Witch is not true about longitudinal waves?

Answer:A

Explanation:

Answer:

D. Mixtures are classified based on the distribution of particles in them.

Explanation:

A is wrong because mixtures are not made of elements that are bonded together chemically.

B is wrong because elements and compounds are types of pure substances.

C is wrong because pure substances are not made up of mixtures.

Please give brainliest

Answer:The answer will be B :) hope this helps!

Explanation:

Answer:

Vf = 39.2 m/s

h = 78.4 m

Explanation:

Using first equation of motion for vertical motion:

Vf = Vi + gt

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 0 m/s

g = 9.8 m/s²

t = time taken = 4 s

Therefore,

Vf = 0 m/s + (9.8 m/s²)(4 s)

Vf = 39.2 m/s

Now, we use second equation of motion

h = Vi t + (1/2)gt²

where,

h = height covered = ?

Therefore,

h = (0 m/s)(4 s) + (1/2)(9.8 m/s²)(4 s)²

h = 78.4 m

Answer:

The value is  [tex]\rho = 0.0180 97 9 \ \Omega m^{-1}[/tex]

Explanation:

From the question we are told that

   The radius of the conductor is [tex]r = 1.20 \ cm = 0.012 \ m[/tex]

    The current it is carrying is  [tex]I = 3.00 \ A[/tex]

    The electric field is  [tex]E = 120 \ V/m[/tex]

Generally the resistivity of the material is mathematically represented as

        [tex]\rho = \frac{EA}{ I }[/tex]

Here A is the area of the conductor which is mathematically represented as

      [tex]A = \pi r^2[/tex]

=>  [tex]A =3.142 * (0.012)^2[/tex]

=>  [tex]A = 0.000452 \ m^2[/tex]

So

    [tex]\rho = \frac{120 * 0.000452}{ 3 }[/tex]

=> [tex]\rho = 0.0180 97 9 \ \Omega m^{-1}[/tex]

Given values,

Now,

The area of conductor,

→ [tex]A = \pi r^2[/tex]

      [tex]= 3.142\times (0.012)^2[/tex]

      [tex]= 0.000452 \ m^2[/tex]

hence,

The resistivity will be:

→ [tex]\rho = \frac{EA}{I}[/tex]

By substituting the values, we get

     [tex]= \frac{120\times 0.000452}{3}[/tex]

     [tex]= 0.0180979 \ \Omega m^{-1}[/tex]

Thus the above response is right.  

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Answer:

The gravitational potential energy of the 8.6 kg mass is 5.38x10⁸ J.

Explanation:

We can find the gravitational potential energy of the mass using the following equation:                      

[tex] E_{p} = m*g*h [/tex]

Where:

m: is the mass = 8.6 kg

g: is the gravity = 9.81 m/s^{2}  

h: is the height = Earth's radius = 6371 km

Hence, we have:

[tex]E_{p} = 8.6 kg*9.81 m/s*6371000 m = 5.38 \cdot 10^{8} J[/tex]

Therefore, the gravitational potential energy of the 8.6 kg mass is 5.38x10⁸ J.

I hope it helps you!                                                            

Answer:

1.32142x10^-3 Gy

Explanation:

Mass m = 63kg

Time t = 5.0s

Beta energy = 1.5x19^-13J

1 Ci = 3.7x10¹⁰

3.0Ci = 3x3.7x10¹⁰

= 11.1x10¹⁰decay/s

We have a total of 11.1x10¹⁰ beta particles produced per second

The question says there is 100% absorption

Et = (11.1x10¹⁰)x5x1.5x10^-13

= 0.08325

The radiation dose = Et/m

= 0.08325/63 kg

= 0.001321428J/kg

= 0.001321428 grays

Or 1.32142x10^-3 Gy

The radiation dose of the person is 1.31 x 10⁻⁴ J/kg.

The radiation does is the ratio of the total dose to the mass of the person exposed to the radiation.

3 Ci beta radiation = 3 x (3.7x10¹⁰) = 11.1 x 10¹⁰decay/s

Et = (11.1x10¹⁰) x 5 x 1.5 x 10⁻¹³

Et = 8.25 x 10⁻³ J

Radiation dose of the person is calculated as follows;

Rd = Et/m

Rd = (8.25 x 10⁻³ J) / 63

Rd = 1.31 x 10⁻⁴ J/kg

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Answer:

Humus

Explanation:

Its Humus I believe. I remember learning something like this.

Answer:

B. 100%

Explanation:

When the amplitude of a vibrating membrane increases the loudness of sound increases. Higher amplitude waves will mean more energy and greater intensity which causes the sound to be louder.

