One mathematical idea I've always been curious about is "integration and derivation".
Integration is about assimilating different variables. Derivation is a mathematical process whereby a result is gotten from some initial assumptions.
Integration is used everyday in different aspects of our lives. For example, if a person is travelling from let's say point A to point B, the speed used by the person might vary but through integration, one can easily get the accurate speed.
Through the division of equations into smaller bits, once can use integration to get the answer that one seeks. Architect can use integration in building the right structures at the exact places where the structures fits.
Likewise derivatives can be used by businesses in assessing whether a profit or loss will be made for a particular transaction or sale of product.
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If using the method of completing the square to solve the quadratic equation x 2 − 9 x − 8 = 0 x 2 −9x−8=0, which number would have to be added to "complete the square"?
Answer:
Add 81/4 to both sides.
Step-by-step explanation:
x^2 − 9x − 8 = 0
x^2 - 9x = 8
Take the coefficient of the x term: -9
Divide by 2: -9/2
Square it: 81/4
Add 81/4 to both sides.
a. 15
b. 16
c. 9
d. 14
Answer:
15
Step-by-step explanation:
1-0 =1
3-1 =2
6-3=3
10-6=4
We are adding 1 more each time
10+5 = 15
PLEASE HELPPPPPPPPPP
Answer: SORRY NEED AN ACCOUNT ON - 10
Step-by-step explanation:
To resolve the proposed issue, an explanation is needed in which the subject is addressed
The sum of two positive integers is 19 and the product is 48
Answer:
16 and 3
Step-by-step explanation:
Let x and y represent the positive integers. We know that
[tex]x + y = 19[/tex]
[tex]xy = 48[/tex]
Isolate the top equation for the x variable.
[tex]x = 19 - y[/tex]
Substitute into the second equation.
[tex](19 - y)y = 48[/tex]
[tex]19y - {y}^{2} = 48[/tex]
[tex] - {y}^{2} + 19y = 48[/tex]
[tex] - {y}^{2} + 19y - 48[/tex]
[tex](y - 16)(y - 3)[/tex]
So our values are
16 and 3.
if for men working for hours for 4 days complete for unit of work then how many unit of work will be completed by two men working for two hours per day?
The 2 men working for 2 hours per 2 days will complete 1/2 unit of work. This is calculated by using the proportions formula.
What is the formula for calculating equal proportions?The formula for the given proportions is,
a: b = c: d
⇒ a/b = c/d
⇒ ad = bc
In this way, the required variable is calculated.
Calculation:For the given question, the proportion we can write
M1 × H1 × D1: M2 × H2 × D2 = W1: W2
⇒ M1 × H1 × D1 × W2 = M2 × H2 × D2 × W1
Where M1 = 4; H1 = 4; D1 = 4; M2 = 2; H2 = 2; D2 = 2 and W1 = 4
We need to calculate W2 - required units of work
So, on substituting,
M1 × H1 × D1 × W2 = M2 × H2 × D2 × W1
⇒ 4 × 4 × 4 × W2 = 2 × 2 × 2 × 4
⇒ 64 × W2 = 32
⇒ W2 = 32/64
∴ W2 = 1/2
Thus, the required units of work are 1/2.
So, 2 men working for 2 hours for 2 days will complete 1/2 unit of work.
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Disclaimer: The given question is incomplete. Here is the complete question.
Question: If 4 men working for 4 hours for 4 days complete 4 units of work then how many unit of work will be completed by two men working for two hours per 2 days?
Need to know Anwser yes or no
Answer:
Reflective symmetry over the line y = 4 is No
Reflective symmetry over the line y = 1/7x + 3 is Yes
if qqq=90 what's qqqq+87
Answer: [tex]90\sqrt[3]{90}+87[/tex]
Step-by-step explanation:
[tex]qqq=90\\q^3=90\\\sqrt[3]{q^3} =\sqrt[3]{90}\\q= \sqrt[3]{90}\\\\qqqq+87\\q^3q^1+87\\90\sqrt[3]{90}+87[/tex]
What is the distance between (-5,-5) and (-9,-2)
Answer:
A (5)
Step-by-step explanation:
The distance is the slope/gradientIn the pythogaras theorem [tex]c^{2} = a^{2} + b^{2}[/tex],c represents the slope and a and b represent the two shorter sides of the right angled triangle ( x,y)
x = -9 - (-5 ) = -9 +5 = -4y = -2 - (-5) = -2 +5 = 3[tex]c^{2}[/tex] = [tex]-4^{2} + 3^{2}[/tex]
= 16 + 9
= 25,
therefore [tex]\sqrt{c^{2} }[/tex] = [tex]\sqrt{25}[/tex]
c = 5
For the function f(x) = x^2 + 4x -5 solve the following f(x)=0
That's a question about quadratic function.
Any quadratic function can be represented by the following form:
[tex]\boxed{f(x)=ax^2+bx+c}[/tex]
Example:
[tex]f(x)= -3x^2-9x+57[/tex] is a function where [tex]a=-3[/tex], [tex]b=-9[/tex] and [tex]c=57[/tex].
Okay, in our problem, we need to find the value of x when [tex]f(x)=0[/tex]. That's mean that the result of our function is equal to zero. Therefore, we have the quadratic equation below:
[tex]x^2+4x-5=0[/tex]
To solve a quadratic equation, we use the Bhaskara's formula. Do you remember the value of a, b and c? They going to be important right now. This is the Bhaskara's formula:
[tex]\boxed{x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} }[/tex]
So, let's see the values of a, b and c in our equation and apply them in the Bhaskara's formula:
In [tex]x^2+4x-5=0[/tex] equation, [tex]a=1[/tex], [tex]b=4[/tex] and [tex]c=-5[/tex]. Let's replace those values:
[tex]x=\frac{-b\pm \sqrt{b^2-4ac} }{2a}[/tex]
[tex]x=\frac{-4\pm \sqrt{4^2-4\times1\times(-5)} }{2\cdot1}[/tex]
[tex]x=\frac{-4\pm \sqrt{16-(-20)} }{2}[/tex]
[tex]x=\frac{-4\pm \sqrt{16 + 20)} }{2}[/tex]
[tex]x=\frac{-4\pm \sqrt{36} }{2}[/tex]
[tex]x=\frac{-4\pm 6 }{2}[/tex]
From now, we have two possibilities:
To add:
[tex]x_1 = \frac{-4+6}{2} \\x_1=\frac{2}{2} \\x_1=1[/tex]
To subtract:
[tex]x_2=\frac{-4-6}{2} \\x_2=\frac{-10}{2} \\x_2=-5[/tex]
Therefore, the result of our problem is: [tex]x_1 = 1[/tex] and [tex]x_2=-5[/tex].
I hope I've helped. ^^
Enjoy your studies. \o/
The isosceles triangle and rectangle have the same perimeter find the value of x
Answer:
x=15
Step-by-step explanation:
x+2+x+2+2x-2=9+8+9+8
2x+4=34
2x=30
x=15
18. A triangle has side lengths of 6, 8, and 9. What type of triangle is it?
•
acute
•
obtuse
•
equiangular
•
right
Answer:
obtuse
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Y=square root of x compare to y= - square root of x how they differ and why
Answer:
Simply because x=y2 doesn't imply that y=
√
x
.
Which expression is equivalent to
-32 3/5
-8
-3/325
3/325
1/8
Answer:
[tex]-32^\frac{3}{5} = -8[/tex]
Step-by-step explanation:
Given
[tex]-32^\frac{3}{5}[/tex]
Required
The equivalent expression
We have:
[tex]-32^\frac{3}{5}[/tex]
Rewrite as:
[tex]-32^\frac{3}{5} = (-32)^\frac{3}{5}[/tex]
Expand
[tex]-32^\frac{3}{5} = (-2^5)^\frac{3}{5}[/tex]
Remove bracket
[tex]-32^\frac{3}{5} = -2^\frac{5*3}{5}[/tex]
[tex]-32^\frac{3}{5} = -2^3[/tex]
[tex]-32^\frac{3}{5} = -8[/tex]
Graph the function g(x) = 3^x + 3 and give its domain and range using interval notation.
When a function is plotted on a graph, the domain and the range of the function are the x-coordinate and the y-coordinate respectively.
