Which of the following ordered pairs is represented by a point located on the y-axis?

Select one:

a.(6,-6)

b. (3,3)

c. (0,8)

d. (-5,0)

Answer:

Jorge ran 32 laps

Step-by-step explanation:

The equation is 8x4=32

Answer:

the correct answer is 180.8. i saw that other ppl had this answer on brianly but had 0 star ratings even though they were correct.

Step-by-step explanation: i just took this test and trusted the person who ansered and got it wrong.

Answer:

418

Step-by-step explanation:

Answer: 7.1% and 6%.

Step-by-step explanation:

Given data:

Sample size (n) = 11

Standard deviation = 2.2

Margin of error confidence level 95% = 1.96

Margin of error confidence level of 90% = 1.65

Solution:

P = 2.2/11

= 0.2.

ME = z √p (1-p)/n

at 95% interval

ME = 1.96 * √ 0.2 ( 1 – 0.2 ) / 11

= 1.96 * 0.03636

= 0.071.

= 7.1%

At 90% interval

ME = 1.65 * √ 0.2 ( 1 – 0.2 ) / 11

= 1.65 * 0.03636

= 0.06.

= 6%

Answer:

The volume  [tex]V = \frac{75}{2}[/tex] units

Step-by-step explanation:

From the question we are told that

 The equation of the plane is  [tex]z = 2x + 5y + 1[/tex]

The range of the rectangle on the x and y axis is  [tex]\{ (x, y) | -1 \le x \le 0 , 1 \le y \le 4 \}[/tex]

Generally the volume is mathematically represented as

        [tex]V = \int\limits^{4}_{1} \int\limits^0_{-1} {z} \, da[/tex]

Here stands for the area of the solid

So    

           [tex]V = \int\limits^{4}_{1} \int\limits^0_{-1} {(2x + 5y + 1 )} \, dxdy[/tex]

           [tex]V = \int\limits^{4}_{1} [{(\frac{2x^2}{2} + 5xy + x )} ] | \left \ 0} \atop {-1}} \right. \, dy[/tex]

            [tex]V = \int\limits^{4}_{1} [{(x^2 + 5xy + x )} ] | \left \ 0} \atop {-1}} \right. \, dy[/tex]

          [tex]V = \int\limits^{4}_{1} [{((0)^2 + 5(0)y + (0) )} ] -[{((-1)^2 + 5(-1)y + (-1) )} ] \, dy[/tex]

        [tex]V = \int\limits^{4}_{1} 5y \, dy[/tex]

        [tex]V = 5 [ \frac{y^2}{2} ]|\left \ 4 } \atop { 1 }} \right. \, dy[/tex]

       [tex]V = 5( [ \frac{4^2}{2} ] - [ \frac{1^2}{2} ] )[/tex]

        [tex]V = \frac{75}{2}[/tex]

Answer:

18 students for each teacher and 10 for each tutor, and if the academy had 80 students it would have 8 tutors

Step-by-step explanation:

Answer:

t=3

Step-by-step explanation:

5t-4=|11

+4 |+4

5t= | 15

÷5 | ÷5

t = 3

Answer:

Im pretty sure every hat and mask is 1 dollar

Answer:

k = 3.5

Step-by-step explanation:

From the graph in the picture attached,

Relation between balloons height (y) is directly proportional to the time (x)

y ∝ x

y = kx

Where 'k' is a proportionality constant.

Now we substitute the point (8, 28) in the equation,

28 = k(8)

k = [tex]\frac{28}{8}[/tex]

k = 3.5

k ≈ 3.5

Therefore, value of constant 'k' is 3.5

Answer:

Vectors [tex]p_{1} = 2+5\cdot x + 3\cdot x^{2}[/tex], [tex]p_{2} = 4+11\cdot x +6\cdot x^{2}[/tex] and [tex]p_{3} = 1+2\cdot x +x^{2}[/tex] are linearly independent.

Step-by-step explanation:

From Linear Algebra, we must remember that a set of vectors is linearly independent if and only if coefficients of its linear combinations are all zeroes. That is:

[tex]\Sigma\limits_{i=1}^{n} \alpha_{i}\cdot p_{i}= 0[/tex], where [tex]\alpha_{i} = 0[/tex]. (Eq. 1)

Where:

[tex]p_{i}[/tex] - i-th Polynomial of the set of vectors, dimensionless.

[tex]\alpha_{i}[/tex] - i-th coefficient associated with the i-ith polynomial of the set of vectors, dimensionless.

Let [tex]p_{1} = 2+5\cdot x + 3\cdot x^{2}[/tex], [tex]p_{2} = 4+11\cdot x +6\cdot x^{2}[/tex] and [tex]p_{3} = 1+2\cdot x +x^{2}[/tex] elements of the set of vectors, whose linear combination is:

[tex]\alpha_{1}\cdot p_{1}+\alpha_{2}\cdot p_{2}+\alpha_{3}\cdot p_{3}= 0[/tex]

[tex]\alpha_{1}\cdot (2+5\cdot x+3\cdot x^{2})+\alpha_{2}\cdot (4+11\cdot x +6\cdot x^{2})+\alpha_{3}\cdot (1+2\cdot x+x^{2}) = 0[/tex]

[tex](2\cdot \alpha_{1}+4\cdot \alpha_{2}+\alpha_{3})+(5\cdot \alpha_{1}+11\cdot \alpha_{2}+2\cdot \alpha_{3})\cdot x+(3\cdot \alpha_{1}+6\cdot \alpha_{2}+\alpha_{3})\cdot x^{2} = 0[/tex]

Values of coefficient are contained in the following homogeneous system of linear equations:

[tex]2\cdot \alpha_{1}+4\cdot \alpha_{2}+\alpha_{3} = 0[/tex] (Eq. 2)

[tex]5\cdot \alpha_{1}+11\cdot \alpha_{2}+2\cdot \alpha_{3} = 0[/tex] (Eq. 3)

[tex]3\cdot \alpha_{1}+6\cdot \alpha_{2}+\alpha_{3} = 0[/tex] (Eq. 4)

The solution of this system is:

[tex]\alpha_{1} = 0[/tex], [tex]\alpha_{2} = 0[/tex], [tex]\alpha_{3} = 0[/tex]

Which means that given set of vectors are linearly independent.

Answer:

The first picture is a function. The second picture is not a function.

Step-by-step explanation:

The first one is a function because no x-values repeat. Different x-values can be paired with the same y-function.

The second one is not a function because it fails the horizontal line test. The line would touch in two spots, therefore failing the line test.

Answer:

The range of the following set of points is {4, -2, -8}

Step-by-step explanation:

∵ The set of points is {(3, 4), (7, -2), (11, -8)}

∵ The range is the y-coordinates of these points

∵ The y-coordinates of the points are 4, -2, -8

∴ The range is {4, -2, -8}

∴ The range of the following set of points is {4, -2, -8}

Answer:

31x+21

Step-by-step explanation:

7x+3(8x+7)

7x+24x+21

31x+21

Answer 31x + 21

Step-by-step explanation: can’t

Answer:

The beam of the light is moving along the shoreline at the rate of [tex]\mathbf{ 160 \ \pi \ mi/min}[/tex]

Step-by-step explanation:

From the given information: Let say x is the distance between the lighthouse and the shoreline. Then, the  tangent of  trigonometry can be written as:

[tex]tan (\theta )=\dfrac{x}{4}[/tex]

In respect to time, the expression can be derived as:

[tex]sec^2 (\theta) \dfrac{d \theta}{dt} = \dfrac{1 }{4}\dfrac{dx}{dt}[/tex]

[tex]\dfrac{dx}{dt}=\dfrac{4}{cos ^2 (\theta) }\dfrac{d \theta}{dt}[/tex]

To estimate the value of [tex]\dfrac{dx}{dt}[/tex], we need to know cos²(θ) and D

where;

D = [tex]\sqrt{4^2+4^2}= \sqrt{32}\ mi[/tex]

[tex]cos (\theta) = \dfrac{4}{D}[/tex]

[tex]cos (\theta) = \dfrac{4}{\sqrt{32}}[/tex]

[tex]cos (\theta) = \dfrac{4}{\sqrt{16 \times 2}}[/tex]

[tex]cos (\theta) = \dfrac{4}{4 \sqrt{\ 2}}[/tex]

[tex]cos (\theta) = \dfrac{1}{ \sqrt{\ 2}}[/tex]

[tex]cos ^2 (\theta)= \dfrac{1}{2}[/tex]

Finally, we substitute the value of [tex]cos^2(\theta)[/tex] and [tex]\dfrac{d \theta}{dt}[/tex] in the expression derived earlier.

i.e.

[tex]\dfrac{dx}{dt} = \dfrac{4}{\dfrac{1}{2}}\times 10 \ rev/min[/tex]

where;

10 rev/min = (10 × 2π) rad/min = 20π rad/min

Then:

[tex]\dfrac{dx}{dt} = \dfrac{4}{\dfrac{1}{2}}\times 20 \ \pi[/tex]

[tex]\mathbf{\dfrac{dx}{dt} = 160 \ \pi \ mi/min}[/tex]

Answer:

x = 8

Step-by-step explanation:

Step 1:

17x + 14 + 4x - 2 = 180          Sum of a line

Step 2:

21x + 12 = 180        Combine Like Terms

Step 3:

21x = 168       Subtract 12 on both sides

Step 4:

x = 168 ÷ 21      Divide

Answer:

x = 8

Hope This Helps :)

Step-by-step explanation:

4x - 2 + 17x + 14 = 180

21x + 12 = 180

Subtract 12 from both sides and you get :

21x = 168

Devide

[tex] \frac{21x}{21} = \frac{168}{21} \\ x = 8[/tex]

Complete question :

An electronics store receives a shipment of 35 graphing calculators, including 7 that are defective. 8 of these calculators are selected for a local high school. (A) How many selections can be made? (B) How many of these selections will contain no defective calculators?

Answer:

23535820 ways

3108105 ways

Step-by-step explanation:

A.) How many selections can be made:

Number of ways of selecting 8 calculators from 35

35C8 :

Combination formula :

nCr = n! /(n-r)! r!

35C8 = 35! / (35-8)!8!

35C8 = 35! / 27! 8!

35C8 = (35*34*33*32*31*30*29*28) / (8*7*6*5*4*3*2*1)

35C8 = 948964262400 / 40320

= 23535820 ways

B.) number of non-defective calculators :

35 - 7 = 28

28C8 = n! /(n-r)! r!

28C8 = 28! / (28-8)!8!

28C8 = 28! / 20! 8!

28C8 = (28*27*26*25*24*23*22*21) / (8*7*6*5*4*3*2*1)

28C8 = 2506375872000 / 40320

= 3108105 ways

Answer:

add them all up and subtract 420 from 15+20+12!

Step-by-step explanation:

hope this helps

Answer:

t = 3.74165738677 or 3.74

Step-by-step explanation:

Step 1:

( t - 3 )² = 6      Equation

Step 2:

t² - 3² = 6       Open Parentheses

Step 3:

t² - 9 = 6          Exponents

Step 4:

t² = 14         Add 9 on both sides

Step 5:

t = [tex]\sqrt{14}[/tex]       Find the square root of 14

Answer:

t = 3.74165738677 or 3.74        Round

Hope This Helps :)

Answer:

The arrow is at a height of 48 ft after approximately 0.55s and after 5.45s.

Step-by-step explanation:

took the assignment

Answer:

y =-3/2x+4

Step-by-step explanation:

simple

(1.) 20.4

(2.) 150

(3) 8

(4.) 15

Answer:

C. 125%

Step-by-step explanation:

Because an entire box of 100 is colored, we automatically know it is at least 100%. Which means both A and B are incorrect. There are two tens filled, so we have 120%. There is another 5 boxes are filled, so we have 125%, which is C.

I hope that this helps! :)

Answer:

Option (b)

Step-by-step explanation:

From the graph attached in the figure,

Graph (a) is a scatter plot of a data set.

Data in this graph is not connected. In other words, a scatter plot represents a discrete function.

Similarly, in the graph (b) there is a straight line.

All points lying on this straight line are connected and follow the same rule.

Therefore, graph (b) represents a continuous function.

Therefore, Option (b) is the correct option.

Answer:

14.98

Step-by-step explanation:

I used a calculater

Answer:

205.74 cm

Step-by-step explanation:

Answer:2.00

Step-by-step explanation:

Answer:20

Step-by-step explanation: