what is the frictional force needed to slow an object in motion​

Answer:

Scalar

Explanation:

A physical quantity that is completely described by its magnitude; examples of scalars are volume, density, speed, energy, mass, and time. Other quantities, such as force and velocity, have both magnitude and direction and are called vectors.

Answer: 8.82 N

Fg= (1.5) (9.8) = 14.7

Fk= (0.60) (14.7) = 8.82

Answer:

What is the net force on the runner below if the

applied force is + 40 N and the resistive force is -2

N?

Explanation:

What is the net force on the runner below if the

applied force is + 40 N and the resistive force is -2

N?

Answer:

They subtract the atomic number from the atomic mass

Hope this helps

Please mark as the brainliest

Answer:

A.  The angle between the force and displacement is 180°.

Answer:

a

Explanation:

Amphibians retain a set of gills their whole lives that help them to breathe in the water. So, the correct option is D.

Amphibians are defined as the class of cold-blooded vertebrates which is made up of frogs, toads, salamanders, newts, and caecilians. All amphibians that spend part of their lives in water and part of their lives on land.

Amphibians are born with gills, and some outgrow them when they become adults while others retain them for their entire lives.

Thus, the correct option is D.

Learn more about Amphibians, here:

https://brainly.com/question/14213726

#SPJ1

Answer:

its c. 9km

Explanation:

Because it you add the 4km+5km that gives you a total of 9km

Answer: 300 m/m

Explanation: 5.00 m/s • 60 =300/m/m

Answer:

Explanation:

The velocity of the car can be found by using the formula

[tex]v = \frac{d}{t} \\ [/tex]

d is the distance

t is the time taken

From the question we have

[tex]v = \frac{400}{16} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

it's when the water in water in plants is evaporated and turned into water vapor

Explanation:

hope it helps

Answer:

0.240 g/cm3

Explanation:

Answer:

ANSWER

Initial Velocity (u) = 10 m/sec

Acceleration (a) = 5 m/sec

2

Distance (s) = 30 m

Final velocity (v) = ??

Using Newton's Third law of Motion,

v

2

=u

2

+2as

v

2

=10

2

+2×5×30

v

2

=100+300

v

2

=400

v =

400

v = 20 m/sec

_____________________________

ANSWER =

FINAL VELOCITY = 20 m/sec

Answered By

toppr

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More Questions by difficulty

EASY

MEDIUM

HARD

Explanation:

it's easy

Answer:

The value is [tex]s = 110.32 \ m[/tex]

Explanation:

From the question we are told that

   The initial velocity is  u=  46.5 m/s

Generally from kinematic equations we have that

     [tex]v^2 = u^2 + 2as[/tex]

Here  [tex]a = -g = -9.8 \ m/s^2[/tex]

   The negative sign is because it is moving against gravity

At maximum height v =  0 m/s        

So

     [tex]0 = (46.5)^2 + 2* (-9.8)s[/tex]

=>   [tex]s = 110.32 \ m[/tex]

Answer:

I'm pretty sure it's D

Explanation:

because the greater the mass, the greater the gravitational pull is on it. but you probably shouldn't take my word on it, lol

Answer:

Acceleration, a = 0.04 m/s²

Explanation:

Given the following data;

Force = 60N

Mass = 1500kg

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

[tex] F = ma[/tex]

Where;

F represents force.

m represents the mass of an object.

a represents acceleration.

Making acceleration (a) the subject, we have;

[tex]Acceleration (a) = \frac{F}{m}[/tex]

Substituting into the equation;

[tex]Acceleration (a) = \frac{60}{1500}[/tex]

Acceleration, a = 0.04 m/s²

Answer:

The speed of the plane relative to the man is 245.1 m/s

The direction of the plane is S 88.36⁰ W

Explanation:

Given;

velocity of the man toward the airplane, Vy = 7 m/s

velocity of the airplane, Vx = 245 m/s west

The speed of the plane relative to man is given by;

<----------------------

                          ↑

                          ↑

                          ↑

Complete this diagram to form a right angled triangle, with the hypotenuse as the relative velocity of the plan with respect to the man.

R² = 245² + 7²

R² = 60074

R = √60074

R = 245.1 m/s

The direction of the plane is given by;

tan θ = 245 / 7

tan θ = 35

θ = tan ⁻¹ (35)

θ = 88.36°

The direction of the plane is S 88.36⁰ W

Answer:

bedrock?

Explanation:

The ground is in the way.

Answer:

545432344455555322 we 45year 7of and

Answer:

V = 61.74m/s

Explanation:

Given the following data;

Acceleration due to gravity = 9.8m/s²

Time, t = 6.3 secs

Since it's a free fall, initial velocity = 0

Thus, to find the final velocity, we would use the first equation of motion;

[tex] V = U + at[/tex]

Substituting into the equation, we have;

[tex] V = 0 + 9.8 * 6.3[/tex]

V = 61.74m/s

Therefore, the final velocity is 61.74m/s

Answer:

f=m×a

f=2.1×3

f=6.3

f=ma

6.3=12.1a

a=0.52m/s²

Answer:

First, remember the conservation of energy.

We can define the kinetic energy as:

K = (1/2)*m*v^2

where m is the mass, and v is the velocity.

The velocity of the person is 6m/s, and the mass is unknown.

Now, when the person rides the skateboard, this kinetic energy must remain constant, if M is the mass of the skateboard, the speed after the person rides ir will be:

K' = (1/2)*(m + M)*v'^2

Where v' is the new velocity.

In this case, we can suppose that the skateboard has really small mass compared with the person.

M < < m

then:

(m + M) ≈ m

then:

K' = (1/2)*m*v'^2 = K = (1/2)*m*v^2

from that equation, we can conclude that:

v' = v

Then if the velocity before riding the skateboard was 6m/s, then after would be also 6m/s.

Answer: initial velocity in y direction

Explanation: coz i did dis before XD

Answer:

The magnitude of the total acceleration of the train is approximately 1.909 meters per square second.

The direction of total acceleration with respect to radial acceleration is approximately -24.578º.

Please note that negative sign indicates that train is decelerating.

Explanation:

From Physics, we know that magnitude of the acceleration experimented by the train ([tex]a[/tex]), measured in meters per square second, while rounding the bend is the Pythagorean identity involving radial and tangential accelerations ([tex]a_{r}[/tex], [tex]a_{t}[/tex]), measured in meters per square second:

[tex]a = \sqrt{a_{t}^{2}+a_{r}^{2}}[/tex] (Eq. 1)

If we assuming that train decelerates at constant rate, then each component is determined by following expressions:

[tex]a_{t} = \frac{v_{f}-v_{o}}{t}[/tex] (Eq. 2)

[tex]a_{r} = \frac{v_{f}^{2}}{R}[/tex] (Eq. 3)

Where:

[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds, measured in meters per second.

[tex]t[/tex] - Deceleration time, measured in seconds.

[tex]R[/tex] - Bend radius, measured in meters.

If we know that [tex]v_{o} = 27.778\,\frac{m}{s}[/tex], [tex]v_{f} = 16.667\,\frac{m}{s}[/tex], [tex]t = 14\,s[/tex] and [tex]R = 160\,m[/tex], then each acceleration component is calculated:

[tex]a_{t} = \frac{16.667\,\frac{m}{s}-27.778\,\frac{m}{s} }{14\,s}[/tex]

[tex]a_{t} = -0.794\,\frac{m}{s^{2}}[/tex]

[tex]a_{r} = \frac{\left(16.667\,\frac{m}{s} \right)^{2}}{160\,m}[/tex]

[tex]a_{r} = 1.736\,\frac{m}{s^{2}}[/tex]

Then, the magnitude of the total acceleration of the train is:

[tex]a = \sqrt{\left(-0.794\,\frac{m}{s^{2}} \right)^{2}+\left(1.736\,\frac{m}{s^{2}} \right)^{2}}[/tex]

[tex]a \approx 1.909\,\frac{m}{s^{2}}[/tex]

The magnitude of the total acceleration of the train is approximately 1.909 meters per square second.

After that, we obtain the angle of acceleration by using the following trigonometric expression:

[tex]\theta = \tan^{-1} \frac{a_{t}}{a_{n}}[/tex] (Eq. 4)

Where [tex]\theta[/tex] is the direction of total acceleration with respect to radial acceleration, measured in sexagesimal degrees.

If we get that [tex]a_{t} = -0.794\,\frac{m}{s^{2}}[/tex] and [tex]a_{r} = 1.736\,\frac{m}{s^{2}}[/tex], the direction of total acceleration experimented by the train is:

[tex]\theta = \tan^{-1}\left(\frac{-0.794\,\frac{m}{s^{2}} }{1.736\,\frac{m}{s^{2}} } \right)[/tex]

[tex]\theta \approx -24.578^{\circ}[/tex]

Please note that negative sign indicates that train is decelerating.

The direction of total acceleration with respect to radial acceleration is approximately -24.578º.

Answer:

5,600

Explanation:

You split x10^15 into x10^12 and x10^3. Our new equation is 5.6x10^3x10^12

We do 5.6x10^3 and we get 5,600. Our new equation is 5,600x10^12. I hope this answered your question.

Answer: A covalent bond, also called a molecular bond, is a chemical bond that involves the sharing of electron pairs between atoms. 

Hope that helps! :)

Answer:

7200 m

Explanation:

From the question given above, the following data were obtained:

Time (t) = 30 mins

Speed (S) = 4 m/s

Distance (d) =.?

Next, we shall convert 30 mins to seconds. This can be obtained as follow:

1 mins = 60 s

Therefore,

30 mins = 30 mins × 60 s / 1 mins

30 mins = 1800 s

Thus, 30 mins is equivalent to 1800 s.

Finally, we shall determine the difference between Manu's house and his school by calculating the distance. This is illustrated below:

Time (t) = 1800 s

Speed (S) = 4 m/s

Distance (d) =.?

Speed = Distance /time

4 = Distance /1800

Cross multiply

Distance = 4 × 1800

Distance = 7200 m

Therefore, the difference between Manu's house and his school is 7200 m

Answer:

78.02 V

Explanation:

Given that,

Primary voltage in a transformer is 120 V

No of windings in the primary coil is 100

No of windings in the secondary coil is 65

We need to find the outgoing voltage of the transformer. For a transformer, the ratio of primary voltage to the secondary voltage is equal to the ratio of turns in Primary coil to the turns in secondary coil are equal. So,

[tex]\dfrac{V_p}{V_s}=\dfrac{N_p}{N_s}\\\\\dfrac{120}{V_s}=\dfrac{100}{65}\\\\V_s=\dfrac{120\times 65}{100}\\\\V_s=78\ V[/tex]

So, out of the given options, the correct one is option (d) i.e. 78.02 V