What is the value of g(-4)?

Answer for this prob

Answer:

10c^2-c-2

Step-by-step explanation:

FOIL method

or just multiply all of the numbers by each other, if you get 4 numbers you did it right then simplify;

(5c+2)(2c-1) 5c*2c; 2*-1; -1*5c; 2*2c = 10c^2, -2, -5c, 4c, simplify, 10c^2 -c -2. Hope this helps :)

Answer:

10c² - c - 2

Step-by-step explanation:

(5c+2)(2c-1)

10c² - 5c + 4c - 2

10c² - c - 2

Answer:

22/25

Step-by-step explanation:

Multiples of 8 are 8,16,24,32,40,48

That means there are 6 multiples of 8

50 -6 = 44

There are 44 non multiples of 8

P( non multiples of 8) = non multiples of 8 / total

                                   = 44/50

                                  =22/25

Answer:

Less than 3.6 years.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 5.8 years, and  standard deviation of 1.7 years.

This means that [tex]\mu = 5.8, \sigma = 1.7[/tex]

The 10% of items with the shortest lifespan will last less than how many years?

Less than the 10th percentile, which is X when Z has a p-value of 0.1, so X when Z = -1.28.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1.28 = \frac{X - 5.8}{1.7}[/tex]

[tex]X - 5.8 = -1.28*1.7[/tex]

[tex]X = 3.6[/tex]

Less than 3.6 years.

Answer:

if I am not mistakedn the answe id e

The correct answer is H. B is the 200% of A.

Since A is the sum of the first 50 multiples of 3, while B is the sum of the first 50 multiples of 6, to determine what percentage of A is B, the base numbers of both calculations must be considered, that is, 3 and 6. Thus, since 6 is 200% of 3 (6/3 = 2), B is 200% of A.

Learn more about percentages in https://brainly.com/question/18925632.

Answer:

(x-5)^2 + (y+6)^2 = 4

Step-by-step explanation:

The equation of a circle is given by

(x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius

(x-5)^2 + (y- -6)^2 = 2^2

(x-5)^2 + (y+6)^2 = 4

Step-by-step explanation:

tan Z=p/b

=48/14

=24/7

Keep smiling and hope u are satisfied with my answer.Have a good day :)

Answer:

18

Step-by-step explanation:

Because angle A and C are equal, it is an isoceles traingle.

This means that side BA is equal to side BC.

Thus, you can set 6x equal to 3x + 9.

Solving that gives you x = 3.

6(3) = 18    3(3) +9 = 18

Answer:

B. 18

Step-by-step explanation:

Since angles A and C are congruent, then sides BA and BC are congruent.

6x = 3x + 9

3x = 9

x = 3

AB = 6x = 6(3) = 18

Answer: B. 18

Answer:

1) A

B) 5.818 stops

Step-by-step explanation:

Number One is less than or equal to 21 because the person only has 21 dollars, so she can't spend more than 21.

B can be solved through the equation by first subtracting $5, and then dividing 2.75 by 16.

Answer:

x-4y=2 can be written as y=(x-2)/4

(2,0) when x=2, y=0 and (6,1) when x=6, y=1

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this question:

Fleet of 18 means that [tex]N = 18[/tex]

9 are carrying nuclear weapons, which means that [tex]k = 9[/tex]

9 are destroyed, which means that [tex]n = 9[/tex]

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

[tex]P(X \leq 1) = P(X = 0) + P(X = 1)[/tex]

In which

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021[/tex]

[tex]P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666[/tex]

Then

[tex]P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687[/tex]

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Answer:

Mean = Sum of all numbers divided by the amount of numbers

[tex]Mean/Average=\frac{3+1+1.5+1.25+2.25+4+1+2}{8} =\frac{16}{8} =2[/tex]

Median = the middle number when the ordered from least to greatest.

If there are two middle numbers, find the mean/average of those numbers:

[tex]\frac{1.5+2}{2} =\frac{3.5}{2} =1.75[/tex]

Therefore, the answer would be:

[tex]\\ \large\sf\longmapsto -\dfrac{4x^3}{3y^2}[/tex]

[tex]\\ \large\sf\longmapsto -\dfrac{4(3)^3}{3(4)^2}[/tex]

[tex]\\ \large\sf\longmapsto -\dfrac{4(27)}{3(16)}[/tex]

[tex]\\ \large\sf\longmapsto -\dfrac{108}{48}[/tex]

[tex]\\ \large\sf\longmapsto -\dfrac{9}{4}[/tex]

Answer:

Answer:

D) 0.89

Step-by-step explanation:

round 0.885 to 0.89

Answer:

.

Step-by-step explanation:

For the hole in one pythagores theorem would work because a right angled triangle eill be formed and hole in one would be the hypotenuse which can be found using the theorem.

b²+p² = h²

Answered by Gauthmath must click thanks and mark brainliest

Answer:

it should be 3

Step-by-step explanation:

I hope this help

Answer:

6.286;

0.0165

0.976

0.1995

Step-by-step explanation:

Given that :

Mean, μ = 243. 4

Standard deviation, σ = 35

Sample size, n = 31

1.)

Standard Error

S. E = σ / √n = 35/√31 = 6.286

2.)

P(x < 230) ;

Z = (x - μ) / S.E

P(Z < (230 - 243.4) / 6.286))

P(Z < - 2.132) = 0.0165

3.)

P(x > 231)

P(Z > (231 - 243.4) / 6.286))

P(Z > - 1.973) = 0.976 (area to the right)

4)

P(x < 248)

P(Z < (248 - 243.4) / 6.286))

P(Z < 0.732) = 0.7679

P(x < 255)

P(Z < (255 - 243.4) / 6.286))

P(Z < 1.845) = 0.9674

0.9674 - 0.7679 = 0.1995

Answer:

A

Step-by-step explanation:

in the question given, the goal is to rationalize the denominator, or in other words get rid of any square roots.

recall this formula :

(a-b)(a+b) = a^2 - b^2

in this case, to rationalize the denominator of 3 - [tex]\sqrt{6x}[/tex] , we will multiply it and the numerator by its conjugate. the conjugate of    3 -

after multiplying the denominator by its conjugate, we get:

(3 - [tex]\sqrt{6x}[/tex]) (3 +

at this point there is no need to solve the numerator as there is only one answer with this denominator.

hope this helps  :)

Answer:

Step-by-step explanation:

Answer:

graphs 1, 2, 3, and 4, can represent a function

graphs 5 and 6 can not represent a function.

Step-by-step explanation:

If for a given graph of a relationship you can draw a vertical line that intersects the graph in more than one point, then we can conclude that the graph does not represent a function.

Now, if we look at the first four graphs, we can see that no vertical line intersects more than one point, so the first four can represent functions.

The special case here is graph number 2, where we can see a white dot right below a colored dot, and if we draw a vertical line there, the line will touch both points. But, a white dot means that the exact point does not belong to the graph, so if the line passes through there, it will not intersect the graph.

For the last two, this is not the case, in graph 5 and graph 6 we could draw vertical lines that intersect the graphs twice

(any line like x = n, with n < 0, intersects two points in graph 5, while the line x = 0 intersects twice the graph number 6)

So graph 5 and graph 6 can't represent functions.

Answer:

dogs = 79

dats = 90

fish = 183

Step-by-step explanation:

let the total number of dogs owned be x

no. of cats owned = x+11

no. of fish owned = x+11+x+14= 2x+25

hence,

2x+25+x+11+x=352

4x=316

x=316/4= 79mil

no. of cats owned = 79 + 11 = 90

no. of fish owned = 2(79)+25=183

Answer:

Pretty sure it's A

Step-by-step explanation:

The x outside the parenthesis means that there's an x intercept at (0,0) and (x-3) means there's another one at (3,0)

Answer:

[tex]12x^{2} (x^{3}-5)^{3} (x^{4}+3)^{5} +20x^{3} (x^{3}-5)^{4} (x^{4}+3)^{4}[/tex]

Step-by-step explanation:

Answer:

28462.5

Step-by-step explanation:

During the first year it gained 10% and during his second year he gained 15% so you first add those and you get 25%.

