Answer:
The CORRECT answer is:
C. Independent assortment results in different combinations of genes in sex cells.
E. Independent assortment occurs when chromosomes randomly line up in the middle of the cell.
The statements describe independent assortment are Independent assortment results in different combinations of genes in sex cells and Independent assortment occurs when chromosomes randomly line up in the middle of the cell.
The correct options are C and E.
What is independent assortment?The Principle of Independent Assortment depicts how various qualities autonomously separate from each other when regenerative cells create. Free combination of qualities and their comparing attributes was first seen by Gregor Mendel in 1865 during his investigations of hereditary qualities in pea plants.
So, Independent assortment results in different combinations of genes in sex cells.
Also, Independent assortment occurs when chromosomes randomly line up in the middle of the cell.
Thus, correct options are C and E.
Learn more about independent assortment.
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Kate is creating two models to describe the effect of thermal energy on the movement of particles in a liquid. She draws the first model of a liquid sample. Her model is shown below.
Explanation:
so sorry
don't know but please mark me as brainliest please
How long would it take light to travel round trip to Mars when it is 2x1010m from the Earth?
a) 0.015s
b) 0.03s
c) 66.7s
d) 133s
Show calculation
Answer:
66.7s
Explanation:
Given parameters:
Distance between Mars and Earth = 2 x 10¹⁰m
Unknown:
Time it takes for light to travel = ?
Solution:
The speed of light is given as 3 x 10⁸m/s
Now;
Speed = [tex]\frac{distance}{time}[/tex]
Time = [tex]\frac{distance}{speed}[/tex]
Insert the parameters and solve;
Time = [tex]\frac{2 x 10^{10} }{3 x 10^{8} }[/tex] = 66.7s
Find the y-component of this
vector:
Answer:
Dy = 49.01 [m]
Explanation:
The vertical component of the vector can be determined with the sine of the angle.
Dy = 92.5*sin(32)
Dy = 49.01 [m]
what is the mass of the 40 kg object on the moon?
Answer:
6.64 Newtons
On the moon that 40 kg child would have a weight of 6.64 Newtons (kg multiplied by gravity) because the moon's gravity is 1/6th of the Earth's gravity. Your mass on any planet on the solar system (Jupiter, Venus, Earth, or anywhere else) is the same because the amount of matter in you does not change.
Explanation:
A 2.00 kg mass is located at (4.00 m, 0.00 m, 0.00 m) and a 4.00 kg mass is located at (0.00 m, 3.00 m, 0.00 m). If this system of masses rotated about the Z-axis perpendicular to the X-Y plane, then the moment of inertia of this system is:_______
Answer:
The moment of inertia of this system is 68 kilogram-square meters.
Explanation:
We have two particles rotating about the z-axis, which is orthogonal to xy plane, the moment of inertia of the system ([tex]I_{z}[/tex]), measured in kilogram-square meters, is determined by the following formula:
[tex]I_{z} = \Sigma \limits_{i=1}^{2}m_{i}\cdot r_{i}[/tex] (1)
Where:
[tex]m_{i}[/tex] - Mass of the i-th particle, measured in kilograms.
[tex]r_{i}[/tex] - Distance of the i-th particle from axis of rotation, measured in meters.
By Pythagorean Theorem we calculate each distance:
[tex](x_{1}, y_{1}, z_{1}) = (4\,m, 0\,m,0\,m)[/tex]
[tex]r_{1}=\sqrt{(4\,m-0\,m)^{2}+(0\,m-0\,m)^{2}+(0\,m-0\,m)^{2}}[/tex]
[tex]r_{1} = 4\,m[/tex]
[tex](x_{2},y_{2}, z_{2}) = (0\,m, 3\,m, 0\,m)[/tex]
[tex]r_{2} = \sqrt{(0\,m-0\,m)^{2}+(3\,m-0\,m)^{2}+(0\,m-0\,m)^{2}}[/tex]
[tex]r_{2} = 3\,m[/tex]
If we know that [tex]m_{1} = 2\,kg[/tex], [tex]r_{1} = 4\,m[/tex], [tex]m_{2} = 4\,kg[/tex] and [tex]r_{2} = 3\,m[/tex], then the moment of inertia of the system is:
[tex]I_{z} = m_{1}\cdot r_{1}^{2}+m_{2}\cdot r_{2}^{2}[/tex] (1b)
[tex]I_{z} = (2\,kg)\cdot (4\,m)^{2}+(4\,kg)\cdot (3\,m)^{2}[/tex]
[tex]I_{z} = 68\,kg\cdot m^{2}[/tex]
The moment of inertia of this system is 68 kilogram-square meters.
Help me , what is the properties of fluids ?
The properties of fluids are Density,Viscosity,Temperature, Pressure,Specific Volume,Specific Weight,Specific Gravity.
What is the wavelength of an FM radio wave of frequency 90Mhz?
a) 0.033m
b) 0.3m
c) 3.3m
d) 30m
Show calculation
Answer:
3.3m
Explanation:
Given parameters:
Frequency = 90Mhz
Unknown:
Wavelength = ?
Solution:
To find the wavelength, use the expression below;
V = f x wavelength
V is the speed of light = 3 x 10⁸m/s
f is the frequency
Now;
Insert the parameters
3 x 10⁸ = 90 x 10⁶ x wavelength
Wavelength = [tex]\frac{3 x 10^{8} }{9 x 10^{7} }[/tex] = 3.3m
A man steps off a diving platform lands in the water below. If he were to miss the water and land on the concrete, his change in momentum would be the same as if he landed in the water. Why is the change in momentum the same for both situations?
Answer:
if he were to land on concrete, he would most likely die and stop all momentum and for the water, he'd most likely live/die (mostly live) and slow momentum to a stop and rise up to the surface
Explanation:
that's the explanation now i gotta execute order 66
Give one suggestion how to increase the velocity of water rocket?
Answer:
Streamline the body of the rocket to reduce drag
Keep weight to a minimum
Use higher pressures
Use the right amount of water
help me please answer this
Answer:
that's fusion
Explanation:
Answer:
the answer is fusion for this
Nicolas is playing with his toy car. A parachute in the back of the car is released to help slow down the car.
If the forces act on the car as shown in the picture, what is the net force?
Answer:3 N —->
Explanation:
In the case when the forces act on the car as shown in the picture so here the net force should be 3N.
Calculation of the net force:Since
A parachute in the back of the car is released to help slow down the car.
So here the net force should be
= 10 N - 7N
= 3 N
Hence, In the case when the forces act on the car as shown in the picture so here the net force should be 3N.
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How much work is done when you push a table with 300 N of force 5 m across a room?
Part One: Defining the Problem and Sub-Problems
Choose one of the real-world problems about natural resources to research. Explain which one you chose here.
Research this problem to learn more about it. Use the research tools given in the lesson if you need help.
After you have researched the problem, explain in your own words who the problem impacts and why it is important.
List two sub-problems that are part of the bigger problem but are more manageable and solvable.
Explain how these sub-problems are related to or a direct result of the overall problem.
Part Two: Criteria, Constraints, and Prioritizations
Choose one sub-problem that you will investigate further and explain which one you chose here.
List two realistic criteria for the sub-problem.
Explain why it is important for these criteria to be met in order to solve the problem.
List two constraints for the sub-problem.
Explain why these constraints exist. (How do they limit solutions to the problem?)
Prioritization of the criteria and constraints and an explanation supporting the decisions made based on research.
Ranking Criteria or Constraint Reason for Prioritization
1
2
3
4
Part Three: Generate Solutions
List two solutions that you have generated for the chosen sub-problem.
Describe how the sub-problem can be solved, and include the research supporting each solution.
Explain how prioritization was involved in designing each solution.
Explain how both solutions to the sub-problem play a role in solving the larger problem.
List of the sources (at least three) you used for research, following the MLA style guide.
Answer:
Part One: Defining the Problem and Sub-Problems
1. Choose one of the real-world problems about natural resources to research. Explain which one you chose here.
o I chose pollution, due to the overwhelming pollution in todays day and age.
