10. A local park is located on a triangular piece of land. What is the area of the park to the nearest tenth? (1 point) S 75 m 40° R 150 m T Area = m2​

Step-by-step explanation:

the ratio of boys and girls is equal to 4:5

let the number of boys be x

and the number of girls be y

so form 1st statement

x:y=4:5

now 2nd statements

x:y-100=6:7

Therefore solving equations 1 and 2

x=1200

y=1500

Answer:

25 gallons of sulfuric acid

Step-by-step explanation:

Find how much sulfuric acid is in the tank by finding 50% of 50 (the total gallons of solution):

50(0.5)

= 25

So, there are 25 gallons of sulfuric acid.

Answer:

v=(h/t)+gt

Step-by-step explanation:

h=vt-gt^2

h+gt^2=vt

v=(h/t)+gt

Answer:

ABC=BCD

so, X=60'

Z= 70'

Y=50'

Step-by-step explanation:

you're going to solve for y in the first equation and then substitute it in for the second equation and solve.

Hey there! I'm happy to help!

We see that Jack has already run 25 miles.

25

He also wants to run 2.5 miles every day. This means we will multiply 2.5 miles by the number of days he runs. We will call the number of days x.

25+2.5x

And he needs this to equal 275.

25+2.5=275

We subtract 25 from both sides.

2.5x=250

We divide both sides by 2.5

x=100

So, Jack will need to run 100 days to meet his goal.

Have a wonderful day and keep on learning! :D

Answer:

Step-by-step explanation:

Start with the Big 3. The Big three are the ones on your calculator. The other three are the reciprocals of the big 3.

Sin A = 0.5878

Cos A = 0.8090

Tan A = 0.7265

=============

Now for the reciprocals. I'll leave you to put them in the order that the question asks for.

Cot A = 1/ Tan(A) = 1/0.7265 = 1.3763

CSC A = 1/sin (A) = 1/0.5878 = 1.7013

SEC A = 1/ Cos(A) = 1/0.8090 = 1.236

Answer:

1st sequence is F

2nd sequence is B

3rd sequence is G

4th sequence is A

5th sequence is D

6th sequence is E

7th sequence is C

Step-by-step explanation:

A) 1600*0.25= 400- the first term of the sequence

1600*0.25^2= 100- the second term

so it is 4th sequence

B) y=800* (1/2)^x

The first term is 800*1/2=400

The second term is 800*(1/2)^2= 800*1/4=200

the 2nd sequence

C) y= 2/5*5^x

The first term is y=0.4*5=2

The second term is y= 0.4*5^2=10

7th sequence

D) y=1/5* 5^x

The first term is y=1/5*5=1

The second term is y= 1/5 *5*5=5

The 5th sequence

E) y=2000*(1/2)^x

The first term of 2000*1/2=1000

The only sequence with such the first term is 6th sequence

F) y=1/3*3^x

y= 1/3*3=1 - the first term

y= 1/3*3*3=3

1st sequence

G) y= 2*2^x

y=2*2= 4 - the first term

it is the third sequence

9514 1404 393

Answer:

  (b)  {yly = -9, -3, 0, 5, 7}

Step-by-step explanation:

The range is the set of y-values in the ordered pairs. It is usually convenient to list a set in alphanumeric order.

The second values of the ordered pairs are 0, -3, -9, 5, 7. So, the range is ...

  y ∈ {-9, -3, 0, 5, 7} . . . . . matches the second choice

Answer:

16 degrees

Step-by-step explanation:

147+17+x=180

164+x=180

subtract 164 from both sides

X = 16

Step-by-step explanation:

we know all measure of angles of triangle is 180⁰

so angle A + B + C = 180⁰

so 147⁰ + 17⁰ + C = 180⁰

so 164⁰ + C = 180⁰

so C = 180⁰- 164⁰

so C =16⁰

so third angle will be 16⁰

MARK AS BRAINLIST IF IT IS USEFUL

Answer:

19)tu=12

20) true

Step-by-step explanation:

19) (22+5x)+(19-2x)=35

   3x+41=35

   3x=-6

  x=-2

TU=22+5*-2

     =12

Answer:

10^3 kg

Step-by-step explanation:

Think about it that you have the total yield 10^8 kg of rice from 10^5 km^2 of land. You now only want How much does 1 km^2 of land produce. Which can be shown as

10^8/10^5=??/1. To get the denominator to equal one you divide the top and bottom of the first problem by 10^5. 10^8/10^5 is 10^3. So it's 10^3 kg

Answer:

Since −13 is a proper fraction, it cannot be written as a mixed number.