The domain and the range of the given function are:
Domain: [tex](-\infty,\infty)[/tex]
Range: [tex](3,\infty)[/tex]
The given function is:
[tex]g(x) = 3^x + 3[/tex]
First, we plot the graph of g(x)
To do this, we need to generate values for x and g(x). The table is generated as follows:
[tex]x = 0 \to g(0) = 3^0 + 3 = 4[/tex]
[tex]x = 1 \to g(1) = 3^1 + 3 = 6[/tex]
[tex]x = 2 \to g(2) = 3^2 + 3 = 12[/tex]
[tex]x = 3 \to g(3) = 3^3 + 3 = 30[/tex]
[tex]x = 4 \to g(4) = 3^4 + 3 = 84[/tex]
The generated values in tabular form are:
[tex]\begin{array}{cccccc}x & {0} & {1} & {2} & {3} & {4} \ \\ g(x) & {4} & {6} & {12} & {30} & {84} \ \end{array}[/tex]
Refer to the attached image for graph of g(x)
To determine the domain, we simply observe the x-axis.
The curve stretches through the x-axis, and there are no visible endpoints on the axis. This means that the curve starts from [tex]-\infty[/tex] to [tex]+\infty[/tex]
Hence, the domain of the function is: [tex](-\infty,\infty)[/tex]
To determine the range, we simply observe the y-axis.
The curve of g(x) starts at y = 3 on the y-axis and the curve faces upward direction. This means that the curve of g(x) is greater than 3 on the y-axis.
Hence, the range of the function is: [tex](3,\infty)[/tex]
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Function: [tex]g(x) = 3^{x} + 3[/tex]. Domain: [tex]Dom \{g(x)\} = \mathbb{R}[/tex], Range: [tex]Ran \{g(x) \} = (3, +\infty)[/tex], respectively.
In Function Theory, the domain of a function [tex]f(x)[/tex] represents the set of values of the independent variable ([tex]x[/tex]), whereas the range of the function is the set of values of the dependent variable.
The Domain of the Function represents the set of values of [tex]x[/tex] (horizontal axis), whereas the Range it is the set of values of [tex]y[/tex] (vertical axis). After analyzing the existence of Asymptotes, we complement with graphic approaches and conclude where domain and range (in Interval notation) are.
Analytically speaking, the domain of exponential functions is the set of all real numbers and the range of [tex]g(x)[/tex] is any number between [tex]\lim_{x \to -\infty} g(x)[/tex] and [tex]\lim_{x \to +\infty} g(x)[/tex]. In a nutshell, we get the following conclusions in interval notation:
Domain: [tex]Dom \{g(x)\} = (-\infty, +\infty)[/tex], Range: [tex]Ran \{g(x) \} = (3, +\infty)[/tex]
Lastly, we proceed to complement this analysis by graphing function with the help of a graphing tool.
According to the image, domain and range coincides with outcomes from analytical approaches.
What is the solution of log(4-3) = log(17-41)?
O4
O 5
O 15
O 20
Explanation:
The rule is that if log(A) = log(B), then A = B
Using this idea, we can then say,
log(t - 3) = log(17 - 4t)
t - 3 = 17 - 4t
t+4t = 17+3
5t = 20
t = 20/5
t = 4
The solution to the logarithmic equation is t = 5
What is Logarithm?The power to which a number must be increased in order to obtain another number is known as the logarithm. A power is the opposite of a logarithm. In other words, if we subtract an exponentiation from a number by taking its logarithm
The properties of Logarithm are :
log A + log B = log AB
log A − log B = log A/B
log Aⁿ = n log A
Given data ,
Let the logarithmic equation be represented as A
Now , the value of A is
log ( t - 3 ) = log (17 - 3t ) be equation (1)
On simplifying , we get
The bases of the logarithm are equal
So , the values are equal and therefore
t - 3 = 17 - 3t
Adding 3t on both sides , we get
4t - 3 = 17
Adding 3 on both sides , we get
4t = 20
Divide by 4 on both sides , we get
t = 20 / 4
t = 5
Therefore , the value of t is 5
Hence , the logarithmic equation is solved
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PLEASE HELP OR IM gonna FAILLLLLLLL!!!!!!!!
