When something heats up, new energy is created, and when something cools down, energy is destroyed. agree disagree

Answer:

The correct answer is A

Explanation:

Endothermic is a reaction of which heat is provided to break down the reacted molecules

Answer:

I think the w/w% of this question is 10.

The w/w% of a solution that contains 10 grams of solute and 100 grams of solvent is 9.09%

Mass percentage is another name of w/w % or weight /weight % .

To determine the weight/weight % of a solution :

we divide the mass of solute by mass of the solution (solute and solvent together) and multiply by 100 to obtain per cent.

[tex]\dfrac{w}{w} \; \%\; =\;\rm\dfrac{mass \;of\; solute}{mass\; of \; solute\;+\;mass\;of\;solvent} \times 100[/tex]

It is given that , mass of solute = 10 grams and mass of solvent = 100 grams

So,

[tex]\dfrac{w}{w} \; \%\; =\;\rm\dfrac{10}{10+100} \times 100[/tex]

[tex]\dfrac{w}{w} \; \%\; =\;\rm\dfrac{10}{110} \times 100\\\\\dfrac{w}{w} \; \%\; =\;\rm\dfrac{100}{11}\\\\\dfrac{w}{w} \; \%\; =\; 9.09 \;\%[/tex]

The w/w% of a solution that contains 10 grams of solute and 100 grams of solvent is 9.09% .

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Answer:

See Explanation

Explanation:

The equation of the reaction is;

C7H16(g) + 11O2(g) ---->7CO2(g) + 8H2O(g)

1a) Number of moles in 228 g of H2O = 228 g/18 g/mol = 12.67 moles

From the reaction equation;

11 moles of O2 yields 8 moles of H2O

x moles of O2 yields 12.67 moles of H2O

x = 11 * 12.67/8

x = 17.4 moles of O2

Since 1 mole of O2 occupies 22.4 L

17.4 moles of O2 occupies 17.4 moles * 22.4 L/1 mole = 389.76 L

1b) Molar mass of C7H16 = 100 g/mol

Number of moles in 300 g of C7H16 = 300 g/100g/mol = 3 moles

1 mole of C7H16 yields 7 moles of CO2

3 moles of C7H16 yields 3 * 7/1 = 21 moles of CO2

If 1 mole of CO2 occupies 22.4 L

21 moles of CO2 occupies 21 moles * 22.4 L/1 mole = 470.4 L of CO2

2) Number of moles in 202 L of H2 is obtained by;

1 mole of H2 occupies 22.4 L

x moles of  H2 occupies 202 L

x = 1 mole * 202 L/22.4 L =  9 moles of H2

From the reaction equation;

3 moles of H2 yields 2 moles of PH3

9 moles of H2 will yield 9 * 2/3 = 6 moles of PH3

Mass of 6 moles of PH3 = 6 moles of PH3 * 34 g/mol = 204 g of PH3

Answer:

C Condensation of water vapor

Explanation:

One of the components of the atmosphere is water vapour. Water vapour is always present in air.

This water vapour may combine with particles of dust and smoke and condense around them to form clouds.

As more water vapour condenses and coalesces, the clouds become thicker and precipitation eventually follows.

Answer:

Sand has a melting point of 1550

Salt has a melting point of 1474

Copper Chloride has a melting point of 928.4

Sugar has a melting point of 366.8

Based on this information I am sure you can determine sugar has the lowest melting point

i) diffusion, concentration differences in gas and fluid disappears when particles of sugar are evenly spread in solution

ii)  Heating the solution, mixing the solution

b)  Distillation, solution is heated until water is vaporized and water vapour condenses in another part of apparatus.

Sugar is separated from water by evaporation of the sugar solution to dryness.

i) The process of that causes the sugar to spread throughout the water is called solvation.  Solvation simply refers to the interaction of a solute and a solvent.

ii) To make the sugar to dissolve quicker;

b)To obtain pure water from sugar, the sugar is evaporated to dryness. This is done by heating the sugar in a set up as shown in the image attached.

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Question :—

1. Calculate the mass percent of salt in salt water if 1 gram of salt is dissolved into 99 grams of water. Show the steps in your calculation.

Answer :—

Mas of common salt (solute)=1 g

Mas of common salt (solute)=1 Mass of water (soluted) =99 g

Mas of common salt (solute)=1 gMass of water (soluted) =99 gmass of solution =1+99 = 100

gconcentration of solution= mass of solution (M mass of solute) ×100 [tex] = > \frac{1}{100} \times 100[/tex]

=> 1% [/tex]Hence, the concentration of the solution is 1%

The  mass percent of salt in salt water if 1 gram of salt is dissolved into 99 grams of water is 1%.

The way of expressing a concentration is mass percent. Moreover, it describes the component in a particular mixture. The solution composition can be understood in a mass percentage. It shows the mass of solute present in a given mass of solution. The quantity of solute is expressed in mass or by moles.

The mass percent may be a way of expressing a degree. Moreover, it describes the component during a particular mixture. The solution composition is often described in mass percentage. It shows the mass of solute present during a given mass of solution. The number of solutes is expressed in mass or by moles.

Percentage of mass = (solute’s mass ÷ mass of solution) x 100%, substitution of values gives 1/100×100=1%.

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Answer:

the correct answer is option C