Answer:
So the answer is the first one
When I visit a local cafe, there's an $80\%$ probability that I'll order a sandwich, and a $70\%$ probability that I'll order a soup. If there's a $5\%$ probability that I don't order the sandwich or soup, then what's the probability that I order both the sandwich and soup
Answer:
There is 55% probability that I order both the sandwich and soup
Step-by-step explanation:
P(sandwich) = 0.8
P(Soup) = 0.7
P(neither sandwich nor soup) = 0.05
P(sandwich or soup) = 1 - P(neither sandwich nor soup)
P(sandwich or soup) = 1 - 0.05 = 0.95
P(Sandwich & Soup) = x
P(Sandwich only) = 0.8 - x
P(Soup only) = 0.7 - x
P(sandwich or soup) = P(Sandwich only) + P(Soup only) + P(Sandwich & Soup)
Note that P(neither sandwich nor soup) has already been used to get the P(sandwich or soup) and should not be included in the above formula. Don't make that mistake!
0.95 = 0.8 - x + 0.7 - x + x
0.95 = 1.50 - x
x = 1.50 - 0.95
x = 0.55
There is 55% probability that I order both the sandwich and soup
% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidence in newspapers is (a) exactly five, (b) at least six, and (c) less than four.
Complete Question:
41% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidence in newspapers is (a) exactly five, (b) at least six, and (c) less than four.
Answer:
a) P(exactly 5) = 0.209
b) P(at least six) = 0.183
c) P(less than four) = 0.358
Step-by-step explanation:
Sample size, n = 10
Proportion of adults that have very little confidence in newspapers, p = 41% p = 0.41
q = 1 - 0.41 = 0.59
This is a binomial distribution question:
[tex]P(X=r) = nCr p^{r} q^{n-r}[/tex]
a) P(exactly 5)
[tex]P(X=5) = 10C5 * 0.41^{5} 0.59^{10-5}\\P(X=5) = 10C5 * 0.41^{5} 0.59^{10-5}\\P(X=5) = 252 * 0.01159 * 0.072\\P(X=5) = 0.209[/tex]
b) P(at least six)
[tex]P(X \geq 6) = P(6) + P(7) + P(8) + P(9) + P(10)[/tex]
[tex]P(X\geq6) = (10C6 * 0.41^6*0.59^4) + (10C7*0.41^7*0.59^3) + (10C8*0.41^8*0.59^2) + (10C9 *0.41^9*0.59^1) + (10C10 *0.41^{10})\\P(X\geq6) = 0.1209 + 0.0480 + 0.0125 + 0.0019 + 0.0001\\P(X\geq6) = 0.183[/tex]
c) P(less than four)
[tex]P(X < 4) = 1 - [x \geq 4][/tex]
[tex]P(X<4)= 1 - [P(4) + P(5) + P(x \geq 6)][/tex]
[tex]P(X <4)= 1 - [(10C4*0.41^4*0.59^6) + 0.209 + 0.183]\\P(X <4)= 0.358[/tex]
3) For a certain good we have LaTeX: q=f\left(p\right)=200e^{-0.4p}q = f ( p ) = 200 e − 0.4 p.
a) Find the elasticity of demand at price p = $50.
b) At p = $50, is the demand elastic, inelastic, or does it have unit elasticity? Explain what this means for this product.
c) Find the elasticity of demand at price p = $20.
d) At p = $20, is the demand elastic, inelastic, or does it have unit elasticity? Explain what this means for this product.
Answer:
(a)20
(b)Elastic
(c)8
(d) Elastic
Step-by-step explanation:
Elasticity of demand(E) indicates the impact of a price change on a product's sales.
The general formula for an exponential demand curve is given as:
[tex]y=ae^{-bp}[/tex]
Given the demand curve formula
[tex]q=f\left(p\right)=200e^{-0.4p}[/tex]
The formula for Elasticity of demand, E
[tex]E = -\dfrac{p}{q}\dfrac{\text{d}q}{\text{d}p}[/tex]
(a)When Price, p = $50
p=50
[tex]q=200e^{-0.4*50}=200e^{-20}[/tex]
[tex]\dfrac{\text{d}q}{\text{d}p}=-0.4*200e^{-0.4p}=-80e^{-0.4p}[/tex]
Therefore:
[tex]E = -\dfrac{50}{200e^{-20}}*-80e^{-0.4*50}\\=\dfrac{1}{4e^{-20}}*80e^{-20}\\\\E=20[/tex]
(b)At p = $50, Since elasticity is greater than 1, the demand is elastic.
An elasticity value of 20 means that a 1% increase in price causes a 20% decrease in demand.
(c)At p=$20
p=20
[tex]q=200e^{-0.4*20}=200e^{-8}[/tex]
[tex]\dfrac{\text{d}q}{\text{d}p}=-0.4*200e^{-0.4p}=-80e^{-0.4p}[/tex]
Therefore:
[tex]E = -\dfrac{20}{200e^{-8}}*-80e^{-0.4*20}\\=\dfrac{1}{10e^{-20}}*80e^{-20}\\\\E=8[/tex]
(d)At p = $20, the demand is elastic.
An elasticity value of 8 means that a 1% increase in price causes a 8% decrease in demand.
Find the GCF of -10c2d and 15 ca2
Answer:
5c
Step-by-step explanation:
5c is the only value you can take out of both factors
Is 343060 divisible by 8?
Answer:
no 8 is not divisible to 343060
is csc2 x + sec2x=1 an identity
Answer:
Step-by-step explanation:
=
sin
2
x
+
cos
2
x
sin
2
x
cos
2
x
=
1
Answer:
explanation is below happy to help ya!
Step-by-step explanation:
Find the general solution of the simple homogeneous "system" below, which consists of a single linear equation. Give your answer as a linear combination of vectors. Let x2 and x3 be free variables. 3x1 - 6x2 9x3
Answer:
[tex]= \left[\begin{array}{ccc}x_1\\x_2\\x_3\end{array}\right] = x_2 \left[\begin{array}{ccc}2\\1\\0\end{array}\right] + x_3 \left[\begin{array}{ccc}-3\\0\\1\end{array}\right][/tex]
Step-by-step explanation:
Given: 3x1 - 6x2 + 9x3 = 0
x2 and x3 are free variables
We have:
3x1 = 6x2 - 9x3
divide all sides by 3, we have:
x1 = 2x2 - 3x3
Finding the general solution, we have:
[tex] \left[\begin{array}{ccc}x_1\\x_2\\x_3\end{array}\right] = \left[\begin{array}{ccc}2x_2 - 3x_3\\x_2\\x_3\end{array}\right] [/tex]
[tex] = \left[\begin{array}{ccc}2x_2\\x_2\\0\end{array}\right] + \left[\begin{array}{ccc}-3x_3\\0\\x_3\end{array}\right][/tex]
[tex]= x_2 \left[\begin{array}{ccc}2\\1\\0\end{array}\right] + x_3 \left[\begin{array}{ccc}-3\\0\\1\end{array}\right][/tex]
The general solution is
[tex]= \left[\begin{array}{ccc}x_1\\x_2\\x_3\end{array}\right] = x_2 \left[\begin{array}{ccc}2\\1\\0\end{array}\right] + x_3 \left[\begin{array}{ccc}-3\\0\\1\end{array}\right][/tex]
The city manager made a scatter plot of the number of retail stores in a
city over many years. The trend line for the scatter plot has the equation y =
11x + 12, where y is the total number of stores and x is the number of years
after 1990. Predict how many retail stores there were in 1997.
Answer:
There were 89 retail stores in 1997.
Step-by-step explanation:
You know:
y = 11*x + 12
where y is the total number of stores and x is the number of years after 1990.
Being this a linear function (Linear functions are those functions that have the form y = mx + b as it happens in this case), to know the total number of stores and, then you must know the value of x, that is, the number of years after 1990, and replace that value in the given function.
To find out how many retail stores there were in 1997, then since 1990 7 years have passed, calculated by subtracting: 1997 - 1990 = 7
So, 7 is the number of years after 1990, then x=7
Replacing in the function y=11*x + 12 you get:
y=11*7+12
Solving:
y=77+12
y=89
There were 89 retail stores in 1997.
