Answer:
x = -5 or x = 1
Step-by-step explanation:
[tex] 3{x}^{2} + 12x - 15 = 0 \\ {x}^{2} + 4x - 5 = 0 \\ (x + 5)(x - 1) = 0 \\ x = - 5 \: or \: x = 1[/tex]
hope this makes sense:)
what is the volume of a hempisphere with a radius of 9.7 cm rounded to the nearest 10th of a cubic centimeter
Answer:
volume of hemisphere =1912.26cm^3
Step-by-step explanation:
Radicals and Exponents. Tutorial Use the properties of exponents to simplify the expression. (y 3/2 x-1/2)4 =
What is the 21st term of the sequence with a1 = -6 and d = 4?
a) 70
b) 74
c) -40
d) 78
Answer:
74
Step-by-step explanation:
for this question you have to use the formula of the nth term which is Tn=a+(n-1)d,
T21=-6+(21-1)4
=-6+(20)4
=-6+80
=74
I hope this helps
look at the image below urgent plz over 100 points
Answer: 1,526.04 yd³ (this is what i got on my calculator others may vary use any rounding you need)
VOLUME of CONE is: V= Pir² h / 3
Pi= 3.14
r= 9
h= 18
V= (3.14) x (9)² x (18)
9²= 81
3.14 x 81= 254.34 x 18= 4,578.12
4,578.12 / 3= 1,526.04 <-- answer
find the value of x, circles and angles
Answer:
x = 50
Step-by-step explanation:
When two secants intersect in the interior of a circle, the angles formed are the average of the arc an angle and its vertical intercept. In this case, our angle, 73, should be the average of x and 96. We can translate this to an equation and solve:
[tex]\frac{x+96}{2} = 73[/tex]
x + 96 = 146
x = 50
HELP!!!!! ASAP I'm getting confused and It's to long to solve it online!
Answer:
Step-by-step explanation:
Which point on the number line shows the graph
Answer:
B
Step-by-step explanation:
Simplify (6z-4y+2x)+(3z-5x+2y)
Answer:
9z-2y-3x
Step-by-step explanation:
(6z-4y+2x)+(3z-5x+2y)
Combine like terms
6z+3z-4y+2y+2x-5x
9z-2y-3x
Answer:
-3x - 2y + 9z
Step-by-step explanation:
Since you are adding two polynomials, the parentheses are unnecessary, so you can just drop them. Then combine like terms. Like terms are terms that have the same variable part such as 6z and 3z.
(6z - 4y + 2x) + (3z - 5x + 2y) = Original problem.
= 6z - 4y + 2x + 3z - 5x + 2y Drop unnecessary parentheses.
= 2x - 5x - 4y + 2y + 6z + 3z Rearrange terms to group like terms.
= -3x - 2y + 9z Combine each set of like terms.
Answer: -3x - 2y + 9z
A 12 ounce bag of rice costs $4.08. A 16-ounce bag of the same rice costs $5.76. Which bag is the better by
and by how much
Answer:
16 once is the better one.
Answer: 12-ounce bag is better by $0.02 per ounce
Concept:
When coming across questions that ask for a comparison between prices, we should make the final unit [price per object].
In finding [price per object], simply do [Total price / number of objects].
Solve:
A 12-ounce bag of rice costs $4.08
Total price / number of objects = 4.08 / 12 = $0.34 per ounce
A 16-ounce bag of rice costs $5.76
Total price / number of objects = 5.76 / 16 = $0.36 per ounce
$0.36 - $0.34 = $0.02
$0.34 < $0.36, therefore, 12-ounce bag is better by $0.02 per ounce.
Hope this helps!! :)
Please let me know if you have any questions
PLS HELP! VERY URGENT PICTURE INCLUDED!!
Answer:
y = 6x ^2 - 6x + 9
Step-by-step explanation:
hopefully it's visible
:)
help please !!!!!!!!
Answer:
first choice..
first choice
Answer:
FIRST CHOISE FIRST CHOISE
Step-by-step explanation:
What statement is not true? A) a square is a rhombus C) a rhombus is a rectangle D) a square is a rectangle
B) a rhombus is a parallelogram
Answer:
A square is a retangle
Step-by-step explanation:
Because a squre is a rectangle
Which function has a maximum with the same maximum value as
Answer:
Step-by-step explanation:
Find the greatest common factor of 65a3b4 and 39a4b5.
Step-by-step explanation: Let's begin by finding the
greatest common factor for the numbers 65 and 39.
I would make a factor tree and break up 65 and 39.
So 65 is 13 x 5 and 39 is 13 x 3.
Since the 13's match up, the greatest
common factor between 65 and 39 is 13.
For the variables, we use the smallest power on each of them.
So we use a^3 and b^4 to get 13a^3b^4 as our GCF.
Find the missing side or angle.