Answer:
C. 1/(4^10)
Step-by-step explanation:
Let's break it down: 4^-2 = 1/(4^2)(1/(4^2))^5 = (1^5)/(4^2)^5 = 1/(4^10)Molly and Lynn both set aside money weekly for their savings. Molly already has $650 set aside and adds $35 each week. Lynn already has $825 set aside but adds only $15 each week. Which inequality could they use to determine how many weeks, w, it will take for Molly’s savings to exceed Lynn’s savings?
FINAL ANSWER: D
Given : Molly and Lynn both set aside money weekly for their savings.
Molly already has $650 set aside and adds $35 each week.
Lynn already has $825 set aside but adds only $15 each week.
To Find : inequality to determine how many weeks, w, it will take for Molly’s savings to exceed Lynn’s savings
Solution:
Molly already has $650
adds $35 each week.
=> added in w weeks = 35w
After w weeks = 650 + 35w
Lynn already has $825
adds $15 each week.
added in w weeks = 15w
After w weeks = 825 + 15w
Molly’s savings to exceed Lynn’s savings
⇒ 650 + 35w > 825 + 15w
⇒ 20w > 175
⇒ 4w > 35
⇒ w > 35 /4
At least 9 weeks
Answer:
D
Step-by-step explanation:
First, to eliminate some answers you can figure out which way the sign should go. The question wants to know when Molly's savings will be larger so the sign should open towards her side of the equation. Since her savings are represented on the left the sign should be a greater than, >.
Then, figure out where the variables belong. The variable represents the number of weeks that have passed, so they should be multiplied by the number that is affected by the passing of weeks. This is the amount each person saves, aka the independent variable. So the "w" variable should be next to the 35 and 15.
Help! I need help with these two questions (10 points each!)
Answer:
see image...
the (x-h) shifts the curve left right (east west)
and the +k at the end shifts it up/down (north/south)
Step-by-step explanation:
please help find the solution to the system of equations
Answer:
x = 2 y = 3
Step-by-step explanation:
-2x + 7 = 5x - 7
-7x + 7 = -7
-7x = -14
x = 2
y = -2(2) + 7
y = -4 + 7
y = 3
*20 points*
how do you get the weighted average from this table?
Answer:
it is
[(2+3+4+6)-2*4]:4=1.75
I THINK
Step-by-step explanation:
What is the height of spanning tree obtained from Wn by the breadth-first search, starting at the central vertex of Wn?
Answer:
The height of the spanning tree is one by the breadth-first search at the central vertex of Wn.
Step-by-step explanation:
The graph is connected and has a spanning tree where the tree can build using a depth-first search of the graph. Start with chosen vertex, the graph as the root, and root add vertices and edges such as each new edge is incident with vertex and vertices are not in path. If all vertices are included, it will do otherwise, move back to the next level vertex and start passing. It is for depth-first search. For breadth-first search, start with chosen vertex add all edges incident to a vertex. The new vertex is added and becomes the vertices at level 1 in the spanning tree, and each vertex at level 1 adds each edge incident to vertex and other vertex connected to the edge of the tree as long as it does not produce.
One card is randomly selected from a deck of cards. Find the odds against drawing a black 10.
The odds against drawing a black ten are ___:___.
(Simplify your answers.)
Answer:
25/26 or 26/27 depending on free hands.
The first is if you don't use jokers/free cards
There is 13 cards in a single set, and a single 10 card.
Two sets are black and two sets a red.
Hearts, Spades, Clubs, and Diamonds
There is only 2 black tens out of 52 or 54 cards, so we can set it up as
50/52 or 52/54 which is simplified to
25/26 or 26/27 depending on free hands.
