Which function has a domain and range that includes all real values?

Answer:

I can say for sure that the answer is not segment GH ≅ segment FH because the tangents that create the segment FG share a common endpoint.  I believe the answer is segment GH ≅ segment FH because arc EF ≅ arc GF.

Step-by-step explanation:

Again, I'm not sure about the correct answer but I know for sure it isn't segment GH ≅ segment FH because the tangents that create the segment FG share a common endpoint.  

The segment GH and the segment FH are equal to each other because the line AH is coming from the center of the circle and is bisecting the line GF.

The circumcenter of a triangle can be constructed by drawing any two of the three perpendicular bisectors. For three non-collinear points, these two lines cannot be parallel, and the circumcenter is the point where they cross.

Any point on the bisector is equidistant from the two points that it bisects, from which it follows that this point, on both bisectors, is equidistant from all three triangle vertices

Hence the segment GH and the segment FH are equal to each other because the line AH is coming from the center of the circle and is bisecting the line GF.

To know more about a Circumscibed circle follow

https://brainly.com/question/2699432

Answer:

5

Step-by-step explanation:

Calculate the square root of 25 and get 5.

This is because there's one side we want (that's labeled "8") out of 12 sides total. This is of course if each side is equally likely.

Side note: this 12-sided die is known as a dodecahedron.

9514 1404 393

Answer:

  (d) 6√3

Step-by-step explanation:

There are several ways to work multiple-choice problems. One of the simplest is to choose the only answer that makes any sense. Here, that is 6√3.

y is the hypotenuse of the medium-sized right triangle, so will be longer than that triangle's longest leg. y > 9

The only answer choice that meets this requirement is ...

  y = 6√3

__

In this geometry, all of the right triangles are similar. This means corresponding sides have the same ratio. For y, we're interested in the ratio of long leg to hypotenuse.

  long leg/hypotenuse = y/(9+3) = 9/y

  y² = 9(9+3) = 9·4·3

  y = 3·2·√3 . . . . . . take the square root

  y = 6√3

__

Additional comments

You may notice that y is the root of the product of the longer hypotenuse segment (9) and the whole hypotenuse (9+3 = 12). We can say that y is the "geometric mean" of these segment lengths. Similarly (pun only partially intended), x will be the root of the product of the short segment (3) and the whole hypotenuse (12)

  x = √(3·12) = 6

This is another "geometric mean" relation.

Further, the altitude will be the geometric mean of the two segments of the hypotenuse:

  h = √(9·3) = 3√3

A way to summarize all of these relations is to say that the legs of the right triangle that are not the hypotenuse are equal to the geometric mean of the segments of the hypotenuse that the leg intercepts.

  x = √(3·12)

  y = √(9·12)

  h = √(3·9)

Answer:

b(-2,-5)

Step-by-step explanation:

Answer:

h) a+20 = 80 (vert. opp angles)

a = 60

i) 3a+48 = 180

3a = 132

a = 44

a) 3x + 2x = 180

5x = 180

x = 36

∡y = 72

∡z = 108

∡r = 144

∡x = 180-144 = 36

b) p:b = 3:1

4u = 180

u = 45

∡p = 135

∡b = 45

∡q = ∡p = 135 (vert. opp)

∡a = ∡b = 45 (vert. opp)

Answer:

hello,

as i have taken the time to draw the picture

Step-by-step explanation:

Answer:

68%

Step-by-step explanation:

6,753/100=67.53 which rounds up to 68%

The statement that odd degree polynomials have a u-shaped graph and even degree polynomials have an s-shaped graph is FALSE.

Odd degree polynomials have branches that go in opposing directions which means that they will form an s-shaped graph.

Even degree polynomials on the other hand, have graphs that go in the same direction which is why they form u-shaped graphs.

In conclusion, the above statement is false.

Find out more on polynomials at https://brainly.com/question/9696642.

Answer:

anser b

Step-by-step explanation:

i had it

Answer:

x = √74

y = √17

Answered by GAUTHMATH

Answer:18

Step-by-step explanation:

Answer:

(0,-4)

Step-by-step explanation:

The plot for x intercept is at -4,0 and the y intercept is at 0,5

type it in as (0,-4), some require the (#,#) format

Hope the picture above will help you

Hi there!  

»»————-　★　————-««

I believe your answer is:  

20%

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

⸻⸻⸻⸻

[tex]100\% - 80\% = \boxed{20\%}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

0.25

Step-by-step explanation:

16/4 = 4

4/4 = 1

1/4 = 0.25

0.25/4 = 0.0625

0.0625/4 = 0.015625

give me brainliest please:)

Answer:

a) 0.125 = 12.5% probability that it’s not raining and there is heavy traffic and I am not late.

b) 0.2292 = 22.92% probability that I am late.

c) 0.5454 = 54.54% probability that it rained that day.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

Question a:

2/3 probability of not raining.

If not raining, 1/4 probability of heavy traffic.

1 - 0.25 = 0.75 = 3/4 probability of not late.

So

[tex]p = \frac{2}{3} \times \frac{1}{4} \times \frac{3}{4} = \frac{2}{16} = 0.125[/tex]

0.125 = 12.5% probability that it’s not raining and there is heavy traffic and I am not late.

b. What is the probability that I am late?

0.5 of (1/3)*(1/2) = 1/6(rainy and heavy traffic).

0.25 of (1/3)*(1/2) = 1/6(rainy and no traffic).

1/8 = 0.125 of (2/3)*(3/4) = 1/2(not rainy and no traffic).

0.25 of (2/3)*(1/4) = 1/6(not rainy and traffic). So

[tex]P(A) = 0.5\frac{1}{6} + 0.25\frac{1}{6} + 0.125\frac{3}{6} + 0.25\frac{1}{6} = \frac{0.5 + 0.25 + 3*0.125 + 0.25}{6} = 0.2292[/tex]

0.2292 = 22.92% probability that I am late.

c. Given that I arrived late at work, what is the probability that it rained that day?

Event A: Late

Event B: Rained

0.2292 = 22.92% probability that I am late.

This means that [tex]P(A) = 0.2292[/tex]

Probability of late and rain:

0.5 of 1/6(rain and heavy traffic).

0.25 of 1/6(rain and no traffic). So

[tex]P(A \cap B) = 0.5\frac{1}{6} + 0.25\frac{1}{6} = \frac{0.5 + 0.25}{6} = \frac{0.75}{6} = 0.125[/tex]

Probability:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.125}{0.2292} = 0.5454[/tex]

0.5454 = 54.54% probability that it rained that day.

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data:

May August

95 100

72 80

78 95

50 65

89 85

92 98

75 70

90 96

65 87

The appropriate test is a paired t test :

d = difference between May and August

d = (-5, -8, -17, -15, 4, -6, 5, -6, -22)

The hypothesis :

H0 : μd = 0

H1 : μd ≠ 0

The test statistic :

T = dbar / (Sdbar/√n)

Where, dbar and Sdbar are the mean and standard deviation of 'd' respectively.

Using calculator :

dbar = - 7.777 ; Sdbar = 9.052

Test statistic = - 7.777 / (9.052 /√9)

Test statistic = - 2.577

The Pvalue, df = n - 1 = 9 - 1 = 8

Pvalue(-2.577, 8) = 0.0327

At α = 0.05

Pvalue < α ; WE reject the H0 ; and conclude that there has been a change in score

Answer:

Permutation ; 210 ways

Step-by-step explanation:

Permutation and combination methods refers to mathematical solution to finding the number of ways of making selection for a group of objects.

Usually, selection process whereby the order of selection does not matter are being treated using permutation, while those which takes the order of selection into cognizance are calculated using combination.

Here, selecting 2 players from 15 ; since order does not matter, we use permutation ;

Recall :

nPr = n! ÷ (n - r)!

Hence,

15P2 = 15! ÷ (15 - 2)!

15P2 = 15! ÷ 13!

15P2 = (15 * 14) = 210 ways

Answer:

$147

Step-by-step explanation:

0.15x = $22.05

Divide both sides by 15

22.05/0.15 = $147

Answer:

d = 6 , a₁ = - 6 and a₁₀ = 48

Step-by-step explanation:

The nth term of an arithmetic progression is

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₃ = 6 and a₇ = 30 , then

a₁ + 2d = 6 → (1)

a₁ + 6d = 30 → (2)

Subtract (2) from (1) term by term to eliminate a₁

4d = 24 ( divide both sides by 4 )

d = 6

Substitute d = 6 into (1)

a₁ + 2(6) = 6

a₁ + 12 = 6 ( subtract 12 from both sides )

a₁ = - 6

Then

a₁₀ = - 6 + (9 × 6) = - 6 + 54 = 48

----------------------------------------------------

Answer:

d=6

a=-6

Step-by-step explanation:

use the formula for the nth term which is

Tn=a+(n-1)d..you will have to create two equations then solve them as a simultaneous equation

T3=6 and T7=30

T3=a+(3-1)d

6=a+2d........... first equation

T7=a+(7-1)d

30=a+6d.......... second equation

then solve them as a simultaneous equation

a+2d=6

a+6d=30

-4d/-4=-24/-4

d=6

a+2d=6

a+2(6)=6

a=6-12

a=-6

I hope this helps

9514 1404 393

Answer:

  13 < √181 < 14

Step-by-step explanation:

Apparently, you're supposed to know that ...

  13² = 169

  14² = 196

so √181 will lie between 13 and 14.

  13 < √181 < 14

Answer:

Hence the required probability is, 3/4

Step-by-step explanation:  

At the shelter, he likes :  

a male coolie, a female coolie, a male boxer, a female boxer, a male beagle, a female beagle, a male Labrador, and a female Labrador.  

Let, A denote the event of selecting a male coolie and B denote the event of selecting a male Labrador.  

P(A) = 1/8 = P(B)  

Here the probability of selecting a puppy except A & B is,  

P(AUB)c = 1 - P(AUB) = 1 - { P(A) + P(B) } = 1 - 1/8 - 1/8 = 3/4

Answer:

50

Step-by-step explanation:

So we know that 42/3=14.

3 years before was:

14-3=11

42-3=39

The sum of 11+39 is 50

Answer:

2.25

Step-by-step explanation:

We can write a ratio to solve

1.69           x

------     = ---------------

3/4 lb              1 lb

Using cross products

1.69 * 1 = 3/4 *x

1.69 = 3/4 x

Multiply by 4/3

1.69 * 4/3  = x

x=2.25333

Rounding to the nearest cent

Answer:

x^2 + 91x + 2500

-----------------------------------------------------------------------------

x^2 + 3x + 50

(x-r)(x-s)

-> x^2-(r+s)x+rs

rs = 50, r + s = -3

-> (rs)^2 = 2500

(r+s)^2 = 9

-> r^2 + 2rs + s^2 = 9

-> r^2 + 2(50) + s^2 = 9

-> r^2 + s^2 + 100 = 9

-> r^2 + s^2 = -91

(x-r^2)(x-s^2)

-> x^2-(r^2+s^2)x+(rs)^2

-> x^2 - (-91)x + 2500

x^2 + 91x + 2500

Answer:

a) The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b) The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

Sample of 120 registered voters in order to predict the winner of a local election. The Democrat candidate was favored by 62 of the respondents.

So 120 - 62 = 58 favored the Republican candidate, so:

[tex]n = 120, \pi = \frac{58}{120} = 0.4833[/tex]

99% confidence level

So [tex]\alpha = 0.01[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].  

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 - 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.3658[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 + 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.6001[/tex]

The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b. If a candidate needs a simple majority of the votes to win the election, can the Republican candidate be confident of victory? Justify your response with an appropriate statistical argument.

The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

Answer:

D.√85

Step-by-step explanation:

We can find the distance between two points using the distance between two points formula

Distance between two points formula:

d = √(x2 - x1)² + (y2 - y1)²

Where the x and y values are derived from the given points

We are given the two points (-2,7) and (7,9)

Using these points let's define the variables ( variables are x1, x2, y1, and y2)

Remember points are written as follows (x,y)

The x value of the first point is -2 so x1 = -2

The x value of the second point is 7 so x2 = 7

The y value of the first point is 7 so y1 = 7

The y value of the second point is 9 so y2 = 9

Now that we have defined each variable let's find the distance between the two points

We can do this by substituting the values into the formula

Formula: d = √(x2 - x1)² + (y2 - y1)²

Variables: x1 = -2, x2 = 7, y1 = 7, y2 = 9

Substitute values in formula

d = √(7 - (-2))² + (9 - 7)²

Evaluation:

The two negative signs cancel out on 7-(-2) and it changes to +7

d = √ (7+2)² + (9-7)²

Add 7+2 and subtract 9 and 7

d = √ (9)² + (2)²

Simplify exponents 9² = 81 and 2² = 4

We then have d = √ 81 + 4

Finally we add 81 and 4

We get that the distance between the two points is √85

Answer:

The correct solution is "23.58 and 71.89".

Step-by-step explanation:

Given:

Sample,

n = 45

df = 45 - 1

   = 44

then,

⇒ [tex]X_R^2 = X_{\frac{\alpha}{2},df }^2[/tex]

          [tex]=71.89[/tex]

or,

⇒ [tex]X_L^2 = X_{1-\frac{\alpha}{2}, df }^2[/tex]

         [tex]=23.58[/tex]

Answer: y=29 / (4,29)

Step-by-step explanation:

By graphing [tex]f(x)=8x-3[/tex] and [tex]f(4)=0[/tex] on Desmos. You'll be able to find that when x is 4, y is 29.

Similarly, you can plugin 4 into the original equation ([tex]f(x)=8x-3[/tex]) Which looks like:

[tex]8(4)-3\\32-3=29[/tex]

Additionally, you can change [tex]f(x)=[/tex] to [tex]y=[/tex] as it is the exact same thing. With that in mind, you can do the same with [tex]f(x)=0[/tex] and just change it to x=4. As you're wanting to know what the y-value is when x=4.

Answer:

4x²-3x+c is our original equation

Step-by-step explanation:

we have an independent number I called this number c

put 4 from x and try to find c

f(4)=4*(4²)-3*(4)+c=0

we have to be careful about f(4) is 0

64-12+c=0 and c is -52 so our original equation is 4x²-3x-52