6. Find the missing side. Round to the nearest tenth ​

Answer:

7/3 is the answer

Step-by-step explanation:

Answer:

√5/121

Step-by-step explanation:

formula: a^½=√a

(⁵/¹²¹)^½=√⁵/¹²¹

144 x 1.25 = 180

Answer: 144

Answer:

144

Step-by-step explanation:

144 × 1.25 = 180

We add the 1 to .25 to represent the original value plus the 25% increase.

Or you could have divided 180 by 1.25 to find original price.

Answer:

2 • (59x10 - 60)

 ————————————————

        5  

Step-by-step explanation:

Answer:

m∠F = 45°

Step-by-step explanation:

Notice the lengths of the given sides and the right angle. This is enough information to prove that this is a 45-45-90 triangle, or just basically a square cut diagonally.

Regardless if even just one side is given for a 45-45-90 triangle, all 45-45-90 triangles have one thing in common. The sides that form the right angle are equivalent and the hypotenuse is equal to one of the sides that form the right angle times the square root of two. I'm aware that it sounded confusing, as I'm awful at explaining, so just look at the picture I've attached instead of trying to understand my explanation that seemed like trying to learn a second language.

Look at the picture. See that FD = x times that square root of 2 and that DE = x. Now look back at your picture. It's connecting, now isn't it?

Now that we know that this is indeed a 45-45-90 triangle, we can confirm that m∠F = 45°

Answer:

Option b, (4,2)

Option d, (8,4)

Option e, (12,6)

Answered by GAUTHMATH

Answer:

Option b, (4,2)

Option d, (8,4)

Option e, (12,6)

Step-by-step explanation:

the person above me is correct

Answer:

The 95% confidence interval for the true difference between the mean amounts of time spent exercising each week by people who work out in the morning and those who work out in the afternoon or evening at the three health centers is (0.5, 0.9).

Step-by-step explanation:

Before building the confidence intervals, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

In the morning:

Sample of 57, mean of 5.2, standard deviation of 0.6, so:

[tex]\mu_1 = 5.2[/tex]

[tex]s_1 = \frac{0.6}{\sqrt{57}} = 0.0795[/tex]

In the afternoon/evening:

Sample of 70, mean of 4.5, standard deviation of 0.4, so:

[tex]\mu_2 = 4.5[/tex]

[tex]s_2 = \frac{0.2}{\sqrt{70}} = 0.0239[/tex]

Distribution of the difference:

[tex]\mu = \mu_1 - \mu_2 = 5.2 - 4.5 = 0.7[/tex]

[tex]s = \sqrt{s_1^2+s_2^2} = \sqrt{0.0795^2 + 0.0239^2} = 0.083[/tex]

Confidence interval:

The confidence interval is:

[tex]\mu \pm zs[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

The lower bound of the interval is:

[tex]\mu - zs = 0.7 - 1.96*0.083 = 0.5[/tex]

The upper bound of the interval is:

[tex]\mu + zs = 0.7 + 1.96*0.083 = 0.9[/tex]

The 95% confidence interval for the true difference between the mean amounts of time spent exercising each week by people who work out in the morning and those who work out in the afternoon or evening at the three health centers is (0.5, 0.9).

Here we want to create algebraic expressions for different quantities.

i) Nazaneen has  3*m marbles.

ii) Karly has m + 4 marbles.

a) The given data is:

Shireen has m marbles.

Nazaneen has three times as many marbles as Shireen.

Knowing that Shireen has m marbles, we can conclude that Nazaneen has:

3*m marbles.

Karly has 4 more marbles than Shireen, then Karly has m + 4 marbles.

Then the equations for the number of marbles that each one has are:

Shireen = m

i) Nazaneen has  3*m marbles.

ii) Karly has m + 4 marbles.

