which of the following represents the number of units between -5 and -2 on the number line?

Answer:

Step-by-step explanation:

Taxable income = $ 91,307

Tax for $ 17,850 = 10% of 17850 = 0.1*17850 = $ 1785

Tax for $17,850 to $72,500 = 15% of (72,500-17850) = 0.15* 54650 = $ 8197.5

Tax  $72,500 to $91,307 = 25% of (91307-72500)=0.25*18807= $ 4701.75

Total tax = 1785 + 8197.5 + 4701.75 = 14684.25

Total tax = $14684

Answer:

13 and 17 units

Step-by-step explanation:

explaination is in pic.

The length of the diagonals of the quadrilateral AC and BD are 13 units and 17 units respectively, as per length between two points.

The length between two given points (x₁, y₁) and (x₂, y₂) will be:

√[(x₂ - x₁)² + (y₂ - y₁)²] units

Given, the vertices of a quadrilateral are A(4,-3),B(7,10),C(-8,2)and D(-1,-5).

Therefore, the diagonals of the quadrilateral will be AC and BD.

The coordinates of the diagonal AC are (4, - 3) and (- 8, 2).

Now, the length of the diagonal AC will be:

= √[(-8 - 4)² + (2 - (- 3))²] units

= √[(- 12)² + (5)²] units

= √[144 + 25] units

= √(169) units

= 13 units                                  (length can't be negative)

Similarly, the coordinates of the diagonal BD are (7, 10) and (- 1, - 5).

Now, the length of the diagonal BD will be:

= √[(-1 - 7)² + (- 5 - 10)²] units

= √[(- 8)² + (- 15)²] units

= √[64 + 225] units

= √(289) units

= 17 units                                  (length can't be negative)

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Answer:

TRUE

Step-by-step explanation:

The answer is TRUE.

========================================================

Work Shown:

(6 servings)/(4 oz of sauce) = (8 servings)/(x oz of sauce)

6/4 = 8/x

6*x = 4*8

6x = 32

x = 32/6

x = 5.333 approximately

x = 6 we round up despite 5.333 being closer to 5, than it is to 6.

If we went with 5 ounces, then we wouldn't clear the hurdle needed to serve 8 people.

The section below goes over why this is the case in more detail.

---------

6 servings : 4 ounces

6/4 servings : 4/4 ounces

1.5 servings : 1 ounce

So one ounce of sauce gets us 1.5 servings.

If we multiply both sides by 5, then,

1.5 servings : 1 ounce

5*1.5 servings : 5*1 ounce

7.5 servings : 5 ounces

This shows that 5 ounces of sauce will only produce 7.5 servings, which comes up short compared to 8 servings.

If we multiplied both sides by 6, then

1.5 servings : 1 ounce

6*1.5 servings : 6*1 ounce

9 servings : 6 ounces

This shows that 6 ounces of sauce yields 9 servings. We've gone overboard, but it's better to do that than come up short.

Answer:

C

Step-by-step explanation:

Because in graph there are boxes

And boxez are squre

And C is the answer

You Fool

Yoo Fool

The transformation of a function may involve any change. The function, g(x) that represents function f(x) moved 4 units downwards is g(x)=7x-1.

The transformation of a function may involve any change.

Usually, these can be shifted horizontally (by transforming inputs) or vertically (by transforming output), stretched (multiplying outputs or inputs) etc.

If the original function is y = f(x), assuming horizontal axis is input axis and vertical is for outputs, then:

Horizontal shift (also called phase shift):

Vertical shift:

Stretching:

Given the function f(x)=7x+3, now, if the function is moved down by d units, then the function can be transformed down wards by 4 units as shown below.

g(x) = f(x) moved down by 4 units

g(x) = f(x) - 4

g(x) = 7x + 3 - 4

g(x) = 7x - 1

Hence, the function, g(x) that represents function f(x) moved 4 units downwards is g(x)=7x-1.