A real estate agent has 17 properties that she shows. She feels that there is a 40% chance of selling any one property during a week. The chance of selling any one property is independent of selling another property. Compute the probability of selling less than 5 properties in one week. Round your answer to four decimal places.
Answer:
0.126 = 12.6% probability of selling less than 5 properties in one week.
Step-by-step explanation:
For each property, there are only two possible outcomes. The chance of selling any one property is independent of selling another property. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
A real estate agent has 17 properties that she shows.
This means that [tex]n = 17[/tex]
She feels that there is a 40% chance of selling any one property during a week.
This means that [tex]p = 0.4[/tex]
Compute the probability of selling less than 5 properties in one week.
[tex]P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)[/tex]
In which
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{17,0}.(0.4)^{0}.(0.6)^{17} = 0.0002[/tex]
[tex]P(X = 1) = C_{17,1}.(0.4)^{1}.(0.6)^{16} = 0.0019[/tex]
[tex]P(X = 2) = C_{17,2}.(0.4)^{2}.(0.6)^{15} = 0.0102[/tex]
[tex]P(X = 3) = C_{17,3}.(0.4)^{3}.(0.6)^{14} = 0.0341[/tex]
[tex]P(X = 4) = C_{17,4}.(0.4)^{4}.(0.6)^{13} = 0.0796[/tex]
[tex]P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0002 + 0.0019 + 0.0102 + 0.0341 + 0.0796 = 0.126[/tex]
0.126 = 12.6% probability of selling less than 5 properties in one week.
You are given 2 to 1 odds against tossing three heads with three coins, meaning you win $2 if you succeed and you lose $1 if you fail. Find the expected value (to you) of the game. Would you expect to win or lose money in 1 game? In 100 games? Explain.
Answer:
- $0.625
Step-by-step explanation:
To win 3 heads must be obtained, the probability of this is:
p = (1/2) ^ 3 = 0.125
Now, let's review the other scenarios:
HHH -> 0.125
HHT
THH ----> p (2H, 1T) = 3 * 0125 = 0.375
HTH
HTT
TTH ----> p (1H, 2T) = 3 * 0125 = 0.375
THT
TTT -> 0.125
So the waiting value would be:
EV = 2 * 0.125 - 1 * 0.375 - 1 * 0.375 - 1 * 0.125
EV = - 0.625
That is to say that the waiting value is - $ 0.625
The outcome og 1 game cannot be predicted but 100 you loss because the expected value is negative
The waiting value would be "-$0.625", the expected value will be negative so the outcome of game 1 can't be predicted but the 100 games you lose.
According to the question,
Three heads must be obtained to win.The probability will be:
→ [tex]p= (\frac{1}{2} )^3[/tex]
[tex]= 0.125[/tex]
Now,
HHH:
→ 0.125
THH:
→ [tex]p(2H, 1T) = 3\times 0.125[/tex]
[tex]= 0.375[/tex]
TTH:
→ [tex]p(1H, 2T) = 3\times 0.125[/tex]
[tex]= 0.375[/tex]
hence,
The waiting value will be:
→ [tex]EV = 2\times 0.125 -1\times 0.375-1\times -0.375-1\times 0.125[/tex]
[tex]= -0.625[/tex]
Thus the above response is correct.
Learn more:
https://brainly.com/question/13753898
Find the relationship between zeros and x-intercepts of a2 + 5a + 6.
Answer:
The x-intercepts, or zeros, which are the values of x(or a in this problem) for which the function is 0, are x = a = -2 and x = a = -3.
Step-by-step explanation:
Suppose we have a function y = f(x). The zeros, which are the values of x for which y = 0, are also called the x-intercepts of the function.
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
[tex]ax^{2} + bx + c, a\neq0[/tex].
This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:
[tex]x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}[/tex]
[tex]x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}[/tex]
[tex]\bigtriangleup = b^{2} - 4ac[/tex]
In this question:
I will write the function as a function of x, just exchanging a for x.
[tex]f(x) = x^{2} + 5x + 6[/tex]
[tex]\bigtriangleup = 5^{2} - 4*1*6 = 1[/tex]
[tex]x_{1} = \frac{-5 + \sqrt{1}}{2*1} = -2[/tex]
[tex]x_{2} = \frac{-5 - \sqrt{1}}{2*1} = -3[/tex]
The x-intercepts, or zeros, which are the values of x(or a in this problem) for which the function is 0, are x = a = -2 and x = a = -3.
Solve for e - 9e+4=−5e+14+13e
Answer:
e=1o ajjajajajajkananwnwnwhhshssh
The formula for the volume of a cube of side length L is: V = L X L X L What is the value of V when L= 5? *
Solution,
Length=5
Volume of cube=(L)^3
= 5*5*5
=125
hope it helps
Good luck on your assignment
Consider the following system of linear equations: Instructions: Solve the system by reducing its augmented matrix to reduced row echelon form (RREF). Yes, you must reduce it all the way to RREF. Write out the matrix at each step of the procedure, and be specific as to what row operations you use in each step. At the end of the procedure, clearly state the solution to the system outside of a matrix. 1. If the solution is unique, express the solution in real numbers. 3. If there are infinitely many solutions, express the solution in parameter(s). 3. If there is no solution, say so, and explain why.All of the following are possible ranks of a 4x3 matrix except:0123 4 How is the number of parameters in the general solution of a consistent linear system related to the rank of its coefficient matrix? Let r= number of rows in the coefficient matrix c= number of columns in the coefficient matrix p= number of parameters in the general solution R=rank of the coefficient matrix 1. R=p+r 2. R=C+p 3. R=r-p 4. R=C-p 5. R=p-
Answer:
Consider the following system of linear equations: 2 + 3y + 2z = 5 - 2x + y - z= -2 2x + 3z = 11 Instructions: • Solve the system by reducing its augmented matrix to reduced row echelon form (RREF). Yes, you must reduce it all the way to RREF. • Write out the matrix at each step of the procedure, and be specific as to what row operations you use in each step. • At the end of the procedure, clearly state the solution to the system outside of a matrix. • If the solution is unique, express the solution in real numbers. • If there are infinitely many solutions, express the solution in parameter(s). . If there is no solution, say so, and explain why.
All of the following are possible ranks of a 4x3 matrix EXCEPT O 1 2 3 4
How is the number of parameters in the general solution of a consistent linear system related to the rank of its coefficient matrix? Let r= number of rows in the coefficient matrix c= number of columns in the coefficient matrix p= number of parameters in the general solution R=rank of the coefficient matrix 1. R=p+r 2. R=C+p 3. R=r-p 4. R=C-p 5. R=p-r
Step-by-step explanation:
x + 3y +2z = 5
-2x + y - z = -2
2x + 3z = 11
Here,
[tex]A = \left[\begin{array}{ccc}1&3&2\\-2&1&-1\\2&0&3\end{array}\right][/tex]
[tex]B =\left[\begin{array}{ccc}5\\-2\\11\end{array}\right][/tex]
[tex]X=\left[\begin{array}{ccc}x\\y\\z\end{array}\right][/tex]
i.e AX=B
We can write as augmented matrix
[tex]\left[\begin{array}{ccc|c}1&3&2&5\\-2&1&-1&-2\\2&0&3&11\end{array}\right][/tex]
[tex]\frac{R_2\rightarrow R_2+2R_1}{R_3\rightarrow R_3-2R_1} \left[\begin{array}{ccc|c}1&3&2&5\\0&7&3&8\\0&-6&-1&1\end{array}\right][/tex]
[tex]\frac{R_3\rightarrow R_3+\frac{6R_2}{7} }{R_1\rightarrow R_1-\frac{3R_2}{7} } \left[\begin{array}{ccc|c}1&0&5/7&11/7\\0&7&3&8\\0&0&11/7&55/7\end{array}\right][/tex]
[tex]\frac{R_2\rightarrow\frac{R_2}{7}}{R_3\rightarrow\frac{7}{11}R_3} \left[\begin{array}{ccc|c}1&0&5/7&11/7\\0&1&3/7&8/7\\0&0&11/7&55/7\end{array}\right][/tex]
[tex]\frac{R_1\rightarrow R_1 -\frac{5}{7}R_3}{R_2\rightarrow R_2 -\frac{3}{7}R_3} \left[\begin{array}{ccc|c}1&0&0&-2\\0&1&0&-1\\0&0&1&5\end{array}\right][/tex]
Since Rank (A|B) = Rank (A) = 3 = number of variables
⇒ systems has unique solution and x = -2 , y = -1 , z = 5In the Journal of Shell and Spatial Structures (December 1963), environmental researcher Vivek Ajmani studied the performance of truss and frame structures subjected to uncertain loads. The load was assumed to have a normal distribution with a mean of 20,000 pounds. Also, the probability that the load is between 10,000 and 30,000 pounds is 0.95. Based on this information, find the standard deviation of the load distribution. Put your answer in three decimal places.
Answer:
The standard deviation of the load distribution is of 5102.041 pounds.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 20000[/tex]
Also, the probability that the load is between 10,000 and 30,000 pounds is 0.95.
10,000 pounds and 30,000 pounds are equidistant from the mean. Due to this, and the probability of 0.95 of having a value in this range, 10000 is the (100-95)/2 = 2.5th percentile and 30000 is the (100+95)/2 = 97.5th percentile. Applying one of them, we find the standard deviation.
30,000 is the 97.5th percentile:
This means that when X = 30000, Z has a pvalue of 0.975. So when X = 30000, Z = 1.96. Then
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]1.96 = \frac{30000 - 20000}{\sigma}[/tex]
[tex]1.96\sigma = 10000[/tex]
[tex]\sigma = \frac{10000}{1.96}[/tex]
[tex]\sigma = 5102.041[/tex]
The standard deviation of the load distribution is of 5102.041 pounds.
Petra jogs 5 miles in 40 minutes. At this rate, how long would it take her to jog 11 miles?
AHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH
Answer:
88 mins
Step-by-step explanation:
Divide 40 by 5 to get 8. That is your mile per minute ratio. Then multiply 11 by 8 to get the time of 11 miles!
What is the mean for the data set? 138,142,105,112,108,134,106,181,164,105
Write an equation that represents the following:
The ages of two sisters are consecutive integers . The sum of the older sister's age and three times the younger sister's age is 61.
Answer:
(o+y) + 3y = 61
to solve divide by 5 because there is 4 younger sister age + 1 for the older sister. 61-1=60. we subtract because the sister is older by 1 year
60/5=12 so the younger sister is 12
(13+12) + 36 = 61
Consecutive means in order like 3,4,5 or 11,12,13
Hope this helps
Step-by-step explanation:
during each cycle, the velocity v (in meters per second) of a robotic welding device is given by v=9t-2/9+t^2, where t is time in seconds. find the expression for the displacement s (in meters) as a function of t if s=0 when t=0.
Answer:
[tex]d = \dfrac{9t^{2} }{2} - \dfrac{2}{9} t + \dfrac{t^3}{3}[/tex]
Step-by-step explanation:
Given the equation of velocity w.r.to time 't':
[tex]v=9t-\dfrac{2}{9}+t^2 ...... (1)[/tex]
Formula for Displacement:
[tex]Displacement = \text{velocity} \times \text{time}[/tex]
So, if we find integral of velocity w.r.to time, we will get displacement.
[tex]\Rightarrow \text{Displacement}=\int {v} \, dt[/tex]
[tex]\Rightarrow \int {v} \, dt = \int ({9t-\dfrac{2}{9}+t^2}) \, dt \\\Rightarrow \int{9t} \, dt - \int{\dfrac{2}{9}} \, dt + \int{t^2} \, dt\\\Rightarrow s=\dfrac{9t^{2} }{2} - \dfrac{2}{9} t + \dfrac{t^3}{3} + C ....... (1)[/tex]
Here, C is constant (because it is indefinite integral)
Formula for integration used:
[tex]1.\ \int({A+B}) \, dx = \int {A} \, dx + \int{B} \, dx \\2.\ \int({A-B}) \, dx = \int {A} \, dx - \int{B} \, dx \\3.\ \int{x^{n} } \, dx = \dfrac{x^{n+1}}{n+1}\\4.\ \int{C } \, dx = Cx\ \{\text{C is a constant}\}[/tex]
Now, it is given that s = 0, when t = 0.
Putting the values in equation (1):
[tex]0=\dfrac{9\times 0^{2} }{2} - \dfrac{2}{9}\times 0 + \dfrac{0^3}{3} + C\\\Rightarrow C = 0[/tex]
So, the equation for displacement becomes:
[tex]s=\dfrac{9t^{2} }{2} - \dfrac{2}{9} t + \dfrac{t^3}{3}[/tex]
In a data distribution, the first quartile, the median and the means are 30.8, 48.5 and 42.0 respectively. If the coefficient skewness is −0.38
a) What is the approximate value of the third quartile (Q3 ), correct to 2 decimal places.
b)What is the approximate value of the variance, correct to the nearest whole number
Answer:
a) The third quartile Q₃ = 56.45
b) The variance = 2633.31
Step-by-step explanation:
a) The coefficient of skewness formula is given as follows;
[tex]SK = \dfrac{Q_{3}+Q_{1}-2Q_{_{2}}}{Q_{3}-Q_{1}}[/tex]
Plugging in the values, we have;
[tex]-0.38 = \dfrac{Q_{3}+30.8-2 \times 48.5_{_{}}}{Q_{3}-30.8}[/tex]
Solving gives Q₃ = 56.45
b) To determine the variance, we use the skewness formula as follows;
[tex]SK_{p} = \dfrac{Mean-\left (3\times Median - 2\times Mean \right )}{\sigma } = \dfrac{3\times\left ( Mean - Median \right )}{\sigma }[/tex]
Plugging in the values, we get;
[tex]-0.38= \dfrac{42-\left (3\times 48.5- 2\times 42\right )}{\sigma } = \dfrac{-19.5}{\sigma}[/tex]
[tex]\therefore \sigma =\dfrac{-19.5}{-0.38} = 51.32[/tex]
The variance = σ² = 51.32² = 2633.31.
The reading speed of second grade students in a large city is approximately normal, with a mean of 90 words per
minute (wpm) and a standard deviation of 10 wpm. Complete parts (a) through (f).
-
(b) What is the probability that a random sample of 10 second grade students from the city results in a mean
reading rate of more than 96 words per minute?
The probability is ___
(Round to four decimal places as needed.)
Answer:
The probability that a random sample of 10 second grade students from the city results in a mean reading rate of more than 96 words per minute
P(x⁻>96) =0.0359
Step-by-step explanation:
Explanation:-
Given sample size 'n' =10
mean of the Population = 90 words per minute
standard deviation of the Population =10 wpm
we will use formula
[tex]Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }[/tex]
Let X⁻ = 96
[tex]Z = \frac{96-90 }{\frac{10}{\sqrt{10} } }[/tex]
Z = 1.898
The probability that a random sample of 10 second grade students from the city results in a mean reading rate of more than 96 words per minute
[tex]P(X^{-}>x^{-} ) = P(Z > z^{-} )[/tex]
= 1- P( Z ≤z⁻)
= 1- P(Z<1.898)
= 1-(0.5 +A(1.898)
= 0.5 - A(1.898)
= 0.5 -0.4641 (From Normal table)
= 0.0359
Final answer:-
The probability that a random sample of 10 second grade students from
= 0.0359
Rangers tagged and released 300 salmon into a Maine lake. A
month later, fishermen on the lake were surveyed. They reported
catching 80 salmon, 12 of which had tags. Using this sample,
estimate the salmon population in the lake.
Answer:
2,000 salmon
Step-by-step explanation:
The point estimate of the fraction of salmon that corresponds to the tagged Salmon released by the rangers, based on the fishermen report, is:
[tex]p = \frac{12}{80}\\p=0.15[/tex]
This means that the 300 salmon released into the lake correspond to 15% of the total salmon population. The estimate for the salmon population is:
[tex]P= \frac{300}{0.15}\\P=2,000\ salmon[/tex]
The estimate is 2,000 salmon.
Answer:
The estimate of the salmon population will be 2,000
Step-by-step explanation:
Rangers tagged and released 300 salmon into a Maine lake.
The fishermen reported catching 80 salmon of which 12 had tags
Thus we have 12/80 as a fraction of the tagged and released 300
12/80 = 0.15 which is about 15% of the population of tagged and released 300.
To then estimate the salmon population, we have 300/0.15 = 2,000
Hallar el área y el perímetro de un rombo cuyas diagonales menor y mayor miden, respectivamente,10 cm y 24 cm
Answer:
The area is 120 cm²
the perimeter is 52 cm
Step-by-step explanation:
The rhombus area is given by:
A = D * d / 2
that is, the larger diagonal D by the smaller diagonal d, between two, we know that D = 24 cm and d = 10 cm, replacing:
A = 24 * 10/2
A = 120
The area is 120 cm²
To calculate the perimeter use the Pythagorean theorem
h² = a² + b²
Since if you look at the rhombus it is formed by four right triangle we will take 1 of them with the following measures 5 cm (10/2) and height 12 cm (24/2) and replace:
h² = 5² + 12²
h² = 169
h = 13
now, the perimeter would be the sum of all its sides, which in this case are equal and measure 13 cm, therefore:
p = 4 * 13
p = 52
which means that the perimeter is 52 cm
which graph represents this equation 5y=x+5
Answer: A
Step-by-step explanation: 5y=x+5 simplified to slope-intercept form is y = 1/5x + 1
The equation 5y = x + 5 is a linear equaton, and the graph A represents the equation 5y = x + 5
How to determine the graph?The equation is given as:
5y = x + 5
Make x = 0.
So, we have:
5y = 0 + 5
This gives
5y = 5
So, we have:
y = 1
The point is represented as (0,1)
Make y = 0.
So, we have:
5 * 0 = x + 5
This gives
0 = x + 5
So, we have:
x = -5
The point is represented as (-5,0)
This means that the graph of 5y = x + 5 passes through the points (0,1) and (-5,0)
From the list of options, only graph (A) passes through the points (0,1) and (-5,0)
Hence, the graph A represents the equation 5y = x + 5
Read more about linear equations at:
https://brainly.com/question/14323743
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A wire 18cm long is cut into 2 pieces. the longer piece is 2 cm longer than the shorter piece. Find the lenght of the shorter piece
Answer:
8cm
Step-by-step explanation:
If the pieces are 8cm and 10cm they will still add up to 18cm but the longer piece is 2cm longer so both conditions are satisfied.
Which of the following are solutions to the quadratic equation x squared plus 8x=9
Answer:
X=1 x=-9
Step-by-step explanation:
(x^2)+8x=9
(x^2)+8x-9=0
(x-1)(x+9)=0
x=1 x=-9
coin is tossed and an eight-sided die numbered 1 through 8 is rolled. Find the probability of tossing a tail and then rolling a number greater than 5. The probability of tossing a tail and then rolling a number greater than 5 is nothing. (Round to three decimal places as needed.)
Answer:
The probability of tossing a tail and then rolling a number greater than 5 is 0.188
Step-by-step explanation:
Independent events:
If two events, A and B, are independent, we have that:
[tex]P(A \cap B) = P(A)*P(B)[/tex]
In this question:
The coin and the die are independent. So
Event A: Tossing a tail.
Event B: Rolling a number greater than 5.
Probability of tossing a tail:
Coin can be heads or tails(2 outcomes), so the probability of a tail is [tex]P(A) = \frac{1}{2} = 0.5[/tex]
Probability of rolling a number greater than 5:
8 numbers(1 through 8), 3 of which(6,7,8) are greater than 5. So the probability of rolling a number greater than 5 is [tex]P(B) = \frac{3}{8} = 0.375[/tex]
Probability of A and B:
[tex]P(A \cap B) = P(A)*P(B) = 0.5*0.375 = 0.188[/tex]
The probability of tossing a tail and then rolling a number greater than 5 is 0.188
What is the sum of 8 and 10?
Answer:
18
Step-by-step explanation:
pls mark brainliest
idk if this is a joke
What is 2 3/4 in a decimal format
Answer:
2.5
Step-by-step explanation:
Answer:
2.75
Step-by-step explanation:
2 x 4=8 + 3=11/4=2.75
What is the quotient of (x^3+3x^2+5x+3) divided by (x+1)
Answer:
x^2+2x+3 I sent the answer