What product is formed when each compound is treated with either LiAlH4 (followed by H2O), or NaBH4 in CH3OH

Answer:

B. Combustion .

Explanation:

Hello.

In this case, since this reaction is started by pentyne and oxygen which are converted to carbon dioxide and water, we can infer this is a combustion reaction because it involves the burnt of a fuel, in this case the pentyne, by using oxygen in order to yield carbon dioxide and water, which are smaller molecules than the original pentyne.

It is important to notice that these reactions are very exothermic because they go to break the C-H bonds in the fuel which release a considerably high amount of energy.

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Answer:

The moon orbits quite fast: it moves about 0.5 degrees per hour in the sky. In 24hrs it moves 13 degrees. the moons observed motion eastward results from its physical motion of the moon along its orbit around the earth

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Answer:

false

Explanation:

Answer:

20.3%

Explanation:

Given mass of impure ore = 896g and mass of pure iron to be 182g after purification,

[tex]\frac{(896-182)g}{896}[/tex] × 100

= 79.7%

in subtracting the weight of impure mass from that of the pure sample, we are left with the mass of the impurities alone.

This means the mass percent of pure iron in this iron ore sample is 20.3%.

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Answer:

Reaction product A is more likely to form in the epoxide ring-opening reaction

Explanation:

The diagram for the reaction can be seen in the image attached below.

An epoxide is any class of organic compound, cyclic ethers, having a three-membered ring; they are usually prepared by selective oxidation of alkenes or by ring-closure of halohydrins(any class of organic compound having a hydroxyl functional group and a halogen on neighboring carbon atom ) which are used in making plastic.

yes they decrease when the temperature drops so it's true

Answer:

The charges are typically used to determine the mole ratio and composition of the individual atoms of elements in the compound

Explanation:

Take for instance the following compounds:

[tex]NaOH[/tex] and [tex]H_{2} O[/tex]

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Answer:

1. Weigh 3.27 ×10⁻⁴ ng of NaOH  in a special balance for weighing in nanograms

2. Measure a volume of 650 mL in a test tube

3. Make the solution by mixture

Explanation:

NaOH is a strong base. As every strong base, can be completely dissociated:

NaOH →  Na⁺  +  OH⁻

If pH is 13.90, we can calculate the [OH⁻], so we would know the molarity of NaOH.

1 mol of NaOH can generate 1 mol of OH⁻

[OH⁻] = 10⁻¹³'⁹ = 1.26×10⁻¹⁴ M

In conclussion, molarity of NaOH is 1.26×10⁻¹⁴ M

M = moles of NaOH / volume of solution

We convert the volume from mL to L

650 mL . 1 L /1000mL = 0.650 L

Moles of NaOH = 0.650 L . 1.26×10⁻¹⁴ M = 8.18×10⁻¹⁵ moles

We convert the moles to mass, to determine the grams:

8.18×10⁻¹⁵ moles .  40 g/mol = 3.27 ×10⁻¹³ g

We can convert the grams to ng = 3.27 ×10⁻⁴ ng

Answer:

for the Lewis diagram of water, hydrogens should go on the outside with oxygen in the center

Explanation:

hydrogens always go on the outside

Answer:

2.91M is the concentration of the household ammonia solution

Explanation:

18.2mL of a 0.800M HCl solution to neutralize 5.00mL

The reaction of HCl with NH3 is:

HCl + NH3 → NH4Cl

Thus, the moles of HCl needed to neutralize the household are equal to moles of NH3. That is:

18.2mL = 0.0182L * (0.800mol / L) = 0.01456 moles HCl = Moles NH3.

In 5.00mL = 0.005L:

0.01456 moles NH3 / 0.005L =

Explanation:

The substances that "go in" to a chemical reaction are called the reactants (by convention these are usually listed on the left side of a chemical equation), and the substances found that "come out" of the reaction are known as the products (by convention these are usually found on the right side of a chemical equation

Answer: The reactants that go into the chemical reaction are on the left of the equation. The substances that come out of the chemical reaction are usually on the right side of the equation.

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Answer:

Equilibrium

Explanation:

Correct on edge 2020

Answer:

A - Equilibrium

Explanation:

For edge:)

Answer:

22.4 g

Explanation:

Calculate the mass of sodium acetate that must be added to 500.0 mL of 0.300 M acetic acid to form a pH  = 5.00 buffered solution.

Step 1: Given data

Volume of solution: 500.0 mL

[acetic acid]: 0.300 M

pH = 5.00

pKa of acetic acid: 4.74

Step 2: Calculate the concentration of sodium acetate

We will use the Henderson-Hasselbach equation.

pH = pKa + log [sodium acetate]/[acetic acid]

5.00 = 4.74 + log [sodium acetate]/0.300 M

[sodium acetate] = 0.546 M

Step 3: Calculate the moles of sodium acetate

We have 500.0 mL of a 0.546 M sodium acetate solution

0.5000 L × 0.546 mol/L = 0.273 mol

Step 4: Calculate the mass of sodium acetate

The molar mass of sodium acetate is 82.03 g/mol.

