What things contribute to the amount of greenhouse gasses on Earth?

Answer:

CaCl2 and KI- ionic

PCl3 and CH4-dispersion forces

NH2OH- hydrogen bonding

Explanation:

Complete question

Physical properties such as melting point, boiling point, and solubility are all dependent on the type of interparticle forces a substance experiences. Identify the type of interparticle force that has the greatest influence on the physical properties for each substance. Cl2, NH2OH, PCl3, CH4, CaCl2, KI

Solution

Calcium and Potassium are metal and they form ionic bonds with the non metal such as CaCl2 and KI

PCl3 and CH4- have dispersion forces as their structural arrangement distribute electrons around any atom and molecule.

NH2OH- hydrogen bonding - Due to the presence of H and O atoms, there exists hydrogen bond with in this molecule.

Answer:

thank for the points ❤️

Explanation:

pa breinlyest po

Answer:

13.672

Explanation:

2 moles of OH in Ba(OH)₂

0.235 M × 2 mol OH = 0.47 M OH

pOH = -log[OH-] ; pOH = -log[0.47 M OH] ; 0.328 = pOH (consider significant figures)

14 - pOH = pH because pH + pOH = 14

14 - 0.328 = 13.672 [there are three decimal places after the OH concentration, so there should be in the answer as well - 13.672]

Answer:

A

Explanation:

hope this help sweetie <$

Answer:

194g of distilled water.

Explanation:

Hello there!

In this case, according to the given information for this problem, it turns out possible for us to use the given mass of the solution and the percent by mass of NaF to firstly calculate the grams of this solute as shown below:

[tex]\%m=\frac{m_{solute}}{m_{solution}} *100\%\\\\m_{solute}=\frac{\%m*m_{solution}}{100\%} \\\\m_{solute}=\frac{3.0\%*200.0g}{100\%} \\\\m_{solute}=6g[/tex]

And finally, since the mass of solution is calculated by adding mass of solute and mass of solvent we obtain the mass of water (solvent) as follows:

[tex]m_w=200g-6g=194g[/tex]

Therefore, the answer is 194g of distilled water

Regards!

Answer:0.104

Explanation:

Answer:

0.104

Explanation:

convert grams to moles “10.0 x 1/40”

divide moles by the liters 0.25/2.4

answer: 0.104

Answer:

https://www.clutchprep.com/chemistry/practice-problems/70217/hi-aq-h2o-l-h3o-aq-i-aq-identify-each-as-either-a-bronsted-lowry-acid-bronsted-l

Explanation:

https://www.clutchprep.com/chemistry/practice-problems/70217/hi-aq-h2o-l-h3o-aq-i-aq-identify-each-as-either-a-bronsted-lowry-acid-bronsted-l

Answer:

4

Explanation:

Applying,

pH = 14-pOH.................... Equation 1

But,

pOH = -log(OH⁻)

Where OH⁻ = Hydroxyl ion concentration of NaOH.

From the question,

Given: OH⁻ = (1×10⁻¹⁰) M

Substitute these values into equation 1

pH = 14-log((1×10⁻¹⁰)

pH = 14-10

pH = 4

Hence the pH of NaOH with a molarity of 1.0 x 10-10M = 4

CONJUGATE ACID

the acid's conjugate base because it can theoretically reform the acid by aaccepting a proton.

I hope this is correct >.<

Answer:

316.227766

Explanation:

Explanation:

thank you for the points

Answer: 6.01

Explanation:

Answer:

H2O2 reduces itself to H2O and also oxidizes to O2 simultaneously thereby acting both as an oxidizing and reducing agent .

Explanation:

When

H2O2 acts as an oxidizing agent

H2O2 + 2e- 2H+--->   2H2O

Reducing agent

H2O2 --> O2 + 2e + 2H+

H2O2 reduces itself to H2O and also oxidizes to O2 simultaneously thereby acting both as an oxidizing and reducing agent .

Answer:

C. 13.65.

Explanation:

With the given hydroxide ion concentration [OH⁻] we can calculate the pOH of the solution, using the following formula:

Then, with the pOH we can proceed to calculate the pH of the solution, with the formula:

The correct answer is option C. 13.65.

Answer:

Virus

Explanation:

Hope this helped :)

Answer:

This question is incomplete, however, it is asking to calculate the empirical formula of the compound.

The empirical formula is N2O3

Explanation:

The following information about a compound was got from the question:

N = 36.8%

O = 63.2%

It can be said that the compound contains 36.8g of nitrogen (N) and 63.2g of oxygen (O).

Next, we convert each mass composition to moles by dividing by their respective molar masses.

N = 36.8g ÷ 14g/mol = 2.628mol

O = 63.2g ÷ 16g/mol = 3.95mol

Next, we divide each mole value by the smallest value (2.628mol).

N = 2.628mol ÷ 2.628 = 1

O = 3.95mol ÷ 2.628 = 1.5

We multiply each value by 2 to get a empirical ratio.

N = 2

O = 3

The ratio of N:O is 2:3, hence, the empirical formula is N2O3.

