Which experiment led to the idea that atoms contained a nucleus?
O A. Niels Bohr's photoelectric effect experiment
O B. Ernest Rutherford's gold foil experiment
O C. J. J. Thomson's cathode ray experiment
O D. Robert Millikan's oil drop experiment

Answer:Conductors and insulators are both important in the field of electronics. Electrical conductors allow electric current to flow easily because of the make up of their atoms. In a conductor, the outer electrons of the atom are loosely bound and can freely move through the material when an electric charge is applied.

Explanation:hope its help

Answer:

C 100% correct. trust me

Explanation:

Only when the given temperature and the other physical variables remain constant does Ohm's law apply. Increasing the current causes the temperature to rise in some components. Here the voltage is 110 V and the current is 240, so the resistance can be measured. The correct option is C.

The relationship between electric current and potential difference is stated by Ohm's law. Under the assumption that all physical parameters and temperatures remain constant, Ohm's law asserts that the voltage across a conductor is directly proportional to the current flowing through it.

Most conductors' current is directly proportional to the voltage applied to them. German physicist Georg Simon Ohm was the first to empirically confirm Ohm's law. Ohm's law is one of the most fundamental and significant principles governing electrical circuits.

The equation is V = IR, 'R' is the resistance and 'I' is the current and 'V' is the voltage.

Thus the correct option is C.

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5.76 g of [tex]O_2[/tex] are consumed when [tex]C_6H_1_2[/tex] is burned to yield 5.3 grams of [tex]CO_2[/tex].

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others.

Calculating moles of [tex]CO_2[/tex]

Number of mole of [tex]CO_2[/tex] = [tex]\frac{\;Given \;mass}{\;Molar \;mass}[/tex]

[tex]\frac{\;Given \;mass}{\;Molar \;mass}[/tex] = [tex]\frac{5.3g}{44 g/mol}[/tex] = 0.12 mol

As is clear from the reaction stoichiometry, 9 moles of [tex]O_2[/tex]6 moles of [tex]CO_2[/tex].

Calculating the number of moles of [tex]CO_2[/tex]

[tex]\frac{0.12 X 9}{6}[/tex] = 0.18 mol

Mass of [tex]O_2[/tex] =5.76 g

Hence, 5.76 g of [tex]O_2[/tex] are consumed when [tex]C_6H_1_2[/tex] yield 5.3 grams of [tex]CO_2[/tex].

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Answer:

Cause the size of the moon is what determines how long it takes so that means the moon is small

Explanation:

Answer:

70.1 mL

Explanation:

First let's look at the formula for magnesium nitrate, and get the molar mass, we should end up with Mg(NO3)2 for the formula and this should have a molar mass of 148.3 g/mol.

Lets get the number of moles of the magnesium by taking the number of grams over the molar mass, (21.94 g)/(148.3 g/mol). grams cancel and we're left with approximately 0.148 moles.

Now let's plug our numbers into the molarity formula, M = n/L, this should give us 2.11 mol/L = (0.148 mol)/L, now let's solve for L, divide both sides by 0.148 which will give us 14.26 L^-1 = 1/L now we take the inverse of both sides to get 0.07012 L = L.

Now we have the liters, but the question askes for milliliters, so let's multiply by 1000, and then after rounding to sig figs we will get 70.1 mL as our answer. (Note: I used the exact values instead of the approximations throughout this explanation, so if you calculate the answer by plugging in these values, it might be slightly off.)

Answer:

17.92L or 17.92dm³1

Explanation:

number of moles of a gas = volume of that gas/ 22.4(S.V.P)

0.8 mol = x / 22.4

cross multiplication

x = 22.4 × 0.8

x = 17.92

:. the volume of 0.8 mol of nitrogen gas is 17.92dm³ or 17.92L

Answer:

= 6.21x10^21

Explanation:

It's the train track method, where you try to cancel all the units and end with units that you need. Here we want to end with number of atoms of N.

500 mg N x 1 g N/1000 mg N x 1 mol N/194.19 g N x 4 mol N/1 mol of caffeine x (6.022 x 10^23 particles of N / 1 mol N)

= 6.21x10^21

Answer:

Unbalanced: SiO2 + HF = SiF4 + H2O

Explanation:

Unbalanced: SiO2 + HF = SiF4 + H2O

Answer:

SiO2 + HF = SiF4 + H2O

Answer:

reactants are hydrogyn and oxygen, the product is water

Explanation:

Reactants are what start the reaction, they are joined together making a reaction that can result in a mix of both or a really new product. The product is, as named, the product of the reactants reaction, it is the outcome. In this case, hydrogen and oxygen join together, making a reaction that ended up with water(the product).

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5.76 g of [tex]O_2[/tex] are consumed when [tex]C_6H_1_2[/tex] is burned to yield 5.3 grams of [tex]CO_2[/tex].

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others.

Calculating moles of [tex]CO_2[/tex]

Number of mole of [tex]CO_2[/tex] = [tex]\frac{\;Given \;mass}{\;Molar \;mass}[/tex]

[tex]\frac{\;Given \;mass}{\;Molar \;mass}[/tex] = [tex]\frac{5.3g}{44 g/mol}[/tex] = 0.12 mol

As is clear from the reaction stoichiometry, 9 moles of [tex]O_2[/tex] are consumed to yield 6 moles of [tex]CO_2[/tex].

Calculating the number of moles of [tex]CO_2[/tex]

[tex]\frac{0.12 X 9}{6}[/tex] = 0.18 mol

Mass of [tex]O_2[/tex] consumed is = 0.18 X 32.0 =2.7 g =5.76 g

Hence, 5.76 g of [tex]O_2[/tex] are consumed when [tex]C_6H_1_2[/tex] is burned to yield 5.3 grams of [tex]CO_2[/tex].

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Answer:

sp³ hybridization

Explanation:

Formula to calculate hybridization :

H = 1/2 × [V + U - C + A]

Solving :

⇒ H = 1/2 × [5 - 0 - 0 + 3]

⇒ H = 1/2 × 8

⇒ H = 4

⇒ The molecule has sp³ hybridization

Answer:

As metals are giant lattice structures, the number of electrostatic forces to be broken is extremely large

Explanation:

This means that the melting point and boiling point of metals are more similar to those for ionic compounds than for covalent substances.

Answer:

0.72 grams

Explanation:

Answer:

-1  

Explanation:

Neutrons have no charge

Protons = +

Electrons = -

16 - 17 = -1

Answer:

2 M

Explanation:

mole weight of CaBr2 = 40 + 2 * 79.9 = 199.8 gm

20 gm is then   20/199.8 =.1 mole

.1 mole / .50 liter = 2 M

The percent yield of methane is 85.5%.

The percent yield of a reaction is the ratio of the actual yield and the expected yield expressed as a percentage.

Equation of reaction is given below:

1 mole of methane produces 2 moles of water

16 g of methane produces 36 grams of water

52 g of methane will produce 117 g of water

Percent yield = 100/117 × 100% = 85.5%

Therefore, the percent yield of methane is 85.5%.

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Answer:

0.24mol/L

Explanation:

The molarity of a solution is also its Concentration (C)

C = [tex]\frac{Moles(n)}{Volume (V)}[/tex]

mass of CaF = 55.43g

volume = 3.87L

Molar mass of CaF = 58.99g/mol

moles = [tex]\frac{55.43g}{58.99g/mol}[/tex]

          =0.94mol

∴ Concentration = [tex]\frac{0.94mol}{3.87L}[/tex]

                             = 0.24mol/L

Answer:

The vapor pressure of the pure solvent will be equal to 55.7 mmHg.

You're dealing with a solution of sucrose, which is your solute, dissolved in ethanol, which is your solvent.

Since sucrose is a non-volatile solute, the vapor pressure of the solution can be expressed using the mole fraction of the solvent - this is known as Raoult's Law.

P

solution

=

χ

solvent

⋅

P

∘

solvent

, where

P

solution

- the vapor pressure of the solution;

χ

solvent

- the mole fraction of the solvent;

P

∘

solvent

- the vapor pressure of the pure solvent.

The mole fraction of the solvent is defined as the number of moles of ethanol divided by the total number of moles present in the solution.

Use sucrose and ethanol's respective molar masses to determine how many moles of each you have

10.0

g

⋅

1 mole sucrose

342.3

g

=

0.0292 moles sucrose

and

100.0

g

⋅

1 mole ethanol

46.07

g

=

2.171 moles ethanol

The total number of moles will be

n

total

=

0.0292

+

2.171

=

2.20 moles

The vapor pressure of the pure solvent will thus be

P

∘

solvent

=

P

solution

χ

solvent

P

∘

solvent

=

55.0 mmHg

2.171

moles

2.20

moles

=

55.7 mmHg

Explanation:

Answer:

0.07

Explanation:

to find mole you divide mass by the relative atomic mass

Now you find the relative atomic of of moles pf he number sodium sulfide

then you thequation for finding moles to find mole of sodium

The following steps can be taken

Answer:

29.25g

Explanation:

m=0.5×(23+35.5)

Answer:

29.25 g

Explanation:

[tex]mole = \dfrac{mass}{molar \: mass}[/tex]

mass = 0.5 × 58.5 [ 23 + 35.5]

= 29.25 gm

Answer:

12

Explanation:

The coefficient of the CO2 shows the amount of CO2 needed in the reaction so to react with 11 water, 12 molecules of carbon dioxide is needed.

Dalton's Law

P tot = P H₂O + P gas

769 = 23.8 + P gas

P gas = 745.2 torr

Molarity (M) = Moles of Solute (mol) / Liters of Solution (L)

List Known Quantities into Above Equation

A. Molarity of Glucose Solution = 0.4 M

B. Liters of Glucose Solution = 0.5 L

Substitute Known Quantities into Above Equation

A. 0.4 M = x mol / 0.5 L

Solve for unknown value "x"

A. 0.5 * 0.4 = x

B. x = 0.2 mol of Glucose in the Solution

Answer:

C₄H₁₀ + O₂ --> CO₂ + H₂O

Explanation:

The other reactant is stated below the reaction, which is oxygen.

Oxygen is a diatomic element meaning there are usually 2 bonded oxygens. O is incorrect since oxygen is never found as a single atom.

The products are stated below the question. The products are:

- Carbon dioxide

- Water

The chemical formula for carbon dioxide is CO₂

The chemical formula for water is H₂O

Both of the above formulas are very common and are widely known.

Due to its higher oxygen content and based on its structure dietheylene glycol has a higher energy efficiency (cal/g) compared to isopropanol and paraffin wax.

The calorific value of a fuel is the amount of heat energy released from the combustion of the fuel under standard conditions.

Dietheylene glycol, isopropanol and paraffin wax are all used as fuels.

However, due to it higher oxygen content and based on its structure, diethethylene glycol has a higher calorific value than either isopropanol or paraffin wax.

Therefore, dietheylene glycol has a higher energy efficiency (cal/g) compared to isopropanol and paraffin wax.

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