Step-by-step explanation:
The angle θ between 5i-j+k & 2i-j+k is
Step-by-step explanation:
Let,
[tex] \sf \vec{a} = 5 \hat{i} - \hat{j} + \hat{k} \\ \therefore \: \sf \: | \vec{a}| = \sqrt{ {5}^{2} + {( - 1)}^{2} + {1}^{2} } \\ = \sqrt{25 + 1 + 1} \\ = \sqrt{27} \\ \\ \sf \vec{b} = 2\hat{i} - \hat{j} + \hat{k} \\ \therefore \: \sf \: | \vec{b}| = \sqrt{ {2}^{2} + {( - 1)}^{2} + {1}^{2} } \\ = \sqrt{4 + 1 + 1} \\ = \sqrt{6} \\ \\\sf \: \vec{a}. \vec{b} = (5 \hat{i} - \hat{j} + \hat{k}).(2\hat{i} - \hat{j} + \hat{k}) \\ = 5 \times 2 + ( - 1) \times ( - 1) + 1 \times 1 \\ = 10 + 1 + 1 \\ = 12 \\ \\ \sf \: angle \: between \: \vec{a} \: and \: \vec{b} \: = \theta \\ \\ \: so \\ \sf \vec{a}. \vec{b} = | \vec{a}| . | \vec{b}| cos\theta \\ = > \sf \: cos \theta \: = \frac{ \vec{a}. \vec{b}}{ | \vec{a}| . | \vec{b}| } \\ = > cos \theta = \frac{12}{ \sqrt{27} \times \sqrt{6} } = 0.94 \\ = > \theta = {cos}^{ - 1} (0.94) \\ = > \green{\theta = 19.47 ^{ \circ} }[/tex]
A survey of 30-year-old males provided data on the number of auto accidents in the previous 5 years. The sample mean is 1.3 accidents per male. Test the hypothesis that the number of accidents follows a Poisson distribution at the 5% level of significance.
No. of accident No. of males
0 39
1 22
2 14
3 11
>=4 4
Required:
a. What's the Expected probability of finding males with 0 accidents?
b. What's the Expected probability of finding males with 4 or more accidents?
Answer:
0.2725
0.0431
Step-by-step explanation:
The distribution here is a poisson distribution :
λ = 1.3
The poisson distribution :
p(x) = [(e^-λ * λ^x)] ÷ x!
Expected probability of finding male with 0 accident ; x = 0
p(0) = [(e^-1.3 * 1.3^0)] ÷ 0!
p(0) = [0.2725317 * 1] ÷ 1
p(0) = 0.2725317
= 0.2725
2.)
P(x ≥ 4) = 1 - P(x < 4)
P(x < 4) = p(x = 0) + p(x. = 1) + p(x = 2) + p(x = 3)
p(x = 0) = p(0) = [(e^-1.3 * 1.3^0)] ÷ 0! = 0.2725
p(x = 1) = p(1) = [(e^-1.3 * 1.3^1)] ÷ 1! = 0.35429
p(x = 2) = p(2) = [(e^-1.3 * 1.3^2)] ÷ 2! = 0.23029 p(x = 3) = p(3) = [(e^-1.3 * 1.3^3)] ÷ 0! = 0.09979
P(x < 4) = 0.2725 + 0.35429 + 0.23029 + 0.09979 = 0.95687
P(x ≥ 4) = 1 - 0.95687 = 0.0431
How much wrapping is needed to cover a cubed gift box that is 9 inches high? (Include the bow which takes 115 sq. inches.)
Answer:
601 in²
Step-by-step explanation:
To obtain the amount of wrapping needed to cover the cube shaped gift box, including the bow
Area of bow = 115 in²
Surface area of cube shaped box = 6a²
a = side length of cube = 9
Hence,
Surface area of gift box = 6 * 9²
Surface area = 6 * 81 = 486 in²
Total wrapping required = area of gift box + area of bow = (486 in² + 115 in²) = 601 in²
Need the value of P please
Answer:
B. 35°
Step-by-step explanation:
First, find the two interior angles that are adjacent to angles 90° and 125° respectively.
Thus:
Interior angle 1: 180° - 90° = 90° (linear pair)
Interior angle 2: 180° - 125° = 55° (linear pair)
P + 90° + 55° = 180° (sum of interior angles in a triangle)
P + 145° = 180°
Subtract 145° from each side
P = 180° - 145°
P = 35°
A soccer team wants new uniforms. A jersey costs $42, shorts cost $26, socks cost $6, and shinguards cost $18. How much does one
uniform cost?