From the given graph, it is clear that the element with highest mass ate a volume of 3 cm³is lead and that with least mass is aluminium.

Density of a substance is the measure of its mass per unit volume. Thus, mathematically it is the ratio of mass to the volume. Therefore, as the mass increases density also increase.

Density of an element depends on its mass, volume, temperature and pressure. In periodic table, from left to right density decreases whereas down a group density increases.

From the graph showing the mass-volume-density relation it is clear that the element with with higher mass at a particular volume is lead and the element with least mass among the group is aluminium. The density of these elements also showing the same trend.

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Answer:

There are 2 types of forces, contact forces and act at a distance force. Every day you are using forces. Force is basically push and pull. When you push and pull you are applying a force to an object.

Explanation:

Answer: Hello attached below is the complete question and using data from ALEKS data tab

answer:

PbCl₂ :  Yes , PH = 3

CaC0₃ : Yes, PH = 3

AgCn : Yes , PH = 3 .

Explanation:

For PbCl₂  

PbCl₂ solubility will change ( decrease )  with increase in PH, and the PH at which PbCl₂ will be most soluble is at PH = 3

For CaC0₃

Addition of -ions which increases the PH level will cause a decrease in the solubility of  CaC0₃ hence the PH at which it will be most soluble in an aqueous solution is PH = 3

For AgCn

Increase in the PH level there would be a decrease in the solubility of AgCn hence the PH at which AgCn is most soluble ( highest solubility ) = 3

The ability of a solute to be able to dissolve is called solubility. Yes, at pH 3, the solubility of lead chloride, calcium carbonate, and silver cyanide.

The ability of the solute to get dissolved in a solvent to form a saturated solution is called solubility.

For lead chloride, the solubility will decrease as the pH will increase and is most soluble at a pH of 3.

For calcium carbonate, the addition of ions increases the pH will result in a decreased solubility, and will be most soluble at pH 3.

For silver cyanide increased pH decreases the solubility and is most soluble at a pH of three.

Therefore, solubility decrease with an increase in pH due to the concentration factor.

Learn more about solubility here:

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Answer:

The starting substances of a chemical reaction are called the reactants, and the new substances that result are called the products.

Answer:

H⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + OH⁻(aq) → Na⁺(aq) + NO₃⁻(aq) + H₂O(l)

Explanation:

First, we will write the molecular equation for the neutralization reaction between nitric acid and sodium hydroxide.

HNO₃(aq) + NaOH(aq) → NaNO₃(aq) + H₂O(l)

The total ionic equation includes all the ions and the molecular species.

H⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + OH⁻(aq) → Na⁺(aq) + NO₃⁻(aq) + H₂O(l)

Answer:

An element is an ATOM or aggregate of atoms all of which have the same number of protons. In pure form, they will also have the same number of electrons. Each element has its own unique number of protons. For example, hydrogen always has one proton, helium always has two and lithium always has three.

Explanation:

Answer: 0.45

Explanation:

Answer:

105mL of 0.7500M of NaOH are required

Explanation:

Phosphoric acid, H₃PO₄, reacts with sodium hydroxide, NaOH, as follows:

H₃PO₄ + 3 NaOH → Na₃PO₄ + 3H₂O

Where 1 mole of phosphoric acid reacts with 3 moles of NaOH

To solve this question we must find, as first, the moles of H3PO4 that react. Using the chemical equation we can find the moles of NaOH required to neutralize this acid. And, with its concentration, we can find the volume oof NaOH required:

Moles H3PO4:

35.00mL = 0.03500L * (0.7500mol / L) = 0.2625 moles H3PO4

Moles NaOH:

0.2625 moles H3PO4 * (3mol NaOH / 1mol H3PO4) = 0.07875 moles NaOH

Volume NaOH:

0.07875 moles NaOH * (1L / 0.7500mol) = 0.105L =

The 3.13 g of K would be needed to completely react with the remaining [tex]Cl_2[/tex].

To determine which reactant is limiting, we need to calculate the amount of product that can be formed from each reactant and compare them. The reactant that produces less product is the limiting reactant, since the reaction cannot proceed further once it is consumed.

The balanced chemical equation for the reaction between solid potassium and chlorine gas is:

2 K(s) + [tex]Cl_2[/tex](g) -> 2 KCl(s)

From the equation, we can see that 2 moles of K react with 1 mole of [tex]Cl_2[/tex] to form 2 moles of KCl.

First, we need to convert the masses of K and [tex]Cl_2[/tex] into moles:

moles of K = 15.20 g / 39.10 g/mol = 0.388 mol

moles of [tex]Cl_2[/tex] = 2.830 g / 70.90 g/mol = 0.040 mol

Now, we can use the mole ratio from the balanced equation to calculate the theoretical yield of KCl from each reactant:

Theoretical yield of KCl from K: 0.388 mol K x (2 mol KCl / 2 mol K) = 0.388 mol KCl

Theoretical yield of KCl from [tex]Cl_2[/tex]: 0.040 mol [tex]Cl_2[/tex] x (2 mol KCl / 1 mol [tex]Cl_2[/tex]) = 0.080 mol KCl

We can see that the theoretical yield of KCl from K is 0.388 mol, while the theoretical yield of KCl from [tex]Cl_2[/tex] is 0.080 mol. Therefore, the limiting reactant is [tex]Cl_2[/tex], since it produces less product.

To determine how much more of the limiting reactant would be needed to completely consume the excess reactant, we can use the stoichiometry of the balanced equation.

We know that 1 mole of [tex]Cl_2[/tex] reacts with 2 moles of K to produce 2 moles of KCl. Therefore, the amount of additional K needed to react with the remaining [tex]Cl_2[/tex] can be calculated as follows:

moles of K needed = 0.040 mol [tex]Cl_2[/tex] x (2 mol K / 1 mol [tex]Cl_2[/tex])

                                = 0.080 mol K

This means that 0.080 moles of K would be needed to completely consume the remaining [tex]Cl_2[/tex]. We can convert this to a mass by multiplying by the molar mass of K:

mass of K needed = 0.080 mol K x 39.10 g/mol

                              = 3.13 g K

Therefore, The 3.13 g of K would be needed to completely react with the remaining.

Example verification:

Suppose we had an additional 0.50 g of [tex]Cl_2[/tex] in the reaction. Would all of the K be consumed, or would there still be excess K?

Moles of additional [tex]Cl_2[/tex] = mass of [tex]Cl_2[/tex] / molar mass of [tex]Cl_2[/tex]

Moles of additional [tex]Cl_2[/tex] = 0.50 g / 70.90 g/mol

Moles of additional [tex]Cl_2[/tex] = 0.0070 mol

The theoretical yield of KCl that can be formed from the additional [tex]Cl_2[/tex] is:

0.0070 mol [tex]Cl_2[/tex] x (2 mol KCl / 1 mol [tex]Cl_2[/tex]) x (74.55 g KCl / 1 mol KCl) = 1.04 g KCl

Therefore, the total amount of KCl that can be formed from all of the [tex]Cl_2[/tex] is:

5.95 g + 1.04 g = 6.99 g

The amount of K that would be needed to completely consume all of the [tex]Cl_2[/tex].

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Answer: The pressure is 1137.5 mm Hg its pressure if its volume is increased to 150 [tex]cm^{3}[/tex] at 35 °C

Explanation:

Given: [tex]P_{1}[/tex] = 750 mm Hg,    [tex]V_{1} = 130 cm^{3}[/tex],     [tex]T_{1} = 20^{o}C[/tex]

[tex]P_{2}[/tex] = ?,          [tex]V_{2} = 150 cm^{3}[/tex],            [tex]T_{2} = 35^{o}C[/tex]

Formula used to calculate the new pressure is as follows.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{750 mm Hg \times 130 cm^{3}}{20^{o}C} = \frac{P_{2} \times 150 cm^{3}}{35^{o}C}\\P_{2} = 1137.5 mm Hg[/tex]

Thus, we can conclude that the pressure is 1137.5 mm Hg its pressure if its volume is increased to 150 [tex]cm^{3}[/tex] at 35 °C.

Answer:

(a) 157.7 g

(b) 7.04 g/dm³

Explanation:

(a) From the question,

According to Avogadro's Law,

1 mole of every gas at STP occupies a volume of 22.4 dm³

But mass of 1 mole of the diatomic gas  = molar mass of the gas.

This Implies that,

The molar mass of the gas at STP occupies a volume of 22.4 dm³

From the question,

If,

0.25 L bottle contain 1.76 g of the gas,

Therefore,

Molar mass of the gas = (1.76×22.4)/0.25

Molar mass of the gas = 157.7 g.

(b) Density of the gas = mass/volume

D = m/v

Given: m = 1.76 g, v = 0.25 L = 0.25 dm³

Therefore,

D = 1.76/0,25

D = 7.04 g/dm³

Answer: The electron configuration of carbon atom is written as 1s²,2s², 2p².

Explanation:

The electronic configuration of an atom is defined as the arrangement of electrons into the shells or orbit of an atom. The constituents of an atom are proton, neutron and electron. the nucleus of an atom, where most of its mass are concentrated, consists of neutrons and protons fused together. Electrons occupy the shells surrounding the nucleus. The shells are lettered K, L, M, N and so on. Numerically, K shell is numbered 1, L is 2 and so on. These numbers also correspond with the increase in the energy level. All the electrons in K shell for instance belong to the first energy level and they have equal energy.

There is a limit to the number of electrons that can be found in a shell. This can be obtained by a formula 2n² where "n" is the energy level number of the shell.

K: 2n² = 2 × 1² = 2

L: 2n² = 2× 2² = 8

These shells are further subdivided into subshells. There are 4 subshells, s, p, d, and f. Each subshell can hold a different number of electrons.

This electron configuration of carbon can be written as 1s² 2s² 2p² where 1s, 2s, and 2p are the occupied subshells, and the superscript "2" is the number of electrons in each of these subshells.