2. Research this problem to learn more about it. Use the research tools given in the lesson if you need help.
o There are 4 main types of pollution Air Pollution, Water Pollution, Soil Pollution, Noise Pollution.
o Air pollution refers to the release of harmful contaminants into the earth’s atmosphere.
o Water pollution is said to occur when toxic pollutants and particulate matter are introduced into water bodies such as lakes, rivers and seas.
o Soil pollution, also called soil contamination, refers to the degradation of land due to the presence of chemicals or other man-made substances in the soil.
o Noise pollution refers to the excessive amount of noise in the surrounding that disrupts the natural balance.
o Pollution is harmful things within an environment, that can cause decay within an environment.
3. After you have researched the problem, explain in your own words who the problem impacts and why it is important.
o It impacts the environment, people, animals, water, food, and the atmosphere. Its important to try and stop pollution to- a. make the world a cleaner place and b. stop such harmful substance from killing the environment around us.
4. List two sub-problems that are part of the bigger problem but are more manageable and solvable.
o Man made factories, cars, and garbage dumps.
o Being a litter bug (throwing trash on the ground).
5. Explain how these sub-problems are related to or a direct result of the overall problem.
o Cars create air pollution, along with factories. With being a litter bug and garbage dumps it causes soil pollution.
Part Two: Criteria, Constraints, and Prioritizations
1. Choose one sub-problem that you will investigate further and explain which one you chose here.
o Cars/fuel
2. List two realistic criteria for the sub-problem.
o Reducing fuel and oil can help fix the problem.
o Also using more electric ways to charge the car to run could be based off solar power to create a better environment.
3. Explain why it is important for these criteria to be met in order to solve the problem.
o It would create less air pollution, and could help with sickness, plants dying, and animals dying.
4. List two constraints for the sub-problem.
o Electric cars are a bit to expensive for the average person.
o People need to drive for work/travel, so they need gas for their car and due to the higher priced cars, it makes it almost impossible for this goal to be reached.
5. Explain why these constraints exist. (How do they limit solutions to the problem?)
o They exist due to the underpayment of workers and the average and below average social class. As for limiting the solutions, that is currently happening due to two oil factories shutting down raising the price on gas and limiting more gas for people. But causing more global panic/ angry people, due to not being able to receive what they need to continue their life by driving.
6. Prioritization of the criteria and constraints and an explanation supporting the decisions made based on research.
Ranking Criteria or Constraint Reason for Prioritization
1. Fuel and oil Its highly needed to run cars but causes sever pollution.
2. Prices for electric cars We could possibly have less pollution though its too expensive to afford a car that runs off electric. Because it may reduce pollution but the average paid person couldn’t afford it.
3. Under payment Within underpayment it causes more fuel and oil to be used in older cars that cant use electric charging.
4. Solar powered electric charge stations Low pollution and easily earth friendly acceptable.
Part Three: Generate Solutions
1. List two solutions that you have generated for the chosen sub-problem.
o Lowering prices on electric cars.
o Creating solar powered charge stations to reduce more pollution.
2. Describe how the sub-problem can be solved, and include the research supporting each solution.
o Lowering prices on electric cars and creating less fuel and oil providing cars could reduce pollution dramatically due to the burning fuels not polluting the air. And along with lowering car prices creating a solar energy charge station creates a more natural charge station instead of causing soil pollution with factories and under ground pipes.
3. Explain how prioritization was involved in designing each solution.
o Lowering prices on electric cars and creating less fuel and oil providing cars could reduce pollution dramatically due to the burning fuels not polluting the air.
4. Explain how both solutions to the sub-problem play a role in solving the larger problem.
o Both of my solutions would stop both soil and air pollution when it comes to cars and factories.
You accidentally drop a watch from the roof of a six-story building. While picking up the watch , you notice that it stopped 2s after it was dropped. How tall is the building?
Answer:
20 m
Explanation:
Area under the speed-time graph = Distance Traveled
Area under Graph 1/2(2)(20)
=20 m
_________ players per team are allowed to be on the floor at a time during a game.
Group of answer choices
1
5
7
10
Answer:
5
Explanation:
Answer:
5
Explanation:
Which method of heat transfer transmits heat from the lower layers of air to the upper layers of air as the lower layers of air warm up and rise and replace the upper layers of air that cool off and sink down?
Answer:
Convection
Explanation:
The method of heat transfer that allows heat to rise via vertical transport of heated part of a fluid (gas or liquid) and replace the fluid upper layers is called "convection"
Answer:
Convection
Explanation:
Its Convection
What is the magnitude of the applied electric field inside an aluminum wire of radius 1.5 mm that carries a 5.5-A current?