$62
$74
$83
$92
Answer:
$92
Step-by-step explanation:
42 + 26 + 6 + 18 = 92
Q: Solve for x: 8x-2-5x=8
A. OX=13
B. OX=2 1/2
C. OX=3 1/3
D. OX=7
Answer:
c. 3 1/3
Step-by-step explanation:
8x-2-5x=8
3x=10
x=10/3=3 1/3
Answer:
x=[tex]3\frac{1}{3}[/tex]
Step-by-step explanation:
Hi there!
We want to find the value of x in this expression:
8x-2-5x=8
Our goal is to isolate x on one side
Combine like terms on the left side (add the terms with x together)
3x-2=8
Add 2 to both sides (-2+2=0)
3x-2=8
+2 +2
__________
3x=10
Divide both sides by 3
x=[tex]\frac{10}{3}[/tex]
Simplify the improper fraction
x=[tex]3\frac{1}{3}[/tex]
Hope this helps!
4. find possible value for m if
X=-3 and (3m-x)2=81
Answer:
m = 12.5
Step-by-step explanation:
x = - 3
(3m - x) 2= 81
(3m - (-3)) 2= 81
(3m + 3) 2= 81
6m + 6 = 81
- 6 - 6
6m = 75
[tex]\frac{6m}{6}[/tex] = [tex]\frac{75}{6}[/tex]
m = 12.5
hope this helps! if you have an questions, pls let me know!
The resistors produced by a manufacturer are required to have an average resistance of 0.150 ohms. Statistical analysis of the output suggests that the resistances can be approximated by a normal distribution with known standard deviation of 0.005 ohms. We are interested in testing the hypothesis that the resistors conform to the specifications.
Requied:
a. Determine whether a random sample of 10 resistors yielding a sample mean of 0.152 ohms indicates that the resistors are conforming. Use alpha = 0.05.
b. Calculate a 95% confidence interval for the average resistance. How does this interval relate to your solution of part (a)?
Answer:
a) The p-value of the test is 0.2076 > 0.05, which means that the sample indicates that the resistors are conforming.
b) The 95% confidence interval for the average resistance is (0.147, 0.153). 0.152 is part of the confidence interval, which means that as the test statistic in item a), it indicates that the resistors are conforming.
Step-by-step explanation:
Question a:
The resistors produced by a manufacturer are required to have an average resistance of 0.150 ohms.
At the null hypothesis, we test if this is the average resistance, that is:
[tex]H_0: \mu = 0.15[/tex]
We are interested in testing the hypothesis that the resistors conform to the specifications.
At the alternative hypothesis, we test if it is not conforming, that is, the mean is different of 0.15, so:
[tex]H_1: \mu \neq 0.15[/tex]
The test statistic is:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.
0.15 is tested at the null hypothesis:
This means that [tex]\mu = 0.15[/tex]
Sample mean of 0.152, sample of 10, population standard deviation of 0.005.
This means that [tex]X = 0.152, n = 10, \sigma = 0.005[/tex]
Value of the test statistic:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]z = \frac{0.152 - 0.15}{\frac{0.005}{\sqrt{10}}}[/tex]
[tex]z = 1.26[/tex]
P-value of the test and decision:
The p-value of the test is the probability of the sample mean differing from 0.15 by at least 0.152 - 0.15 = 0.002, which is P(|z| > 1.26), given by two multiplied by the p-value of z = -1.26.
Looking at the z-table, z = -1.26 has a p-value of 0.1038.
2*0.1038 = 0.2076
The p-value of the test is 0.2076 > 0.05, which means that the sample indicates that the resistors are conforming.
Question b:
We have to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]
Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].
That is z with a p-value of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.
Now, find the margin of error M as such
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
[tex]M = 1.96\frac{0.005}{\sqrt{10}} = 0.003[/tex]
The lower end of the interval is the sample mean subtracted by M. So it is 0.15 - 0.003 = 0.147.
The upper end of the interval is the sample mean added to M. So it is 0.15 + 0.003 = 0.153.
The 95% confidence interval for the average resistance is (0.147, 0.153). 0.152 is part of the confidence interval, which means that as the test statistic in item a), it indicates that the resistors are conforming.
