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Ignoring the stress we feel is not a possible thing as long as it persist. We must identify the source that creates stress and try to eliminate or reduce its effect through relaxation techniques.

There isn't a one-size-fits-all approach to managing stress. Your stress-reduction routine will be very different from someone else's depending on the kind and frequency of your stress. However, it's useful to have a toolkit of stress-reduction methods on hand in case you require them.

It's common to have difficult circumstances in life. The daily commute and paying taxes are only two examples of daily pressures. It has an impact on everyone. The key is to learn how to control it so that our stress levels don't become too high.

There are many relaxation techniques to get rid of stresses such as yoga, community work out, music therapy. etc. Be active and control yourselves always and proper food and positive talks make everything out of stress.

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Answer:

Object 3

Explanation:

The object has the greatest acceleration is Object 2.

The following information should be considered;

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Answer: d)

Both Assertion and Reason are false

Explanation:

The least distance of distinct vision for normal human beings is 25 cm. That is,

normal eye can not be able to see clearly the objects placed closer than 25 Centimetre.

Havong an Assertion that normal human eye can see clearly all the objects below and above 25 cm is false. And since the assertion is false, the reason behind it is invalid. Therefore, having a reason that the human eye has the capacity to suitable adjust the focal length of its lens to a certain extent is also false.

Answer:

1.) Time = 3.5 seconds

2.) Range = 21 m

3.) Velocity = 34.8 m/s

Explanation:

Given that the

Height h = 60 m

Initial velocity U = 6 m/s

1.) The time taken to hit the river for a single droplet of water can be achieved by using second equation of motion

h = Ut + 1/2gt^2

Let assume that the water drops from rest. Therefore, U = 0

60 = 1/2 × 9.8t^2

60 = 4.9t^2

t^2 = 60/4.9

t^2 = 12.24

t = sqrt (12.24)

t = 3.5s

2.) The range of the projectile for a single droplet of water will be calculated by using the formula

R = Ut

Range R = 6 × 3.5 = 20.99

Range = 21 m

3.) The velocity (diagonal) when it hits the water.

Using third equation of motion

V^2 = U^2 + 2gH

Substitute values into the equation

V^2 = 6^2 + 2 × 9.8 × 60

V^2 = 36 + 1176

V^2 = 1212

V = sqrt (1212)

V = 34.8 m/s

Answer:

Pressure= force/ area

12/ 2033.33= 24400 N/m2.

i believe this is it :)

Answer:

radios work when electrons are speeding up and dow the attena, patters structure and shape make music pleasing to hear. (more info below)

Explanation:

a radio works when electrons are speeding up and down the antenna, sending out electromagnetic waves. Radiation waves travel through the air at the speed of light. When the radio waves reach the antenna, the electrons vibrate within the antenna and reproduce the initial signal. to make music pleasing to hear it has to have patterns, structure, shape.

hope this helped!

Answer:

Its D

Explanation:

Answer:

Explanation:

The formula P=VI, just rearrange to find I

So

I=P/V

=75/120

=0.625amps

625mA

Answer:The answer must be The weight of the man and the vertical distance moved.

Explanation: you calculate it by the force you applied times the distance you moved

Answer:

10,000 N

Explanation:

Force = mass · acceleration

F = m · a

Jake's car:

Accelerates at 10 m/s²

Weighs 1000 kg

F = 1000 · 10

F = 10000 N

Answer:

10,000 Newtons

Please mark my answer.

Cheers, Jake

Answer:

Kepler studied the periods of the planets and their distance from the Sun, and proved the following mathematical relationship, which is Kepler's Third Law: The square of the period of a planet's orbit (P) is directly proportional to the cube of the semimajor axis (a) of its elliptical path.

Explanation:

Answer:

D

Explanation:

Just got a 100 on the test

Answer: V = 15 m/s

Explanation:

As  stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. The observed frequency the car will be experiencing will be addition of the two frequency. That is,

F = 2.1 × 10^10 + 1030 = 2.100000103×10^10Hz

Using doppler effect formula

F = C/ ( C - V) × f

Where

F = observed frequency

f = source frequency

C = speed of light = 3×10^8

V = speed of the car

Substitute all the parameters into the formula

2.100000103×10^10 = 3×10^8/(3×10^8 -V) × 2.1×10^10

2.100000103×10^10/2.1×10^10 = 3×108/(3×10^8 - V)

1.000000049 = 3×10^8/(3×10^8 - V)

Cross multiply

300000014.7 - 1.000000049V = 3×10^8

Collect the like terms

1.000000049V = 14.71429

Make V the subject of formula

V = 14.71429/1.000000049

V = 14.7 m/s

The speed of the car is 15 m/s approximately

Answer: 7.36m/s

Explanation:

(Fo- f)/fo = 2v/c

1030/2.10 x 10^10 = 2v/ 3 x 10^10

4.905= 2v/3 x 10^10

Rearrange for v

V = ((1030/2.10 x 10^10) x (3x 10^10)) / 2

V = 7.36 ( right for acellus)

Answer:

it will most likely turn off?

