Answer:
A. Its temperature is uniform.
Explanation:
Cosmic Microwave Background radiation is a remnant of the Big Bang talks about the universe being very hot thereby causing its expansion with a corresponding cooling of the gases within it. The Cosmic Microwave Background radiation being what is left of the radiation after the Big Bang occurrence.
The temperature was uniform with very little fluctuations which makes the A the right choice.
Answer:
a
Explanation:
1. An electric iron has a
power rating of 750W
a. How many joules of
electric energy does it
change into heat energy
every second?
b. How many joules of
work can it do in 3
seconds
c. How long does it take
the iron to do 1500J of
work?
2. Use the kinetic particle
theory to explain why a
solid has a definite shape
and liquid has none.
Explanation:
a) E = P × t
E = 750 × 1 s = 750 J
b) E = P × t
E = 750 × 3s = 2250 J
c) E = P × t
1500 = 750 × t
t = 1500/750
t = 2 s
Lilly is doing a science experiment with a substance in a sealed jar. At first the substances molecules are moving around each other. What will happen to Lily substance if she transfers energy into the substance and causes a face change? after the phase change, the substance molecules will move...
Explanation:
faster and the substance will be a gas.
According to the forces of attraction and principles of phase change the substance molecules will move faster and the substance will be a gas.
What are forces of attraction?Forces of attraction is a force by which atoms in a molecule combine. it is basically an attractive force in nature. It can act between an ion and an atom as well.It varies for different states of matter that is solids, liquids and gases.
The forces of attraction are maximum in solids as the molecules present in solid are tightly held while it is minimum in gases as the molecules are far apart . The forces of attraction in liquids is intermediate of solids and gases.
The physical properties such as melting point, boiling point, density are all dependent on forces of attraction which exists in the substances.
Learn more about forces of attraction,here:
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which of the following statements is/are true for a 0.10 m solution of a strong acid (HA)?
The question is incomplete; the complete question is;
Which of the following statements is/are true for a 0.10 M solution of a weak acid HA?
a. [ H+] >> [ A−]
b. [ H+] = [ A−]
c. The pH is 1.00.
d. The pH is less than 1.00.
Answer:
b. [ H+] = [ A−]
Explanation:
Given the acid as HA, we know that being a weak acid, its dissociation in water can never be 100%. If it were a strong acid, then it could have undergone a 100% dissociation in solution. The conjugate base of a weak acid is a always a weak base hence A^- is expected to act as a weak base. At the same concentration, weak acids have a higher pH value than strong acids. Hence if the pH of a strong acid HA is 1, then the pH of a weak acid HA must be greater than 1.
But, we look at the equation for the dissociation of the weak acid HA
HA(aq)⇄H^-(aq) + A^-(aq). This implies that the HA dissociates in a 1:1 ratio therefore; [H+] = [ A−], hence the answer given above.
Consider the following reaction where Kc = 77.5 at 600 K: CO(g) + Cl2(g) COCl2(g) A reaction mixture was found to contain 4.24×10-2 moles of CO(g), 4.48×10-2 moles of Cl2(g) and 0.114 moles of COCl2(g), in a 1.00 Liter container. Indicate True (T) or False (F) for each of the following: T 1. In order to reach equilibrium COCl2(g) must be produced. T 2. In order to reach equilibrium Kc must decrease. T 3. In order to reach equilibrium CO must be produced. F 4. Qc is greater than Kc. F 5. The reaction is at equilibrium. No further reaction will occur.
Answer:
The reaction mentioned in the question is:
CO (g) + Cl₂ (g) ⇔ COCl₂ (g), the equilibrium constant or Kc will be 77.5 at 600 K. In the given mixture, the moles of CO given is 4.24 × 10⁻² moles, the moles of Cl₂ given is 4.48 × 10⁻² moles, and the moles of COCl₂ given is 0.114 moles. The volume of the container is 1.00 L.
