Which of the following statement regarding electromagnetic waves is FALSE?

a) In vacuum, the wave travels in a straight line.

b) The energy in the wave is proportional to the product of the electric and magnetic fields.

c) The speed of the wave in vacuum is given by c = 1/sqrt ε0μ0

d) The magnetic field is much greater in magnitude than the electric field

Answers

Answer 1

Answer:

hi

Explanation:

your answer is

The energy in the wave is proportional to the product of the electric and magnetic fields.


Related Questions

calculate the opportunity acost of the production of good x at each point .what law dose the ternd in those value exhibit ?​

Answers

Answer:

a

Explanation:

What is the final velocity if you have an initial velocity of 5 m/s with an acceleration of 3 m/s2 over a 4 second interval?

Answers

Answer: 17 m/s

Explanation:

Using the formula Vf=Vi+at

Vf=5m/s+3m/s^2(4s)

Vf= 17m/s

A magnifying glass produces a maximum angular magnification of 5.4 when used by a young person with a near point of 20 cm. What is the maximum angular magnification obtained by an older person with a near point of 65 cm

Answers

67 points to the 55th power add it then you get exactly 1500

Two forces are acting on a body. One acts east, the other at 35° north of east. If the
two forces are equal in magnitude of 50 N, find the resultant using the Law of Sines
and the Law of Cosines. Please answer with full solution. Thanks

Answers

A=B=50NAngle=theta=35°

We know

[tex]\boxed{\sf R=\sqrt{A^2+B^2+2ABcos\Theta}}[/tex]

[tex]\\ \sf\longmapsto R=\sqrt{50^2+50^2+2(50)(50)cos35}[/tex]

[tex]\\ \sf\longmapsto R=\sqrt{2500+2500+2(2500)\times (-0.9)}[/tex]

[tex]\\ \sf\longmapsto R=\sqrt{5000+5000(-0.9)}[/tex]

[tex]\\ \sf\longmapsto R=\sqrt{5000+(-4500)}[/tex]

[tex]\\ \sf\longmapsto R=\sqrt{5000-4500}[/tex]

[tex]\\ \sf\longmapsto R=\sqrt{-500}[/tex]

[tex]\\ \sf\longmapsto R=22.4i[/tex]

Resultant using the Law of Sines and the Law of Cosines will be R=95 N

What is force?

Force is an external agent applied on any object to displace it from its position. Force is a vector quantity, so with magnitude it also requires direction. Direction is necessary to examine the effect of the force and to find the equilibrium of the force.

The Magnitude of two forces =50 N

Angle between the forces = 35

By using the resultant formula

[tex]\rm R=\sqrt{A^2+B^2+2ABCos\theta}[/tex]

[tex]\rm R=\sqrt{50^2+50^2+2(50)(50)Cos35}[/tex]

[tex]\rm R=\sqrt{5000+5000(0.81)}[/tex]

[tex]\rm R=\sqrt{5000+4500}[/tex]

[tex]\rm R=95\ N[/tex]

Hence the Resultant using the Law of Sines and the Law of Cosines will be R=95 N

To know more about force follow

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a model car moves round a circular path of radius 0.3m at 2 revolutions per secs what is its angular speed, the period of the car and the speed of the car

Answers

Answer:

a) T = 0.5 s

b) v = 1.2π m/s ≈ 3.77 m/s

Explanation:

It makes two revolutions in one second so makes one revolution in ½ second

circumference of the circle is

C = 2πr = 0.6π m

which it traverses in one time period

0.6π m / 0.5 s = 1.2π m/s

To solve this, we must be knowing each and every concept related to speed and its calculations. Therefore, the angular speed of a model car moves round a circular path of radius 0.3m at 2 revolutions per secs is 3.77 m/.

What is speed?

Speed may be defined as the distance traveled by an item in the amount of time it requires to travel that distance. In other words, it measures how rapidly an item travels but does not provide direction.

Speed may be calculated in Science. The speed equation is a scientific formula that is used to calculate various types of speed.

Mathematically, the formula for speed can be given as

speed= distance/time

Values that are given

Time period= 0.5 s

Circumference = 2πr = 0.6π m

substituting all the given values in the above equation, we get

speed     =0.6π m / 0.5 s

On calculations, we get

              = 1.2π m/s

              =3.77 m/s

Therefore, the angular speed of a model car moves round a circular path of radius 0.3m at 2 revolutions per secs is 3.77 m/.

To learn more about speed, here:

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The image shows a facility that converts the energy of moving water into
electrical energy. What is one advantage of using this technology in place of a
coal-burning power plant?
A. It is fueled by a nonrenewable resource.
B. It causes no harm to ecosystems.
оооо
C. It produces more water pollution.
D. It does not emit greenhouse gases.

Answers

Answer:

D. It does not emit greenhouse gases.

Explanation:

D. It does not emit greenhouse gases.

What is a downside of nonprofit fitness centers?


They offer fewer luxury services than for-profit health centersThey offer fewer luxury services than for-profit health centers , ,

Very few people live near a nonprofit fitness center.Very few people live near a nonprofit fitness center. , ,

Members tend to be wealthy and lack diversity. Members tend to be wealthy and lack diversity. , ,

Membership costs more than it does in for-profit centers.Membership costs more than it does in for-profit centers. , ,

Answers

they offer fewer luxury services because they lack the money to provide them.

If you jump off a 5 m diving platform how long will take you hit the water

Answers

Answer:

t = 1.0s

Explanation:

^d = v_0*t + (1/2)*a*t²

(5m-0m) = 0m/s*t + (.5)(9.81m/s²)*(t)²

5m = (4.905m/s²)*t²

t² = 1.01937s²

t = √1.01937s²

t = 1.0s

Someone help me with these questions please!

Answers

Answer:

a 25 and b 25

2. 26

60n

A rubber ball and a steel ball are dropped from the same height onto a concrete floor. They have the same mass, and lets assume that they both rebound to the same height after hitting the ground. How would the average forces experienced by the balls compare. Group of answer choices The steel ball would experience the greater average force The average forces would be the same The rubber ball would experience the greater average force

Answers

Answer:

The average forces would be the same

Explanation:

Both have the same velocity on impact as they fell from the same height.

Both have the same velocity after the bounce because they reach the same height.

Both have the same mass

Both will thus experience the same impulse because both have the same change in momentum.

Therefore both experience the same average force.

which sources of associated with the line emission spectrum?
1) electric fire
2) neon street sign
3) red traffic light
4) sun​

Answers

Answer:

Answer if this question neon street sign

Explanation:

may this answer is helpful for you

how is the area of a circle measured​

Answers

Answer:

Area of circle is measured using formula πr² which means π×radius×radius and π could be 22/7 or 3.14

Explanation:

If you like my answer than please mark me brainliest

A boat is able to move at 7.6 m/s in still water. If the boat is placed on the south shore of a river (water current of 3.4 m/s [SE]), and the captain wants to head straight across to the north shore:

a) In what direction should the captain point the boat?
b) Calculate the time it will take to cross (the river is 212.0 m from the south to the north shore).

Answers

Answer:

I don't get it rewrite please

As a skydiver accelerates downward, what force increases? A. Gravity B. Thrust C. Air resistance D. Centripetal

Answers

Answer:

(A) Gravity is you're answer.

Explanation:

When an object or human is falling at an increased rate, The force of gravity is taking place.

a bullet is dropped from the same height when another bullet is fired horizontally. they will hit the ground

Answers

Answer:

it will drop simultaneously

Two long straight wires are suspended vertically. The wires are connected in series, and a current from a battery is maintained in them. What happens to the wires? What happens if the battery is replaced by an a-c source?

Answers

Answer:

(i) When a battery is connected inseries to two long parallel wires, the currents in the two wires will be in opposite directions. Due to which a force of repulsion will be acting between them and they are moving further apart.

(ii) When a battery is connected in parallel to two long parallel wires, the currents in the two wires will be in same direction. Due to it, a force of attraction will be acting between them and they are coming closer to each other.

hope it's help you ....!!!!!

plz mark as brain list and follow me #rishu...!!!!

Explanation:

Hope it will helps you lot!

find the velocity of the object for all relevent times find the position of the object for all relevent times a softball is popped up vertically velocity of 32 m/s

Answers

Answer:

whats the formula

Explanation:

Help again! Thank you all xoxo

Answers

Answer:

Amount of charge

Explanation:

Mark me brainliest

Select the correct answer. Which of Newton's laws explains why your hands get red when you press them hard against a wall? A. Newton's law of gravity B. Newton's first law of motion C. Newton's second law of motion D. Newton's third law of motion

Answers

Answer:

D newton third law

Explanation:

good luck

A train moving west with an initial velocity of 20 m/s accelerates at 4 m/s2 for 10 seconds. During this tim
moves a distance of
meters.

Answers

Answer:

400m

Explanation:

[tex]x = v_{0}t + \frac{at^{2} }{2} \\x = 20*10+\frac{4*10x^{2} }{2} = 400m[/tex]

A very long straight wire carries a 12 A current eastward and a second very long straight wire carries a 14 A current westward. The wires are parallel to each other and are 42 cm apart. Calculate the force on a 6.4 m length of one of the wires.

Answers

Answer: 5.12x10∧-4N

Explanation:

Force = I B L

L = 6.4m

Let Current (I) I₁ = I₂= 14A

Distance of the wire = 42cm = 0.42m

BUT

B = μ₀I / 2πr

=(2X10∧-7 X 12) / 0.42

       B =5.714×10∧-6T

Force = I B L

Force = 14x [5.714×10-6]×6.4

Force = 5.12x10∧-4N

Light of wavelength 600 nm illuminates a diffraction grating. The second-order maximum is at angle 39.2. How many lines per millimeter does this grating have?

Answers

Answer:

Diffraction equation applies in this case:

d*Sin x = m*wavelength, where d = spacing of lines, x = angle = 39.5°, m = order of maximum = 2

Substituting;

d* Sin 39.5 = 2*600*10^-9

d = (2*600*10^-9)/Sin 39.5 = 1.88656*10^-6 m

In 1 mm (or 0.001 m), the number of lines is given as;

Number of lines = 0.001/d = 0.001/(1.88656*10^-6) = 530.065 ≈ 530 lines

For example, we can take Water
In (A) Water has same mass and great volume
In (B) Water has same mass and lower volume
Will there be any change in its density then?

Answers

Answer:

yes there will be change in its density

An electron is moving at speed of 6.3 x 10^4 m/s in a circular path of radius of 1.7 cm inside a solenoid the magnetic field of the solenoid is perpendicular to the plane of the electron's path. Find its relevatn motion.

Answers

Answer:

Here, m=9×10

−31

kg,

q=1.6×10

−19

C,v=3×10

7

ms

−1

,

b=6×10

−4

T

r=

qB

mv

=

(1.6×10

−19

)(6×10

−4

)

(9×10

−31

)×(3×10

7

)

=0.28m

v=

2πr

v

=

2πm

Bq

=

2×(22/7)×9×10

−31

(6×10

−4

)×(1.6×10

−19

)

=1.7×10

7

Hz

Ek=

2

1

mv

2

=

2

1

×(9×10

−31

)×(3×10

7

)

2

J

=40.5×10

−17

J=

1.6×10

−16

40.5×10

−17

keV

=2.53keV

What is not one of the main uses of springs?
A. Car suspension
B. Bike suspension
C. The seasons
D. Clock making

Answers

Hi! I believe the answer is C. or The seasons because all the other options use springs when making cars, bikes, and clocks. I hope this helped. Goodluck :)

Which of the following exhibit the Tyndall Effect?


A flashlight beam through air in a room.

A laser beam through salt water.

Car headlights on a foggy night.

A laser beam through a soda drink.

Answers

Answer:

Probably all but (a)

The Tyndall Effect is caused by dispersion of the incident light by the individual molecules in the liquid.

Salt water and a foggy night will cause dispersion of the incident light.

A soda drink may also cause this dispersion, but and not sure.

If the horizontal range and the max height of a body projected at an angle titre to the horizontal is K and Q respectively. Show that the muzzle velocity Vo is given by: Vo=√[2gQ + K²/8Q]​

Answers

Explanation:

Recall that

[tex]K = \dfrac{v_0^2\sin2\theta}{g}\:\:\:\:\:\:\:\:\:(1)[/tex]

and

[tex]Q = \dfrac{v_0^2\sin^2\theta}{2g}\:\:\:\:\:\:\:\:\:(2)[/tex]

From Eqn(2), we can write

[tex]\sin\theta = \sqrt{\dfrac{2gQ}{v_0^2}}\:\:\:\:\:\:\:\:\:(3)[/tex]

Using the identity [tex]\sin\theta = 2\sin\theta \cos\theta[/tex], we can rewrite Eqn(1) as

[tex]\dfrac{gK}{2v_0^2} = \sin\theta \cos\theta[/tex]

Squaring the above equation, we get

[tex]\dfrac{g^2K^2}{4v_0^4} = \sin^2\theta \cos^2\theta[/tex]

[tex]\:\:\:\:\:\:\:\:\:=\sin^2\theta(1 - \sin^2\theta)\:\:\:\:\:\:\:(4)[/tex]

Use Eqn(3) on Eqn(4) and we will get the following:

[tex]\dfrac{g^2K^2}{4v_0^4} = \dfrac{2gQ}{v_0^2}(1 - \dfrac{2gQ}{v_0^2})[/tex]

This simplifies to

[tex]\dfrac{gK^2}{8v_0^2Q} = 1 - \dfrac{2gQ}{v_0^2}[/tex]

Rearranging this further, we get

[tex]1 = \dfrac{2gQ}{v_0^2} + \dfrac{gK^2}{8v_0^2Q}[/tex]

Putting [tex]v_0^2[/tex] to the left side, we get

[tex]v_0^2 = 2qQ + \dfrac{gK^2}{8Q}[/tex]

Finally, taking the square root of the equation above, we get the expression for the muzzle velocity [tex]v_0[/tex] as

[tex]v_0 = \sqrt{2gQ + \dfrac{gK^2}{8Q}}[/tex]

when 999mm is added to 100m ______ is the result​

Answers

Answer:

what,     100.999m

Explanation:

convert 999 mm into meters, which is 0.999m and add that to a 100 m and that will make the total 100.999 m

The result of the addition of the two values is equal to 100.999 meters.

Given the following data:

Value 1 = 999 millimetersValue 2 = 100 meters

To determine the result of the addition of the two values:

First of all, we would convert the value in millimeter (mm) to meter (m) as follows:

Conversion:

1 millimeter = 0.001 meter

999 millimeter = X meter

Cross-multiplying, we have:

[tex]X = 0.001 \times 999[/tex]

X = 0.999 meter.

For the result:

[tex]Result = 0.999 +100[/tex]

Result = 100.999 meters.

Read more on measurements here: https://brainly.com/question/24842282



5. An electron is moving north in a region where

the magnetic field is south. The magnetic force

exerted on the electron is:

A.Zero

B. up

C. down

D. east

E. west

Answers

Answer:

eastlove india

Two resistors connected in series have an equivalent resistance of 690 Ohms. When they are connected in parallel, their equivalent resistance is 118 Ohms. Find the resistance of each resistor.

Answers

Explanation:

Let [tex]R_1[/tex] and [tex]R_2[/tex] be the the resistances of the resistors. We are given that

[tex]R_1 + R_2 = 690\:Ω\:\:\:\:\:\:\:(1)[/tex]

and

[tex]\dfrac{1}{R_1} + \dfrac{1}{R_2} = \dfrac{1}{118\:Ω}\:\:\:\:\:(2)[/tex]

From Eqn(1), we can write

[tex]R_2 = 690\:Ω - R_1[/tex]

and then plug this into Eqn(2):

[tex]\dfrac{1}{R_1} + \dfrac{1}{690\:Ω - R_1} = \dfrac{1}{118\:Ω}[/tex]

or

[tex]\dfrac{690\:Ω}{(690\:Ω)R_1 - R_1^2}= \dfrac{1}{118\:Ω}[/tex]

[tex]\Rightarrow R_1^2 - (690\:Ω)R_1 + (690\:Ω)(118\:Ω)= 0[/tex]

or

[tex]R_1^2 - 690R_1 + 81420 = 0[/tex]

Using the quadratic formula, we find that the above equation has two roots:

[tex]R_1 = 151.1\:Ω,\:\:538.9\:Ω[/tex]

This means that if you choose one root value for [tex]R_1[/tex], the other root will be the value for [tex]R_2[/tex].

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