Why is water sometimes called the universal solvent.

Answer:

alright you take the numbers of the speed and d

irection and multiply ........ example....234×567 =?

Answer:

The ballon would be inflated. The reason is that the sodium bicarbonate in baking soda reacts with acetic acid in vinegar to produce gas.

Explanation:

The main component of baking soda is sodium bicarbonate, [tex]{\rm Na_{2}CO_{3}}[/tex].

Vinegar is mostly a solution of acetic acid [tex]{\rm CH_{3}COOH}[/tex] in water.

Acids such as acetic acid react with carbonate salts. One of the products of such reactions is carbon dioxide [tex]{\rm CO_{2}}[/tex], a gas.

In this question, when the acetic acid in vinegar reacts with sodium bicarbonate in the baking soda, the following reaction would occur:

[tex]\begin{aligned}& {\rm Na_{2}CO_{3}}\, (aq) + 2\, {\rm CH_{3}COOH}\, (aq) \\ &\to 2\, {\rm CH_{3}COONa}\, (aq) + {\rm CO_{2}}\, (g)\end{aligned}[/tex].

The [tex]{\rm CO_{2}}[/tex] produced would then inflate the ballon placed on the opening of the bottle.

Explanation:

For nearly nine decades, science's favorite explanation for the origin of life has been the “primordial soup”. This is the idea that life began from a series of chemical reactions in a warm pond on Earth's surface, triggered by an external energy source such as lightning strike or ultraviolet (UV) light.

The graph of the potential energy pass through zero origin, cuts across positive x-axis and negative x-axis.

The slope of the graph when the potential energy of a particle constrained in on x-axis is determined as follows;

F = -dU/dx

-dU = Fdx

dU = -Fdx

U = -∫(kx + ax³)dx

U = kx²/2 - ax⁴/4

When, x = 0, U = 0

When U = 0;

[tex]x = \pm \sqrt{\frac{2k}{a} }[/tex]

The graph of the potential energy pass through zero origin, cuts across positive x-axis and negative x-axis.

Complete question is below:

Suppose that the potential energy of a particle constrainedon x-axis and subjected to a force in the same direction, at a fuction of F(x) = -kx + ax³.

Find the functional form of the potential energy.

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E=1. 55× 10−19 J.

ultraviolet light

When an electron drops from n = 2 to n = 1, it emits a photon of ultraviolet light. The step from the second energy level to the third is much smaller. It takes only 1.89 eV of energy for this jump. It takes even less energy to jump from the third energy level to the fourth, and even less from the fourth to the fifth.

Answer:

See below ~

Explanation:

Work is the energy used in applying a force to displace an object. It is defined as the dot product of force and displacement. Depending on the direction, it is classified as :

===============================================================

By deriving the units of Force and Displacement respectively, we will get:

Although Nm is the common standard unit for Torque, the standard unit for work is Joules (J).

It has many other units as well, namely :

The unit of work is Joules (J)

Work has general formula

When there is an angle included the formula becomes

When he swings a rubber bung around his head on a string, the centripetal force is caused by the tension in the string.

When an object travels in circular path, a force which makes an object to continue to move in circular motion is the centripetal force which is directed towards the center of the path.

Thus, When he swings a rubber bung around his head on a string, the tension force is developed in the string which is in turn balanced by the centripetal force.

Thus, the centripetal force is caused by the tension in the string.

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Answer:

The answer is the third one.

C.

Hope this helps!

Answer:

a is the correct answer

Explanation:

period T=1/f

where f=60hertz

then T= 1/60 which give 0.01666666 but putting it in standard form and rounding up give 1.7×10^-2

Answer:

Explanation:

According to ohm's law, we know that:

Where,

Substituting the values, we get:

→ 2000 = 200 × R

→ 2000/200 = R

→ 10 = R

Hence,

Answer: Hello Miko here to help!

Explanation: The answer is c!

The tension in the string which supports the 5.0 kg cylinder of solid iron and submerged in water is 42.8 N.

Tension is the pulling force carried by the flexible mediums like ropes, cables and string. Tension in a body due to the weight of the hanging body is the net force acting on the body.

A 5. 0 kg cylinder of solid iron is supported by a string while submerged in water. The density of iron is 7860 kg/m3 and that of water is 1000 kg/m3.

The tension in string can be find out using the following formula,

[tex]T=mg\left(1-\dfrac{\rho_w}{\rho_i}\right)[/tex]

Here, m is the mass of solid, g is gravitational force, ρ is the density and subscript (w and i) is for water and iron respectively.