Then you multiply 25% with 37,950.

25/100 * 37950 = 948,750/100

= 9487.5

To get the original amount you subtract 9487.5 from 37,950

37,950 - 9487.5 = 28462.5

So the original amount was 28462.5

Answer:

A.

Step-by-step explanation:

A. is the answer because they list all of the sandwiches, soups, and beverages with every possible combination.

The volume of the water is: [tex]\pi (2)^2(8) - 6 (\frac{4}{3} \pi (1.5)^3)[/tex]

The volume of a cylinder is;

[tex]V = \pi r^2h[/tex]

For the cylinder, we have:

[tex]d = 4[/tex] -- diameter

[tex]h = 8[/tex] --- height of the water in the cylinder

The radius of the cylinder is:

[tex]r =d/2 = 4/2 = 2[/tex]

So, the volume is:

[tex]V = \pi * 2^2 * 8[/tex]

[tex]V = \pi * (2)^2 (8)[/tex]

For the 6 marbles, we have:

[tex]d = 3[/tex] --- the diameter of each

The shape of the marble is a sphere. So, the volume of 1 marble is:

[tex]V = \frac{4}{3}\pi r^3[/tex]

The radius of 1 marble is:

[tex]r = d/2 = 3/2 = 1.5[/tex]

So, the volume of 1 marble is:

[tex]V_1 = \frac{4}{3} * \pi * (1.5)^3[/tex]

Multiply both sides by 6 to get the volume of the 6 marbles

[tex]6 * V_1 = 6 * \frac{4}{3} * \pi * (1.5)^3[/tex]

[tex]6V_1 = 6 * \frac{4}{3} * \pi * (1.5)^3[/tex]

[tex]6V_1 = 6 (\frac{4}{3} \pi (1.5)^3)[/tex]

Recall that the volume of the cylinder is:

[tex]V = \pi * (2)^2 (8)[/tex]

The volume of the water in the marble is the difference between the volume of the cylinder and the volume of the 6 marbles

So, we have:

[tex]Volume = \pi (2)^2(8) - 6 (\frac{4}{3} \pi (1.5)^3)[/tex]

The expression [tex]V = \pi \cdot (2\,in)^{2}\cdot (8\,in) -6\cdot \left[\frac{4\pi}{3}\cdot (1.5\,in)^{3} \right][/tex] can be used to calculate the volume of water in the vase.

As vase is of cylindrical form and the six marbles are spherical, we shall derived an expression from volume formulas respective to Cylinder and Spheres. Firstly, we know that volume of water in the vase is equal to the Volume of the vase minus the volume occupied by the six marbles, that is to say:

[tex]V = V_{v}-6\cdot V_{m}[/tex] (1)

Where:

[tex]V_{v}[/tex] - Volume of the vase, in cubic inches.

[tex]V_{m}[/tex] - Volume of the marble, in cubic inches.

[tex]V[/tex] - Volume of water in the vase, in cubic inches.

Then, we expand (1) by volume formulas for the cylinder and sphere:  

[tex]V = \pi\cdot R^{2}\cdot H - 6\cdot \left(\frac{4\pi}{3} \cdot r^{3} \right)[/tex] (2)

Where:

[tex]R[/tex] - Radius of the vase, in inches.

[tex]H[/tex] - Height of the vase, in inches.

[tex]r[/tex] - Radius of the marble, in inches.

If we know that [tex]R = 2\,in[/tex], [tex]H = 8\,in[/tex], [tex]r = 1.5\,in[/tex], then the following expression can be used to calculate the volume of water in the base:

[tex]V = \pi \cdot (2\,in)^{2}\cdot (8\,in) -6\cdot \left[\frac{4\pi}{3}\cdot (1.5\,in)^{3} \right][/tex]

In a nutshell, the expression [tex]V = \pi \cdot (2\,in)^{2}\cdot (8\,in) -6\cdot \left[\frac{4\pi}{3}\cdot (1.5\,in)^{3} \right][/tex] can be used to calculate the volume of water in the vase.