Answer:
Weight of the car F = m*g ; Here, g = 9.81 N/kg ;
So, we can find from the formula mentioned above m = F/g ;
Mass m is equal about 764 kg.
Explanation:
A force is applied to a 2.1 kg mass and produces 3 m/s- acceleration.
What acceleration would be produced by the same force applied to a 12.1 kg mass?
Answer in units of m/s2.
Answer:
f=m×a
f=2.1×3
f=6.3
f=ma
6.3=12.1a
a=0.52m/s²
Select the correct answer. In which situation is maximum work considered to be done by a force? A. The angle between the force and displacement is 180°. B. The angle between the force and displacement is 90°. C. The angle between the force and displacement is 60°. D. The angle between the force and displacement is 45°. E. The angle between the force and displacement is 0°.
Answer:
A. The angle between the force and displacement is 180°.
Answer:
a
Explanation:
PLEASE ANSWER
For an object launched horizontally the acceleration in the y direction will always be ____.
Answer: initial velocity in y direction
Explanation: coz i did dis before XD
A horse is riding 9m/s. In two seconds it slows down to 1m/s, what is the acceleration of the horse.
Answer:
-4m/s²
Explanation:
Given parameters:
Initial velocity = 9m/s
Final velocity = 1m/s
Time taken = 2s
Unknown:
Acceleration = ?
Solution:
The acceleration of a body is the change in velocity of a body with time.
Acceleration = [tex]\frac{Final velocity - Initial velocity }{time}[/tex]
Insert the parameters and solve;
Acceleration = [tex]\frac{1 - 9}{2}[/tex] = -4m/s²
We can say, the car is decelerating at a rate of 4m/s²
On a wall, there are several 1 - 4 mm elongated drops with a large bloody rectangular patch in the center. The rectangle's long side faces toward the bottom of the wall. Running through the pattern are four smear lines about 0.5 - 1 cm apart and perpendicular to the bottom of the wall. No other marks are found on the other walls. Which best explains the sequence of events?
A. The victim was hit in the head with a blunt object, his face hit the wall, and his hand slid down along the wall as he collapsed.
B. The victim was shot with a gun and collapsed on the floor beneath.
C. The victim's throat was cut and he collapsed on the floor.
D. The victim was stabbed and cut multiple times before collapsing on the floor.
Answer: this might be wrong but my answer is A.
Explanation: it said "Running through the pattern are four smear lines about 0.5 - 1 cm apart and perpendicular to the bottom of the wall." and "perpendicular" is like not that big and not that small and A is "and his hand slid down along the wall as he collapsed." so I think it is A.
If a cheetah can maintain a constant speed of 5.00 m/s, how far does it travel in 1.00 minute?
Answer: 300 m/m
Explanation: 5.00 m/s • 60 =300/m/m
A bowling ball is dropped from rest. What is the ball's velocity after falling for 5 seconds?
Equation: Vy =g*t
Answer:
545432344455555322 we 45year 7of and
What is a quantity Described completely by its magnitude
Answer:
Scalar
Explanation:
A physical quantity that is completely described by its magnitude; examples of scalars are volume, density, speed, energy, mass, and time. Other quantities, such as force and velocity, have both magnitude and direction and are called vectors.
Describe how resistance affects the flow of current in a circuit
what is a convalent bond
I JUST NEED A ANSWER DONT CARE WHAT IT IS
Answer: A covalent bond, also called a molecular bond, is a chemical bond that involves the sharing of electron pairs between atoms.
Hope that helps! :)
Manu takes 30 minutes from his house to reach his school on a bicycle. If the cycle has a speed of 4m/s find the difference between his house and the school.
Answer:
7200 m
Explanation:
From the question given above, the following data were obtained:
Time (t) = 30 mins
Speed (S) = 4 m/s
Distance (d) =.?
Next, we shall convert 30 mins to seconds. This can be obtained as follow:
1 mins = 60 s
Therefore,
30 mins = 30 mins × 60 s / 1 mins
30 mins = 1800 s
Thus, 30 mins is equivalent to 1800 s.
Finally, we shall determine the difference between Manu's house and his school by calculating the distance. This is illustrated below:
Time (t) = 1800 s
Speed (S) = 4 m/s
Distance (d) =.?
Speed = Distance /time
4 = Distance /1800
Cross multiply
Distance = 4 × 1800
Distance = 7200 m
Therefore, the difference between Manu's house and his school is 7200 m
A person weighing 645 N climbs up a ladder to a height of 4.55 m. What is the
increase in gravitational potential energy?
Answer:
P.E = 2934.75
Explanation:
Potential energy can be defined as an energy possessed by an object or body due to its position.
Mathematically, potential energy is given by the formula;
[tex] P.E = mgh[/tex]
Where, P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
Given the following data;
Weight =645
Height = 4.55
[tex] P.E = mgh[/tex]
But we know that weight = mg = 645N
Substituting into the equation, we have;
[tex] P.E = 645 * 4.55 [/tex]
[tex] P.E = 2934.75 J[/tex]
Potential energy, P.E = 2934.75 Joules.
In a transformer, the incoming primary voltage is 120 V. There are 100 windings in the primary coil. The secondary coil has 65 windings. What is the outgoing voltage of this transformer?
a
151.9 V
b
64.41 V
c
102.8 V
d
78.02 V
Answer:
78.02 V
Explanation:
Given that,
Primary voltage in a transformer is 120 V
No of windings in the primary coil is 100
No of windings in the secondary coil is 65
We need to find the outgoing voltage of the transformer. For a transformer, the ratio of primary voltage to the secondary voltage is equal to the ratio of turns in Primary coil to the turns in secondary coil are equal. So,
[tex]\dfrac{V_p}{V_s}=\dfrac{N_p}{N_s}\\\\\dfrac{120}{V_s}=\dfrac{100}{65}\\\\V_s=\dfrac{120\times 65}{100}\\\\V_s=78\ V[/tex]
So, out of the given options, the correct one is option (d) i.e. 78.02 V
A mischievous cat sees a flowerpot sitting at rest on a windowsill. If it takes 1.2 s for the flowerpot to fall from the window, how high up was the window?
Given that,
Initial speed of a cat is 0 because it was at rest.
If it takes 1.2 s for the flowerpot to fall from the window, we need to find the height reached by the cat.
Using second equation of motion to find it as follows :
[tex]d=ut+\dfrac{1}{2}at^2[/tex]
Put u = 0 and a = g
[tex]d=\dfrac{1}{2}gt^2\\\\d=\dfrac{1}{2}\times 9.8\times (1.2)^2\\\\d=7.05\ m[/tex]
So, it will move to a height of 7.05 m.
According to the fundamental law of nature called the conservation of energy, the total
amount of energy in a system _____ no matter what happens inside the system.
A) increases B)remains constant C)decreases
Answer: B, remains constant.
A 1.5 kg block is pulled across a horizontal surface that has a coefficient of kinetic friction of 0.60. a. What is the force of friction exerted by the surface on the block?
Answer: 8.82 N
Fg= (1.5) (9.8) = 14.7
Fk= (0.60) (14.7) = 8.82
1. What is the density of a piece of cork that has a mass of 0.65 g and a volume of 2.71 cm??
Answer:
0.240 g/cm3
Explanation:
3. A satellite orbits Earth at a constant speed.
What part of the satellite's motion is
changing?
A speed
B friction
C inertia
D acceleration
you weigh 500n,what stops you from falling to the center of the earth
Answer:
bedrock?
Explanation:
The ground is in the way.
A train slows down as it rounds a sharp horizontal turn, going from 100 km/h to 60.0 km/h in the 14.0 s it takes to round the bend. The radius of the circle is 160 m. Compute the total acceleration and the angle at the moment the train speed reaches 60.0 km/h.
Answer:
The magnitude of the total acceleration of the train is approximately 1.909 meters per square second.
The direction of total acceleration with respect to radial acceleration is approximately -24.578º.
Please note that negative sign indicates that train is decelerating.
Explanation:
From Physics, we know that magnitude of the acceleration experimented by the train ([tex]a[/tex]), measured in meters per square second, while rounding the bend is the Pythagorean identity involving radial and tangential accelerations ([tex]a_{r}[/tex], [tex]a_{t}[/tex]), measured in meters per square second:
[tex]a = \sqrt{a_{t}^{2}+a_{r}^{2}}[/tex] (Eq. 1)
If we assuming that train decelerates at constant rate, then each component is determined by following expressions:
[tex]a_{t} = \frac{v_{f}-v_{o}}{t}[/tex] (Eq. 2)
[tex]a_{r} = \frac{v_{f}^{2}}{R}[/tex] (Eq. 3)
Where:
[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds, measured in meters per second.
[tex]t[/tex] - Deceleration time, measured in seconds.
[tex]R[/tex] - Bend radius, measured in meters.
If we know that [tex]v_{o} = 27.778\,\frac{m}{s}[/tex], [tex]v_{f} = 16.667\,\frac{m}{s}[/tex], [tex]t = 14\,s[/tex] and [tex]R = 160\,m[/tex], then each acceleration component is calculated:
[tex]a_{t} = \frac{16.667\,\frac{m}{s}-27.778\,\frac{m}{s} }{14\,s}[/tex]
[tex]a_{t} = -0.794\,\frac{m}{s^{2}}[/tex]
[tex]a_{r} = \frac{\left(16.667\,\frac{m}{s} \right)^{2}}{160\,m}[/tex]
[tex]a_{r} = 1.736\,\frac{m}{s^{2}}[/tex]
Then, the magnitude of the total acceleration of the train is:
[tex]a = \sqrt{\left(-0.794\,\frac{m}{s^{2}} \right)^{2}+\left(1.736\,\frac{m}{s^{2}} \right)^{2}}[/tex]
[tex]a \approx 1.909\,\frac{m}{s^{2}}[/tex]
The magnitude of the total acceleration of the train is approximately 1.909 meters per square second.
After that, we obtain the angle of acceleration by using the following trigonometric expression:
[tex]\theta = \tan^{-1} \frac{a_{t}}{a_{n}}[/tex] (Eq. 4)
Where [tex]\theta[/tex] is the direction of total acceleration with respect to radial acceleration, measured in sexagesimal degrees.
If we get that [tex]a_{t} = -0.794\,\frac{m}{s^{2}}[/tex] and [tex]a_{r} = 1.736\,\frac{m}{s^{2}}[/tex], the direction of total acceleration experimented by the train is:
[tex]\theta = \tan^{-1}\left(\frac{-0.794\,\frac{m}{s^{2}} }{1.736\,\frac{m}{s^{2}} } \right)[/tex]
[tex]\theta \approx -24.578^{\circ}[/tex]
Please note that negative sign indicates that train is decelerating.
The direction of total acceleration with respect to radial acceleration is approximately -24.578º.
A man is walking toward the back of an airplane at 7 m/s. The plane is flying West at 245 m/s. What is the speed and direction of the plane relative to the man?
Answer:
The speed of the plane relative to the man is 245.1 m/s
The direction of the plane is S 88.36⁰ W
Explanation:
Given;
velocity of the man toward the airplane, Vy = 7 m/s
velocity of the airplane, Vx = 245 m/s west
The speed of the plane relative to man is given by;
<----------------------
↑
↑
↑
Complete this diagram to form a right angled triangle, with the hypotenuse as the relative velocity of the plan with respect to the man.
R² = 245² + 7²
R² = 60074
R = √60074
R = 245.1 m/s
The direction of the plane is given by;
tan θ = 245 / 7
tan θ = 35
θ = tan ⁻¹ (35)
θ = 88.36°
The direction of the plane is S 88.36⁰ W
What is the velocity of a car that travels 400meters in 16 seconds
Answer:
The answer is 25 m/sExplanation:
The velocity of the car can be found by using the formula
[tex]v = \frac{d}{t} \\ [/tex]
d is the distance
t is the time taken
From the question we have
[tex]v = \frac{400}{16} \\ [/tex]
We have the final answer as
25 m/sHope this helps you
A type of elevator called a cage is used to raise and lower miners in a mine
shaft. Suppose the cage carries a group of miners down the shaft. If the
unbalanced force on the cage is 60.0 N, and the mass of the loaded cage is
1.50 x 10²kg, what is the acceleration of the cage?
Answer:
Acceleration, a = 0.04 m/s²
Explanation:
Given the following data;
Force = 60N
Mass = 1500kg
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
[tex] F = ma[/tex]
Where;
F represents force.
m represents the mass of an object.
a represents acceleration.
Making acceleration (a) the subject, we have;
[tex]Acceleration (a) = \frac{F}{m}[/tex]
Substituting into the equation;
[tex]Acceleration (a) = \frac{60}{1500}[/tex]
Acceleration, a = 0.04 m/s²
Stacey sees a person pushing a lawn mower across level ground. She is
walking at constant speed and pushing the mower with constant force.
Could the lawn mower move faster than the person is walking?
Answer:
No, the lawn mover will maintain the same speed as the person pushing itExplanation:
To understand this, we need to reflect back to the law of motion, the first law to be précised.
It states that "A body will continue to be at rest or uniform/constant motion unless acted upon by an external force which is greater than the current force"
So we can see that since the person continues to apply the same force at the same speed, the effect on the mover will be the same.
Help plz
Which of the following graphs best represents the expected experimental data between the force of gravitational attraction between two varying masses positioned 1 m apart
Answer:
I'm pretty sure it's D
Explanation:
because the greater the mass, the greater the gravitational pull is on it. but you probably shouldn't take my word on it, lol
When two strands of DNA line up, adenine always pairs up with _____.
guanine
phosphate
thymine
cytosine
A car starts from a spotlight and is traveling with a velocity of 10 m/s Ein
20 seconds. What is the acceleration of the car?
Answer:
ANSWER
Initial Velocity (u) = 10 m/sec
Acceleration (a) = 5 m/sec
2
Distance (s) = 30 m
Final velocity (v) = ??
Using Newton's Third law of Motion,
v
2
=u
2
+2as
v
2
=10
2
+2×5×30
v
2
=100+300
v
2
=400
v =
400
v = 20 m/sec
_____________________________
ANSWER =
FINAL VELOCITY = 20 m/sec
Answered By
toppr
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Explanation:
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What is the net force on the runner below if the
applied force is + 40 N and the resistive force is -2
N?
Answer:
What is the net force on the runner below if the
applied force is + 40 N and the resistive force is -2
N?
Explanation:
What is the net force on the runner below if the
applied force is + 40 N and the resistive force is -2
N?
Ashley rides her bike 200 meters in 20 seconds. what is her speed?
Answer: 10 meters
Explanation:
Divide 200 by 20, for 20 seconds.
200 ÷ 20 = 10
The answer to the question is 10.
a rocket is fired upwards with an intial velocity of 46.5 m/s. find the rocket's maximum height
Answer:
The value is [tex]s = 110.32 \ m[/tex]
Explanation:
From the question we are told that
The initial velocity is u= 46.5 m/s
Generally from kinematic equations we have that
[tex]v^2 = u^2 + 2as[/tex]
Here [tex]a = -g = -9.8 \ m/s^2[/tex]
The negative sign is because it is moving against gravity
At maximum height v = 0 m/s
So
[tex]0 = (46.5)^2 + 2* (-9.8)s[/tex]
=> [tex]s = 110.32 \ m[/tex]