Put the values,

[tex]T=5\times9.81\left(1-\dfrac{1000}{7860}\right)\\T=42.8\rm\; N[/tex]

Thus, the tension in the string which supports the 5.0 kg cylinder of solid iron and submerged in water is 42.8 N.

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Based on the calculations, the speed required for this satellite to stay in orbit is equal to 1.8 × 10³ m/s.

Given the following data:

In order to determine the speed of this satellite to stay in orbit, the centripetal force acting on it must be sufficient to change its direction.

This ultimately implies that, the centripetal force must be equal to the gravitational force as shown below:

Fc = Fg

mv²/r = GmM/r²

Where:

Making v the subject of formula, we have;

v = √(GM/r)

Substituting the given parameters into the formula, we have;

v = √(6.67 × 10⁻¹¹ × 7.36 × 10²²/4.2 × 10⁶)

v = √(1,168,838.095)

v = 1,081.13 m/s.

Speed, v = 1.8 × 10³ m/s.

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Answer:

Johannes Kelper

Explanation:

Answer:

10000000000000000000000000000000000

Explanation:

Normal (N) and gravity force (W)

assume g = 10 m/s²

a. N = W = m₁.g = 3 x 10 = 10 N

b. W = m₂.g = 1.5 x 10 = 15 N

c. N = (m₁+m₂)g = 4.5 x 10 = 45 N

The greatest observed shift in wavelength, as seen in the scattered photon, when an x-ray photon of wavelength 0. 10 nm is compton-scattered from a free electron is 0.048 nm.

The shift in wavelength can be find out using the Compton effect formula. It is given as,

[tex]\Delta \lambda=\dfrac{h}{m_oC}(1-\cos \theta)[/tex]

Here, h is the planks constant (6.63 × 10⁻³⁴ J-s), m₀ is the mass of electron (9.1×10⁻³¹ kg), C is the speed of light (3×10⁸ m/s).

An x-ray photon of wavelength 0. 10 nm is compton-scattered from a free electron.

At the value of cos theta in above formula equal to -1, we get the greatest observed shift in wavelength. Thus, put the values,

[tex]\Delta \lambda=\dfrac{6.63\times10^{-34}}{9.1\times10^{-31}\times3\times10^8}}(1-(-1))\\\Delta \lambda=4.857\times10^{-12}\rm \; m\\\Delta \lambda=0.048\rm\; nm[/tex]

Thus, the greatest observed shift in wavelength, as seen in the scattered photon, when an x-ray photon of wavelength 0. 10 nm is compton-scattered from a free electron is 0.048 nm.

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The magnitude of their vector sum will be 0.60025 m. Law of vector addition is used in given problem.

A vector is a quantity or phenomena with magnitude and direction that are independent of one another. The phrase also refers to a quantity's mathematical or geometrical representation.

If no vector can be written as a linear combination of the others, a set of vectors is said to be linearly independent.

Angle between Q and S is found as;

θ=123°+32.1°

θ=155.1°

The magnitude of their vector sum,magnitude (m) is found as;

[tex]\rm R = \sqrt{Q^2+S^2+2QS cos \theta } \\\\ R=\sqrt{(0.34)^2+(0.876)^2+2(0.34)(0.870)cos 155.1^0 } \\\\ R=0.6002522 \ m[/tex]

Hence,the importance of their vector sum will be 0.60025 m.

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The velocity of the ball as it passes a treetop 4. 88 m tall and  thrown straight upward with a velocity of 9. 98 m/s is 14 m/s.

The equation of motion is the relation between the distance, velocity, acceleration and time of a moving body.

The third equation of the motion for distance can be given as,

[tex]v^2-u^2=2ah[/tex]

Here, is the u initial body, a is the acceleration of the body and h is the height of it.

The ball is thrown straight upward with a velocity of 9. 98 m/s. The height of it is 4. 88 m. Thus, initial velocity is 4.88 meters and the acceleration due to gravity is 9.98 m/s².

Put the values,

[tex]v^2-u^2=2ah\\v^2-(9.98)^2=2(9.98)(4.88)\\v^2=2(9.98)(4.88)+(9.98)^2\\v\approx 14\rm\; m/s[/tex]

Hence, the velocity of the ball as it passes a treetop 4. 88 m tall and  thrown straight upward with a velocity of 9. 98 m/s is 14 m/s.

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Answer:

Yes it can

Explanation:

Answer:

It says about the motion and the graph of the object is stationary, basically travelling at the same speed at any time of the graph. It will never change.

Explanation:

To draw a diagram:

1. Draw an object and represent the speed as stationary and constant at any time.

Given speed and the distance that must be covered, the time it will take the ultraviolet light to reach the earth is 3.7 × 10⁴ hours.

