The velocity of an object that has been falling freely in a vacuum
for 4 seconds is 39.2 m/s.
The given parameters;
time of motion, t = 4 secondsThe value acceleration due to gravity in vacuum is approximately 9.8 m/s².
The final velocity of the object is calculated as follows;
v = u + gt
where;
u is the initial velocity of the object = 0g is acceleration due to gravity in vacuumSubstitute the given parameters and solve for v;
v = 0 + 9.8(4)
v = 39.2 m/s
Thus, the velocity of an object that has been falling freely in a vacuum
for 4 seconds is 39.2 m/s.
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Match the number in this mathematical expression with the number significant digits they have .
18.34cm +9.02603cm -20.2cm +150cm
1. 150cm. a.4
2. 9.02603 cm. b.6
3. 18.34cm. c. 2
4. 20.2cm. d.3
Answer:
Please check your question well. Otherwise I think there's no matching.
Samantha always feels rushed in the morning, and she often forgets important items when she leave for school
erica wants to attend a a public four- year unviersity
Answer:
go girl
Explanation:
i'm feom public uni too
What will be the final velocity of a car, if it starts
to make from ges and accelerates at 10 m/s² after 5 seconds?
In order to get the most benefits from exercise with the least amount of risk, you should
Answer:
always stretch before you exercise
Explanation:
Last summer, Jose left early in the morning at 5 a.m. and drove to Ensenada 100 miles away. He stopped to get gas and drove an extra 300 miles. He finally stopped in Cabo San Lucas at 1p.m. What was the average speed that Jose was traveling?
Answer:50 miles per hour
A car drives off a cliff at 30 m/s. The car lands 100 meters
from the base of the cliff. How tall is the cliff?
Answer:
Height of the cliff, H = 54.66 m
Explanation:
Given that,
Speed of the car, u = 30 m/s
The car lands 100 m from the base of the cliff.
We need to find the height of the cliff.
First we will find the time time needed for the car to reach the bottom of the cliff. It can be calculated as :
[tex]t=\dfrac{h}{v}\\\\t=\dfrac{100}{30}\\\\t=3.34\ s[/tex]
Let H is the height of the cliff. Using second equation of motion as follows
[tex]H=v_yt+\dfrac{1}{2}gt^2\\\\H=\dfrac{1}{2}gt^2\\\\H=\dfrac{1}{2}\times 9.8\times (3.34)^2\\\\H=54.66\ m[/tex]
So, the cliff is 54.66 m tall.
A baby drops a ball from her hand resting on the serving tray of her high chair. at the
exact same time, she knocks another ball from the same tray at the exact same height.
Which of the following statement or statements is / are true?
1. Both balls strike the ground at the same time.
II. The dropped ball reaches the ground first.
III. The knocked ball reaches the ground first.
IV. Both balls strike the ground at the same speed
O I and IV
O ll only
I only
O Ill only
Answer:
Both balls strike the ground at the same time, and both balls strike the ground at the same speed.
Explanation:
A red ball rolls for 6 meters across a sticky level surface and slows down to a stop. the ball was rolling at 36 meters per second when it began to roll across the sticky surface. find the acceleration, velocity final, the velocity initial, the velocity average, the distance the ball rolled, and the time of the balls roll across the sticky surface
Answer:
The initial velocity of the ball is given as 36 m/s
The final velocity of the ball is given as 0 m/s
The distance the ball rolled is given as 6 meters
The acceleration is 108 m/s²
The time the ball rolls across the sticky surface is 1/3 seconds
The average velocity is 18 m/s
Explanation:
The initial velocity of the ball, u = 36 m/s
The final velocity of the ball, v = 0 m/s
The distance the ball rolled, s = 6 meters
The acceleration, a, is given by;
v² = u² - 2×a×s, where v = 0
u² = 2 × a × s
a = u²/(2 × s) = 36²/(2 × 6) = 108 m/s²
The time the ball rolls across the sticky surface is given by the following equation;
v = u - a×t, v = 0
∴ u = a×t
t = u/a = 36/108 = 1/3 seconds
The time the ball rolls across the sticky surface = 1/3 seconds
The average velocity = Distance/time = 6/(1/3) = 18 m/s
The average velocity = 18 m/s.
On the moon, Bob weighs 160N. Fred weighs 882N on Eartch. Who has the greater mass?
Answer:
Fred weighs more than bob
Explanation:
length measures the amount of matter in a substance or an object. true or false ?
Answer:
false
Explanation:
A rocket is shot out of a navy battleship to test a new rocket. It takes 16 seconds for the rocket
to reach its destination after leaving the barrel. If its final velocity was found to be 200 m/s,
then what was the rocket's acceleration?
What is an application of this model?
А
It highlights the artistic abilities of scientists.
B
It illustrates the basic structure of an atom. .
С
It shows how the parts of an atom interact.
D
It demonstrates how atoms form and function.
What is Terminal Velocity
Answer:
the maximum velocity attainable by an object as it falls through a fluid or the air
Explanation:
two asteroids crashed. The crash caused both asteroids to change speed. Scientists want to use the change in speed and motion to figure out which asteroid has more mass. Based on the information in the diagram, which statement is correct? In your answer, explain what the forces were like and why the asteroids changed their motion.
Asteroid 1 has more mass than Asteroid 2.
Asteroid 1 and Asteroid 2 are the same mass.
Asteroid 1 has less mass than Asteroid 2.
Answer:
The answer is asteroid 1 has more mass
Explanation:
If the initial speed of both asteroids before the collision is equal, then the asteroid with more mass has more momentum before collision while the asteroid with lesser mass has greater momentum after the collision.
What is law of conservation of linear momentum?According to the principle of conservation of linear momentum, the sum of the momentum before the collision must equal the sum of the momentum after the collision.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where m₁ and m₂ is the mass of the objects that collided, u₁ and u₂ is their initial speed and v₁ & v₂ is their final speed.
The linear momentum is the product of the mass of the object times the velocity of that object. Conservation of momentum is a property exhibited by any object where the total amount of momentum never changes.
The principle of conservation of linear momentum states that if two objects collide with each other, then the total momentum before and after the collision will remain the same if there will be no external force acting on the colliding objects.
Therefore, the linear momentum of both asteroids will be conserved as no external force acting on them. The asteroid with more mass has more momentum before collision while the asteroid with lesser mass has greater momentum after the collision so that total momentum remains conserved.
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convert 72km\hr into SI unit
Answer:
hello we can't convert 72 into s18 because that is another one and another one
Explanation:
0 please Marks as brainleast
DESPERATE WILL GIVE BRAILIST
Which of the following is NOT an agent of change in the rock cycle?
A. Cooling and crystallization
B. Weathering and erosion
C. Cementation and compaction
D. Drying and decaying
Answer:
A
Explanation: I don't think I ever heard of Crystalization being apart of the rock Cycle but I could be wrong hope this helps
Melanie is given an unknown substance by her teacher. Melanie’s teacher tells her that the substance has a bitter taste. Melanie also observes that the substance is slippery. These properties indicate that the substance may be which of the following?
Answer:
base
Explanation:
I hope this helps
Answer:base
Explanation:
In the data table, distance is measured in meters and time is in seconds. Calculate the boy’s average velocity using the equation
average velocity= total distance / total time
Answer:
23.59 for the average pls give brainliest sis
Answer: 23.59
HOPE THIS HELPS :D
create an acrostic poem for the words "INERTIA"
Answer:
I- In all circumstances,
N- Never relenting to pressure.
E- Ever remaining constant and stable,
R- Resisting any form of association with other things,
T- This force will always be the same.
I- In whatever manner or pattern the force may come from.
A- Always true to the core, never changing, never relenting.
Explanation:
An acrostic poem is the formation of a poem/ poetry by using certain letters of the word to form a poem. This means that certain letters of any given word will be used as the basis for the construction and formation of a poem.
The acrostic poem for the word "INERTIA" is as follows-
I- In all circumstances,
N- Never relenting to pressure.
E- Ever remaining constant and stable,
R- Resisting any form of association with other things,
T- This force will always be the same.
I- In whatever manner or pattern the force may come from.
A- Always true to the core, never changing, never relenting.
I- In all circumstances,
N- Never relenting to pressure.
E- Ever remaining constant and stable,
R- Resisting any form of association with other things,
T- This force will always be the same.
I- In whatever manner or pattern the force may come from.
A- Always true to the core, never changing, never relenting.
What is an inertia?The inertia of any object is defined as when any object is at rest then it will be always at rest until and unless the external force is not applied on it. Also, if it is in motion, it will always in the motion until and unless an external force is not applied on it to stop it.
An acrostic poem is the formation of a poem/ poetry by using certain letters of the word to form a poem. This means that certain letters of any given word will be used as the basis for the construction and formation of a poem.
The acrostic poem for the word “INERTIA” is as follows-
I- In all circumstances,
N- Never relenting to pressure.
E- Ever remaining constant and stable,
R- Resisting any form of association with other things,
T- This force will always be the same.
I- In whatever manner or pattern the force may come from.
A- Always true to the core, never changing, never relenting.
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Electromagnetic energy travels through space in the form of what
A. electric charges
B. shape
C. waves
D. lower
E. higher
F. chemical
G. electrical
H. nuclear
Answer:
c
Explanation:
electromagnetic energy is transmitted through space in the form of waves.
A sheet of BCC iron 1.5-mm thick was exposed to a carburizing atmosphere on one side and an carburizing atmosphere on the other side at 725°C. After having reached steady state, the iron was quickly cooled to room temperature. The carbon concentrations at the two surfaces were determined to be 0.012 and 0.0069 wt%. Calculate the diffusion coefficient if the diffusion flux is 3.6 × 10-8 kg/m2-s, given that the densities of carbon and iron are 2.25 and 7.87 g/cm3, respectively.
Answer:
Diffusion coefficient D = 2.6613 × 10⁻¹¹ m²/s
Explanation:
From the given information:
Carbon concentration [tex]C_c[/tex] = 0.012
Iron concentration [tex]C_{Fe}[/tex] = 100 - 0.012 = 99.988
Density of carbon = 2.25 g/cm³
Density of iron = 7.87 g/cm³
We can convert the carbon concentrations from weight percentage to kilograms carbon per meter cubed by using the formula.
[tex]C^*_c = \dfrac{C_c}{\dfrac{C_c}{\rho_c}+\dfrac{C_{Fe}}{\rho_{Fe}}}\times 10^3[/tex]
[tex]C^*_c = \dfrac{0.012}{\dfrac{0.012}{2.25 \ g/cm^3}+\dfrac{99.988}{7.87 \ g/cm^3}}\times 10^3[/tex]
[tex]C^*_c = \dfrac{0.012}{0.00533 \ g/cm^3 + 12.71 \ g/cm^3} \times 10^3[/tex]
[tex]C^*_c = 0.9437 \ kgC/m^3[/tex]
However; for 0.0069 wt% C
[tex]C^*_c = \dfrac{C_c}{\dfrac{C_c}{\rho_c}+\dfrac{C_{Fe}}{\rho_{Fe}}}\times 10^3[/tex]
[tex]C^*_c = \dfrac{0.0069}{\dfrac{0.0069}{2.25 \ g/cm^3}+\dfrac{99.9931}{7.87 \ g/cm^3}}\times 10^3[/tex]
[tex]C^*_c =0.5429 \ kgC/m^3[/tex]
Thus; the diffusion coefficient can be computed by using the formula:
[tex]D = - J \begin {bmatrix} \dfrac{x_A-x_B}{C_A-C_B}\end {bmatrix}[/tex]
[tex]D = - (3.6 \times 10^{-8} \ kg/m^2-s) \begin {bmatrix} \dfrac{-15^{-3} \ m }{0.9437 \ kgC/m^3 - 0.5429 \ kgC/m^3}\end {bmatrix}[/tex]
D = 2.6613 × 10⁻¹¹ m²/s
1. How does Newton’s first law prove that planets are moving in a circular pattern?
2. How does Newton’s third law prove that Earth is moving and the Sun is not?
3.Using Newton’s law of gravitation and the third law of motion, argue qualitatively how the ratio between the orbital period and the radius of a planet do or do not change, based upon Kepler’s third law of motion.
Answer:
Explanation:
Newton's First Law of Motion states that a body in motion keeps the same motion unless acted upon by an outside force. Likewise, if it is not moving, it remains that way unless a force acts on it.
What theory or hypothesis can you find about gravity?
Answer:
That it will always work on earth.
Explanation:
If it's on earth it will not be able to elude gravity.
That's all i've got sorry
1. Compare and Contrast Elements and Atoms (3 column table)
PLeasee help!!
Answer:
A particular atom will have the same number of protons and electrons and most atoms have at least as many neutrons as protons. An element is a substance that is made entirely from one type of atom. For example, the element hydrogen is made from atoms containing just one proton and one electron.