The concentration or Molarity can be determined by using the formula, concentration (M) = mole/volume (L),
The molarity of CO = 4.24 × 10⁻² moles / 1.00 L = 4.24 × 10⁻² M
The molarity of Cl₂ = 4.48 × 10⁻² moles / 1.00 L = 4.48 10⁻² M
The molarity of COCl₂ = 0.114 moles / 1.00 L = 0.114 M
The reaction quotient or Qc,
Qc = [COCl2]/[CO][Cl2]
Qc = 0.114 / 4.24 × 10⁻² × 4.48 × 10⁻²
Qc = 60.03
Thus, Qc is less than Kc. Hence, the reaction will proceed in forward direction so that equilibrium can be attained, that is, until Qc becomes equal to Kc.
Therefore, the product (COCl₂) will be produced, and the reactants CO and Cl₂ will get consumed.
1. The given statement is true.
2. The given statement is true.
3. The given statement is false. In order to reach equilibrium, the reactants must be consumed.
4. The given statement is true.
5. The given statement is false, that is Qc is not equal to Kc.
The catalyst used in the industrial production of ammonia: Select the correct answer below: A. enables equilibrium to be reached more quickly B. increases the equilibrium constant C. shifts the equilibrium of the reaction to favor the products D. none of the above
Answer: A. enables equilibrium to be reached more quickly..
Explanation:
The catalyst can be define as an important ingredient may be a protein in the form of enzyme that is used to speed up the rate of the chemical reaction. The catalyst cause a transformational change in the substrate to produce product. The catalyst do not get consumed in the reaction. In the availability of the catalyst, the forward and reverse rates of the reactions will speed up this will allow the equilibrium to reach faster.
A solution of a compound in ethanol shows an absorbance of 0.58 at 236 nm in a cell with a 1-cm light path. Its molar absorptivity in ethanol at that wavelength is 12,600 M−1cm−1. What is the concentration of the compound? Express your answer to two significant figures and include the appropriate units.
Answer:
C = 4.60x10⁻⁵ M
Explanation:
The concentration of the compound can be calculated using Beer-Lambert Law:
[tex]A = \epsilon*C*l[/tex]
Where:
A: is the absorbance of the ethanol = 0.58
ε: is the molar absorptivity of the ethanol = 12600 M⁻¹cm⁻¹
C: is the concentration of the compound =?
l: is the optical path length = 1 cm
Hence, the concentration of the compound is:
[tex]C = \frac{A}{\epsilon*l} = \frac{0.58}{12600 M^{-1}cm^{-1}*1 cm} = 4.60 \cdot 10^{-5} M[/tex]
Therefore, the concentration of the compound is 4.60x10⁻⁵ M.
I hope it helps you!
According to collision theory, what three factors govern the effect of temperature on the rate of a chemical reaction?
Answer:
Collision theory states that the rate constant for a chemical reaction is composed
of three factors, (1) the absolute number of collisions, Z, between molecules; (2) The
fraction of collisions, f, with an energy greater than the activation energy; and (3) the
fraction of molecules, p, in which the molecules are in the correct orientation to react.
k = Zfp Equation 1
The absolute number of collisions, Z, increases with temperature. However, it has
been shown that at 25o
C, the increase in the number of collisions accompanying a 10o
C
increase in temperature accounts for only about 2% of the increase in the reaction rate.
Similarly, while it is important that molecules be in the proper orientation to react when
they collide, molecular orientation is independent of temperature. Thus it follows that the
major factor controlling reaction rates is the fraction, f, of molecules in the reaction
mixture with an energy greater than the activation energy. This factor, f, depends on the
absolute temperature. It has been shown that f is related to Ea by the following equation
Explanation:
The reaction that takes place in a hydrogen-oxygen fuel cell is
2H2(g)+O2(g)⟶2?
Select the major product of the reaction and determine whether the reaction is exothermic or endothermic.
H2O2 , endothermic
H2O2 , exothermic
H2O , endothermic
H2O , exothermic
Answer:
H20; exothermic
Explanation:
A fuel cell is a device that converts chemical potential energy (energy stored in molecular bonds) into electrical energy. A PEM (Proton Exchange Membrane) cell uses hydrogen gas (H2) and oxygen gas (O2) as fuel. The products of the reaction in the cell are water, electricity, and heat.
OH- (aq) + HCO3- (aq) --- H2O (l) + CO32-(aq)
If OH is considered base 1, the right conjugates are..
Answer: The right conjugate of [tex]OH^-[/tex] is [tex]H_2O[/tex]
Explanation:
According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.
For the given chemical equation:
[tex]OH^-(aq)+HCO_3^-(aq)\rightleftharpoons H_2O(l)+CO_3^{2-}(aq)[/tex]
Here, [tex]OH^-[/tex] is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms [tex]H_2O[/tex] which is a conjugate acid.
Thus the right conjugate of [tex]OH^-[/tex] is [tex]H_2O[/tex]
Juan works as a tutor for $7 an hour and as a waiter for $14 an hour. This month, he worked a combined total of 103 hours at his two jobs. Let be the number of hours Juan worked as a tutor this month. Write an expression for the combined total dollar amount he earned this month.
Answer:
An expression for the combined total dollar amount he earned this month is $(7x + 14y) where x + y = 103.
Explanation:
Let the no. of hours worked as tutor be x
Earning as tutor in 1 hour = $7
Earning as tutor in x hour = $7*x = $7x
Let the no. of hours worked as waiter be y
Earning as waiter in 1 hour = $14
Earning as waiter in y hour = $14*y = $14y
Given that total hours worked in the month = 103 hours
therefore, x + y = 103 ----> (1)
Total amount earned in the month = Earning as tutor in x hour + Earning as waiter in y hour = $(7x + 14y)
An expression for the combined total dollar amount he earned this month is $(7x + 14y) where x + y = 103.
17. Consider the reaction shown and identify the statement that is not true.
825°C
CaCO3(s)
+ CaO(s) + CO2(g)
a.
This reaction is balanced as written.
b. The reactant must be heated for this reaction to occur.
c. The products are a solid and a gas.
d. Water must be present for this reaction to occur.
There are no solutions used in this reaction.
e.
Answer: Water must be present for this reaction to occur.
Explanation:
Decomposition reactions require breaking of bonds which require energy and thus all of the decomposition reactions are endothermic reactions.
The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) whereas liquids are represented by (l) and gases are represented by (g) after their chemical formulas.
The balanced chemical reaction of [tex]CaCO_3[/tex] decomposition is:
[tex]CaCO_3(s)\rightarrow CaO(s)+CO_2(g)[/tex]
The decomposition of [tex]CaCO_3[/tex] requires heat and leads to formation of CaO as solid and [tex]CO_2[/tex] as product.
Thus the the statement that is not true is Water must be present for this reaction to occur.
An iceberg has a volume of 0.1642 ML. What is the mass of the ice(in kg) composing the iceberg( at 0o C)? The density of ice at 0o C is 0.917g/cm^3
Answer:
1.5x10¯⁴Kg
Explanation:
Data obtained from the question include the following:
Volume = 0.1642mL = 0.1642cm³
Density = 0.917g/cm³
Mass =.?
The Density of a substance is simply defined as the mass per unit volume of the substance. Mathematically, it is represented as:
Density = Mass /volume
With the above formula, we can calculate the mass of the ice as follow:
0.917 = Mass / 0.1642
Cross multiply
Mass = 0.917 x 0.1642
Mass = 0.151g
Finally, we shall convert 0.1506g to kg. This is illustrated below:
1000g = 1k
Therefore, 0.151g = 0.151/1000 = 1.5x10¯⁴Kg
Calculate the mean free path of electrons in a metal, such as silver, at room temperature form heat capacity and heat conduction measurements. Take EF ¼ 5 eV, K ¼ 4:29 102 J/s m K, and Cel v ¼ 1% of the lattice heat capacity. (Hint: Remember that the heat capacity in (21.8) is given per unit volume!)