Speed is simply referred to as distance traveled per unit time.

Mathematically, Speed = Distance ÷ time.

Given the data in the question;

We substitute our given values into the expression above.

Speed = Distance ÷ time

1.08 × 10⁹km/h = 4.0 × 10¹³km ÷ t

t = 4.0 × 10¹³km ÷ 1.08 × 10⁹km/h

t = 3.7 × 10⁴ hrs

Therefore, given speed and the distance that must be covered, the time it will take the ultraviolet light to reach the earth is 3.7 × 10⁴ hours.

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The magnitude of the force on a 0. 0150 kg particle placed at p will be -8 N. Force is defined as the product of mass and acceleration. Its unit is Newton.

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

The velocity is found as;

[tex]\rm v= \frac{dx}{dt}\\\ v= \frac{d}{dt} (13.00+2.00t+4.00 t^2-3.00t^3)\\\\ v= 2+ 8t -9t^2[/tex]

The acceleration is found as;

[tex]\rm a = \frac{dv}{dt} \\\\ a= \frac{d}{dt} (2-8t-9t^2)\\\\ a = \frac{d}{dt} 98t-9t^2)\\\\\ a=8-18t\\\\ a=8-(18 \times 3.4)\\\\a=-53.2 m/sec^2[/tex]

The value of the force for the given mass is;

[tex]\rm F= maas \times acceleration \\\\ F = m\times a\\\\ F= 0.150 \times (-53.2) \\\\ F= -7.98 \ N\\\\ F= -8\ N[/tex]

Hence, the value of the force is -8 N .

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Answer:

A. a person riding a bicycle

Explanation:

Mechanical energy is when something moves. Like a car moving from place to place and ball rolling. Every thing else is not moving.

The force does the car and wall collide will be  57,000 J. Option A is correct.

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.

The given data in the problem;

Mass (m)= 1900 kg

Velocity(V)=30m/s

From the Newtons second law of motion;

I =  Δ P

F Δ t = m(v-u)

If the time of the collision is too short, can be neglected;

F = 1900(30-0)

F = 57,000 J

Hence, the force does the car and wall collide will be 57,000 J.

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The power output is, 2800 watt. Power is defined as the rate of the work done.

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.

The power output is found as;

[tex]\rm P = \frac{W}{t} \\\\ P= \frac{F \times d }{t} \\\\ P= \frac{2800 \ N \times 80.0\ m}{8.0 \ sec} \\\\ P=2800 \ Watt[/tex]

Hence,the power output is, 2800 watt.

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The acceleration of electron and protons are[tex]a = 2.64 \times 10^{13[/tex]m/s² [tex]a = 1.44 \times 10^{10[/tex] m/s² respectively.

Electric field is a region around a charged particle or object within which a force would be exerted on other charged particles or objects.

Given that,

Magnitude of electric field is

E = 150N/C

a. Acceleration of election?

The charge on an electron is

[tex]q = -1.602\times 10^{-19[/tex]

then, the force in electric field is given as

F=qE

[tex]F = 150\times 1.602\times 10^{-19[/tex]

[tex]F = 2.403\times10^{-17} N[/tex]

Using second law of motion

F= ma

Then, [tex]a =\dfrac{ F}{m}[/tex]

Then, mass of electron is

[tex]m = 9.11 \times 10^{-31}kg[/tex]

Therefore,

[tex]a =\dfrac{ F}{m}[/tex]

[tex]a = \dfrac{2.403\times 10^{-17}}{9.11\times 10^{-31}}[/tex]

[tex]a = 2.64 \times 10^{13}[/tex]

That’s the magnitude of the electron’s acceleration.

Since the electron has a negative charge the direction of the force on the electron (and also the acceleration) is opposite the direction of the electric field.

b. Same procedure

Acceleration of proton?

The charge on a proton is

[tex]q = +1.602\times 10^{-19}[/tex]

then, the force in electric field is given as

F=qE

[tex]F = 150\times 1.602\times 10^{-19}[/tex]

[tex]F = 2.403\times 10^{-17} N[/tex]

Using second law of motion

F= ma

Then, [tex]a =\dfrac{ F}{m}[/tex]

Then, mass of proton is

[tex]m = 1.67 \times 10^{-27}\ kg[/tex]

Therefore,

[tex]a =\dfrac{ F}{m}[/tex]

[tex]a = \dfrac{2.403\times 10{^-17}}{1.67\times 10^{-27}}[/tex]

a = 1.44 ×10^10m/s²

That’s the magnitude of the proton's acceleration.

Since the proton has a positive charge the direction of the force on the proton (and also the acceleration) is in the same direction of the electric field.

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