Answer:

Abiotic

Explanation:

The non living factors of the ecosystem which is essential for the survival of living factors of the ecosystem are abiotic factors.

Examples for abiotic factors include temperature, sunlight, water, wind etc....

Answer:

B

Explanation:

is the correct answer

Answer: K.E = 8.3 J

Explanation:

The given parameters are

Height h = 169.2 m

Mass m = 0.005kg

From conservation of energy, at the top of the monument, the total energy will be kinetic energy which is equal to the potential energy. That is,

K.E = P.E

And

P.E = mgh

Where g = 9.81 m/s^2

Substitutes all the parameters into the formula

P.E = 0.005 × 9.81 × 169.2

P.E = 8.2908 J

Therefore, the kinetic energy (KE) of the nickel in her shirt pocket at the top of the monument is approximately 8.3 Joule.

The kinetic energy (KE) of the nickel in her shirt pocket at the top of the monument is 8.2908 Joules.

Given the following data:

Scientific data:

To calculate the kinetic energy (KE) of the nickel in her shirt pocket at the top of the monument, we would apply the law of conservation of energy.

According to the law of conservation of energy, the kinetic energy (KE) of the nickel is equal to the potential energy (PE) possessed by the nickel at the top of the monument.

Mathematically, this is given by this expression:

[tex]K.E =P.E =mgh[/tex]

Substituting the given parameters into the formula, we have;

[tex]K.E = 0.005 \times 9.8 \times 169.20[/tex]

K.E = 8.2908 Joules.

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Answer:

[tex]E_T=[-27739.6\hat{i}-55479\hat{j}]\frac{N}{C}[/tex]

Explanation:

You have four charges at the corners of a square of side a=5.2cm

In order to calculate the electric field at the center of the square, you sum the contribution of the electric field generated by each charge.

The total electric field is given by:

[tex]E_T=E_1+E_2+E_3+E_4\\\\[/tex]    (1)

each contribution to the total electric field has two components x and y. The signs of the components depends of the direction of the field, which is given by the sign of the charge that produced the electric field. Then, you have

[tex]E_1=k\frac{q_1}{r^2}cos\theta\hat{i}-k\frac{q_1}{r^2}sin\theta\hat{j}\\\\E_1=k\frac{q_1}{r^2}(cos\theta \hat{i}-sin\theta \hat{j})[/tex]   (2)

q1 = 11.8*10^-9 C

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

For a square you obtain that

[tex]r=\sqrt{2}a=\sqrt{2}(5.2cm)=7.35cm=7.35*10^{-2}m[/tex]

and the angle is 45°

Then, you have in the equation (2):

[tex]E_1=(8.98*10^9Nm^2/C^2)\frac{11.8*10^{-9}C}{(7.35*10^{-2}m)^2}(cos45\° \hat{i}-sin45\° \hat{j})=[13869.7\hat{i}-13869.7\hat{j}]\frac{N}{C}[/tex]

In the same way you obtain for the other contributions to the total electric field:

For E2:

[tex]E_2=k\frac{q_2}{r^2}(cos45\°\hat{i}+sin45\° \hat{j})\\\\E_2=[13869.7\hat{i}+13869.7\hat{j}]\frac{N}{C}[/tex]

For E3:

[tex]E_3=k\frac{q_3}{r^2}(-cos45\°\hat{i}+sin45\°\hat{j})\\\\E_3=(8.98*10^9Nm2/C^2)\frac{23.6*10^{-9}C}{(7.35*10^{-2}m)^2}(-cos45\°\hat{i}+sin45\°\hat{j})\\\\E_3=39229.58(-cos45\°\hat{i}+sin45\°\hat{j})\frac{N}{C}\\\\E_3=[-27739.5\hat{i}+-27739.5\hat{j}]\frac{N}{C}[/tex]

for E4:

[tex]E_4=k\frac{q_4}{r^2}(-cos45\°\hat{i}-sin45\°\hat{j})\\\\E_4=[-27739.5\hat{i}-27739.5\hat{j}]\frac{N}{C}[/tex]

Finally, you sum component by component the four contributions to the total electric field (equation (1)):

