what is the formula of the hydride formed by aluminum

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Answer 1

The formula of the hydride formed by aluminum is AlH3.A hydride is a compound that is formed by hydrogen and a less electronegative element, according to Chemistry.

In this case, the hydride is formed by aluminum, hence it is referred to as aluminum hydride.The formula of aluminum hydride is written as AlH3. It contains one aluminum atom and three hydrogen atoms. It is important to note that the ratio of aluminum to hydrogen in aluminum hydride is 1:3,

The bonding between aluminum and hydrogen in aluminum hydride is considered to be mostly covalent rather than ionic because aluminum is a metalloid and hydrogen is a nonmetal.

A bond between a metal and a nonmetal is usually ionic in nature. However, aluminum and hydrogen do not have enough of a difference in electronegativity for them to form an ionic bond. As a result, the bond is considered to be covalent.

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4. Fluorine-18 is used in PET scans. It has a nuclear half-life of 110 minutes and a biological half-life of 24.5 minutes. A radiopharmaceutical company packages and ships a 250.mg sample of F−18 for delivery to a hospital. By the time it arrives it is only 35.2mg. How much time had elapsed? Give your answer in hours

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The time elapsed between packaging and delivery is approximately 182.6 minutes, which is equivalent to 3.04 hours.

To solve this question, we can use the formula for radioactive decay:

A = A0 * e^(-kt)

Where:

A = Final amount

A0 = Initial amount

k = Decay constant

t = Time elapsed

Let's determine the decay constant, k. We can do this by using the formula:

t1/2 = (ln 2) / k

Where t1/2 is the half-life of the isotope.

Given that the nuclear half-life of Fluorine-18 is 110 minutes, we can substitute this value into the equation:

110 min = (ln 2) / k

Solving for k:

k = (ln 2) / 110 ≈ 0.00631 min^-1

Now, we can use the formula for radioactive decay to find the time elapsed. We know that the sample delivered to the hospital was 35.2 mg, while the original sample was 250 mg. Therefore, the fraction that remained after delivery is:

(amount remaining / initial amount) = A / A0 = 35.2 / 250 = 0.1408

Substituting this value, along with the other values we have, into the radioactive decay formula:

0.1408 = e^(-0.00631t)

Taking the natural logarithm on both sides, we get:

ln(0.1408) = -0.00631t

Solving for t, we find:

t = -ln(0.1408) / 0.00631 ≈ 182.6 minutes

Therefore, the time elapsed between packaging and delivery is approximately 182.6 minutes, which is equivalent to 3.04 hours. Hence, the answer is 3.04 hours.

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