Explanation:
A child appears to be running into the street aheadIt takes 23 seconds for the driver to react and begin to brake, but this time at a rate of - 7.5 m/s ^ 2 . What is the stopping distance for the car in this situation?
Answer:
Explanation:
Given
acceleration a = - 7.5 m/s^2
time t = 23secs
Required
Stopping distance S
First let us get the initial velocity if the child using:
v = u + at
Note that v = 0
0 = u -7.5(23)
u = 7.5 * 23
u =172.5m/s
Using the equation of motion to get the stopping distance:
v² = u²+2aS
0 = u²+2aS
-u² = 2aS
-172.5² = 2(-7.5)S
29,756.25 = 15S
S =29,756.25/15
S = 1,983.75m
Hence the stopping distance is 1,983.75m
where are the new skin cells made
Answer:
epidermis
The top 18 to 23 layers of your skin are made of dead cells. New skin cells form at the bottom of the epidermis, which is the top part of your skin. Skin cells change shape. They start off kind of fat and square.
Explanation:
A dragster's top acceleration is 60m/s2. If it accelerates for 3 seconds from the starting line, how fast will it be going
Answer:
180 m/s
Explanation:
acceleration = 60 m/s2
time = 3 secs
u(initial velocity) = 0 m/s
v(final velocity) = ?
equation used is = v = u + at
0 + 60*3
v = 180 m/s
A dragster's top acceleration is 60 meters/second². If it accelerates for 3 seconds from the starting line, then the total distance covered by it would be
What is acceleration?The rate of change of the velocity with respect to time is known as the acceleration of the object.
As given in the problem a dragster's top acceleration is 60 meters/second². If it accelerates for 3 seconds from the starting line, then we have to find out the total distance traveled by it,
top acceleration of the dragster = 60 meters/second²
time period to accelerate = 3 seconds
By using the second equation of motion,
s = ut + 1/2at²
s = 0 + 0.5×60×3²
s = 270 meters
Thus, the total distance covered by the dragster would be 270 meters
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Two blocks are arranged at the ends of a massless cord over a frictionless massless pulley as
shown in the figure. Assume the system starts
from rest. When the masses have moved a distance of 0.317 m, their speed is 1.33 m/s.
The acceleration of gravity is 9.8 m/s
2
What is the coefficient of friction between
m2 and the table?
What is the magnitude of the tension in the
cord?
Answer in units of N.
Answer:
The coefficient of friction between m₂ and the table is approximately 0.2703
The magnitude of the tension in cable is 28.737 N
Explanation:
The given parameters are;
The mass of the block on the table, m₂ = 5.8 kg
The mass of the hanging block, m₁ = 4.5 kg
The distance in which the block has moved = 0.317 m
The speed after the block moves = 1.33 m/s
The acceleration due to gravity, g = 9.8 m/s²
The coefficient of friction between m₂ and the table = μ
The acceleration, a, of the blocks is given from the formula of speed, v, of a body at a given distance, s, from rest as follows;
v² = 2 × a × s
Where;
v = 1.33 m/s
s = 0.317 m
Substituting the values gives;
1.33² = 2 × a × 0.317
a = 1.33²/(2 × 0.317) ≈ 2.79
The acceleration, a ≈ 2.79 m/s²
Therefore, we have the force acting on the system given as follows;
Weight of m₁ - Frictional force of m₂ = (m₁ + m₂) × a
4.5 × 9.8 - 5.8 × 9.8 × μ = (4.5 + 5.8) × 2.79
4.5 × 9.8 - 5.8 × 9.8 × μ = 28.737 N
(4.5 × 9.8)N - 28.737 N = 5.8 × 9.8 × μ
44.1 N - 28.737 N =56.84 N × μ
15.363 N = 56.84 N × μ
μ = 15.363 N/(56.84 N) ≈ 0.2703
The coefficient of friction between m₂ and the table = μ ≈ 0.2703
The coefficient of friction between m₂ and the table ≈ 0.2703
The magnitude of the tension in cable = (m₁ + m₂) × a = 28.737 N.
The magnitude of the tension in cable = 28.737 N
carl walks a distance of 100 meters at a speed of 4 m/s. how much time does it take? ( please show step-by-step explanation )
Answer:
25s
Explanation:
To find the amount of seconds it takes, you divide 100 (the meters) by 4 (the meters per second) the meters then cancel out, and you are left with 25 s