Answer:
E = 2.17 x 10⁻² V/m
Explanation:
First we will find out the current density by using the formula:
J = I/A
where.
J = Current Density = ?
I = Current = 5.5 A
A = Cross-Sectional Area = πr² = π(1.5 x 10⁻³ m)² = 7.068 x 10⁻⁶ m²
Therefore,
J = 5.5 A/7.068 x 10⁻⁶ m²
J = 0.778 x 10⁶ A/m²
Now, we calculate the magnitude of applied field:
E = ρJ
where,
E = Magnitude of applied field = ?
ρ = resistivity of Aluminum = 2.8 x 10⁻⁸ Ω.m
Therefore,
E = (2.8 x 10⁻⁸ Ω.m)(0.778 x 10⁶ A/m²)
E = 2.17 x 10⁻² V/m
A projectile is launched straight upward at 50 m/s. Neglecting air resistance its speed upon returning to its starting point is:________.
Answer:
The speed of the projectile upon returning to its starting point is 50 m/s.
Explanation:
Given;
initial velocity of the projectile, u = 50 m/s
The velocity of the projectile is maximum before hitting the ground. As the object moves upward, the velocity reduces as it approaches the maximum height, at the maximum height the velocity becomes zero. Also, as the object moves downward, the velocity starts to increase and becomes maximum before hitting the ground.
Therefore, the speed of the projectile upon returning to its starting point is 50 m/s.
Sully is riding a snowmobile on a flat, snow-covered surface with a constant velocity of 10 meters/second. The total mass of the snowmobile, including Sully, is 280 kilograms. If Sully accelerates to a velocity of 16 meters/second over 10 seconds, what’s the force exerted by the snowmobile to accelerate? Use F = ma, where . A. 160 N B. 168 N C. 248 N D. 280 N E. 324 N
Answer:
280.6N
Explanation:
According to Newton's second law;
Force = mass * acceleration
Given
Mass = 280kg
velocity = 10m/s
Time = 10 secs
Acceleration = velocity?/Time
Force = mass * velocity/time
Force = 280 + (16-10/10)
Force = 280 + 0.6
Force = 280.6N
Hence the force exerted by the snowmobile to accelerate is 280.6N
Answer:168 N
Explanation:
A syringe has a fine needle with an inside diameter of 109μm. The barrel has a diameter of 2.22cm and is filled with water. Calculate the velocity of water as it squirts horizontally from the needle if you apply a force of 3.24N onto the plunger. (Hint: you may approximate the area of the barrel to be much larger than the area of the needle).
Answer: the velocity of water as it squirts horizontally from the needle is 4.09196 m/s
Explanation:
Given that;
inside diameter = 109μm
barrel diameter = 2.22 cm so r = 1.11 cm = 0.0111 m
force fair = 3.24 N
We know that the inside diameter is neglected; from the Bernoulli's equation
so
P_inside + 1/2pv²_inside + egy_inside = P_outside + 12pv²_outside + egy_outside
p_inside - p_outside = 1/2e_airv²outside = Fair / Abannel
Fair = 1/2painv²outside . Abannel
therefore
3.24 = 1/2(1000) v²outside (πr²)
3.24 = 1/2(1000) v²outside (π × (0.0111)²
3.24 = 0.1935 v²_outlet
v²_outlet = 3.24 / 0.1934
v²_outlet = 16.7441
v_outlet = √16.7441
v_outlet = 4.09196 m/s
Therefore the velocity of water as it squirts horizontally from the needle is 4.09196 m/s
A 20kg block slides a cross a horizontal surface. If the coefficient of kinetic friction between the block and the surface is 0.20, what is the force of kinetic friction that acts on the block?