Answer:
= 4 * 10-8 = 400 Angstrom
Explanation:
EF = 5 eV, K = 4.29 x 102 J/(s m K), and Cvel = 1% of the lattice heat capacity
K= 1/3 (Cv)*v*l
v is fermi velocity which is equal to [tex]v = (2E_f/m)^{0.5}[/tex]
after putting mass of electron as [tex]9.1 * 10^{-31}kg[/tex] and [tex]E_f = 5 eV[/tex] we get [tex]v= 1.33 * 10^6 m/s[/tex]
[tex]C_v[/tex] is 1% of lattice heat capacity
Heat Capacity of Aluminium is [tex]0.897 J g^{-1}K^-1[/tex]
Density = [tex]2.6989 g \ cm^{-3}[/tex]
For lattice heat capacity you need to use the heat capacity for alimunium given and then multiply with density to get per unit volume term
Heat Capacity per unit volume = [tex]0.897 J g^{-1}K^-1[/tex] * [tex]2.6989 g \ cm^{-3}[/tex]
[tex]= 2.42 J K^{-1} cm^{-3} \\\\= 2.42* 10^6 J K^{-1} m^{-3}[/tex]
Cv = 1% of heat capacity per unit volume
[tex]=0.01 * 2.42* 10^8 J K^{-1} m^{-3} \\\\= 2.42* 10^4 J K^{-1} m^{-3}[/tex]
Putting values in this equation K= 1/3 (Cv)*v*l
[tex]l = 3K/(C_v * v )\\\\ = 3 * 4.29 * 10^2 / (2.42* 10^4 * 1.33 * 10^6 )[/tex]
[tex]= 4 * 10^{-8 }[/tex]
= 400 Angstrom
Solve: Turn off Show summary. Use the Choose reaction drop down menu to see other equations, and balance them. Check your answers and then write the balanced equations.
__Al+ __HCl→ __AlCl3+ __H2
__NaCl → __Na + __Cl2
__Na2S+__HCl→__NaCl+ __H2S
Please help!!
Answer: See below
Explanation:
To balance equations, you want to have the same amount of elements on the product and reactants side.
__Al+ __HCl→__AlCl₃+ __H₂
We see that there are 3 Cl on the products side and 1 on the reactants side, but there are 2 H on the product and 1 on reactant. To fulfill them both, let's put a 6 at HCl.
__Al+ 6HCl→__AlCl₃+ __H₂
Now that we have a 6 at HCl, we can fill in AlCl₃ and H₂.
__Al+ 6HCl→ 2AlCl₃+ 3H₂
All we have left is to fill in Al.
2Al+ 6HCl→ 2AlCl₃+ 3H₂
-----------------------------------------------------------------------------------------------------------------
__NaCl→ __Na+ __Cl₂
Since we have 2 Cl on the products, we must put 2 on the reactants.
2NaCl→ __Na+ 1Cl₂
With 2 NaCl, we can fill in Na.
2NaCl→ 2Na+ 1Cl₂
-----------------------------------------------------------------------------------------------------------------
__Na₂S+ __HCl→ __NaCl+ __H₂S
We see 2 Na on reactants, so we can put 2 on the products.
__Na₂S+ __HCl→ 2NaCl+ __H₂S
With 2 H and 2 Cl on the products, we can put a 2 at HCl.
1Na₂S+ 2HCl→ 2NaCl+ 1H₂S
Decreasing order of C-C bond length is 1) ethene 2)ethyne 3) benzene 4) ethane
Answer:
4>3>1>2.
That is, the C-C bond length in ethane > benzene > ethene > ethyne.
Explanation:
The C-C bond in ethane is single, the C-C bond in ethene is double and the C-C bond in ethyne is triple. As the number of bonds between a C-C increases, the length of the bond decreases with an increase in strength. This explains why the C-C bond length in ethane > ethene > ethyne. For benzene, all the C-C bonds in the aromatic compound has been found to have an identical length of 1.40 Å, compared to ethane (1.54Å), ethene (1.34Å) and ethyne (1.20Å). Hence the trend in bond lengths: ethane > benzene > ethene > ethyne.
Consider a sample of 3.5 mol of N2(g) at T1 = 350 K, that undergoes a reversible and adiabatic change in pressure from p1 = 1.50 bar to p2 = 0.25 bar. Assume that N2(g) under such conditions can be considered an ideal gas with CV,m = 3 R.
A) What is the final temperature T2 of the gas?B) What is ∆U for the gas in the process?C) What are q and w exchanged by the system in the process?D) What is ∆H for the gas in the process?E) What is ∆S for the gas in the process?F) What is ∆Suni for the universe in the process?