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points are

[tex]\boxed{\sf Slope(m)=\dfrac{y_2-y_1}{x_2-x_1}}[/tex]

[tex]\\ \sf\longmapsto m=\dfrac{0-3}{1-0}[/tex]

[tex]\\ \sf\longmapsto m=\dfrac{-3}{1}[/tex]

[tex]\\ \sf\longmapsto m=-3[/tex]

Answer:

[tex]A=2044[/tex]

Step-by-step explanation:

Note that [tex]x\in\mathbb{W}[/tex] denotes that [tex]x[/tex] is a whole number.

By definition, consecutive numbers follow each other when we count up (e.g. 1, 2, 3).

Let's consider our conditions:

Since B is a multiple of 5, the ones digit of B must be either 0 or 5. However, notice that the number before it, A, needs to be a multiple of 4. The ones digit of a number preceding a ones digit of 0 is 9. There are no multiples of 4 that have a ones digit of 9 and therefore the ones digit of B must be 5.

Because of this, we've identified that the ones digit of A, B, and C must be 4, 5, and 6 respectively.

We can continue making progress by trying to identify the smallest possible whole number greater than 2,000 with a units digit of 6 that is divisible by 6. Notice that:

[tex]2000=2\mod6[/tex]

Therefore, [tex]2000-2=1998[/tex] must be divisible by 6. To achieve a units digit of 6, we need to add a number with a units digit of 8 to 1,998 (since 8+8 has a units digit of 6).

The smallest multiple of 6 that has a units digit of 8 is 18. Check to see if this works:

[tex]C=1998+18=2016[/tex]

Following the conditions given in the problem, the following must be true:

[tex]A\in \mathbb{W},\\B\in \mathbb{W},\\C\in \mathbb{W},\\A+1=B=C-1,\\A=0\mod 4,\\B=0\mod 5,\\C=0\mod 6,[/tex]

For [tex]C=2016[/tex], we have [tex]B=2015[/tex] and [tex]A=2014[/tex]:

[tex]A\in \mathbb{W},\checkmark\\B\in \mathbb{W},\checkmark\\C\in \mathbb{W},\checkmark\\A+1=B=C-1,\checkmark\\A=2014\neq 0\mod 6, \times\\B=2015=0\mod 5,\checkmark\\C=2016=0\mod 6\checkmark\\[/tex]

Not all conditions are met, hence this does not work. The next multiple of 6 that has a units digit of 8 is 48. Adding 48 to 1,998, we get [tex]C=1998+48=2046[/tex].

For [tex]C=2046[/tex], we have [tex]B=2045[/tex] and [tex]A=2044[/tex]. Checking to see if this works:

[tex]A\in \mathbb{W},\checkmark\\B\in \mathbb{W},\checkmark\\C\in \mathbb{W},\checkmark\\A+1=B=C-1,\checkmark\\A=2044=0\mod 4,\checkmark\\B=2045=0\mod 5,\checkmark\\C=2046=0\mod 6\checkmark[/tex]

All conditions are met and therefore our answer is [tex]\boxed{2,044}[/tex]

Answer:

3√13

Step-by-step explanation:

3√13

This expression cannot be simplified because you cannot take any common factor outside the root.

Using 3 different methods, we can find that YZ = 25m

For a given triangle rectangle with a known angle θ and a hypotenuse H, we can write the trigonometric relations

sin(θ) = (opposite cathetus)/H

cos(θ) = (adjacent cathetus)/H

tan(θ) = (opposite cathetus)/(adjacent cathetus)

Now, in the given image we can see that:

θ = 30°

H = 50m

XY = adjacent cathetus

YZ = opposite cathetus.

We want to find YZ, so with the known things, we can use the first relation:

[tex]sin(30\°) = YZ/50m[/tex]

[tex]sin(30\°)*50m = YZ = 25m[/tex]

Now let's try another way.

We know that the sum of the internal angles of a triangle is always equal to 180°

In a triangle rectangle, we always have an angle equal to 90°.

Then the missing angle for our triangle can be computed from:

Z + 90° + 30° = 180°

Z = 180° - 90° - 30° = 60°

From this angle, the side YZ is the adjacent cathetus, then we can use the second trigonometric relation:

[tex]cos(60\°) = YZ/50m\\cos(60\°)*50m = YZ = 25m\\[/tex]

Third way.

Whit the same angle we could find the side XY, the opposite cathetus, with:

[tex]sin(60\°) = XY/50m \\sin(60\°)*50m = XY = 43.3m[/tex]

Now that we know one of the catheti, we can use the last trigonometric relation

[tex]tan(60\°) = XY/YZ = 43.3m/YZ \\YZ = 43.3m/tan(60\°) = 25m\\[/tex]

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Answer:

Solve the equation where the sine of 30 degrees is equal to YZ/50.

Solve 180 – (30 + 90) = 60 to find the measure of angle Z. Then use the cosine of Z to write and solve an equation.

Use the 30°-60°-90° triangle theorem to find that YZ = 50/2.

Step-by-step explanation:

edge 2022

25) First, find the amount of minutes in 2 hours. Note that there are 60 minutes in one hour:

2 x 60 = 120 minutes per 2 hours.

Next, the bacteria doubles every 20 minutes. 120/20 = 6, which means that the bacteria will double 6 times:

1 x 2 = 2

2 x 2 = 4

4 x 2 = 8

8 x 2 = 16

16 x 2 = 32

32 x 2 = 64

64 bacteria will be your answer.

~

26) The Area of a circle = πr²

Set the equation:

400π = π(r + 2)²

First, divide common factors from both sides, or π.

(400π)/π = (π(r + 2)²)/π

400 = (r + 2)²

√400 = √(r + 2)²

r + 2 = √400

r + 2 = √(20 x 20)

r + 2 = 20

r + 2 (-2) = 20 (-2)

r = 20 - 2

r = 18

18 is your final answer.

~

27)

The volume of a box can be found by multiplying length x width x height:

[tex]V (box) = l * w * h[/tex]

The volume given is 90, the height 3, and the width is 1 foot less then length:

First solve what you know:

[tex]V(box) = 90\\h = 3\\l = l\\w = l - 1[/tex]

Plug in the corresponding terms with the corresponding variable. Isolate the variable, l. Divide 3 from both sides of the equation:

[tex]90 = 3 * l (l - 1)\\\frac{90}{3} = \frac{3 * l(l -1)}{3}\\30 = l(l - 1)\\[/tex]

Distribute l to both terms in the parenthesis:

[tex]30 = l(l - 1)\\30 = l^2 - l[/tex]

Solve:

[tex]30 = (6)^{2} -6\\30 = 36 - 6\\30 = 30[/tex]

∴ [tex]l = 6[/tex]

Solve for width. Width is 1 less foot then length:

[tex]l - 1 = w\\l = 6\\[/tex]

∴ [tex]6 - 1 = w\\w = 5[/tex]

Equation: [tex]V (box) = l * w * h[/tex]

or

[tex]l = \frac{V(box)}{w * h}[/tex]

[tex]V(box) = 90\\h = 3\\l = 6\\w = 5[/tex]

3rd step

Solution:-

[tex]\\ \sf\longmapsto -2x+8-3x=7[/tex]

[tex]\\ \sf\longmapsto -2x-3x+8=7[/tex]

[tex]\\ \sf\longmapsto -5x+8=7[/tex]

[tex]\\ \sf\longmapsto -5x=7-8[/tex]

[tex]\\ \sf\longmapsto -5x=-1[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{-1}{-5}[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{1}{5}[/tex]

Let x = 3.191919…. Then 100x = 319.191919…, and we have

100x - x = 319.191919… - 3.191919…

99x = 316

x = 316/99

Next, we have

316 = 297 + 19 = 3 × 99 + 19

so

316/99 = (3 × 99 + 19)/99 = 3 + 19/99

Answer:

1/6x = 9

x = 54

Step-by-step explanation:

Let x = number

1/6x = 9

Multiply each side by 6

1/6x * 6 = 9*6

x = 54

Answer:

1/6n = 9 ---> the equation

x = 54 ----> equation's answer

Step-by-step explanation:

The variable used can be either x or n, doesn't really matter.