0.273 mol × 82.03 g/mol = 22.4 g

Answer:

3.22 L

Explanation:

0.00 C = 273 K

k = C +273

606 K + 273 K = 879 K

879/273 = 3.219

V2 = 3.22 L

Answer:

Explanation:

The volume of the gas can be found by using the formula for Boyle's law

[tex]P_1V_1 = P_2V_2[/tex]

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the new volume

[tex]V_2 = \frac{P_1V_1}{P_2} \\[/tex]

We have

[tex]V_2 = \frac{10 \times 1}{5} = \frac{10}{5} \\ [/tex]

We have the final answer as

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Answer:

Explanation:

C₆H₁₂     + H₂O      =     C₆H₁₃OH

hexene                      hexanol

1 mole                             1 mole  

Mol weight of hexene = 84

Mol weight of hexanol   = 102

5.33g of hexene = .06345 moles

4.6 g of hexenol = .0451 moles

percentage yield of hexanol

= .0451 x 100 / .06345

= 71.07 %

Moles of hexene used = .0451 moles

Answer:

0.0003125 g

Explanation:

Given data:

Half life of iodine-125 = 60 days

Mass of iodine pellet  = 0.020 g

Mass of iodine remain after one year = ?

Solution:

one year = 365 days

Number of half lives = Time elapsed/ half life

Number of half lives = 365 days/ 60 days

Number of half lives = 6

At time zero = 0.020 g

At 1st half life = 0.020 g/2 = 0.01 g

At 2nd half life = 0.01 g / 2 = 0.005 g

At 3rd half life = 0.005 g/2 = 0.0025 g

At 4th half life = 0.0025 g / 2 = 0.00125 g

At 5tht half life = 0.00125 g / 2 =  0.000625 g

At 6th half life = 0.000625 g/ 2 = 0.0003125 g

Answer:

177 grams

Explanation:

moles of CaF₂ = [tex]\frac{mass}{molar mass}[/tex] = [tex]\frac{365}{78}[/tex] = 4.67949

moles of F-atom = 2×moles of CaF₂ = 2×4.67949 = 9.35898

(mol)×(molar mass)= 9.35898×19 = 177.82062

Therefore, 177 grams of F are in the mixture.

Answer:

[tex]\mathbf{\lambda = 1.01 \times 10^{3} \ nm}[/tex]

Explanation:

To determine the wavelength; let's first calculate the energy (E) change of the transition by using the Rydberg constant [tex](R_H)[/tex]

[tex]\Delta E = R_H ( \dfrac{1}{n_i^2}- \dfrac{1}{n_f^2})[/tex]

[tex]\Delta E = 2. 18 \times 10^{-18} \ J ( \dfrac{1}{7^2}- \dfrac{1}{3^2})[/tex]

[tex]\Delta E = 1.977 \times 10^{-19 } \ J[/tex]

Now; to calculate the wavelength by using the formula:

[tex]\lambda = \dfrac{c*h}{\Delta E}[/tex]

[tex]\lambda = \dfrac{(3.00 \times 10^8 \ m/s) *(6.63 \times 10^{-34} \ J.s)}{1.977 \times 10^{-19 } \ J}[/tex]

[tex]\lambda = 1.01 \times 10^{-6} \ m[/tex]

To nanometers; we have:

[tex]\lambda = 1.01 \times 10^{-6} \ m \times \dfrac{1 \ nm}{ 1 \times 10^{-9} \ m}[/tex]

[tex]\mathbf{\lambda = 1.01 \times 10^{3} \ nm}[/tex]

Answer:

Bohr

Explanation:

Neils Bohr was the scientist that suggested that electrons follow predictable orbits round the nucleus.

Answer:

schrodinger

Explanation:

jelly benee

Answer:

Explanation:

Option 1 15. Proton 16 neutron 15 electron

Isotopes have same atomic no but different atomic mass

Answer:

The Short Answer: All of the planets in ... Planets that orbit around other stars are called exoplanets. All of the ... So, astronomers use other ways to detect and study these distant planets.

Answer:

253.5mL must be added

Explanation:

To find pH of a buffer we need to use H-H equation:

pH = pKa + log [Acetate] / [Acetic acid]

Where pH is pH we want: 6.42; pKa is 4.752 and [] could be taken as moles of each species.

6.42 = 4.752 + log [Acetate] / [Acetic acid]

1.668 = log [Acetate] / [Acetic acid]

46.5586 = [Acetate] / [Acetic acid] (1)

And moles of acetate buffer = Initial moles of acetic acid are:

975mL = 0.975L * (0.664mol / L) = 0.6474 moles acetate buffer =

0.6474 =  [Acetate] + [Acetic acid] (2)

Replacing (2) in (1):

46.5586 = 0.6474 - [Acetic Acid] / [Acetic acid]

46.5586 [Acetic acid] = 0.6474 - [Acetic Acid]

47.5586 [Acetic acid] = 0.6474

[Acetic acid] = 0.01361 moles

And [Acetate]: 0.6474 - 0.01361moles

[Acetate] = 0.63379moles

Now, in the beginning we have just Acetic acid that is converted in acetate with the use of KOH:

Acetic acid + KOH → Acetate

That means the moles of KOH added are the moles of acetate we need. That means we need to add 0.63379 moles of KOH that comes from a 2.50M. The volume is:

0.63379 moles KOH * (1L / 2.50 moles) = 0.2535L =

Chlorine is a halogen gas element which has atomic number 17 which is in group 17, p block and period 3

The electron configuration of Cl  : [Ne] 3s² 3p⁵ ⇒ 2, 8, 7

So the valence electron is 7, so to achieve stability you will need 1 more electron so it is stable like Argon

Cl will be covalently bonded (using shared electron pairs) with other Cl atoms to form a non-polar molecule, namely Cl₂

Answer:A cell is the smallest unit of a living thing. A living thing, whether made of one cell (like bacteria) or many cells (like a human), is called an organism. Thus, cells are the basic building blocks of all organisms. ... Several systems that function together form an organism (like a human being).

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Answer: Entropy is increasing

Explanation: