Which set of characteristics would you use to classify this planet as an inner or terrestrial planet?

Answer:

A

-1440J

Explanation:

Hello,

This question requires us to calculate the work done on a object to move it from point A to point B

Data

Mass = 60kg

Initial velocity (V1) = 8.0m/s

Final velocity (V2) = 4.0m/s

Workdone on an object is equal to force applied on the object to move it through a particular distance.

Work done = force × distance

Force (F) = mass × acceleration

Distance = s

F = Ma

Work done = M× a × s

But a = velocity (v) / time (t)

Work done = mvs / t

But velocity = distance/ time

Work done = mv × v/

Work done = mv²

Work done = ½mv²

Workdone = ½M(V2² - V1²)

Workdone = ½ × 60 (4² - 8²)

Work done = 30 × (16 - 64)

Workdone = 30 × (-48)

Work done = -1440J

Work done = -1.44kJ

The workdone on the object is equal to -1.44kJ

Answer:

–1,440 J

Explanation:

a on edge 2021

Answer:

2.15 L

Explanation:

M(NaOCl) = 23.0 + 16.0 + 35.5 = 74.5 g/mol

120.3 g *1 mol/74.5 g = 1.615 mol NaOCl

0.750 M = 0.750 mol/L

1.615 mol * 1L/0.750 mol = 2.15 L

Answer:

the valency of oxygen is -2

Answer:

-2

Explanation:

The valency of oxygen is -2. This means oxygen needs to gain or share two electrons for stability.

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Answer:

Heat energy required (Q) = 10.736 KJ

Explanation:

Given:

Specific heat of ethanol (C) = 2.44 J/g °C

Mass of ethanol (M) = 50 gram

Initial temperature (T1) = -20°C

Final temperature (T1) = 68°C

Find:

Heat energy required (Q) = ?

Computation:

Change in temperature (ΔT) = 68°C - (-20°C)

Change in temperature (ΔT) = 88°C

Heat energy required (Q) = mC(ΔT)

Heat energy required (Q) = (50)(2.44)(88)

Heat energy required (Q) = 10,736 J

Heat energy required (Q) = 10.736 KJ

Answer: todos terminan en tu boca

Explanation:

Hahaha

Answer:

B. Solvent

Explanation:

In osmosis, water always moves from low solute concentration to high solute concentration. SOLUTE NEVER MOVES AS IT CANNOT PASS THE SELECTIVELY PERMEABLE MEMBRANE. alot of caps but need to stress this concept cuz otherwise this concept gets very confusing

Answer:

C. 7.4 kJ

Explanation:

Let assume that Mercury is at room temperature (25 °C). The energy required to boil the sample of mercury is the sum of sensible and latent heats. Mercury has a fussion and boiling points of -38.83 °C and 356.7 °C, respectively, and a specific heat of [tex]138\,\frac{J}{kg\cdot ^{\circ}C}[/tex]. Then:

[tex]Q = (25\,g)\cdot \left[\left(0.138\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (356.7^{\circ}C - 25^{\circ}C) + 296\,\frac{J}{g} \right][/tex]

[tex]Q = 8544.365\,J[/tex]

The option that offers the best approximation to the result is C.

Metals are solids, non metals are gasses and metalloids are in between metals and non metals. Also, metals have there atoms all close and packed, non metals have there atoms far apart, and metalloids have there atoms either close or far apart. Metals are separated form the non metals in the periodic table.

Answer:

5.01 g

Explanation:

At STP means at standard temperature and pressure, this is when the pressure is at 1 atm and temperature is at 273 K.  At this point, the volume is 22.4 L for 1 mole of any ideal gas at a temperature equal to 273.15 K and a pressure equal to 1.00 atm

The molar mass of krypton as gotten from the periodic table is 83.8 g/mol. At STP, an ideal gas occupies 22.4 L/mol. Therefore, the grams that 1.3 L of krypton gas would occupy is:

[tex]mass=\frac{1mol}{22.4L} *\frac{83.8g}{1mol} *1.34L=5.01g[/tex]