5 \leq X \leq 89.5)[/tex], which is the pvalue of Z when X = 89.5 subtracted by the pvalue of Z when X = 79.5. So

X = 89.5

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{89.5 - 81.725}{6.6}[/tex]

[tex]Z = 1.18[/tex]

[tex]Z = 1.18[/tex] has a pvalue of 0.8810.

X = 79.5

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{79.5 - 81.725}{6.6}[/tex]

[tex]Z = -0.34[/tex]

[tex]Z = -0.34[/tex] has a pvalue of 0.3669.

0.8810 - 0.3669 = 0.5141

51.41% probability that at least 80 but less than 90 visitors had a recorded entry through the Beaver Meadows park entrance

(c) What is the probability that fewer than 12 visitors had a recorded entry through the Grand Lake park entrance?

6.3% of visitors entered through the Grand Lake park entrance, which means that [tex]p = 0.063[/tex]

[tex]\mu = E(X) = np = 175*0.063 = 11.025[/tex]

[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{175*0.063*0.937} = 3.2141[/tex]

This probability, using continuity correction, is [tex]P(X < 12 - 0.5) = P(X < 11.5)[/tex], which is the pvalue of Z when X = 11.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{11.5 - 11.025}{3.2141}[/tex]

[tex]Z = 0.15[/tex]

[tex]Z = 0.15[/tex] has a pvalue of 0.5596.

55.96% probability that fewer than 12 visitors had a recorded entry through the Grand Lake park entrance.

(d) What is the probability that more than 55 visitors have no recorded point of entry?

22.7% of visitors had no recorded point of entry to the park. This means that [tex]p = 0.227[/tex]

[tex]\mu = E(X) = np = 175*0.227 = 39.725[/tex]

[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{175*0.227*0.773} = 5.54[/tex]

Using continuity correction, this probability is [tex]P(X \leq 55 + 0.5) = P(X \leq 55.5)[/tex], which is the pvalue of Z when X = 55.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{55.5 - 39.725}{5.54}[/tex]

[tex]Z = 2.85[/tex]

[tex]Z = 2.85[/tex] has a pvalue of 0.9978

0.9978 = 99.78% probability that more than 55 visitors have no recorded point of entry

Answer:

The area of the large circle is 16π

The area of one small circle is 4π

The total area of the two small circles will be one-half of the area of the large circle

Step by step explanation:

Area if circle = πr²

area of one large circle with a diameter of 8:

r = diameter/2 = 8/2 = 4

Area = π×4² = 16π

total area of 2 smaller diameter one-half that of the large circle.

Area = πr²

Diameter of small circle = 1/2(bigger circle diameter)

Diameter = 8/2 = 4

radius = 4/2 = 2

Area of one small circle = π×(2)² = 4π

Total Area of Two smaller circles= 2(4π) = 8π

Area of two smaller circle = 1/2(area of bigger circle) = 1/2(16π) 8π

Therefore, based on the answer:

The area of the large circle is 16π

The area of one small circle is 4π

The total area of the two small circles will be one-half of the area of the large circle

Answer:

The area of the large circle is 16 pi.

The area of one small circle is 4 pi.

The total area of the two small circles will be one-half of the area of the large circle.

Step-by-step explanation:

To shorten this down for ya lazy people like me the answers are 1, 2, and 5!!!

I got this right on my UNit test review!!!!!

I hope this helps!!!!!!

Answer:

  9/8

Step-by-step explanation:

time A / time B = (3/2)/(4/3) = (3/2)(3/4) = (3·3)/(4·2)

time A / time B = 9/8

Answer:

Dimensions 30 in x 30 in x 15 in

Surface Area = 2,700 in²

Step-by-step explanation:

Let 'r' be the length of the side of the square base, and 'h' be the height of the bin. The volume is given by:

[tex]V=13,500=h*r^2\\h=\frac{13,500}{r^2}[/tex]

The total surface area is given by:

[tex]A=4*hr+r^2[/tex]

Rewriting the surface area function as a function of 'r':