It says 1/6th of a number is 9 --> write 1/6, n for the number, and then = 9

so, 1/6n = 9

Now, you are going to multiply each side by 6

1/6x * 6 = 9 * 6 --------> 54

x = 54

Answer:

The x-intercepts are reflecting zero-profit: (0, 0) and (6, 0).

The maximum value of the graph is at vertex (3, 120): maximum profit when the price is $3.

The function is increasing until the vertex, between x-value of 0 to 3 and is decreasing once it reached the vertex, between x-value of 3 to 6.

In the first interval the sale and profit increases, in the second interval the sale and profit decreases.

Average rate of change from x = 3 to x = 5 is:

This represents the profit drop of $30 per $1 price increase when price changes from $3 to $5.

Answer:

4

Step-by-step explanation:

5-3x+4x^2

Write the terms from highest power to smallest power

4x^2 -3x +5

The leading coefficient is the term in front of the highest power

4

Answer:

4

Step-by-step explanation:

The first step here is to rearrange the terms of this polynomial in descending order:  x^2, then x, then x^0 (nothing that x^0 = 1):

4x^2 - 3x + 5

The "leading coefficient of the polynomial) is the coefficient of the highest x power, which here is x^2:  4.

Answer:

2(3x+4) = 11x-17

6x+8 = 11x-17

25=-5x

x=-5

11x-17

55-17

38

AC = 38

CD = 38

49-38 = 11

DE = 11

Let me know if this helps!

Step-by-step explanation:

2x+3y+5+4x-7y-8

2x+4x+3y-7y+5-8

6x-4y-3

Answer:

6x - 4y - 3

Step-by-step explanation:

They are basically telling you to sum both equations. So,

(2x + 3y + 5) + (4x - 7y - 8)

= 2x + 4x + 3y - 7y + 5 - 8

= 6x - 4y - 3

Step-by-step explanation:

here u have answer of your question dear

Answer:

Not enough infomation, you need to provide #12

Step-by-step explanation:

Answer:

Hello,

answer 22

Step-by-step explanation:

[tex]\dfrac{1}{j} +\dfrac{1}{k} =\dfrac{1}{3} \\\\\dfrac{k+j}{j*k} =\dfrac{1}{3} \\\\\\3k+3j=j*k\\\\k(3-j)=-3j\\\\k=\dfrac{3j}{j-3} \\\\k=\dfrac{3j-9+9}{j-3} \\\\k=3+\dfrac{9}{j-3} \\\\\\j-3\ must\ be \ a divisor\ of\ 9 ==> 1,3,9\\\\j-3=1 ==> j=4 , k=3+\dfrac{9}{1} =12\\\\j-3=3 ==> j=6 , k=3+\dfrac{9}{3} =6\\\\j-3=9 ==> j=12 , k=3+\dfrac{9}{9} =4\\\\\sum\ k=12+6+4=22\\[/tex]

The sum of all possible values for k is 22.

The fractional bar is a horizontal bar that divides the numerator and denominator of every fraction into these two halves.

Given:

1/j + 1/k= 1/3

Simplifying the fraction

(k+ j)/ kj= 1/3

3k + 3j = kj

k(3- j) = -3j

k = -3j/ (3- j)

k= 3j/ (j-3)

k = 3j + 9 - 9 / (j-3)

k = 3 + 9/ (j-3)

Since (j-3) must be divisor of 9.

j- 3 = 1---> j=4, k= 3 +9 = 12

j- 3 = 3---> j=6, k= 3 +9/3 = 6

j- 3 = 9---> j=12, k= 3 +9/9 = 4

So, The sum is = 12+ 6 + 4 = 22

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Answer:

[tex]54\pi\ cm^2[/tex]

Step-by-step explanation:

1. Approach

In order to solve this problem, one needs to find the height of the cone. This can be done using the Pythagorean theorem. After finding the height of the cone, one can use the formula to find the surface area of a cone, to find the surface area of this particular cone.

2. Find the height of the cone

The Pythagorean theorem is a property that relates the sides of a right triangle. The radius (distance from the center to circumference (outer edge)) of the base, the height of the cone, and the slant of the cone forms a right triangle. Thus, one can use the Pythagorean theorem to solve for the height. The Pythagorean states the following:

[tex]a^2+b^2=c^2[/tex]

Please note that (a) and (b) represent the sides adjacent (next to) the right angle, (c) represents the hypotenuse (the side opposite the right angle). In this case (a) is the height, and (b) is the radius of the base. (c) is the diagonal of the cone. Substitute the given values in and solve for the height,

[tex]a^2+b^2=c^2[/tex]

[tex]a^2+3^3=15^2[/tex]

Simplify,

[tex]a^2+3^3=15^2[/tex]

[tex]a^2+9=225[/tex]

Inverse operations,

[tex]a^2+9=225[/tex]

[tex]a^2=216[/tex]

[tex]a=\sqrt{216}[/tex]

3. Find the surface area of the cone

The following formula can be used to find the surface area of a cone,

[tex]A_s=\pi r(r+\sqrt{h^2+r^2})[/tex]

Where (h) is the height of the cone, (r) is the radius of the base of the cone, and ([tex]\pi[/tex]) represents the value (3.1415...). Substitute the given values into the formula and solve for the surface area,

[tex]A_s=\pi r(r+\sqrt{h^2+r^2})[/tex]

[tex]A_s=\pi(3)(3}+\sqrt{\sqrt{216}^2+3^2}[/tex]

Simplify,

[tex]A_s=\pi(3)(3}+\sqrt{\sqrt{216}^2+3^2}[/tex]

[tex]A_s=\pi(3)(3}+\sqrt{216+9})[/tex]

[tex]A_s=\pi(3)(3}+\sqrt{225})[/tex]

[tex]A_s=\pi(3)(3}+15)[/tex]

[tex]A_s=\pi(3)(18)[/tex]

[tex]A_s=\pi(54)[/tex]

Answer:

No

Step-by-step explanation:

x^3• x^3•x^3

We add the exponents

x^(3+3+3) = x^9

x^3•3•3 x^3 *9

9x^3

These are not equal unless

x^9 = 9x^3

Answer:

perimeter=40m

Step-by-step explanation:

PERIMETER=(AREA ROOT)*4

                   =10*4=40m

Answer:

Step-by-step explanation:

The law of cosine helps us to know the third side of a triangle when two sides of the triangle are already known the angle opposite to the third side is given. The distance between A and B is 85.6 yds.

The law of cosine helps us to know the third side of a triangle when two sides of the triangle are already known the angle opposite to the third side is given. It is given by the formula,

[tex]c =\sqrt{a^2 + b^2 -2ab\cdot Cos\theta}[/tex]

where

c is the third side of the triangle

a and b are the other two sides of the triangle,

and θ is the angle opposite to the third side, therefore, opposite to side c.

The three points A, B, and C will form a triangle. Therefore, using the law of cosine the measure of the third side AB can be written as,

[tex]AB =\sqrt{(AC)^2 + (BC)^2 -2(AC)(BC)\cdot \cos(51.2^o)}\\\\AB =\sqrt{(80)^2 + (104)^2 -2(80)(104)\cdot \cos(51.2^o)}\\\\AB = \sqrt{6400+10816-16640\cos51.2^o}\\\\AB = \sqrt{7328.4}\\\\AB=85.6\rm\ yd[/tex]

Hence, the distance between A and B is 85.6 yds.

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Answer:

Area: x^2+x-6

Perimeter: 4x+2

Step-by-step explanation:

Area: multiply x+3 and x-2 and combine the like terms

Perimeter: multiply the length and width by two, then combine the like terms.

Answer:

Positive/negative = negative

Negative/positive = negative

So -2 ÷ 8 and 15 ÷ (-5) are going to have negative quotients.

Let me know if this helps!

Answer:

10

Step-by-step explanation:

If you multiply 10% of 34,950,101 by 10, you will get the value of 34,950,101.