If you want to learn more, you can read:

https://brainly.com/question/24327241

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

(a) The graph is scaled by a factor of 2, and shifted up 1 unit. The scaling moves each point away from the x-axis by a factor of 2. The points on the x-axis stay there. The translation moves that scaled figure up 1 unit.

__

(b) The graph is reflected across the x-axis and shifted right 4 units. The point on the x-axis stays on the x-axis.

Answer:

P(0 female undergraduate takes on debt) ;

0.00635

Step-by-step explanation:

Probability of taking on debt, p = 0.43

q = 1 - p = 1 - 0.43 = 0.57

Number of samples, number of trials, n = 9

To obtain the probability that none of the female undergraduate take on debt :

P(0 female undergraduate takes on debt)

P(x = 0) ; using the binomial probability relation :

P(x = x) = nCx * p^x * q^(n-x)

P(x = 0) = 9C0 * 0.43^0 * 0.57^(9-0)

P(x = 0) = 9C0 * 0.43^0 * 0.57^9

P(x = 0) = 1 * 1 * 0.006351461955384057

P(x = 0) = 0.006351461955384057

P(x = 0) = 0.00635

Answer:

34.5p-2.75

Step-by-step explanation:

First add -0.5p and 12p together which is 11.5p, then add 23p with 11.5p which is 34.5p And -2.75 remains the same

So the answer is 34.5p-2.75

Answer:

34.5p-2.75

Step-by-step explanation:

-0.5p+12p-2.75+23p=34.5p-2.75

Answer: lol ez

B.

Step-by-step explanation: XD

Answer:

D

Step-by-step explanation:

The general formula for the sine or cosine function is

y = A*Sin(Bx + C) + D

C = 0 in this case

B = pi / 3

The period is given by the formula

P = 2 * pi / B

P = 2 * pi//pi/3

The 2 pis cancel and you are left with 2*3 = 6

============================================

Explanation for part (a)

All distances mentioned are in feet.

We'll have a right triangle which allows us to apply the pythagorean theorem. Refer to the diagram below.

a^2+b^2 = c^2

x^2+y^2 = z^2

Apply the derivative to both sides with respect to t. We'll use implicit differentiation and the chain rule.

[tex]x^2+y^2 = z^2\\\\\frac{d}{dt}[x^2+y^2] = \frac{d}{dt}[z^2]\\\\\frac{d}{dt}[x^2]+\frac{d}{dt}[y^2] = \frac{d}{dt}[z^2]\\\\2x*\frac{dx}{dt}+2y*\frac{dy}{dt}=2z*\frac{dz}{dt}\\\\x*\frac{dx}{dt}+y*\frac{dy}{dt}=z*\frac{dz}{dt}\\\\[/tex]

Now we'll plug in (x,y,z) = (4000,3000,5000). The x and y values are given. The z value is found by use of the pythagorean theorem. Ie, you solve 4000^2+3000^2 = z^2 to get z = 5000. Or you could note that this is a scaled copy of the 3-4-5 right triangle.

We know that dx/dt = 0 because the horizontal distance, the x distance, is not changing. The rocket is only changing in the y direction. Or you could say that the horizontal speed is zero.

The vertical speed is dy/dt = 800 ft/s and it's when y = 3000. It's likely that dy/dt isn't the same value through the rocket's journey; however, all we care about is the instant when y = 3000.

Let's plug all that in and isolate dz/dt

[tex]4000*0+3000*800=5000*\frac{dz}{dt}\\\\2,400,000=5000*\frac{dz}{dt}\\\\\frac{dz}{dt} = \frac{2,400,000}{5000}\\\\\frac{dz}{dt} = 480\\\\[/tex]

At the exact instant that the rocket is 3000 ft in the air, the distance between the camera and the rocket is changing by an instantaneous speed of 480 ft/s.

-----------------------------------------------------------------------

Explanation for part (b)

Again, refer to the diagram below.

We have theta (symbol [tex]\theta[/tex]) as the angle of elevation. As the rocket's height increases, so does the angle theta.