[tex]A=4*\frac{13,500}{r^2} *r+r^2\\A=\frac{54,000}{r}+r^2[/tex]

The value of 'r' for which the derivate of the surface area function is zero, is the length for which the area is minimized:

[tex]A=54,000*r^{-1}+r^2\\\frac{dA}{dr}=0= -54,000*r^{-2}+2r\\\frac{54,000}{r^2}=2r\\ r=\sqrt[3]{27,000}\\r=30\ in[/tex]

The value of 'h' is:

[tex]h=\frac{13,500}{30^2}\\ h=15\ in[/tex]

The dimensions that will ensure the minimum surface area are 30 in x 30 in x 15 in.

The surface area is:

[tex]A=4*15*30+30^2\\A=2,700\ in^2[/tex]

Answer:

the graph of y=f(x)will shift up 9 units

Answer:

spinner green or blue

Step-by-step explanation:

Flipping a coin is 1/2 probability

Rolling a die and getting a number less than 4 is 1/2 probability

spinner green or blue is (4/6) = 2/3

Marbles is 1/2

Answer:

The margin of error for a 95% confidence interval for the population mean is of 1.05 years.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1-0.95}{2} = 0.025[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].

So it is z with a pvalue of [tex]1-0.025 = 0.975[/tex], so [tex]z = 1.96[/tex]

Now, find the margin of error M as such

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population(square root of the variance) and n is the size of the sample.

What is the margin of error for a 95% confidence interval for the population mean

36 students, so [tex]n = 36[/tex]

Variance of 10.24, so [tex]\sigma = \sqrt{10.24} = 3.2[/tex]

[tex]M = 1.96*\frac{3.2}{\sqrt{36}} = 1.05[/tex]

The margin of error for a 95% confidence interval for the population mean is of 1.05 years.

Answer:

[tex] r = -0.39[/tex]

And the determination coeffcient is just the correlation coeffcient square and we got:

[tex] R = r^2 = (-0.39)^2 =0.1521[/tex]

And rounded to the nearest tenth thousand would be 0.1521

Step-by-step explanation:

The correlation coefficient is a measure of variability and is given by this formula:

[tex]r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}[/tex]

For this case we have

[tex] r = -0.39[/tex]

And the determination coeffcient is just the correlation coeffcient square and we got:

[tex] R = r^2 = (-0.39)^2 =0.1521[/tex]

And rounded to the nearest tenth thousand would be 0.1521

Answer:

Step-by-step explanation:

Hello!

Given the variable

X: reading speed of a second-grader. (words per minute)

From a random sample of second-grader the mean and standard deviation were:

X[bar]= 31.6 words per minute

S= 2.4 words per minute

To study the population mean (μ) you have the following sampling scenarios and need to choose the correct statistic.

Sampling scenarios:

(1) The sample has size 100, and it is from a non-normally distributed population with a known standard deviation of 2.6.

For this scenario you have to remember the Central Limit Theorem. The variable of study has a non-normal distribution but the sample is large enough (As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation) you can approximate the distribution of the sample mean to normal: X[bar]≈N(μ;σ²/n); Then it is valid to use an approximation to the standard normal distribution to make inference statements about the population mean.

Statistic: Z

(2) The sample has size 75, and it is from a non-normally distributed population.

Same explanation as the statement before, except that the population variance is unknown. Since the distribution is already an approximation you can use its estimation (sample variance) for the statistic. (It would be less accurate than using the population variance but still valid)

Statistic: Z

(3) The sample has size 12, and it is from a population with a distribution about which we know very little.

To use a student's t the population needs to have a normal distribution, which is not the case, same goes for the standard normal.

To apply the central Limit Theorem you need a sample size equal or greater to 30, this is not the case.

For this sampling example neither distribution is applicable.

(4) The sample has size 14, and it is from a normally distributed population with a known standard deviation of 2.6.

The population has a normal distribution and the population standard deviation is known. The sample size is rather small but it isn't an impediment to apply the standard normal distribution. Also, even tough the population standard deviation is known, a student t is also applicable. In this case both statistics are a viable option.

Statistic: Z or t

(5) The sample has size 16, and it is from a normally distributed population with unknown standard deviation.

The population has a normal distribution, with unknown population standard deviation and the sample size is rather small. You can use a Student t to infer over the population mean.

Statistic: t

I hope this helps!

Answer:

Step-by-step explanation:

(35 units three times a day) comes out to (35 units / day)(3 times per day), or

105 units per day

Answer:

27.41%

Step-by-step explanation:

Data provided in the question

The staffed of Alpha company = 79%

The staffed of Beta company = 62%

Based on the above information, the relative change of staffing from Alpha to beta company is

As we know that

[tex]\bold {\ Relative \ change = \frac{\alpha- \beta }{\beta }}[/tex]

[tex]= \frac{(79 -62)}{62} \% \\\\= \frac{17}{62} \times 100\\\\=0.2741 \times 100\\\\=27.41\ \%[/tex]

By applying the above formula we can get the relative change and the same is to be applied so that the correct percentage could come

Answer:

Step-by-step explanation:

a) What is the population of interest?

The population of interest are college students

b) What is the population parameter of interest?

The population parameter is an average value on how currently enrolled students are placing into their current math class.

c) What is the sampling frame?

Identify currently enrolled students

d) Describe the sample.

The sample will be based on a representative sample that suit the administrators needs or specifically approach individuals with these certain characteristics.

e) What type of sampling method was used for this study?

Judgment or purposive sampling

f) Who was possibly left out of this study?

Answer:

P = 4/13

Step-by-step explanation:

In a deck of 52 cards, there are 3 aces(spade, heart, diamond), 1 club ace, and 12 remaining club cards

=> The probability of randomly drawing 1 card that is an ace card or a club card:

P = number of elements/total number of elements

P = (3 + 1 + 12)/52

P = 16/52

P = 4/13

=> Option A is correct

Answer:

AP = 10

Step-by-step explanation:

According to secant-secant theorem

(PB)(AP)=(PD)(PC)

6(AP) = (5)(12)

AP = 60/6

AP = 10

Answer:

10

Step-by-step explanation:

Applying the secant theorem, we get:

(PB) * (AP) = (PD) * (PC)

6 * (AP) = (5) * (12)

AP = 60/6

= 10

Hope this helps!

Answer:

y = 4.5x

Step-by-step explanation:

y=ax is form of proportional relationship

checking the first pair of numbers:

checking other lines

So the equation is:

Answer:

1) -4/5,3 Decimal form x= -0.8,3

2) ?

3)sq (x+2)(x+3)+sq x^2 +5x-4=0

Step-by-step explanation:

Hope this helps

Answer:

no solution

Step-by-step explanation:

4( − 11) = 15 − 4

-44 = 11

Since this iS FALSE, it means that the equation given has no solution

Answer:

Step-by-step explanation:

This is a test of the mean difference between 2 independent groups or populations.

Let μ1 be the mean annual bonus of Company A's employees and μ2 be the mean annual bonus of Company B's employees.

The random variable is μ1 - μ2 = difference in the mean annual bonus of Company A's employees and the mean annual bonus of Company B's employees

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 ≤ μ2 H0 : μ1 - μ2 ≤ 100

The alternative hypothesis is

H1 : μ1 > μ2 H1 : μ1 - μ2 > 100

This is a right tailed test because of the inequality sign at the alternative hypothesis. We need to take samples of annual bonuses from both company's employees and find the averages. Then we would determine the test statistic as well as the p value. We would use the p value with the level of significance to make decisions

Answer:

112 ounces

Step-by-step explanation:

Clay weighs 9 times as much as his baby sister .

Clay weighs 63 pounds.

His baby sister weigh 63/9.

His baby sister weighs 7 pounds.

But to be converted to ounce.

1 pound = 16 ounces

7 pounds = 7*16 ounces

7 pounds = 112 ounces