Answer:

just restart your device

Answer:

Step-by-step explanation:

This is a "regular" sin graph that's "taller" than the original. The amplitude is 3; other than that, its period is the same and it has not shifted to the right or left, so the equation, judging from the graph, is

[tex]y=3sin(x)[/tex]

Answer:

Hello,

Step-by-step explanation:

Le théorème est faux

since a=9 and b=16 then

[tex]\sqrt{9} +\sqrt{16} =3*4=7 \\\sqrt{9+16} =\sqrt{25} =5\\[/tex]

Answer:

12 type of bread 1 type of meat, 1 type of cheese and 1 type of bread.☺️☺️

Answer: B

Step-by-step explanation:

the parabola having (1,5) as vertex have as equation:

y=k*(x-1)²+5

It is passing through (2,8)

8=k*(2-1)²+5 ==> k+5=8 ==> k=3

equation is  y=3(x-1)²+5

Answer B

Answer:

speed

1)the distance travelled by a body per unit time is known as speed.

2) speed is speed, or something how fast is going,

3) while velocity is speed how fast something is going in a specific direction.

average speed

1) average speed is the speed added up and divided by number of speed .

2)the average of all the instantaneous speed in a give time interval.

3) the average speed as the duration of the time interval approaches zero.

Answer:

x + y = 320

8x + 5y = 1900

Step-by-step explanation:

The equation x + y = 320 represents how 320 tickets were sold in total, from combining the adult and child tickets sold.

Since adult tickets are $8 each, the money from adult ticket sales can be represented by 8x.

The money from child ticket sales can be represented by 5y.

The equation 8x + 5y = 1900 represents how $1900 worth of tickets were sold.

So, the system of equations for the situation is:

x + y = 320

8x + 5y = 1900

Answer:

y = 220

x = 100

Step-by-step explanation:

x + y = 320

8x + 5y = 1900

x = 320 - y

8(320 - y) + 5y = 1900

2560 - 8y + 5y = 1900

2560 -3y = 1900

-2560        -2560

-------------------------

   -3y = -660

   -----    -------

    -3        -3

      y = 220

x + 220 = 320

    -220   -220

----------------------

        x = 100

Answer:

Front = 30

Back = 30

Right = 30

Left = 30

Bottom = 25

Top = 16

Total = 161

Let me know if this helps!

Answer:

10

Step-by-step explanation:

4 * 2.5  = 10

[tex]\\ \sf\longmapsto 75-3y[/tex]

[tex]\\ \sf\longmapsto 3(25-1y)[/tex]

[tex]\\ \sf\longmapsto 3(25-y)[/tex]

Answer:

Step-by-step explanation:

75-3y​

3(25+y)

Answer:

Parallel lines never intersect, but they must be in the same plane. The definition does not require the undefined term point, but it does require plane. Because they intersect, perpendicular lines must be coplanar; consequently, plane is not required in the definition.

Step-by-step explanation:

Its correct trust me.

Answer:

Parallel lines never intersect, but they must be in the same plane. The definition does not require the undefined term point, but it does require plane. Because they intersect, perpendicular lines must be coplanar; consequently, plane is not required in the definition.

Step-by-step explanation:

Answer:

one solution

Step-by-step explanation:

3(x-2)=22-x

Distribute

3x -6 = 22-x

Add x to each side

3x-6+x = 22-x+x

4x-6 =22

Add 6 to each side

4x-6+6 = 22+6

4x = 28

Divide by 4

4x/4 = 28/4

x = 7

There is one solution

Answer:

It has only one solution

Step-by-step explanation:

[tex]3(x - 2) = 22 - x [/tex]

open the brackets:

[tex]3x - 6 = 22 - x[/tex]

collect like terms together:

[tex]3x + x = 22 + 6[/tex]

then solve:

[tex]4x = 28 \\ x = \frac{28}{4} \\ \\ x = 7[/tex]

Answer:

[tex]24x^{3} \sqrt{5x} -4x^{3} \sqrt{10x}[/tex]

Step-by-step explanation:

[tex]2\sqrt{8x^{3} } (3\sqrt{10x^{4} } -x\sqrt{5x^{2} } )[/tex]

[tex]=2.2x\sqrt{2x} (3x^{2} \sqrt{10} -x^{2} \sqrt{5} )[/tex]

[tex]=4x\sqrt{2x} (3x^{2} \sqrt{10} -x^{2} \sqrt{5} )[/tex]

[tex]=12x^{3} \sqrt{2xx10} -4x^{3} \sqrt{2xx5}[/tex]

[tex]=24x^{3} \sqrt{5x} -4x^{3} \sqrt{10x}[/tex]

OAmalOHopeO

Answer:

Intergers

Step-by-step explanation:

A subset is a part of a whole math concept, idea, or sample space.

We need to find what math concept -5 is apart of.

-5 is part of the All Real Numbers section.

-5 is also part of integers as well.

Answer:

y=32x-32    

Step-by-step explanation:

This time no algorithm or equation was needed i saw that if the equation was y=32x there would be ordered pairs (1,32) and (2,64) so to delay it by 1  on the x side just subtract the slope from the y - intercept sorry if that doesn't make sense

Answer:

The terms are - 1, 7 and 15.

Step-by-step explanation:

Let the terms be a-d, a, a+d.

ATQ, a-d+a+a+d=21, a=7 and a+d-(a-d+a)=9. 2d-a=9, d=8. The terms are - 1, 7 and 15.

The first three terms will be :   -1, 7, 15

We have sum of first three terms of an arithmetic series is 21. It is given that if the sum of the first two terms is subtracted from the third term then it would be 9.

We have to find the three terms of the series.

An arithmetic progression or sequence with common difference [tex]d[/tex] is given as -

a, a + d, a + 2d, a + 3d .....

According to the question -

a + (a + d) + (a + 2d) = 21

3a + 3d = 21

3(a + d)=21

a + d = 7                             (Eqn. 1)

(a + 2d) - (a + a + d) = 9

a + 2d - a - a - d = 9

d - a = 9

a = d - 9

Substituting the value of 'a' in Eqn. 1, we get -

d - 9 + d = 7

2d - 9 = 7

2d = 16

d = 8

Therefore -

a = 8 - 9

a = -1

The three terms are -

a = -1

a + d = -1 + 8 = 7

a + 2d = -1 + 2 x 8 = 15

Hence, the first three terms will be - -1, 7, 15

To solve more questions on Arithmetic Sequences and finding the terms, visit the link below -

https://brainly.com/question/20384906

#SPJ2

Answer:

B. y= 6x2, y= -4.5x2, y= -x2

Step-by-step explanation:

y = 6x2, y = −4.5x2, y = −x2

This should be correct )

To solve this problem you must keep on mind the following information: By definition, a quadratic function has the following form:  

 y=ax^{2}+bx+c


Where a
 is the leading coefficient.

If the leading coeficient is closer to zero, the parabola is widest,if it has a larger positive or negative value, the parabola is narrowest.

Therefore, by knowing the information above, you have that the answer is:

y=- x^{2}  \\ y=-4.5 x^{2}  \\ y=6 x^{2}

[tex]\\ \sf\longmapsto 41sin\Theta=40[/tex]

[tex]\\ \sf\longmapsto sin\Theta=\dfrac{40}{41}[/tex]

Now

[tex]\boxed{\sf cos\Theta=\sqrt{1-sin^2\Theta}}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\sqrt{1-\left(\dfrac{40}{41}\right)^2}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\sqrt{1-\dfrac{1600}{1682}}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\sqrt{\dfrac{1681-1600}{1681}}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\sqrt{\dfrac{81}{1681}}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\dfrac{9}{41}[/tex]

We know

[tex]\boxed{\sf tan\Theta=\dfrac{Sin\theta}{Cos\Theta}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{tan\Theta}{1-tan^2\Theta}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{sin\Theta}{cos\Theta}}{1-\dfrac{sin^2\Theta}{cos^2\Theta}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{\left(\dfrac{40}{41}\right)}{\left(\dfrac{9}{41}\right)}}{1-\dfrac{\left(\dfrac{40}{41}\right)^2}{\left(\dfrac{9}{41}\right)^2}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{{40}}{{9}}}{1-\dfrac{{40}^2}{{9}^2}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{40}{9}}{\dfrac{9^2-40^2}{9^2}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{40}{9}}{\dfrac{81-1600}{81}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{40}{9}}{\dfrac{-1519}{81}}[/tex]

[tex]\\ \sf\longmapsto {\dfrac{40}{\cancel{9}}}\times \dfrac{\cancel{81}}{(-1519)}[/tex]

[tex]\\ \sf\longmapsto \dfrac{40\times 9}{(-1519)}[/tex]

[tex]\\ \sf\longmapsto - \dfrac{360}{1519}[/tex]