[tex]E_T=[-27739.6\hat{i}-55479\hat{j}]\frac{N}{C}[/tex]

There still are four chargers in the corners of a square with side a=5.2cm. To compute the electric field just at the center of the composition, add the contributions of each shield's electromagnetic current.

entire electric field

[tex]\to E_T=E_1+E_2+E_3+E_4\ \ \ \ \ \ \ (1)[/tex]

Every contribution to the total electric field is comprised of two components, x, and y. These components' signs were determined by the direction of the field, which is determined by the sign of the charge that produced the electric field. There's

[tex]\to E_1=k\frac{q_1}{r^2}\cos\theta\hat{i}-k\frac{q_1}{r^2}\sin\theta\hat{j}\\\\\to E_1=k\frac{q_1}{r^2}(\cos\theta \hat{i}-\sin\theta \hat{j}) \ \ \ \ (2)\\\\\to q_1 = 11.8\times 10^{-9}\ C\\\\[/tex]

Coulomb’s constant (K) [tex]= 8.98\times 10^9\ \frac{Nm^2}{C^2}[/tex]

square, you obtain that

[tex]\to r=\sqrt{2}\\\\\to a=\sqrt{2}(5.2\ cm)=7.35\ cm=7.35\times 10^{-2}\ m[/tex]

angle= [tex]45\°[/tex]  then, you have in the equation (2):

[tex]\to E_1=(8.98\times 10^9\ \frac{Nm^2}{C^2})\frac{11.8 \times 10^{-9}\ C}{(7.35 \times 10^{-2}m)^2}(\cos 45^{\circ} \hat{i}-\sin 45^{\circ} \hat{j})[/tex]

         [tex]=[13869.7\hat{i}-13869.7\hat{j}]\ \frac{N}{C}[/tex]

Similarly, for other components to the overall electric field, you get:

For E2:

[tex]\to E_2=k\frac{q_2}{r^2}(\cos45^{\circ}\hat{i}+\sin45^{\circ} \hat{j})\\\\ \to E_2=[13869.7\hat{i}+13869.7\hat{j}]\ \frac{N}{C}[/tex]

For E3:

[tex]\to E_3=k\frac{q_3}{r^2}(-\cos45^{\circ}\hat{i}+\sin45^{\circ} \hat{j})\\\\\to E_3=(8.98\times 10^9 \ \frac{Nm^2}{C^2}) \ \frac{23.6 \times 10^{-9}\ C}{(7.35\times 10^{-2}\ m)^2}(-\cos45^{\circ} \hat{i}+\sin45^{\circ} \hat{j})\\\\\to E_3=39229.58(-\cos45^{\circ} \hat{i}+\sin45^{\circ} \hat{j})\frac{N}{C}\\\\\to E_3=[-27739.5\hat{i}+-27739.5\hat{j}]\ \frac{N}{C}\\[/tex]

For E4:  

[tex]\to E_4=k\frac{q_4}{r^2}(-\cos45^{\circ}\hat{i}-\sin45^{\circ}\hat{j})\\\\ \to E_4=[-27739.5\hat{i}-27739.5\hat{j}]\ \frac{N}{C}[/tex]

Finally, we add up the four contributions to the total electric field (equation (1)):

[tex]E_T=[-27739.6\hat{i}-55479\hat{j}]\frac{N}{C}[/tex]

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Answer:

False

Explanation:

First we need to know the definition of work.

Work is done when a body moves through a distance with an applied force.

When swimming in water, you exert a force while moving through a distance. Therefore, work is done!

Answer:

A.) 0.5 m

B.) 2.5 m

C.) 10 m

Explanation:

Given that the

Spring constant K = 20 N/m

From hooks law

F = Ke

Where

F = force applied

K = spring constant

e = extension

A.) When F = 10 N

Substitute F and K into the formula

10 = 20e

e = 10/20 = 0.5 m

B.) When F = 50 N

50 = 20e

e = 50/20 = 2.5 m

C.) When F = 0.2 KN

0.2 × 1000 = 20e

200 = 20e

e = 200/20 = 10m

Answer: V = 299,958589.8 m/s

Explanation: To calculate Rigel velocity relative to us, we should use doppler effect formula.

Fo = (c + Vo) f/ ( c - Vs)

Fo/f = (c + Vo) / ( c - Vs)

If Vo = Vs = V approximately

4.26 × 10^10 = (3×10^8 + V) 6.17×10^14/(3×10^8 - V)

4.26×10^10/6.17×10^14 = (3×10^8 + V)/(3×10^8 - V)

6.9×10^-5 = (3×10^8 + V)/(3×10^8 - V)

Cross multiply

20713.13 - 6.9×10^-5V = 3×10^8 + V

Collect the like terms

6.9×10^-5V + V = 3×10^8 - 20713.13

1.000069V = 299979286.9

V = 299979286.9/1.000069

V = 299,958589.8 m/s

Therefore, Rigel's velocity relative to us is 299,958589.8 m/s

Answer:

no

Explanation:

the goalie can move side to side but cant go out of the goalie box.

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Answer:

1) When [tex]d_{o}[/tex] < [tex]d_{i}[/tex] (hence  [tex]d_{o}[/tex] < f ) and they are both in front of the mirror (positive), the image will be larger and inverted

2) When [tex]d_{o}[/tex] > [tex]d_{i}[/tex] (and [tex]d_{o}[/tex] < f ) such that they are both positive (in front of the mirror), the image will be smaller and inverted

3) When the image is behind the mirror, for convex mirrors and the object is in front the image will be uptight. The magnification of the image will be the ratio of the image distance to the object distance from the mirror

Explanation:

The position of an object in front of a concave mirror of radius of curvature, R, determines the size and orientation of the image of the object as illustrated in the mirror equation

[tex]\dfrac{1}{f}=\dfrac{1}{d_{o}} + \dfrac{1}{d_{i}}[/tex]

[tex]Magnification, \, m = \dfrac{h_{i}}{h_{o}} = -\dfrac{d_{i}}{d_{o}}[/tex]

Where:

f = Focal length of the mirror = R/2

[tex]d_{i}[/tex] = Image distance from the mirror

[tex]d_{o}[/tex] = Object distance from the mirror

[tex]h_{i}[/tex] = Image height

[tex]h_{o}[/tex] = Object height

[tex]d_{o}[/tex] is positive for an object placed in front of the mirror and negative for an object placed behind the mirror

[tex]d_{i}[/tex] is positive for an image formed in front of the mirror and negative for an image formed behind the mirror

m is positive when the orientation of the image and the object is the same

m is negative when the orientation of the image and the object is inverted

f and R are positive in the situation where the center of curvature is located in front of the mirror (concave mirrors) and f and R are negative in the situation where the center of curvature is located behind the mirror (convex mirrors)

∴ When [tex]d_{o}[/tex] < [tex]d_{i}[/tex] (hence  [tex]d_{o}[/tex] < f ) and they are both in front of the mirror (positive), the image will be larger and inverted

When [tex]d_{o}[/tex] > [tex]d_{i}[/tex] (and [tex]d_{o}[/tex] < f ) such that they are both positive (in front of the mirror), the image will be smaller and inverted

When the image is behind the mirror, for convex mirrors and the object is in front the image will be uptight. The magnification of the image will be the ratio of the image distance to the object distance from the mirror.

Answer:

Solenoid with a Metal core

Answer:

Faster

Explanation:

Purple light's frequency is faster than yellow

The frequency of purple light is higher that of yellow light.

The electromagnetic spectrum is the basis for the visual sense of colour. Color perception is connected to an object's light absorption, reflection, emission spectra, and interference, even though color is not an inherent property of matter.

The majority of humans use three different types of cone cells to see color in the visible light spectrum (trichromacy). Other species may have a distinct range of color sensitivity because they have a different number of cone cell types or eyes that are sensitive to a different wavelength, such as bees that can discern ultraviolet.

Different light wavelengths or spectral sensitivity in various cone cell types serve as the basis for animal perception of color, which is then processed by the brain.

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Answer:

The correct option is D

D) Gestalt

Explanation:

In the earlier 20th century, a group of German scientists named Max Wertheimer, Wolfgang Köhler and Kurt Koffka, noticed that people tend to organzie a cluster of information into a Gestalt.

Gestalt is a German word which means the way things are placed or put together as a whole. In the field of phychology, it can be defined as a pattern or configuration. In this context, it included the human mind and its behavior as a whole.

The Gestalt theory states that:

"The whole of anything is greater than its parts and that attributes of the whole can't be deduced by analyzing any of the parts on their own accord"

Answer:

The relation between frequency and time period is given by:

f = 1/T

Explanation:

In a wave motion, the particle move about the mean position with the passage of time. The particles rise to reach the highest point which is crest, and similarly falls to reach the lowest point which is trough. The cycle keeps on repeating.

The time period of the wave can be defined as the time taken to complete one such cycle. Time period is given by:

T = 2π/ω

Frequency can be defined as the number of cycles completed in unit time, which can be taken as the inverse of time period. frequency is given by

f = ω/2π

or

f = 1/T