We can tie together the opposite side y with the adjacent side x with the tangent function of this angle.

[tex]\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(\theta) = \frac{y}{x}[/tex]

Like before, we'll apply implicit differentiation. This time we'll use the quotient rule as well.

[tex]\tan(\theta) = \frac{y}{x}\\\\\frac{d}{dt}[\tan(\theta)] = \frac{d}{dt}\left[\frac{y}{x}\right]\\\\\sec^2(\theta)*\frac{d\theta}{dt} = \frac{\frac{dy}{dt}*x - y*\frac{dx}{dt}}{x^2}\\\\\sec^2(\theta)*\frac{d\theta}{dt} = \frac{800*4000 - 3000*0}{4000^2}\\\\\sec^2(\theta)*\frac{d\theta}{dt} = \frac{3,200,000}{16,000,000}\\\\\sec^2(\theta)*\frac{d\theta}{dt} = \frac{32}{160}\\\\\sec^2(\theta)*\frac{d\theta}{dt} = \frac{1}{5}\\\\[/tex]

Let's take a brief detour. We'll return to this later. Recall earlier that [tex]\tan(\theta) = \frac{y}{x}\\\\[/tex]

If we plug in y = 3000 and x = 4000, then we end up with [tex]\tan(\theta) = \frac{3}{4}\\\\[/tex] which becomes [tex]\tan^2(\theta) = \frac{9}{16}[/tex]

Apply this trig identity

[tex]\sec^2(\theta) = 1 + \tan^2(\theta)[/tex]

and you should end up with [tex]\sec^2(\theta) = 1+\frac{9}{16} = \frac{25}{16}[/tex]

So we can now return to the equation we want to solve

[tex]\sec^2(\theta)*\frac{d\theta}{dt} = \frac{1}{5}\\\\\frac{25}{16}*\frac{d\theta}{dt} = \frac{1}{5}\\\\\frac{d\theta}{dt} = \frac{1}{5}*\frac{16}{25}\\\\\frac{d\theta}{dt} = \frac{16}{125}\\\\\frac{d\theta}{dt} = 0.128\\\\[/tex]

This means that at the instant the rocket is 3000 ft in the air, the angle of elevation theta is increasing by 0.128 radians per second.

This is approximately 7.334 degrees per second.

The distance from the television camera to the rocket is changing at 480 ft/s while the camera's angle of elevation is changing at 0.128 rad/s

Let x represent the distance from the camera to the rocket and let h represent the height of the rocket.

a)

[tex]x^2=h^2+4000^2\\\\2x\frac{dx}{dt}=2h\frac{dh}{dt} \\\\x\frac{dx}{dt}=h\frac{dh}{dt} \\\\At \ h=3000\ ft, \frac{dh}{dt}=800\ ft/s;\\x^2=3000^{2} +4000^2\\x=5000\\\\\\x\frac{dx}{dt}=h\frac{dh}{dt} \\\\5000\frac{dx}{dt}=3000*800\\\\\frac{dx}{dt}=480\ ft/s[/tex]

b)

[tex]tan(\theta)=\frac{h}{4000} \\\\h=4000tan(\theta)\\\\\frac{dh}{dt}=4000sec^2(\theta)\frac{d\theta}{dt} \\\\\\At\ h=3000\ ft;\\\\tan\theta = \frac{3000}{4000}=\frac{3}{4} \\\\sec^2(\theta)=1+tan^2(\theta)=1+(\frac{3}{4})^2=\frac{25}{16} \\\\\\\frac{dh}{dt}=4000sec^2(\theta)\frac{d\theta}{dt}\\\\800=4000*\frac{25}{16}* \frac{d\theta}{dt}\\\\\frac{d\theta}{dt}=0.128\ rad/s[/tex]

Hence, The distance from the television camera to the rocket is changing at 480 ft/s while the camera's angle of elevation is changing at 0.128 rad/s

Find out more at: https://brainly.com/question/1306506

21

12^2 = 144

144 - 123 = 21

11^2 = 121

12^2 = 144

Between these

Answered by Gauthmath must click thanks and mark brainliest

(256⁴-1)

= (256-1)⁴

Using identity (a-b)⁴ = a⁴−4a³b+6a²b²−4ab³+b⁴

Let a be 256 and b be 1

Then

256⁴−4(256)³(1)+6(256)²(1)²−4(256)(1)³+(1)⁴

After solving

(256²-1)²

(a-b)² = a²-2ab+b²

256²-2×256×1+1²

= (256²-1)(256²+1)

Must click thanks and mark brainliest

Answer:

Use identity:

Consider that:

Now factorize:

Answer:

[tex]S_n = \frac{1 (1 - 3^{10})}{1 - 3} = 29524[/tex]

Step-by-step explanation:

There's a handy formula we can use to find the sum of a geometric sequence, and here it is

[tex]S_n = \frac{a_1 (1 - r^n)}{1 - r}[/tex]

The value n represents the amount of terms you want to sum in the sequence. The variable r is known as the common ratio, and a is just some constant. Let's find those values.

First lets visualize this sequence

[tex]n_1 = 1\\n_2 = 1 + 3\\n_3 = 1 + 3 + 3^2\\n_4=1+3+3^2+3^3\\...[/tex]

Okay so there's clearly a pattern here, let's write it a bit more concisely. For each n, starting at 1, we raise 3 to the (n-1) power, add it to what we had for the previous term.

[tex]S_n = \sum{3^{n-1}} = 3^{1 - 1} + 3^{2 - 1} + 3^{3-1} ...[/tex]

Our coefficients of r, and a, are already here! As you can see below, r is just 3, and a is just 1.

[tex]S_n = \sum{a*r^{n-1}}[/tex]

To finish up lets plug these coefficients in and get our sum after 10 terms.

[tex]S_n = \frac{1 (1 - 3^{10})}{1 - 3} = 29524[/tex]

Answer:

D

Step-by-step explanation:

if you draw any vertical line through a function it should have a max of one intersection point so if the graph, reading from left to right doubles back on itself, it is not a function

Answer:

0.15y

Step-by-step explanation:

0.2*0.75*y = 0.15y

Step-by-step explanation:

Lets break this word problem down:

"The difference" means we're going to be finding x - y ("difference" means we're finding how much one value "differs" from the other)

"a number and it's opposite" so we're doing x - y, where y = -x. So already, we can re-write this as x - (-x) or x + x

"is 28" so x + x = 28 ("is" always means "equals")

"Find the number" so we're finding x.

x - (-x) = 28  (I went back a step so I could write everything out more plainly)

simplify

x + x = 28

add

2x = 28

divide both sides by 2 to get x on its own

x = 14

Answer:

14

Answer:

1.46 dollars per pound

Step-by-step explanation:

Take the total cost and divide by the number of pounds

7.30 dollars / 5 pounds

1.46 dollars per pound

Answer:

1.46

Step-by-step explanation:

Unit rate is the amount for only one pound. To do this, divide 7.30 and 5.

Divide:

7.3 / 5 = 1.46

Each pound is $1.46

Hope this helped.

I think its A) (f+g)(z)=|2x+4|-2

Step-by-step explanation:

Answer:

i still se question marks

Step-by-step explanation:

Answer:

0.0049 = 0.49% probability that I spend more than 2 hours and 10 minutes waiting for the bus in one month.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

n instances of a normal variable:

For n instances of a normal variable, the mean is:

[tex]M = n\mu[/tex]

[tex]s = \sigma\sqrt{n}[/tex]

Mean of 4 minutes, standard deviation of 0.5 minutes:

This means that [tex]\mu = 4, \sigma = \sqrt{0.5}[/tex]

30 days:

[tex]M = 30(4) = 120[/tex]

[tex]s = \sqrt{0.5}\sqrt{30} = \sqrt{0.5*30} = \sqrt{15}[/tex]

What is the probability that I spend more than 2 hours and 10 minutes waiting for the bus in one month (30 days)?

2 hours and 10 minutes is 2*60 + 10 = 130 minutes, so this probability is 1 subtracted by the p-value of Z when X = 130. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

In this context, due to the 30 instances of the normal variable:

[tex]Z = \frac{X - M}{s}[/tex]

[tex]Z = \frac{130 - 120}{\sqrt{15}}[/tex]

[tex]Z = 2.58[/tex]

[tex]Z = 2.58[/tex] has a p-value of 0.9951.

1 - 0.9951 = 0.0049

0.0049 = 0.49% probability that I spend more than 2 hours and 10 minutes waiting for the bus in one month.

Answer:

The lowest percentage from all voters combined that must be unmarried in order for Candidate A to win the election is 53.85%.

Step-by-step explanation:

Proportion married:

x are married

1 - x are unmarried.

Will vote for candidate A:

15% of x

80% of 1 - x. So

[tex]0.15x + 0.8(1-x)[/tex]

Candidate A wins:

If his proportion is more than 50%, that is:

[tex]0.15x + 0.8(1-x) > 0.5[/tex]

[tex]0.15x+ 0.8 - 0.8x > 0.5[/tex]

[tex]-0.65x > -0.3[/tex]

[tex]0.65x < 0.3[/tex]

[tex]x < \frac{0.3}{0.65}[/tex]

[tex]x < 0.4615[/tex]

Highest percentage of married is 46.15%, so:

The lowest percentage of unmarried is:

100 - 46.15 = 53.85%.

The lowest percentage from all voters combined that must be unmarried in order for Candidate A to win the election is 53.85%.

Answer:

1000 students in college

2000 students in University

200 out of 2000 are smokers

200 out 1000 are smokers

200 : 2000

1 :10

200 : 1000

1 : 5

Answer:

y=-4x-5

Step-by-step explanation:

The slope of the line is - 4, the equation of line is y=-4x-5

Answer:

x = -1

Step-by-step explanation:

1/4 (4x - 4) = -2(6x + 7)

1x - 1 = -12x - 14

13x = -13

x = -1

I'll be referring to each of these numbers as x and y.

x + y = 4

(x^2) + (y^2) - 3(x)(y) = 76

x = 4 - y

(4 - y)^2 + (y^2) - 3(4 - y)(y) = 76

(4 - y)(4 - y) + y^2 - (3y)(4 - y) = 76

16 - 4y - 4y + y^2 + y^2 - 12y + 3y^2 = 76

16 - 20y + 5y^2 = 76

5y^2 - 20y - 60 = 0

y^2 - 4y - 12y = 0

(y - 6)(y + 2) = 0

y = 6 or -2

x = 4 - 6 = -2

x = 4 - - 2 = 6

As you can see, we got the same numbers for both x and y, -2 and 6. Therefore, the two numbers are -2 and 6. But, we can check our work to ensure that the answer is correct.

x = -2

y = 6

6 - 2 = 4

4 = 4

(-2)^2 + (6^2) - 3(-2)(6) = 76

4 + 36 - 3(-12) = 76

40 + 36 = 76

76 = 76

Hope this helps!

Answer:

X and y = -2 or 6

Step-by-step explanation:

Answer:

Step-by-step explanation:

In order to find out how long it takes for the rocket to hit the ground, we only need set that position equation equal to 0 (that's how high something is off the ground when it is sitting ON the ground) and factor to solve for t:

[tex]0=-4.9t^2+112t+395[/tex]

Factor that however you are factoring in class to get

t = -3.1 seconds and t = 25.9 seconds.

Since time can NEVER be negative, it takes the rocket approximately 26 seconds to hit the ground.