Compute the block's weight:
w = m g = (20 kg) (9.8 m/s²) = 196 N
The net vertical force is 0, so the normal force has the same magnitude:
n + (-w) = 0 → n = 196 N
The frictional force (mag. f ) is proportional to the normal force by a factor of µ = 0.20 such that
f = 0.20 (196 N) = 39.2 N ≈ 39 N
The force of kinetic friction acting on the block of mass 20 Kg having a coefficient of kinetic friction of 0.2 is 39.2 N
We'll begin by calculating the the normal reaction (N). This can be obtained as follow:Mass (m) = 20 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Normal reaction (N) =?N = mg
N = 20 × 9.8
N = 196 NFinally, we shall determine the force of kinetic friction. This can be obtained as follow:Coefficient of kinetic friction (µ) = 0.2
Normal reaction (N) = 196
Force of kinetic friction (F) =?F = µN
F = 0.2 × 196
F = 39.2 NTherefore, the force of kinetic friction acting on the block is 39.2 N
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Which safety rule is MOST important when smelling the product of a chemical reaction?
Group of answer choices
Keep nose directly above open container.
Hold with tongs
Wear closed -toed shoes.
use a wafting motion.
Answer:
group of answer choices
Explanation:
Plz help ASAP I will give brainliest PLZ
The weight of a bucket is 186 N. The bucket is being raised by two ropes. The free-body diagram shows the forces acting on the bucket.
A free body diagram with 3 force vectors. The first vector is pointing downward, labeled F Subscript g Baseline = 186 N. The second vector is pointing up, labeled F Subscript 1 Baseline 105 N. The third vector is pointing upward from the tip of the second using the tail to tip method, labeled F Subscript 2 Baseline = 115 N. The combined two vectors pointing upward are shorter than the one pointing downward.
The acceleration of the bucket, to the nearest tenth, is
m/s2.
Answer:
1.8m/s^2
Explanation:
Since the two ropes are going up, their combined force is 105+115=220N. With a gravitational force of 186N, the force of the two ropes pulling up the will be 220-186=34N.
Now we need the mass of the bucket itself in order to find the acceleration of the bucket (remember that F=ma and m is needed to find a). Since gravitational acceleration is 9.8m/s^2 and F=186N, 186/9.8=18.97959184 kg for the mass of the bucket.
Now that we have the mass of the bucket, we can find the acceleration of the bucket. Since F=34N from earlier, 34N/18.97959184kg=1.791397849m/s^2=1.8m/s^2 is the acceleration of the bucket.
Therefore, 1.8m/s^2 is the correct answer.
Please mark brainliest!
Answer:
1.8
Explanation:
honestly i jus took the test
An astronaut weighs 626 newtons at Earth's surface. If he were to cut his distance from
Earth's center in half, what would be his new weight, to the nearest newton?
A radioactive atom has just undergone nuclear decay. Its mass number is now four less than the original atom. Which type of nuclear decay has occurred?
Answer:
Explanation:
mass number is now 4 times less than the original value so alpha decay occur during alpha decay the mass number is decreased 4 times and atomic number decreased 2 times than the original value
1. A curious physics student drops a book from a high building.
A. What is the VELOCITY of the brick after 3.0s?
B. How FAR(Distance) does the book fall during this time?
2. Suppose a free-fall ride at an amusement park starts at a rest and then drops.
A. What is the VELOCITY of the ride after 2.5s?
B. How FAR do people on the ride fall during the 2.5s time period?
3. You throw a ball downward from a window at a speed of 3.0 m/s.
A. How FAST will it be moving when it hits the sidewalk 2.0m below?
4. If I drop a photo copier off of a 45m tall building and splats on the ground below:
A. Calculate the TIME to hit the ground:
B. Calculate the VELOCITY just before:
Answer:
1.
A. Vf = 29.4 m/s
B. h = 44.1 m
2.
A. Vf = 24.5 m/s
B. h = 30.625 m
3.
A. Vf = 5.5 m/s
4.
A. t = 3.03 s
B. Vf = 29.7 m/s
Explanation:
1.
A.
using 1st equation of motion:
Vf = Vi + gt
where,
Vf = Final Velocity = ?
Vi = Initial Velocity = 0 m/s (since, book starts from rest)
g = 9.8 m/s²
t = time = 3 s
Therefore,
Vf = 0 m/s + (9.8 m/s²)(3 s)
Vf = 29.4 m/s
B.
using 2nd equation of motion:
h = Vi t + (1/2)gt²
h = (0 m/s)(3 s) + (1/2)(9.8 m/s²)(3 s)²
h = 44.1 m
2.
A.
using 1st equation of motion:
Vf = Vi + gt
where,
Vf = Final Velocity = ?
Vi = Initial Velocity = 0 m/s (since, book starts from rest)
g = 9.8 m/s²
t = time = 2.5 s
Therefore,
Vf = 0 m/s + (9.8 m/s²)(2.5 s)
Vf = 24.5 m/s
B.
using 2nd equation of motion:
h = Vi t + (1/2)gt²
h = (0 m/s)(2.5 s) + (1/2)(9.8 m/s²)(2.5 s)²
h = 30.625 m
3.
A.
using 3rd equation of motion:
2gh = Vf² - Vi²
where,
Vf = Final Velocity = ?
Vi = Initial Velocity = 3 m/s
g = 9.8 m/s²
h = height = 2 m
Therefore,
2(9.8 m/s²)(2 m) = Vf² - (3 ms)²
Vf² = 39.2 m²/s² - 9 m²/s²
Vf = √30.2 m²/s²
Vf = 5.5 m/s
4.
A.
using 2nd equation of motion:
h = Vi t + (1/2)gt²
where,
h = height = 45 m
Vi = Initial Velocity = 0 m/s (since, photo copier was initially at rest)
t = time = ?
g = 9.8 m/s²
45 m = (0 m/s)(t) + (1/2)(9.8 m/s²)(t)²
t² = 2(45 m)/(9.8 m/s²)
t = √9.18 s²
t = 3.03 s
B.
using 1st equation of motion:
Vf = Vi + gt
Vf = 0 m/s + (9.8 m/s²)(3.03 s)
Vf = 29.7 m/s
A block of mass 500g is pulled from rest on ahorizontal frictionless bench by a steady force F and travels 8m in 2s find the acceleration?
We are Given:
Mass of the block (m) = 500 grams or 0.5 Kg
Initial velocity of the block (u) = 0 m/s
Distance travelled by the block (s) = 8 m
Time taken to cover 8 m (t)= 2 seconds
Acceleration of the block (a) = a m/s²
Solving for the acceleration:
From the seconds equation of motion:
s = ut + 1/2* (at²)
replacing the variables
8 = (0)(2) + 1/2(a)(2)²
8 = 2a
a = 4 m/s²
Therefore, the acceleration of the block is 4 m/s²
You stand on a merry-go-round which is spinning at f = 0.25 revolutions per
second. You are R = 200 cm from the center.
(a) Find the angular speed ω at which it is spinning.
[3 marks]
(b) Find the centripetal acceleration, ac with which it is spinning. [3 marks]
(c) What is the minimum coefficient of static friction µs between your shoes and
the floor that will keep you from slipping off?
[4 marks]
Answer:
(a) ω = 1.57 rad/s
(b) ac = 4.92 m/s²
(c) μs = 0.5
Explanation:
(a)
The angular speed of the merry go-round can be found as follows:
ω = 2πf
where,
ω = angular speed = ?
f = frequency = 0.25 rev/s
Therefore,
ω = (2π)(0.25 rev/s)
ω = 1.57 rad/s
(b)
The centripetal acceleration can be found as:
ac = v²/R
but,
v = Rω
Therefore,
ac = (Rω)²/R
ac = Rω²
therefore,
ac = (2 m)(1.57 rad/s)²
ac = 4.92 m/s²
(c)
In order to avoid slipping the centripetal force must not exceed the frictional force between shoes and floor:
Centripetal Force = Frictional Force
m*ac = μs*R = μs*W
m*ac = μs*mg
ac = μs*g
μs = ac/g
μs = (4.92 m/s²)/(9.8 m/s²)
μs = 0.5
To overcome an object's inertia, it must be acted upon by __________. A. gravity B. energy C. force D. acceleration
An 11-kilogram cart is pulled with a horizontal force at a constant velocity of 8.0 meters per second, as shown in the diagram. The force of friction between the cart and the floor is 12 newtons. What is the magnitude of the horizontal force?
The cart is pulled at a constant velocity, so it is in equilibrium. In particular, the net horizontal force is zero, and consists of only the pulling force and friction such that
p - f = 0
where p and f denote the magnitudes of the pulling force and friction.
So we have
p - 12 N = 0
p = 12 N