Answer:
Part A is just T2 = 58.3 K
Part B ∆U = 10967.6 x C[tex]_{V}[/tex] You can work out C[tex]_{V}[/tex]
Part C
Part D
Part E
Part F
Explanation:
P = n (RT/V)
V = (nR/P) T
P1V1 = P2V2
P1/T1 = P2/T2
V1/T1 = V2/T2
P = Pressure(atm)
n = Moles
T = Temperature(K)
V = Volume(L)
R = 8.314 Joule or 0.08206 L·atm·mol−1·K−1.
bar = 0.986923 atm
N = 14g/mol
N2 Molar Mass 28g
n = 3.5 mol N2
T1 = 350K
P1 = 1.5 bar = 1.4803845 atm
P2 = 0.25 bar = 0.24673075 atm
Heat Capacity at Constant Volume
Q = nCVΔT
Polyatomic gas: CV = 3R
P = n (RT/V)
0.986923 atm x 1.5 = 3.5 mol x ((0.08206 L atm mol -1 K-1 x 350 K) / V))
V = (nR/P) T
V = ((3.5 mol x 0.08206 L atm mol -1 K-1)/(1.5 x 0.986923 atm) )x 350K
V = (0.28721/1.4803845) x 350
V = 0.194 x 350
V = 67.9036 L
So V1 = 67.9036 L
P1V1 = P2V2
1.4803845 atm x 67.9036 L = 0.24673075 x V2
100.52343693 = 0.24673075 x V2
V2 = P1V1/P2
V2 = 100.52343693/0.24673075
V2 = 407.4216 L
P1/T1 = P2/T2
1.4803845 atm / 350 K = 0.24673075 atm / T2
0.00422967 = 0.24673075 /T2
T2 = 0.24673075/0.00422967
T2 = 58.3 K
∆U= nC[tex]_{V}[/tex] ∆T
Polyatomic gas: C[tex]_{V}[/tex] = 3R
∆U= nC[tex]_{V}[/tex] ∆T
∆U= 28g x C[tex]_{V}[/tex] x (350K - 58.3K)
∆U = 28C[tex]_{V}[/tex] x 291.7
∆U = 10967.6 x C[tex]_{V}[/tex]
How many moles are in 87.62 grams of strontium?
Explanation:
it's one mole because the atomic mass is treated as molar mass and the atomic mass of strontium is 87.62 grams/mol
Determine the boiling point of a solution that contains 70.6 g of naphthalene (C10H8, molar mass = 128.16 g/mol) dissolved in 722 mL of benzene (d = 0.877 g/mL). Pure benzene has a boiling point of 80.1°C and a boiling point elevation constant of 2.53°C/m.
Answer:
Boiling point of the solution is 82.3°C
Explanation:
Boiling point elevation is defined as the increasing of a boiling point of a substance by the addition of a solute. The formula is:
ΔT = K×m×i
Where ΔT is change in temperature (Final T - 80.1°C), K is boiling point elevation constant (2.53°C/m), m is molality of the solution (moles of naphthalene / kg of benzene) and i is Van't Hoff factor (1 for Naphthalene)
Moles of 70.6g of naphthalene are:
70.6g × (1mol / 128.16g) = 0.5509 moles
Kg of 722mL of benzene are:
722mL × (0.877g / mL) × (1kg / 1000g) = 0.633kg of benzene
Replacing in boiling point elevation formula:
(T - 80.1°C) = 2.53°C/m×(0.5509mol / 0.633kg)×1
T - 80.1°C = 2.2°C
T = 80.1°C + 2.2°C
T = 82.3°C
Boiling point of the solution is 82.3°CThe boiling point of the solution is 82.21°C.
Number of moles of solute = 70.6 g/128.16 g/mol = 0.55 moles
Mass of solvent= density of solvent× volume of solvent
= 722 mL × 0.877 g/mL = 633.2 g or 0.6332 Kg
Molality of the solution = 0.55 moles/0.6332 Kg = 0.869 m
We know that;
ΔT = K m i
ΔT = Boiling point depression
K = Boiling point constant
m = molality of solution
i = Van't Hoff factor
ΔT = 2.53°C/m × 0.869 m × 1
ΔT = 2.2°C
Recall that;
ΔT = Boiling point of solution- Boiling point of pure solvent
Boiling point of solution = Boiling point of pure solvent + ΔT
Boiling point of solution = 80.1°C + 2.2°C
Boiling point of solution = 82.21°C
Learn more: https://brainly.com/question/2510654
what forms of technology are scientists using to study El Nino
Answer:
a network of buoys.
Explanation:
It is operated by noaa. The buoys transmit some of the data on a daily basis to NOAA through a satellite in space.
What formula would I use if I was given [OH-] and wanted to find POH?*
1 point
pH = -log[H+]
[H+]= 10^-pH
pOH = -log [OH-]
O [OH-] = 10^-POH
Answer:
pOH = -log[OH-]
Explanation:
Hello,
To calculate the pH or pOH of a substance, we relate it the negative logarithm of either the H+ or OH- concentration.
pOH is used to find the alkalinity of a solution my measuring the concentration of the hydroxide ion [OH-]. Solutions having a pOH value that is greater than 7 are said to be acidic while solutions with value less than 7 are alkaline.
pH = -log[H+]
While
pOH = -log[OH-]
Note: the pOH value of a solution depends on the concentration of the hydroxide ion in the solution.
354.5 g of chlorine gas (MW = 70.9 g/mol) is held in a vessel with a fixed volume of 70. L.
What is the pressure of the gas in atmospheres if it's temperature is 30.0°C?
___ atm
Answer:
1.77 atm
Explanation:
We have to check the values that gives the problem:
V= 70 L
mass =354.5 g
Molas weight= 70.9 g/mol
T=30 ºC
P= ?
We can find the moles of chlorine if we use the molar weight:
[tex]354.5g~\frac{1~mol}{70.9~g}[/tex]
[tex]5~mol[/tex]
Now, we have the moles, volume, temperature therefore we can use the ideal gas equation:
[tex]P*V=n*R*T[/tex]
We know the R value:
[tex]0.082\frac{atm*L}{mol*K}[/tex]
We have “K” units for the temperature, so we need to do the conversion:
[tex]30+273.15=303.15~K[/tex]
With all the data we can plug the values into the equation:
[tex]P*70L=5mol*303.15K*0.082\frac{atm*L}{mol*K} [/tex]
[tex]P=\frac{5mol*303.15K*0.082\frac{atm*L}{mol*K}}{70L}[/tex]
[tex]P=1.77~atm [/tex]
I hope it helps!
A boy reached his home by riding motorcycle within 5 minutes by travelling 8 km distance ,them what is his average velocity?
Answer:24 kilometers
Explanation:Density divided by time
–
Introduction to elapsed time
Ryan started a race at 7:08 AM and finished it at 7:46 AM.
How long did it take him?
A light wave has frequency of 4.5 * 10^19 Hz. How would this number appear on a scientific calculator? a. 4.E195 b. 19E4.5 c. 4.519E d. 4.5E19
Answer:
B
Explanation:
how genetic conditions are transmitted from one person to another
Answer:
there are 5 ways this could happen
Autosomal dominant inheritance: a child recieves a normal gene from one parent and a defective gene from the other parent.
can occur on any of the 22 non-sex chromosomes and have a 50% inheritence rate, gender is not a factor, and disorder differs with inheritance.
examples: Huntington's disease, neurofibromatosis, achondroplasia, familial hypercholesterolemia
Autosomal recessive inheritance: both parents carry the defective gene but they are not affected by the disorder.
there is a 25% chance of defective gene from both parents, a 50% chance of inheriting one gene to become a carrier, gender is not a factor in the pattern of the defective gene.
examples: Tay-Sachs disease, sickle cell anemia, cystic fibrosis, phenylketonuria (PKU)
X-linked (sex-linked) recessive inheritance: mother carries the affective gene on one of the two X chromosomes.
males inherite X chromosomes from their mothers and Y from their father; which gives the son a 50% chance of inheriting the disorder.
daughters have a 50% chance, but they are not affected by the disorder.
examples: Hemophilia A, Duchenne muscular dystrophy
X-linked Dominant: females are affected more so than males; more common for males if they are in the same generation if the mom is affected (because females have two X-chromosomes)
example: Hypophatemic rickets (Vitiamin Dresistant rickets, ornithine transcarbamylase deficiency.
Mitochondrial: can affect both males and femlaes, can only be passed by females due to all mitochondria of all children is from the mother, and can appear in every generation.
examples: Lebrer's hereditary optic neuropathy and Kearns-Sayre syndrome
Explanation:
Scientific notation is
Answer:
Scientific notation is a system in which quantities are too big or too tiny to compose in decimal form.
Key words:
1: Scientific
2: Quantities
3: Decimal
Please mark brainliest
Hope this helps.
Given that benzaldehyde is a meta- director, in the same Marvin editor draw all three resonance structures for the carbocation intermediate that results from STEP 2 in the electrophilic aromatic substitution reaction when benzaldehyde reacts with Br2 in the presence of FeBr3. If you do not remember the structure of the benzene derivative, consult the L3 complete lecture notes slides #21 - 24.
Answer:
The reaction of FeBr3/Br2 with benzaldehyde will yield a major product in which the -Br is attached to the benzaldehyde at the meta position.
Explanation:
In chemistry, resonance is a way of describing bonding in certain molecules or ions by the combination of several contributing structures into a resonance hybrid in valence bond theory. Resonance structures often explain the formation of certain major and minor products in organic chemistry reactions.
Aromatic aldehydes and ketones undergo electrophilic substitution reactions such as nitration, sulphonation and halogenation. Since the aldehydic group (-CHO) and ketonic group (-COR or -COAr) are electron-withdrawing, they are deactivating and m-directing.
In benzaldehyde, the ring becomes deactivated at ortho & para positions due to an electron withdrawing aldehyde group. Hence electrophilic substitution is favored at Meta position.
This implies that the reaction of FeBr3/Br2 with benzaldehyde will yield a major product in which the -Br is attached to the benzaldehyde at the meta position.
Classify each amino acid according to whether its side chain is predominantly protonated or deprotonated at a pHpH of 7.40.7.40. The pKapKa values of the Asp, His, and Lys side chains are 3.65, 6.00, and 10.53,3.65, 6.00, and 10.53, respectively.
Answer: His and Lys are deprotonated but Asp will be protonated.
Explanation:
As the pH is given as 7.4 and pK of His is given as 6.00. There will occur a positive charge on His when it's pH < pK therefore, it is neutral at the given pH.
As the pK value of Lys is 10.53 that is greater than the pH of 7.40. Therefore, charge on Lys is positive.
As the pK value of Asp is 3.65 which is less than the pH value of 7.40. Hence, Asp has a negative charge.
Therefore, we can conclude that His and Lys are deprotonated but Asp will be protonated.
What is the [H+] concentration of blood, given the ph is 2.5?
Answer:
0.00316
Explanation:
You have to use the following equation:
[tex]pH=-log[H^+][/tex]
You are given the pH and need to find the concentration of H+. Plug in the given components and solve.
[tex]2.5=-log[H^+]\\H^+ = 10^{-2.5}\\H^+=0.00316[/tex]
The concentration of H is 0.00316.
In addition to mass balance, oxidation-reduction reactions must be balanced such that the number of electrons lost in the oxidation equals the number of electrons gained in the reduction. This balancing can be done by two methods: the half-reaction method or the oxidation number method. The half-reaction method balances the electrons lost in the oxidation half-reaction with the electrons gained in the reduction half-reaction. In either method H2O(l), OH−(aq), and H+(aq) may be added to complete the mass balance. Which substances are used depends on the reaction conditions.
Answer:
OH−(aq), and H+(aq)
Explanation:
Redox reactions may occur in acidic or basic environments. Usually, if a reaction occurs in an acidic environment, hydrogen ions are shown as being part of the reaction system. For instance, in the reduction of the permanganate ion;
MnO4^-(aq) + 8H^+(aq) +5e-------> Mn^2+(aq) + 4H2O(l)
The appearance of hydrogen ion in the reaction equation implies that the process takes place under acidic reaction conditions.
For reactions that take place under basic conditions, the hydroxide ion is part of the reaction equation.
Hence hydrogen ion and hydroxide ion are included in redox reaction half equations depending on the conditions of the reaction whether acidic or basic.