Loudness is proportional to the square of the amplitude. This will simply mean when the amplitude of a wave is doubled, the sound will be 4 times louder.

In this case, 50% increase in the amplitude of a vibrating membrane will cause a 100% increase in the loudness of sound.

Answer:

I = 6.42 A

Explanation:

Given that,

Potential difference, V = 0.9 V

Length of the wire, l = 1.5 m

Area of cross section, [tex]A=0.6\ mm^2=6\times 10^{-7}\ m^2[/tex]

We need to find the current in the wire. Let I is current. We can find it using Ohm's law as follows :

V = IR

Where R is the resistance of the wire

[tex]I=\dfrac{V}{R}\\\\I=\dfrac{V}{\rho \dfrac{l}{A}}\\\\I=\dfrac{0.9}{5.6\times 10^{-8}\times \dfrac{1.5}{6\times 10^{-7}}}\\\\I=6.42\ A[/tex]

So, the current in the wire is 6.42 A.

Answer:

The value is  [tex]F = 34.3 \ N[/tex]

Explanation:

From the question we are told that

    The mass of the shed is  [tex]m = 25 \ kg[/tex]

    The length of the rope is  [tex]l = 5.0 \ m[/tex]

    The angular speed of the shed is [tex]w = 5 rev/minute = \frac{2* \pi * 5}{60 }= 0.524 \ rad/sec[/tex]

Generally the force exerted on the shed is mathematically represented as

     [tex]F = m * w^2 * l[/tex]

=>  [tex]F = 25 * 0.524^2 * 5[/tex]

=>  [tex]F = 34.3 \ N[/tex]    

The magnitude of the centripetal force on the sled by the rope is 34.3 N.

The given parameters:

The angular speed of the sled is calculated as follows;

[tex]\omega = 5 \ \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1 \min}{60 \ s} \\\\\omega = 0.524 \ rad/s[/tex]

The magnitude of the centripetal force on the sled by the rope is calculated as follows;

[tex]F = ma_c\\\\F = m\omega ^2 r\\\\F = 25 \times (0.524)^2 \times 5\\\\F = 34.3 \ N[/tex]

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Answer:

hellllllllooooooooooooooo

Answer:

d, magnetic attracting metal, because the force is still going on without the magnet touching metal, and you cant see the force

Explanation:

Hope this helps <33

Answer:

B) The rod is subject to tensile stress

Explanation:

Tensile stress is the force induced in the body per unit area in response to externally applied force, which stretches the body.

Tensile stress is attached with tensile forces. It is makes material elongate along the axis of the applied load.

It is given as magnitude (F) of the force that is applied along an elastic rod divided by the cross sectional area (A) of the rod in a direction that is perpendicular to the applied force.

materials such as Doctile have the ability to withstand the load while brittle materials who not have the ability they fail before reaching the ultimate material strength.

Answer:

When the cold weather fills hard surfaces with water, it causes it to freeze and expand, causing cracks in the surface.

Answer:

nucleus made of protons and neutrons because the chemical atom is determined my a number

Answer:

Why do you do sports, when you could be a doctor and helping the sick children, or saving the worlds ocean?

Explanation:

Answer:

Both daughter and parent atoms

Explanation:

Daughter atoms are an offshoot of daughter elements, and are formed when a radioactive element undergoes radioactive decay. The new element is the daughter element, while the initial, the former element is the parent element.

Same analogy goes for daughter atoms and parent atoms..

Radiometric dating is also called radioactive dating or even radioisotope dating. It is a technique that is used to date materials like carbon or even rocks, that has trace radioactive impurities selectively incorporated into it when they were formed.

Radiometric dating is defined as the technique, which is used to date rocks, carbon, or radioactive impurities. The rocks that consist of parent and daughter atoms are used for accurate radiometric dating.

The correct statement for the blank is:

Accurate radiometric dating typically requires that rock contains a measurable amount of parent and daughter atoms.

It can be defined as:

1. Daughter atoms are formed when the radioactive element undergoes radioactive decay. The element formed is the daughter element from which it is formed is known as the parent element.

2. A radioactive isotope is also called radioactive dating, which is used to date rocks and radioactive elements. These elements are incorporated into the elements when they are formed.

Thus, the correct answer is parent and daughter atoms.

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Answer:

None, both objects will hit ground at the same time.

Explanation:

        [tex]\Delta h = \frac{1}{2}*g*t^{2} (1)[/tex]

Answer:

0.5Amperes

Explanation:

Using the conservation of power formula

P = VI

The power we have in this coil is given as

P = 60 watts

Then we have V = 120 watts

Such that when we put these values into the formula above we will get:

60 = 120I

Then when we divide through by 120:

I = 60/120

I = 0.5 amperes

So 0.5 amperes is the rms in the primary coil.

Answer:

Explanation:

Given

torque,τ= 0.97N

radius r= 35cm to m= 0.35m

mass m= 0.75kg

Required

angular acceleration

First, we need the  moment of inertial of the wheel

I=mr^2

I=0.75*0.35^2

I=0.75*0.1225

I=0.09kgm^2

Secondly, the angular moment of inertial is expressed as

a=τ/I

a=0.97/0.09

a=10.77rads/s^2

a=11 rad/s^2 approx.

Answer:D

Explanation:

just got it right

Answer:D

Explanation:

taking the test

Answer:

0.817g

Explanation:

Zn2+ + 2e -----> An

Amount of electricity used

Q = It

= 1.6A x 25 x 60 seconds

= 2400 coulomb's

Number of moles of electrons = Q/f

F = 96500 coulomb's

= 2400/96500

= 0.025mol

From the equation above,

We see that the number of Zn moles firmed is equal to half the number of electrons used.

Molecular weight of Zn = 65.38

0.025x65.38/2

= 0.817 grams of zinc

Thank you!

Answer:

Vf = 86.34 [m/s]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f} ^{2} =v_{o} ^{2} +2*g*y[/tex]

where:

Vf = final velocity [m/s]

Vo = initial velocity = 0 (falls from the rest)

g = gravity acceleration = 9.81 [m/s²]

y = distance = 380 [m]

Vf² = 0 + (2*9.81*380)

Vf = 86.34 [m/s]

Note: The pisitive sign in the equation above means that the movement goes in the same direction of the gravity acceleration, therefore the velocity is increasing when the penny falls.

Answer:

a = 0

Explanation:

The velocity of a sound wave in a straight line is 660 mph. The wave is moving with a constant velocity. It means that the change in velocity is equal to 0.

We know that acceleration of an object is equal to the change in velocity divided by time taken. But here the change in velocity is 0. As a result the acceleration of the sound wave is 0.

Answer:

Is that the question?

Explanation:

its the 3rd one kinetic energy increases as speed increases

Answer:

a) E = 4.5*10⁴ V/m

b) C= 17.7 nF

c) Q = 159. 3 nC  

Explanation:

a)

       [tex]E = \frac{V}{d} = \frac{9.0V}{2*10-4m} =4.5 * 10e4 V/m (1)[/tex]

b)

       [tex]Q = \sigma* A (2)[/tex]

        From (1), we know that V = E*d, but at the same time, applying Gauss'

        Law at a closed surface half within the plate, half outside it , it can be

        showed than E= σ/ε₀, so finally we get:

       [tex]C = \frac{Q}{V} =\frac{\sigma*A}{E*d} = \frac{\sigma*A}{\frac{\sigma}{\epsilon_{o} } d} =\frac{\epsilon_{0}*A}{d} = \frac{8.85e-12F/m*0.4m2}{2e-4m} = 17.7 nF (3)[/tex]

c)    

       [tex]Q = C* V = 17.7 nF * 9.0 V = 159.3 nC (4)[/tex]

a) Electric field between the plates, E = 4.5*10⁴ V/m

b) Capacitance of the capacitor, C= 17.7 nF

c) Magnitude of the charge, Q = 159. 3 nC  

It is the electrostatic force per unit charge, and since the potential difference between plates is just the work done by the field, divided by the charge, assuming a uniform electric field, if V is the potential difference between plates, and d is the separation between plates, the electric field can be expressed as follows:

[tex]E=\frac{V}{d} \\\\E=\frac{90V}{2*10^{-4}m} \\\\E=4.5*10e4V/m[/tex]

For a parallel-plate capacitor, It is the quotient between the charge on one of the plates and the potential difference between them, and assuming a uniform surface charge density σ, we get:

[tex]Q=\sigma*A[/tex]

On comparing equation 1 and 2:

[tex]C=\frac{Q}{V}\\\\C=\frac{\sigma*A}{E*d}\\\\\\C=\frac{\sigma*A}{\frac{\sigma}{E_0}*d}\\\\C=\frac{8.85e^{-12}F/m-0.4m^2}{2e-4m}\\\\C=17.7nF\\\\[/tex]

From equation 3:

[tex]Q=C*V\\\\Q=17.7*9.0\\\\Q=159.3nC\\[/tex]

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