Round to the nearest tenth.
b=15 a=30 c=29 a=[?]. Acellus plz
Answer:
∠ A ≈ 79.0°
Step-by-step explanation:
Using the Cosine rule to find the angle
cosA = [tex]\frac{b^2+c^2-a^2}{2bc}[/tex]
= [tex]\frac{15^2+29^2-30^2}{2(15)(29)}[/tex]
= [tex]\frac{225+841-900}{870}[/tex]
= [tex]\frac{166}{870}[/tex] , then
A = [tex]cos^{-1}[/tex] ([tex]\frac{166}{870}[/tex] ) ≈ 79.0° ( to the nearest tenth )
Christopher has breakfast at a cafe and the cost of his meal is \$36.00$36.00dollar sign, 36, point, 00. Because of the service, he wants to leave a 10\%10%10, percent tip.
What is his total bill including tip?
Answer: $ 39.60
Step-by-step explanation:
36 + (36*0.10) = 39.60
Any number that CAN be divided by 2 without having remainder is considered an _______ number
Step-by-step explanation:
Any number that can be divided by 2 without having remainder is considered an even number.
I hope it helped U
stay safe stay happy
Can I have help I am stuck on this problem It would mean the world if u helped me and tysm!! =-)
9514 1404 393
Answer:
2^6 = 64
Step-by-step explanation:
Each hour the initial value (1) is multiplied by 2 (again). So the number of times 2 multiplies the initial value is the number of passing hours (t).
The number of cells after t hours is ...
c(t) = 1×2^t = 2^t
After 6 hours, this is
c(6) = 2^6 = 64 . . . . cells after 6 hours
_____
Additional comment
As you know, multiplication simplifies repeated addition.
x + x + x = 3x
In a similar way, exponentiation simplifies repeated multiplication.
x·x·x = x³ . . . . (written as x^3 in plain text)
In this problem, we're repeatedly multiplying by 2. After we do that t times, the initial value is multiplied by 2^t.
7. When running you discover you are only in second place. You were initially running at a speed of 18 km/h and
increase your speed to 21 km/h. It takes you 3 seconds to speed up to your new rate. What is your
acceleration
Step-by-step explanation:
check it out.
Hope it helps.
Using only the digits 5, 6, 7, 8, how many different three digit numbers can beformed
Answer:
totally 16 numbers can be formed
It is hard and the condition of repeat of number should be clear if you have formula ( it is obvious to have) you can use that.
Evaluate each expression if r = 3,q = 1, and W =-2
Answer:
2) - 12
3) - 1
4)y = 8
5)r = 4
6)x= -7/29
Hope it helps you
(x
3
+y
3
)(xy
4
+7)
Answer:
question is not proper
Step-by-step explanation:
question is
Graphs of the following equations are straight lines except :
A. 3x+2y=8
B. y=x/2-5
C. x=4y
D. y=x^2+3
Answer:
D.
Step-by-step explanation:
D. This contains an x^2 and is called a parabola ( curved line like a U).
Answer:D
Step-by-step explanation: d is the correct answer
Simplify the equation
(X 2/5) 10
Answer:
x^4
Step-by-step explanation:
x^(2/5) ^10
We know that a^b^c = a^(b*c)
x^(2/5*10)
x^4
Answer:
[tex]{x}^{4} [/tex]
Step-by-step explanation:
[tex] ({x}^{ \frac{2}{5} } ) ^{10} \\ {x}^{ \frac{2}{5} \times 10} \\ {x}^{ \frac{20}{5} } \\ {x}^{4} [/tex]
Which expression is equivalent to the following complex fraction?
Answer:
The correct choice is option B. y+1/y-1
Step-by-step explanation:
if 10x=1/0.001 find the value of x
[tex]\\ \sf\longmapsto 10x=\dfrac{1}{0.001}[/tex]
Turn over the decimal[tex]\\ \sf\longmapsto 10x=\dfrac{1}{\dfrac{1}{1000}}[/tex]
[tex]\\ \sf\longmapsto 10x=1000[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{1000}{10}[/tex]
[tex]\\ \sf\longmapsto x=100[/tex]
[tex]\int\limits^9_3 {\frac{1}{(x+21)\sqrt{x+22} } } \, dx[/tex]
Let y = x + 22 and dy = dx, so the integral becomes
[tex]\displaystyle \int_3^9 \frac{\mathrm dx}{(x+21)\sqrt{x+22}} = \int_{25}^{31} \frac{\mathrm dy}{(y-1)\sqrt{y}}[/tex]
Now let z = √y, so that z ² = y. Then 2z dz = dy, and the integral becomes
[tex]\displaystyle \int_3^9 \frac{\mathrm dx}{(x+21)\sqrt{x+22}} = \int_{\sqrt{25}}^{\sqrt{31}} \frac{2z}{(z^2-1)z} \\\\ = \int_5^{\sqrt{31}} \frac{2}{z^2-1}\,\mathrm dz[/tex]
Expand the integrand into partial fractions:
[tex]\dfrac{2}{z^2-1} = \dfrac1{z-1}-\dfrac1{z+1}[/tex]
Then we have
[tex]\displaystyle \int_3^9 \frac{\mathrm dx}{(x+21)\sqrt{x+22}} = \int_5^{\sqrt{31}}\left(\frac1{z-1}-\frac1{z+1}\right)\,\mathrm dz \\\\ = \left(\ln|z-1|-\ln|z+1|\right)\bigg|_5^{\sqrt{31}} \\\\ =\left[\ln\left|\frac{z-1}{z+1}\right|\right]\bigg|_5^{\sqrt{31}} \\\\ =\ln\left(\frac{\sqrt{31}-1}{\sqrt{31}+1}\right) - \ln\left(\frac{4}{6}\right) \\\\ =\ln\left(32-2\sqrt{31}\right) - \ln\left(\frac23\right) \\\\ =\boxed{\ln\left(48-3\sqrt{31}\right)}[/tex]
Solve for x.
A. 9
B. 12
C. 1
D. 7
Answer:
9
Step-by-step explanation:
use Tangent-chord formula for finding the arc knowing E
x=1/2n
4x+19=1/2n
n=8x+38
both arcs = 360
28x-2+8x+38=360
x=9
look at the image below plz !!!!!!!!!!!!!! U R G E N T PLZ
Answer: Volume is 4.19
Step-by-step explanation:
The equation for the volume of a cone is πr^2(h/3)
r = 1
h = 4
Fill in values into the equation
π(1)^2(4/3) = 4.19
Consider the differential equation: 2y′′−13y′−7y = 0
a. Show that, for any constants A and B, the following is a solution to the above differential equation: y = Ae^(−9x)+Be^(x/3)
b. Find the values A and B that make the above general solution into a solution for the following initial value problem: 2y′′−13y′−7y = 0; y(0) = 3, y′(0) = −5
--------------------------------------------------
Just a correction, the characteristic roots of the equation are [tex]y = 7[/tex] and [tex]y = -\frac{1}{2}[/tex], thus, we should test for:
[tex]y = Ae^{7x} + Be^{-\frac{x}{2}}[/tex]
--------------------------------------------------
Question a:
First, we find the derivatives, thus:[tex]y = Ae^{7x} + Be^{-\frac{x}{2}}[/tex]
[tex]y^{\prime} = 7Ae^{-7x} - \frac{1}{2}Be^{-\frac{x}{2}}[/tex]
[tex]y^{\prime\prime} = 49Ae^{-7x} + \frac{1}{4}Be^{-\frac{x}{2}}[/tex]
Now, we replace into the equation:[tex]2y^{\prime\prime} - 13y^{\prime} - 7y = 0[/tex]
[tex]2(49Ae^{-7x} + \frac{1}{4}Be^{-\frac{x}{2}}) - 13(7Ae^{-7x} - \frac{1}{2}Be^{-\frac{x}{2}}) - 7(Ae^{7x} + Be^{-\frac{x}{2}}) = 0[/tex]
[tex]98Ae^{-7x} + \frac{1}{2}Be^{\frac{x}{2}} - 91Ae^{-7x} + \frac{13}{2}e^{-\frac{x}{2}} - 7Ae^{7x} - 7Be^{-\frac{x}{2}} = 0[/tex]
[tex]98Ae^{-7x} - 91Ae^{-7x} - 7Be^{-\frac{x}{2}} + \frac{1}{2}Be^{\frac{x}{2}} + \frac{13}{2}e^{-\frac{x}{2}} - 7Be^{-\frac{x}{2}} = 0[/tex]
[tex]0A + 0B = 0[/tex]
[tex]0 = 0[/tex], thus, we found the identity, and for each constant A and B, the following is a solution.
--------------------------------------------------
Question b:
[tex]y = Ae^{7x} + Be^{-\frac{x}{2}}[/tex]
Since [tex]y(0) = 3[/tex][tex]A + B = 3 \rightarrow B = 3 - A[/tex]
--------------------------------------------------
[tex]y^{\prime} = 7Ae^{-7x} - \frac{1}{2}Be^{-\frac{x}{2}}[/tex]
Since [tex]y^{\prime}(0) = -5[/tex][tex]7A - \frac{1}{2}B = -5[/tex]
Using [tex]B = 3 - A[/tex]
[tex]7A - \frac{3}{2} + \frac{A}{2} = -5[/tex]
[tex]\frac{14A}{2} + \frac{A}{2} = -\frac{10}{2} + \frac{3}{2}[/tex]
[tex]\frac{15A}{2} = -\frac{7}{2}[/tex]
[tex]15A = -7[/tex]
[tex]A = -\frac{7}{15}[/tex]
--------------------------------------------------
Then, B is given by:
[tex]B = 3 - A = 3 - (-\frac{7}{15}) = \frac{45}{15} + \frac{7}{15} = \frac{52}{15}[/tex]
Thus, the values are: [tex]A = -\frac{7}{15}, B = \frac{52}{15}[/tex]
A similar problem is given at https://brainly.com/question/2456414
