Which expression is equivalent to 206.230?
O a. 2 x 100 + 6 x 10 + 2 x 1 + 3 < 1/10
O b. 2 x 100 + 6 x 1 + 2 x 1/10 + 3 < 1/100
O c. 2 × 10 + 6 x 1 + 2 x 1/10 + 3 * 1/100

Answer:

Step-by-step explanation:

The missing length is 13 because,

Lets say the top triangle is A and the bottom triangle is B.

Triangle A gives us the side GF, and Triangle B gives us the sides TU and ST. Since the triangles are similar(as stated in the problem), we can pair 2 sides GF(A) and TU(B) which is 11:22.(one way I usually figure which sides are similar is by first- matching the hypotenuse, then checking which of the remaining two is longer.. if that made any sense). You can see that their relationship is x2 or /2 (In another word, from A to B is multiplication- ex: 11 * 2 is 22, and from B to A is division- ex 22/2 is 11.) Since the missing number is the hypotenuse of triangle A and you know the Hypotenuse of triangle B all you have to do is divide side TS by 2 to get side SF. So the missing side is 13.

Answer: 13

Answer:

The center is (9,-8) and the diameter is 8

Step-by-step explanation:

(x − 9)^2 + (y + 8)^2 = 16

A circle is in the form

(x − h)^2 + (y -k)^2 = r^2  where (h,k) is the center and r is the radius

(x − 9)^2 + (y -  -8)^2 = 4^2  

The center is (9,-8) and the radius is 4

The diameter is 2 times the radius so the diameter is 8

The center is (9,-8) and the diameter is 8

Answer:

9.89949 or 9.9

Step-by-step explanation:

7^2 + 7^2 = c^2

49+49=98

square root of 98 = 9.89949

Answer:

29.5

Step-by-step explanation:

(5×35)+(5×24)/10

175+120/10

295/10

=29.5

Answer:

C = [tex]\left[\begin{array}{ccc}-2&-4\\-1&1\\\end{array}\right][/tex]

Step-by-step explanation:

A = B+ C then

C = A - B

C = [tex]\left[\begin{array}{ccc}2&-5\\-1&4\\\end{array}\right][/tex] - [tex]\left[\begin{array}{ccc}4&-1\\0&3\\\end{array}\right][/tex] (subtract corresponding elements )

   = [tex]\left[\begin{array}{ccc}2-4&-5-(-1)\\-1-0&4-3\\\end{array}\right][/tex]

   = [tex]\left[\begin{array}{ccc}-2&-4\\-1&1\\\end{array}\right][/tex]

Answer:

[tex]\text{Exact: }AB=25\sqrt{6},\\\text{Rounded: }AB\approx 61.24[/tex]

Step-by-step explanation:

We can use the Law of Sines to find segment AD, which happens to be a leg of [tex]\triangle ACD[/tex] and the hypotenuse of [tex]\triangle ADB[/tex].

The Law of Sines states that the ratio of any angle of a triangle and its opposite side is maintained through the triangle:

[tex]\frac{a}{\sin \alpha}=\frac{b}{\sin \beta}=\frac{c}{\sin \gamma}[/tex]

Since we're given the length of CD, we want to find the measure of the angle opposite to CD, which is [tex]\angle CAD[/tex]. The sum of the interior angles in a triangle is equal to 180 degrees. Thus, we have:

[tex]\angle CAD+\angle ACD+\angle CDA=180^{\circ},\\\angle CAD+60^{\circ}+75^{\circ}=180^{\circ},\\\angle CAD=180^{\circ}-75^{\circ}-60^{\circ},\\\angle CAD=45^{\circ}[/tex]

Now use this value in the Law of Sines to find AD:

[tex]\frac{AD}{\sin 60^{\circ}}=\frac{100}{\sin 45^{\circ}},\\\\AD=\sin 60^{\circ}\cdot \frac{100}{\sin 45^{\circ}}[/tex]

Recall that [tex]\sin 45^{\circ}=\frac{\sqrt{2}}{2}[/tex] and [tex]\sin 60^{\circ}=\frac{\sqrt{3}}{2}[/tex]:

[tex]AD=\frac{\frac{\sqrt{3}}{2}\cdot 100}{\frac{\sqrt{2}}{2}},\\\\AD=\frac{50\sqrt{3}}{\frac{\sqrt{2}}{2}},\\\\AD=50\sqrt{3}\cdot \frac{2}{\sqrt{2}},\\\\AD=\frac{100\sqrt{3}}{\sqrt{2}}\cdot\frac{ \sqrt{2}}{\sqrt{2}}=\frac{100\sqrt{6}}{2}={50\sqrt{6}}[/tex]

Now that we have the length of AD, we can find the length of AB. The right triangle [tex]\triangle ADB[/tex] is a 30-60-90 triangle. In all 30-60-90 triangles, the side lengths are in the ratio [tex]x:x\sqrt{3}:2x[/tex], where [tex]x[/tex] is the side opposite to the 30 degree angle and [tex]2x[/tex] is the length of the hypotenuse.

Since AD is the hypotenuse, it must represent [tex]2x[/tex] in this ratio and since AB is the side opposite to the 30 degree angle, it must represent [tex]x[/tex] in this ratio (Derive from basic trig for a right triangle and [tex]\sin 30^{\circ}=\frac{1}{2}[/tex]).

Therefore, AB must be exactly half of AD:

[tex]AB=\frac{1}{2}AD,\\AB=\frac{1}{2}\cdot 50\sqrt{6},\\AB=\frac{50\sqrt{6}}{2}=\boxed{25\sqrt{6}}\approx 61.24[/tex]

Answer:

[tex] \displaystyle 25 \sqrt{6} [/tex]

Step-by-step explanation:

the triangle ∆ABD is a special right angle triangle of which we want to figure out length of its shorter leg (AB).

to do so we need to find the length of AD (the hypotenuse). With the help of ∆ADC it can be done. so recall law of sin

[tex] \boxed{ \displaystyle \frac{ \alpha }{ \sin( \alpha ) } = \frac{ \beta }{ \sin( \beta ) } = \frac{ c}{ \sin( \gamma ) } }[/tex]

we'll ignore B/sinB as our work will be done using the first two

step-1: assign variables:

step-2: substitute

[tex] \displaystyle \frac{100}{ \sin( {45}^{ \circ} )} = \frac{AD }{ \sin( {60}^{ \circ} )} [/tex]

recall unit circle therefore:

[tex] \displaystyle \frac{100}{ \dfrac{ \sqrt{2} }{2} } = \frac{AD }{ \dfrac{ \sqrt{3} }{2} } [/tex]

simplify:

[tex]AD = 50 \sqrt{6} [/tex]

since ∆ABD is a 30-60-90 right angle triangle of which the hypotenuse is twice as much as the shorter leg thus:

[tex] \displaystyle AB = \frac{50 \sqrt{6} }{2}[/tex]

simplify division:

[tex] \displaystyle AB = \boxed{25 \sqrt{6} }[/tex]

and we're done!

Answer:

[tex]\frac{4x+9}{2x+5}[/tex]

Step-by-step explanation:

Answer:

false

Step-by-step explanation:

i'm not sure if this is a true or false question, but if so, it is false

the x-axis has a positive side and a negative side, so the coordinate isn't necessarily negative. it could also be zero if the point is at the origin

hope this helps!

Answer:

4 Flaps per second

Step-by-step explanation:

M = 120/30

Answer:

4 times per second

Step-by-step explanation:

120 ÷ 30 = 4

30 ÷ 30 = 1

4 flaps per 1 second

so basically 4

Answer:

Given,

[tex] \sqrt{ {x}^{2} + 4x + 4} - 3 = 0 \\ = > \sqrt{ {x}^{2} + 4x + 4} = 3 \\ = > {( \sqrt{ {x}^{2} + 4x + 4} })^{2} = {3}^{2} \\ = > {x}^{2} + 4x + 4 = 9 \\ = > {x}^{2} + 4x + 4 - 9 = 0 \\ = > {x}^{2} + 4x - 5 = 0 \\ = > {x}^{2} + 5x - x - 5 = 0 \\ = > x(x + 5) - 1(x + 5) = 0 \\ = > (x - 1)(x + 5) = 0 \\ \\ \sf \: either \: x - 1 = 0 \: \: \: \: \\ = > x = 1 \: \: \\ \\ \sf \: or \\ x + 5 = 0 \\ = > x = - 5 \\ \\ \green{ \boxed{ \bf \: \: \: \: \: x = 1 \: \: or \: - 5}}[/tex]

But if we put the value of x = 5 then it doesn’t satisfy the equation.

So,

X = 1

Answer:

The answer is [tex]x=1[/tex].

Step-by-step explanation:

To solve this problem, start by factoring the equation using the perfect square trinomial rule, which is states that the middle term is the first term multiplied by the last term, and then multiplied by 2. The formula for the perfect square trinomial rule looks like [tex]a^2+2ab+b^2[/tex], where [tex]a=x[/tex] and [tex]b=2[/tex]. The equation will look like [tex]\sqrt{(x+2)^2}-3=0[/tex].  

Next, pull out the terms from under the radical, assuming positive real numbers, which will look like [tex]x+2-3=0[/tex]. Then, simplify the equation by subtracting 3 from 2, which will look like [tex]x-1=0[/tex]. Finally, add 1 to both sides of the equation, and the answer will be [tex]x=1[/tex].

Answer:

I assume you'd already figured out the other questions so you just don't understand the question E

Step-by-step explanation:

The product of the first 2 numbers its stating is -28 and 48, and it's asking if the product (multiply -28 by 48 to get the product) is equal to the HCF and LCM you got in the previous answer.

Answer:

$1.50

Step-by-step explanation:

The change would be $1.50 because $5.00 - $3.50 = $1.50

Answer:

∠ DCV = ∠ VBD = 50°

Step-by-step explanation:

The inscribed angles DCV and VBD are half the measure of their intercepted arcs, that is

∠ DCV = [tex]\frac{1}{2}[/tex] DV = [tex]\frac{1}{2}[/tex] × 100° = 50°

∠ VBD = [tex]\frac{1}{2}[/tex] DV = [tex]\frac{1}{2}[/tex] × 100° = 50°

Answer:

-117 is irrational number

Answer:

Irrational

Step-by-step explanation:

Irrational number can't be written as a faction, -11pie can't be written as a fraction. Therefore it is a irrational number.

Answer:

x = 2y

Step-by-step explanation:

we don't need to do complicated trigonometric conversions. just try to express x by a term of y (or vice versa) and look.

so, starting with x = 2y.

if that is the case, then what is our equation looking like ? is it true ?

sin(2y - y)/sin(y) + cos(y - 2y)/cos(y) = 2

sin(y)/sin(y) + cos(-y)/cos(y) = 2

1 + cos(-y)/cos(y) = 2

cos(-y)/cos(y) = 1

cos(-y) = cos(y)

and yes, this is indeed true for all y. cos decreases from 1 to -1 with the increase of the absolute value of the angle from 0 to 180 degrees (meaning we could go up or down the same angle from 0, and cos would be the same), and then increases again to +1 for the increase of the absolute value of the angle from 180 to 360 degrees. and then it all starts again. and again, and again, ...

so, since the original equation is true under the assumption x=2y, this must be the correct option.

Answer:

C

Step-by-step explanation:

f is neither even nor odd

______________________________

[tex]\sf\bold{The\:above\:graph\:says:}[/tex]

$\space$

$\sf\bold{here:}$

$\space$

$\sf\bold{Find\:acceleration\:by\:v-t\:graph:}$

$\mapsto$ $\sf\small{TanØ =}$ $\sf\dfrac{slope\:of\:y}{slope\:of\:x}$= $\sf\dfrac{20}{8}$ $\sf{m/s^2}$

$\space$

$\space$

$\sf\bold{Now,calculate\:the\:distance:}$

$\space$

$\sf\bold{Given\:parameters:}$

$\space$

$\sf\bold{Substituting \: the\:values:}$

$\mapsto$ $\sf\small{s=0+}$ $\sf\dfrac{1}{2}$ $\times$ $\sf\dfrac{5}{8}$ $\sf\small{8^2}$

$\space$

$\longmapsto$ $\sf\underline\bold\purple{S=80m}$

$\space$

❍Therefore , the acceleration is $\sf\bold{2.5m/s^2}$ and the distance traveled by car is $\sf\bold{80m.}$

_______________________________

80 m is distance ! Please mark as brainliest

Answer:

17) The answer is option B. 273.8 m^2

16) The answer is option A. 2.9887

Step-by-step explanation:

Answer:

If you add a picture I can help

Step-by-step explanation:

I need to see what the figure looks like

Answer:

Eldrick can use both of these samples to find the mean frequency of each duck.

Step-by-step explanation:

Given

See attachment for samples

Required

Determine which is true

Reading through the options, we can see that Eldrick needs to evaluate the mean frequency of both samples.

To do this, both samples have to be put into consideration in order to arrive at the right value.

Considering the options, we can conclude that (a) is correct.

Answer:

B

Step-by-step explanation:

the answer is B cause I did A and it was wrong trust me, and have a good day

consindering the equation ""yvariable m is the intercept ,,c constant

therefore from the equation by comparing...=mx+c where y

Complete question is;

An online store receives customer satisfaction ratings between 0 and 100, inclusive. In the first 10 ratings the store received, the average (arithmetic mean) of the ratings was 75. What is the least value the store can receive for the 11th rating and still be able to have an average of at least 85 for the first 20 ratings?

Answer:

50

Step-by-step explanation:

We are told that In the first 10 ratings the store received arithmetic mean of the ratings = 75.

Thus;

Sum of the first 10 ratings = 75 × 10 = 750

Now, for the mean of the first 20 ratings to be at least 85, it means that the sum of the first 20 ratings would be; 85 × 20 = 1700

Thus, the sum of the next 10 ratings would be; 1700 − 750 = 950.

If maximum rating = 100, then the maximum possible value of the sum of the 12th to 20th ratings is given by;

9 × 100 = 900.

Now, in order to make the store have an average of at least 85 for the first 20 ratings, the least value for the 11th rating is;

950 − 900 = 50

Answer:

90 I guess so

It might be wrong

Answer:

C and A

Step-by-step explanation:

C and A are correct answers

Answer:

First, find the function of the line:

Therefore, the function is [tex]y=\frac{3}{4} x[/tex].

Since it's the area under the graph that's shaded(not ≥ or >) and the graphed line is dotted(not ≤ or ≥), then the inequality would be [tex]y<\frac{3}{4} x[/tex].

Area = Side^2

Area =( 4x + 2 )^2

Area = (4x)^2 + 2(4x)(2) + (2)^2

Area = 16x^2 + 16x + 4

Thus the correct answer is option B .

Answer:

18.9

Step-by-step explanation:

if 200miles = 9gallons

then 420miles = ?

note:if more less divide and if less more divide.

so it is 420/200×9=18.9

Answer:

shift the graph up 1 unit

Step-by-step explanation:

d is the vertical shift

+1 means we shift the graph up 1 unit

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

Short answer: to solve this problem, follow directions.

Let c and p represent numbers of cakes and pies produced daily. Then the constraints are ...

  2c +3p ≤ 108 . . . . . . . . available hours of preparation time

  1c +0.5p ≤ 20 . . . . . . . available hours of decoration time

  p ≥ 0, c ≥ 0 . . . . . . . . . negative numbers of cakes or pies cannot be produced

__

It works well to let a graphing calculator do this.

The feasible region is the doubly-shaded area with vertices ...

  (0, 0), (0, 36), (3, 34), (20, 0)

__

Profit is $25 per cake and $12 per pie, so is ...

  p = 25c +12p

__

The attached table shows the profit for the various mixes of cakes and pies in the feasible region. The most profit is had by production of cakes only.

The maximum profit is $500 per day for production of 20 cakes.

_____

Additional comment

We have used x for cakes and y for pies in the attachment, because those are variables that the Desmos calculator prefers.

As is sometimes the case, the production point giving maximum profit leaves one of the resources (preparation time) only partially utilized.