7 root 3 by 3 minus 3 root 2 by root 15 minus 3 root 2 minus 2 root 5 by root 6 + root 5 ​

dime: 5 cents

nickel: 10 cents

quarter: 25 cents

let's start with quarters, (2)

25 + 10 + 5

25 + 5 + 5 + 5

nickels, (4)

10 + 10 + 10 + 10

10 + 10 + 10 + 5 + 5

10 + 10 + 5 + 5 + 5 + 5

10 + 5 + 5 + 5 + 5 + 5 + 5

dimes, (1)

5 + 5 + 5 + 5 + 5 + 5 + 5 + 5

7 combinations.

hope it helps :)

Answer:

x = 6; y = -6

Step-by-step explanation:

-4x - 2y = -12

4x + 8y = -24

Add the two equations, so x is eliminated:

6y = -36

6y/6 = -36/6

y = -6

Plug in y, to solve for x

-4x - 2y = -12

-4x - 2(-6) = -12

-4x +12 = -12

-4x = -12 -12

-4x = -24

-4x/-4 = -24/-4

x = 6

Answer from Gauthmath

Answer:

Tedyxhcj eydyfhxrstetdhsawe

Answer:

45x=-44

x=-44/45

Step-by-step explanation:

is this a free question?

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Answer:

  B) (4,–1)

Step-by-step explanation:

A graph can help you figure this out. The point (4, -1) is in the doubly-shaded area, so is a solution to this system.

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Explanation:

Choice A can be ruled out because

[tex]y \le x+1\\\\5 \le 0+1\\\\5 \le 1\\\\[/tex]

which is false.

Choices C and D are similar, so they can be ruled out as well.

---------------------

Choice B is the answer because it makes both inequalities true.

If we plug the coordinates of (4,-1) into the first inequality, we get

[tex]y > -x\\\\-1 > -4[/tex]

which is a true statement because -1 is to the right of -4 on the number line.

Now try the other inequality

[tex]y \le x+1\\\\-1 \le 4+1\\\\-1 \le 5\\\\[/tex]

that's true also. So again, (4,-1) makes both inequalities true, and that's why choice B is the answer.

Explanation:

A = values on the die greater than 1

A = {2,3,4,5,6}

B = values on the die less than 5

B = {1,2,3,4}

Union those two sets together

C = A u B = {1,2,3,4,5,6}

Effectively, we get every possible value on the die. This is due to the "or" keyword. If it was "and", then it would be a difference story.

So the probability of getting anything in set C is 100% or just 1. We have guaranteed certainty we'll have this event happen.

Answer:

[tex]x = \frac{5}{2}[/tex]

Step-by-step explanation:

Step 1:  Find an equivalent fraction

[tex]\frac{1}{4} = \frac{x}{10}[/tex]

[tex]4(x) = 1(10)[/tex]

[tex]4x = 10[/tex]

[tex]x = \frac{10}{4}[/tex]

[tex]x = \frac{5}{2}[/tex]

Answer:  [tex]x = \frac{5}{2}[/tex]

Answer:

x = 19.2

Step-by-step explanation:

tan(58)=x/12

x=12×tan(58)

x=19.2

Answered by GAUTHMATH

Answer:

[tex]\frac{\sqrt{2} }{2}[/tex]

Step-by-step explanation:

[tex]\frac{2}{2\sqrt{2} }[/tex] * [tex]\frac{2\sqrt{2} }{2\sqrt{2} }[/tex]    =[tex]\frac{4\sqrt{2} }{8}[/tex] = [tex]\frac{\sqrt{2} }{2}[/tex]

Answer:

X =224

Y= -10

Step-by-step explanation:

To solve this question it's better to convert the fractions to decimals this way it will be easy to solve.

0.25x+0.6y= -4

0.2x+0.25y=-0.9

0.2(0.25x+0.6y=-4)

0.25(0.2x+0.25y=-0.9)

0.05x+0.12y=-0.8

0.05x+0.06y=-0.225

0.0575y/0.0575=-0.575/0.0575

Y=-10

To find x you replace the value of y in any of the equations

0.25x+0.6y=-4

0.25x+0.6(-10)=-4

0.25x=-4+60

0.25x/0.25=56/0.25

X=224

I hope this helps and sorry if it's wrong

Answer:

CI 90% = ( 0.227 ; 0.273)

Step-by-step explanation:

Information from the survey:

sample size   n = 938

number of people with yes answer  x = 235

proportion of people  p = 235/938

p = 0.25    then  q = 1 - 0.25    q = 0.75

Confidence Interval 90 % .

CI 90% = ( p ± SE )

CI 90% = ( p ± z(c)*√(p*q)/n)

CI 90 %   then significance level is  α = 10 %   α/2 = 5%

α/2 = 0.05  we find in z-table z (c) = 1.64

√(p*q)/n  = √0.25*0.75/938

√(p*q)/n  = √0.000199

√(p*q)/n  = 0.014

CI 90% = ( p ± z(c)*√(p*q)/n)

CI 90% = ( 0.25 ± 1.64*0.014)

CI 90% = ( 0.25 ± 0.023 )

CI 90% = ( 0.227 ; 0.273)

Answer:

here's the answer to your question

Answer:

55°

Step-by-step explanation:

Vertical angles are similar

Answered by GAUTHMATH

Answer:

B

Step-by-step explanation:

The sum of all of them will result in 180. 15x-45=180. x=15. P=55, Q=70 and R=55. It's an isosceles triangle

Answer:

b

Step-by-step explanation:

its b

Answer:

a=35

b=55

c=110

Step-by-step explanation:

a=35

Opposite angles which are non-adjacent angles formed by two intersecting lines are equal

b+35+90=180 sum of interior angle of a triangle equal to 180

b=180-125

  =55

c+70=180  Angles on a straight line add up to 180°

c=180-70

 =110

Answer:

The hottest month for the northern hemisphere is August.

The hottest month for the southern hemisphere is January and February (these top two might be the opposite)

It's globally warmer during the months of June July and August

During april and november, the southern hemisphere and northern hemisphere are the same, or very close.

During July and August the southern and northern hemispheres have the largest difference in temperature

Answer:

x- 1

y-5

z-3

Step-by-step explanation:

all u have to do is calculate the distance, so for example y is 5 because - -4 -3 -2 -1 0 1 and that is a 5 number distance

Answer:

The length of the loan was 2 years.

Step-by-step explanation:

Given that a computer is selling for $ 883, and the finance value is $ 1077.26 under an 11% simple interest loan, to determine what is the length of the loan, the following calculation must be performed:

883 x 0.11 = 97.13

(1077.26 - 883) / 97.13 = X

194.26 / 97.13 = X

2 = X

Therefore, the length of the loan was 2 years.

Answer:

2 24" X 24" square cakes are needed.

Step-by-step explanation:

This question is solved by proportions.

Area of a square:

The area of a square of side l is given by:

[tex]A = l^2[/tex]

8" X 8" square cake serves 8 people

Thus:

[tex]A = 8*8 = 64[/tex]

Area of 64 serves 8 people, so for 1 people, an area of 64/8 = 8 is needed.

144 people

The total area needed is:

[tex]A = 144*8 = 1152[/tex]

How many 24" X 24" square cakes?

24*24 = 576

1 cake - 576

x cakes - 1152

Applying cross multiplication:

1152/576 = 2

2 24" X 24" square cakes are needed.

Answer:

They walked a total distance of 290 miles every morning.

Step-by-step explanation:

First, we have to subtract 214 and 138.

= Jay walks 76 miles.

Next, we have add 214 and 76.

= 290 mi.

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Answer:

  10 and 24

Step-by-step explanation:

We know that some of the Pythagorean triples that appear in math problems are (3, 4, 5), (5, 12, 13), (7, 24, 25), (8, 15, 17).

These have (perimeter, area) values of (12, 6), (30, 30), (56, 84), (40, 60).

For some scale factor n, we want (p·n, a·n²) = (60, 120). Of the triangles listed, we see that the (5, 12, 13) triangle scaled by n=2 will satisfy the problem requirements. (30·2, 30·2²) = (60, 120)

The side lengths are 10 and 24.

__

Check

For the side lengths we found, the perimeter is 10+24+26 = 60; the area is 1/2(10)(24) = 120. The hypotenuse is 2×13 = 26 = 24+2.

__

In the attached, one side is x, the other is y. The hypotenuse is (x+2). The square root equation comes from ...

  x² +y² = (x+2)²   ⇒   y² = (x² +4x +4) -x²   ⇒   y² = 4x +4 = 4(x +1)

_____

Additional comment

The graph shows the solution of the various constraints. At least, the combination of constraints will give a quadratic equation in x. They can be combined in a way that gives a cubic equation in x. Either way, we prefer the graphical or "guess and check" approach (above) as being easier to do.

Using the third equation in the attachment to write an expression for y, we have ...

  y = 58 -2x

Substituting that into the second equation gives ...

  (x(58 -2x)/2 = 120

  29x -x² = 120

  x² -29x +120 = 0

  (x -5)(x -24) = 0 . . . . x = 5 or 24.

The root x=5 is a legitimate solution to the pair of equations we chose to solve. The line y=58-2x intersects the hyperbola xy/2 = 120 in two places. However, (x, y) = (5, 48) does not satisfy the hypotenuse requirement that x+2 > y.

Answer:

[tex]\sqrt{-(x +72)^3} - 72 = -(3\sqrt x - 72 +72)^3[/tex]

Step-by-step explanation:

Given

[tex]g(x) = 3\sqrt x - 72[/tex]

[tex]h(x) = -(x +72)^3[/tex]

Required

Show that they are inverse functions

For g(x) and h(x) to be inverse, then:

[tex]g(h(x)) = h(g(x))[/tex]

We have:

[tex]g(x) = 3\sqrt x - 72[/tex]

Replace x with h(x)

[tex]g(h(x)) = 3\sqrt{h(x)} - 72[/tex]

Substitute value for h(x)

[tex]g(h(x)) = 3\sqrt{-(x +72)^3} - 72[/tex]

Similarly;

[tex]h(x) = -(x +72)^3[/tex]

Replace x with g(x)

[tex]h(g(x)) = -(g(x) +72)^3[/tex]

Substitute value for g(x)

[tex]h(g(x)) = -(3\sqrt x - 72 +72)^3[/tex]

Recall that:

[tex]g(h(x)) = h(g(x))[/tex]

So:

[tex]\sqrt{-(x +72)^3} - 72 = -(3\sqrt x - 72 +72)^3[/tex]

Its c

explanation:

on edge

Answer:

[tex]V(x) = [\frac{x}{x + 1} + \frac{2}{x-3}] * \frac{x^3 - 9x}{x}[/tex]

[tex]V(x) = [\frac{(x^2-x+2)(x + 3)}{(x + 1)}][/tex]

[tex]V(50) = 2548.17[/tex]        [tex]V(100) = 10098.10[/tex]       [tex]V(1000) = 999201.78[/tex]

[tex]x = 54.78[/tex]

Step-by-step explanation:

Given

[tex]V(x) = [C_1(x) + C_2(x)](H(x))[/tex]

[tex]C_1(x) = \frac{x}{x+1}[/tex]

[tex]C_1(x) = \frac{2}{x-3}[/tex]

[tex]H(x) = \frac{x^3 - 9x}{x}[/tex]

Solving (a): Expression for V(x)

We have:

[tex]V(x) = [C_1(x) + C_2(x)](H(x))[/tex]

Substitute known values

[tex]V(x) = [\frac{x}{x + 1} + \frac{2}{x-3}] * \frac{x^3 - 9x}{x}[/tex]

Solving (b): Simplify V(x)

We have:

[tex]V(x) = [\frac{x}{x + 1} + \frac{2}{x-3}] * \frac{x^3 - 9x}{x}[/tex]

Solve the expression in bracket

[tex]V(x) = [\frac{x*(x-3) + 2*(x+1)}{(x + 1)(x -3)}] * \frac{x^3 - 9x}{x}[/tex]

[tex]V(x) = [\frac{x^2-3x + 2x+2}{(x + 1)(x -3)}] * \frac{x^3 - 9x}{x}[/tex]

[tex]V(x) = [\frac{x^2-x+2}{(x + 1)(x -3)}] * \frac{x^3 - 9x}{x}[/tex]

Factor out x

[tex]V(x) = [\frac{x^2-x+2}{(x + 1)(x -3)}] * \frac{x(x^2 - 9)}{x}[/tex]

[tex]V(x) = [\frac{x^2-x+2}{(x + 1)(x -3)}] * (x^2 - 9)[/tex]

Express as difference of two squares

[tex]V(x) = [\frac{x^2-x+2}{(x + 1)(x -3)}] * (x- 3)(x + 3)[/tex]

Cancel out x - 3

[tex]V(x) = [\frac{x^2-x+2}{(x + 1)}] *(x + 3)[/tex]

[tex]V(x) = [\frac{(x^2-x+2)(x + 3)}{(x + 1)}][/tex]

Solving (c): V(50), V(100), V(1000)

[tex]V(x) = [\frac{(x^2-x+2)(x + 3)}{(x + 1)}][/tex]

Substitute 50 for x

[tex]V(50) = [\frac{(50^2-50+2)(50 + 3)}{(50 + 1)}][/tex]

[tex]V(50) = \frac{(2452)(53)}{(51)}][/tex]

[tex]V(50) = 2548.17[/tex]

Substitute 100 for x

[tex]V(100) = [\frac{(100^2-100+2)(100 + 3)}{(100 + 1)}][/tex]

[tex]V(100) = \frac{9902)(103)}{(101)}[/tex]

[tex]V(100) = 10098.10[/tex]

Substitute 1000 for x

[tex]V(1000) = [\frac{(1000^2-1000+2)(1000 + 3)}{(1000 + 1)}][/tex]

[tex]V(1000) = [\frac{(999002)(10003)}{(10001)}][/tex]

[tex]V(1000) = 999201.78[/tex]

Solving (d): V(x) = 3000, find x

[tex]V(x) = [\frac{(x^2-x+2)(x + 3)}{(x + 1)}][/tex]

[tex]3000 = [\frac{(x^2-x+2)(x + 3)}{(x + 1)}][/tex]

Cross multiply

[tex]3000(x + 1) = (x^2-x+2)(x + 3)[/tex]

Equate to 0

[tex](x^2-x+2)(x + 3)-3000(x + 1)=0[/tex]

Open brackets

[tex]x^3 - x^2 + 2x + 3x^2 - 3x + 6 - 3000x - 3000 = 0[/tex]

Collect like terms

[tex]x^3 + 3x^2- x^2 + 2x - 3x - 3000x + 6 - 3000 = 0[/tex]

[tex]x^3 + x^2 -3001x -2994 = 0[/tex]

Solve using graphs (see attachment)

[tex]x = -54.783[/tex] or

[tex]x = -0.998[/tex] or

[tex]x = 54.78[/tex]

x can't be negative. So:

[tex]x = 54.78[/tex]

Answer:

10

Step-by-step explanation:

(-12) + (-8) +30

-(12+8)+30

-20 + 30

10

Answer:

number 7 the answer is 50,000

Answer:

I hope this helps

Step-by-step explanation: