Which point should Julio use to determine the amount of pizza sauce he needs to bring?
A
B
C
D
On a coordinate plane, a graph titled Pizza Recipe has Pizzas on the x-axis and Cups of Pizza Sauce on the y-axis. Point A is (3, 2), point B is (4, 2.6), point C is (4.5, 3), point D is (6, 4).

Answer:

Step-by-step explanation:

Area of circle equation:

Let the radius of bigger circle is x.

We have:

Solve for x:

19.8cm

Step-by-step explanation:

First find area of small circle:

A = πr2

A = 22/7 x 14 x 14

A = 22 x 2 x 14

A = 616cm2

Area of bigger circle is double that of the small circle:

= 616 x 2

= 1,232 cm2

πR2 = A

22/7 x r2 = 1,232

r2 = (1,232 x 7) ÷ 22

r2 = 8624 ÷ 22

[tex] \sqrt{r ^{2} } = \sqrt{392} [/tex]

radius of bigger circle = 19.8cm

the number in which 8 is in tenth place is

6875.1234

plese mark me as braniliest

Step-by-step explanation:

It Jun glt tm my tb my tu meri of ft me rh my

Answer:

(-1/3)x

Step-by-step explanation:

You can either solve this algebraically or solve it by testing one possible answer at a time.

First example:  To (5/6)x - 4, add (-1/3)x.  Result:  (3/6)x - 4.  This is correct.

The correct answer is the first one:  (-1/3)x.

Answer: B

No, because y does not change by 5 every time x changes by 1

Step-by-step explanation:

rate of change is basically slope

if the rate of change of the function of 5, then the slope will be 5/1

The x changes by 1 every time y changes by 4

so the slope of the function is 4

In matrix form, the given system is written as

[tex]\begin{bmatrix}1&1&0\\6&2&-3\\k&0&-1\end{bmatrix}\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}3-k\\1\\-3\end{bmatrix}[/tex]

and the system has no solution is the coefficient matrix is singular. The determinant is

[tex]\begin{vmatrix}1&1&0\\6&2&-3\\k&0&-1\end{vmatrix} = -3k+4[/tex]

and this is zero when k = 4/3.

On the other hand, in case you are missing a factor of z in the first equation, so that the system should read

x + y + (k - 1) z = 2

6x + 2y - 3z = 1

kx - z = -3

reframing it as a matrix equation gives

[tex]\begin{bmatrix}1&1&k-1\\6&2&-3\\k&0&-1\end{bmatrix}\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}2\\1\\-3\end{bmatrix}[/tex]

Then the determinant of the coefficient matrix is

[tex]\begin{vmatrix}1&1&k-1\\6&2&-3\\k&0&-1\end{vmatrix} = -2k^2-k+4[/tex]

and the determinant is zero at two values, k = (-1 ± √33)/4.

Answer:

m<PQR = 18.7°

Step-by-step explanation:

Apply the Law of Sines,

[tex] \frac{Sin A}{a} = \frac{Sin B}{b} [/tex]

Where,

Sin A = Sin 140

a = 100 m

Sin B = Sin R (<PRQ)

b = 50 m

Substitute

[tex] \frac{Sin 140}{100} = \frac{Sin R}{50} [/tex]

Cross multiply

[tex] 100*Sin(R) = 50*Sin(140) [/tex]

Divide both sides by 100

[tex] Sin(R) = \frac{50*Sin(140)}{100} [/tex]

[tex] Sin(R) = 0.32139 [/tex]

[tex] R = Sin^{-1}(0.32139) [/tex]

R ≈ 18.7° (nearest tenth)

m<PQR = 18.7°

The angle PRO is 1.7 degrees.

Given that,

The diagram shows three points P, Q, and R on horizontal ground.

PQ = 50 m, PR = 100 m and angle PQR = 140°.

We have to determine,

The angle PRO.

According to the question,

The value of angle PRO is determined by using the sin rule-following all the steps given below.

[tex]\rm \dfrac{sina}{a} = \dfrac{sinb}{b}[/tex]

Where,  Sin A = Sin 140 , a = 100 m , Sin B = Sin R (<PRQ) , b = 50 m

Substitute all the values in the formula,

[tex]\rm \dfrac{sin140}{100} = \dfrac{sinR}{50}\\\\ \dfrac{0.64}{100} = \dfrac{sinR}{50}\\\\0.0064 = \dfrac{sinR}{50}\\\\0.0064 \times 50 = sinR\\\\0.321 = sinR\\\\R = sin{-1}(0.321)\\\\R = 18.7 \ degree[/tex]

Hence, The angle PRO is 1.7 degrees.

For more details refer to the link given below.

https://brainly.com/question/12895249

Step-by-step explanation:

here's the answer to your question

Answer:

y = 30.555 and x = 19.444

Step-by-step explanation:

We are given:

x + y = 50 and

x / y = 7/11

use substitution taking

x + y = 50

x = 50 - y

then

x / y = 7/11 and from above substitute for x

(50 - y)/ y = 7/11

(50 - y) = 7y/11

11(50 - y) = 7y

550 - 11y = 7y

550 = 18y

y = 550/18 = 30.555 so

x + y = 50

x = 50 - y

x = 50 - 30.555 = 19.444

Answer:

20 students are absent

Step-by-step explanation:

75/100 × 80 = 60

If 60 were present out of the 80

80 - 60 = 20

Have a great day :)

Answer:

The answer is a translation

Step-by-step explanation:

In Math, translation is the displacement of a shape or object from one place to another.

Since the picture shows that the shape moved from one place to the next while remaining the same size, it is translation.

Answer:

Fraction form: x = -21/4

Decimal Form: x = -5.25

Step-by-step explanation:

See the picture for steps :)

Answer:

a^2+2ab = 21

(a+b)^2= 25

Step-by-step explanation:

(a+b)^2 = a^+2ab+b^2

sub a=3 and b=2 and simplify  

Answer:

If you multiply the numbers you will get

0.030634

Answer:

C.

Step-by-step explanation:

Dis means apart and junc means join so disjunction means the "state of being disconnected".

Answer:

12 minutes

Step-by-step explanation:

We can use the formula

1/a+ 1/b = 1/c  where a and b are the times alone and c is the time together

1/20 + 1/30 = 1/c

Multiply by the common denominator to clear the fractions

60c(1/20 + 1/30 = 1/c)

3c +2c = 60)

5c = 60

Divide by 5

5c/5 = 60/5

c = 12

12 minutes

Answer: 12 minutes

Step-by-step explanation: To solve this kind of a problem, which is called a work problem, it's important to understand the following idea:

Since Barry can eat a bag of popcorn in 30 minutes, we know that in 1 minute, Barry can eat 1/30 of the bag of popcorn and in 2 minutes, Barry can eat 2/30 of the bag of popcorn. Therefore, in t minutes, Barry can eat t/30 of the bag of popcorn. The same thing applies for Andrea. In t minutes, Andrea can eat t/20 of the bag of popcorn.

Now to solve the problem, we use the following formula:

Part of Job done by Barry + Part of Job done by Andrea = 1 job done

The part of job done by Barry is t/30 and the part

of the job done by Andrea is t/20.

So we have t/30 + t/20 = 1.

To solve for t, multiply both sides by the common denominator of 60.

So we get 2t + 3t = 60 or 5t = 60 so t = 12.

So Barry and Andrea can eat 1 bag together in 12 minutes.

Answer:

b

Step-by-step explanation:

area of triangle = 1/2 x c x d =cd/2

area of semicircle = 1/2 x π x r^2 = 1/2 x π x (a/2)^2 = 1/2 x π x a^2/4 =πa^2/8

area of shape = area of triangle + area of semicircle

Answer:

True

Step-by-step explanation:

Office resources can be defined as all those means, facilities or equipments, including manpower that are utilized in the operation of various office procedures on a daily basis. Thus, office resources comprises means of communication, means of transportation, manpower (workers or employees), furniture, computer, etc.

Basically, the proper and efficient utilization of office resources determine the level of success that would be achieved in any office.

In Business management, office resources are generally grouped into five (5) main categories and these include;

I. Communication.

II. Transportation.

III. Material and office supplies.

IV. Sources of income (finance).

V. Manpower (human resources).

Manpower is also referred to as human resources or office personnels and it can be defined as the total number of people working from the lower hierarchy to top hierarchy of an organization, engaged in various jobs or tasks at different levels.

Basically, manpower is considered to be the most important type of office resources because it is vital for achieving the organizational goal.

This ultimately implies that, the most valuable assets of an organization is its qualitative manpower because it comprises human competence, skills and knowledge.

Answer:

See explanation.

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Functions

Calculus

Differentiation

Derivative Property [Multiplied Constant]:                                                           [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]

Derivative Property [Addition/Subtraction]:                                                         [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]

Basic Power Rule:

Derivative Rule [Chain Rule]:                                                                                 [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]

Step-by-step explanation:

We are given the following and are trying to find the second derivative at x = 2:

[tex]\displaystyle f(2) = 2[/tex]

[tex]\displaystyle \frac{dy}{dx} = 6\sqrt{x^2 + 3y^2}[/tex]

We can differentiate the 1st derivative to obtain the 2nd derivative. Let's start by rewriting the 1st derivative:

[tex]\displaystyle \frac{dy}{dx} = 6(x^2 + 3y^2)^\big{\frac{1}{2}}[/tex]

When we differentiate this, we must follow the Chain Rule:                             [tex]\displaystyle \frac{d^2y}{dx^2} = \frac{d}{dx} \Big[ 6(x^2 + 3y^2)^\big{\frac{1}{2}} \Big] \cdot \frac{d}{dx} \Big[ (x^2 + 3y^2) \Big][/tex]

Use the Basic Power Rule:

[tex]\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} (2x + 6yy')[/tex]

We know that y' is the notation for the 1st derivative. Substitute in the 1st derivative equation:

[tex]\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} \big[ 2x + 6y(6\sqrt{x^2 + 3y^2}) \big][/tex]

Simplifying it, we have:

[tex]\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} \big[ 2x + 36y\sqrt{x^2 + 3y^2} \big][/tex]

We can rewrite the 2nd derivative using exponential rules:

[tex]\displaystyle \frac{d^2y}{dx^2} = \frac{3\big[ 2x + 36y\sqrt{x^2 + 3y^2} \big]}{\sqrt{x^2 + 3y^2}}[/tex]

To evaluate the 2nd derivative at x = 2, simply substitute in x = 2 and the value f(2) = 2 into it:

[tex]\displaystyle \frac{d^2y}{dx^2} \bigg| \limits_{x = 2} = \frac{3\big[ 2(2) + 36(2)\sqrt{2^2 + 3(2)^2} \big]}{\sqrt{2^2 + 3(2)^2}}[/tex]

When we evaluate this using order of operations, we should obtain our answer:

[tex]\displaystyle \frac{d^2y}{dx^2} \bigg| \limits_{x = 2} = 219[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

Answer:

Part A:

c = .86*p

c =1.72 for 2 lbs

Part B:

c =.81p

Step-by-step explanation:

Part A:

Total cost = cost per pound * number of pounds

c = .86*p

Let p = 2

c = .86*2

c =1.72

Part B:

Total cost = cost per pound * number of pounds

c = .(.86-.05)*p

c =.81p

Answer:

below

Step-by-step explanation:

that's is the solution above

Answer:

y = a^x is an exponential function with an x intercept.

Step-by-step explanation:

y = a^x is the standard form of an exponential function.

Answer:

x is 3.[tex]\overline{72}[/tex]

Step-by-step explanation:

The given points on the line are;

R(-5, -6), S(1, 5) and T(x, 10)

The number of points required to find the equation of the line = 2 points

The slope, m, of the line using points R(-5, -6) and S(1, 5) is given as follows;

m = (5 - (-6))/(1 - (-5)) = 11/6

The equation of the line in slope and point form, using point S(1, 5) is therefore;

y - 5 = (11/6)·(x - 1) = 11·x/6 - 11/6

y - 5 = 11·x/6 - 11/6, given that the x-value is required, we have;

x = (y - 5 + 11/6) × 6/11 = 6·y/11 - 19/11

x = 6·y/11 - 19/11

At point T(x, 10), y = 10, therefore, we have;

x = 6×10/11 - 19/11 = 41/11 = 3.[tex]\overline{72}[/tex]

x = 3.[tex]\overline{72}[/tex].

9514 1404 393

Answer:

  17.078 square units

Step-by-step explanation:

The area of a segment is given by the formula ...

  A = 1/2r²(θ -sin(θ)) . . . . where θ is in radians

The angle θ is 48°, or π(48°/180°) radians = 4π/15 radians.

Then the segment area is ...

  A = (1/2)(19²)(4π/15 -sin(48°)) = 17.078 . . . square units

Answer:

[tex]3^{\frac{7}{10} }[/tex]

Step-by-step explanation:

[tex]\sqrt{3} *\sqrt[5]{3}[/tex] = 3^1/2 x 3^1/5 = 3^(1/2 +1/5) = 3^7/10

Answer:

Step-by-step explanation:

Exponent law: [tex]a^{m}*a^{n}=a^{m+n}[/tex]

[tex](\sqrt{3} ) )*(\sqrt[5]{3})= 3^{\frac{1}{2}}*(3^{\frac{1}{5}})\\\\=3^{\frac{1}{2}+\frac{1}{5}}\\\\=3^{\frac{1*5}{2*5}+\frac{1*2}{5*2}}\\\\= 3^{\frac{5}{10}+\frac{2}{10}}\\\\=3^{\frac{5+2}{10}}\\\\=3^{\frac{7}{10}}[/tex]

Answer:

70

Step-by-step explanation:

we have the angle of vertex in the isosceles triangle = 180-2*bottom coner= 180-65/2=50

3 angles in the equilateral triangle are equal to 60

we have 50 + 60 +h =the angle of PQR =180

h=70

Answer: h = 70°

In the triangle with Angle R = 65

It is a isoceles triangle as two sides are equal

So base angles will be equall too

Then the third angle will which is the q one will be

65+65+q = 180

q = 180 - 130

q = 50

In the other triangle with all sides equal will be equilateral triangle which means all angles equal = 60

So

Now ATQ

60 + 50 + h = 180

h = 180 - 110 (Angles on a straight line adds upto 180)

h = 70

Must click thanks and mark brainliest

Answer:

30-60-90

Step-by-step explanation:

A 30-60-90 triangle is a right angled triangle

Please mark it as brainliest if it helped

Answered by Gauthmath

Answer:

A (30 - 60 - 90) right triangle has the side ratios: [tex]x, x\sqrt{3}, 2x[/tex].

Step-by-step explanation:

A right triangle with the angle measures (30 - 60 - 90) is often referred to as a special right triangle becaase its sides follow the following ratio,

The side;                                                          Angle it's opposite to;

[tex]x[/tex]                                                                        30

[tex]x\sqrt{3}[/tex]                                                                   60

[tex]2x[/tex]                                                                      90

[tex] \large \tt{{❃ \: S \: O \: L \: U \: T \: I \: O \: N : }}[/tex]

[tex] \large{ \tt{❁ \:x + x + 98 = 180 \degree \: [ Sum\: of \: angle \: of \: a \: triangle ]}}[/tex]

[tex] \large{ \tt{⟶2x + 98 \degree= 180 \degree}}[/tex]

[tex] \large{ \tt{⟶ \: 2x = 180 \degree - 98 \degree}}[/tex]

[tex] \large{ \tt{⟶ \: 2x = 82 \degree}}[/tex]

[tex] \large{ \tt{ ⟶x = \frac{82 \degree}{2} }}[/tex]

[tex] \large{ \tt{⟶ \: x = 41 \degree}}[/tex]

[tex] \large{ \tt{ ↔\angle \: 1 = x \degree = \boxed{41 \degree}}}[/tex] [ Being alternate angles ]

- Alternate angles are the non-adjacent interiors pair of angles lying to the opposite side of a transversal when it intersects two straight line segments. Alternate angles form ' Z ' shape.