Answer: y= x^2/16-6x/16+41/16
Step-by-step explanation:
The equation of a parabola will be; y = x^2/16 - 6x/16 + 41/16
What is vertex form of a quadratic equation?If a quadratic equation is written in the form
y=a(x-h)^2 + k
then it is called to be in vertex form. It is called so because when you plot this equation's graph, you will see vertex point(peak point) is on (h,k)
Otherwise, we had to use calculus to get critical points, then second derivative of functions to find the character of critical points as minima or maxima or saddle etc to get the location of vertex point.
This point (h,k) is called the vertex of the parabola that quadratic equation represents.
WE need to find the equation of a parabola that has a vertical axis, passes through the point (–1, 3), and has its vertex at (3, 2)
Thus, the equation of a parabola will be;
y = x^2/16 - 6x/16 + 41/16
Learn more about vertex form of a quadratic equation here:
https://brainly.com/question/9912128
#SPJ2
The mean number of travel days per year for salespeople employed by hardware distributors needs to be estimated with a 0.90 degree of confidence. For a small pilot study the mean was 150 days and the standard deviation was 14 days. If the population mean is estimated within two days, how many salespeople should be sampled
Answer:
133
Step-by-step explanation:
Given that :
Degree of confidence, α = 0.90 ; The Zcritical vlaue at α = 90% is 1.645
The margin of error, MOE = ±2
Standard deviation, s = 14
Using the relation :
n = (Zcritical * standard deviation) / MOE
n = ((1.645 * 14) / 2)²
n = (23.03 /2)²
n = 11.515²
n = 132.595
n = 133 samples
Evaluate f(x) when x = 3.
Answer:
56
Step-by-step explanation:
Since 3 is between -6 and 9 we use the first definition
f(3) = 6 x^2 +2
= 6(3)^2+2
= 6(9) +2
= 54+2
= 56
I miss the equation, point D.
Find the number in which 4 has highest value.
6050.4837
6834.2590
6986.0432
6748.9251
Step-by-step explanation:
the number in which 4 has the highest value is
6748.9251
Answer:
6834.2590
Step-by-step explanation:
..................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................
pls help geometry! Surface area
Answer: SA = 368
Step-by-step explanation:
Answer:
The surface area of the figure is 368[tex]in^{2}[/tex]
Step-by-step explanation:
To find the surface area of a rectangular prism you must know the formula.
A=2(wl+hl+hw)
Hope this helps!
use the ratio of a 45-45-99 triangle to solve for the variables.
Answers:
[tex]a = 18\sqrt{2}[/tex]
[tex]b = 18[/tex]
==============================================================
Explanation:
For any 45-45-90 triangle, the two legs are the same length. We consider triangles like this to be isosceles. So we have b = 18 as the vertical leg because the horizontal leg is also 18 units long.
The hypotenuse of these types of triangles is always [tex]\sqrt{2}[/tex] times longer compared to the leg length. So the hypotenuse is [tex]a = 18\sqrt{2}[/tex]
As an alternative, you can use the pythagorean theorem to find the hypotenuse.
1. 9+x-7
2. 8-2x+5x
3. -x-9+3x
4. 4x-6-4x
Answer:
1)9-7+x
2+x
2)8-2x+5x
8+3x
3)-x+3x-9
2x-9
4)4x-4x-6
-6
you have to group the like terms
I hope this helps and sorry if they are wrong
HELP HURRY PLEASE i dont understanddd
Answer:
see image
Step-by-step explanation:
put a point on .5 on the x axis and a point on -3 on the y axis draw a line through them and shade the space under the line
Which expression is equivalent to….
Answer:
the answer is {2^5}
hope it helps :)
(2^1/2×2^3/4)^2
(2^(2/4+3/4))^2
(2^5/4)^2
2^(5/4×2)
2^(5/2)
√2^5
Answered by Gauthmath must click thanks and mark brainliest
Two cars leave the park at the same time opposite directions one goes 3 times faster after 6 hours they travel 140miles how fast did theyg go
Answer:
Their speeds are;
5.83 mph and 17.49 mph
Step-by-step explanation:
We are told that they leave the park the same time.
Let the speed one car traveled be v
Since the other car is 3 times faster, then it means that, it's speed is 3v.
Now, after 6 hours they travel 140 miles.
We know that;
Speed = distance/time.
Thus;
(v + 3v) = 140/6
4v = 140/6
v = 140/24
v = 5.83 mph
Thus, second car's speed = 3v = 3 × 5.83 = 17.49 mph
given: ray FEH bisects
hhhahahshhehrhhehrhrhrhrh
A jar contains 5 blue marbles, 2 black marbles, and 7 brown marbles.
Answer:
5/13
five blue marbles, but one blue removed thus 5/13
Step-by-step explanation:
Answer:
C 5/13
Step-by-step explanation:
A coin is tossed. If it shows heads, a marble is drawn from Box 1, which contains one white and two black marbles. If it lands tails, a marble is drawn from Box 2, which contains two white and two black marbles. Find P(black|coin fell tails).
Answer:
P(black|coin fell tails) = ¼
Step-by-step explanation:
Since a coin has a head and a tail, then probability of landing tail is;
P(tail) = ½
Now, if it falls tails, a marble is drawn from Box 2, which contains two white and two black marbles.
Thus, probability of getting a black marble is; 2/4 = ½
Thus;
P(black|coin fell tails) = ½ × ½ = ¼
Vail skied 2 km north, 2 km west, 1 km north, and 2 km west. How far was she from her starting point?
Answer:
5.0645km
Step-by-step explanation:
For the first part of the journey where Vail skied 2 km north, 2 km west
displacement = √2² + (-2)²
displacement = √4+4
displacement = √8
displacement = 2√2 km
d1 = 2√2 km
For the second part of the journey where he skeid 1 km north, and 2 km west. How far was she from her starting point?
displacement = √1² + (-2)²
displacement = √1+4
displacement = √5
d2 = √5 km
Total displacement = d1 + d2
Total displacement = 2√2 + √5
Total displacement = 2(1.4142) + 2.2361
Total displacement = 2.8284+ 2.2361
Total displacement = 5.0645km
Hence she was 5.0645km from her starting point
5a + 18 < −27 pre algibra
Answer:
X < -9
Step-by-step explanation:
5a +18 < -27
5a < -27 -18
5a < - 45
5a/5 < - 45/5
a < - 9
Answred by Gauthmath
Answer: -9
Step-by-step explanation:
5a+18 < -27
5a< -27-18
5a<-45
a< -45/5
a< -9
Select the correct answer. If x- 12sqrt x +36 = 0 , what is the value of x?
Answer:
36
Step-by-step explanation:
Let a² = x
a²-12a+36=0
or, (a-6)²=0
or, a-6=0
or, a = 6
Now a² = x, so x = 6² = 36
helpppp please.......
The equation your teacher has given you is an identity. We can prove this by transforming one side into the other. I'll transform the right hand side (RHS) into the left hand side (LHS).
This means I'll keep the LHS the same for each line. I'll only change the RHS. The goal is to get the same thing on both sides (I could go the other way around but I find this pathway is easier).
[tex]\tan^4(\theta)+\sec^2(\theta) = \sec^4(\theta)-\tan^2(\theta)\\\\\tan^4(\theta)+\sec^2(\theta) = \left(\sec^2(\theta)\right)^2-\tan^2(\theta)\\\\\tan^4(\theta)+\sec^2(\theta) = \left(\tan^2(\theta)+1\right)^2-\tan^2(\theta) \ \text{ ... see note 1}\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+2\tan^2(\theta)+1-\tan^2(\theta)\\\\[/tex]
[tex]\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\tan^2(\theta)+1\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\sec^2(\theta)-1+1 \ \text{ ... see note 2}\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\sec^2(\theta) \ \ \Large \checkmark\\\\[/tex]
note1: I use the identity [tex]\tan^2(\theta)+1 = \sec^2(\theta)[/tex] which is derived from the pythagorean trig identity [tex]\sin^2(\theta)+\cos^2(\theta) = 1[/tex]note2: based on the previous note, we can say [tex]\tan^2(\theta) = \sec^2(\theta)-1[/tex]So because we've arrived at the same thing on both sides, the original equation is an identity. It always true no matter what theta value you plug in, as long as theta is in the domain. So something like theta = pi/2 won't work because tan(pi/2) = undefined and sec(pi/2) = undefined. It's based on how cos(pi/2) = 0 and this value is in the denominator. Dividing by zero is undefined.
Consequently, this means all solutions to cos(theta) = 0 will be excluded from the domain. Everything else works.
The sum of (-12) and (5) is
(A) 6 (B) 8 (C) -7
Answer:
-7
Step-by-step explanation:
-12 +5
Since the signs are different
Take the larger number and subtract the smaller number
12-5 =7
Take the sign of the larger
-7
Answer:
-7 is the answer
[tex]( - 12) + (5) \\ = 7[/tex]
-8z^{-2} Write the expression using only positive exponents. Assume no denominator equals zero.
Answer:
Step-by-step explanation:
-8z⁻² = -8/z²
what describes how to determine if a relation given in a table is a function
Answer:
You could set up the relation as a table of ordered pairs. Then, test to see if each element in the domain is matched with exactly one element in the range. If so, you have a function!
Step-by-step explanation:
Devin volunteers at Big Pup Rescue. He is mixing up shampoo solution for the dog washing station. He needs 2 cups of shampoo concentrate for every 9 cups of water. Devin will use 36 cups of water.
How much shampoo concentrate should Devin add to the water to make the shampoo solution?
Answer:
8
Step-by-step explanation:
Make a ratio
2:9 = 11
In total there will be 11 cups of solution.
2:9 = 11
?:36 = ?
Divide
36 / 9 = 4
Now that you have found the scale factor, multiply
2 × 4 = 8
So, you will need 8 cups of shampoo concentrate.
Please help me anyone
Replace x with -11 and solve:
Y = (-11)^2 + 11
(-11)^2 = 121
Y = 121 + 11
Y = 132
Answer: 132
Answer:
132
Step-by-step explanation:
y = x^2 +11
Let x = -11
y = (-11)^2 +11
= 121+11
= 132
Anyone Answer Please
Answer:
shift of 6 units left
Step-by-step explanation:
Given f(x) then f(x + a) is a horizontal translation of f(x)
• If a > 0 then a shift left of a units
• If a < 0 then a shift right of a units
f(x) = 3 | x + 6 | + 9
Represents a horizontal shift of the parent function 6 units left
can someone help me with this
Answer:
Infenitely many solutions
Graph the function need ASAP help
Is it a, b , c or d?
Answer:
D
Step-by-step explanation:
(the line is a / shape, so the slope is positive)
(the line crosses the y axis at (0,-2)
(using the above information, the equation is y=2x-2)
Answer:
y = 2x - 2
Step-by-step explanation:
Start with
y = mx + b
The graph shows the y-intercept -2.
We have y = mx - 2
slope = m = rise/run
The slope is rise of 2 and run of 1, so m = 2.
y = 2x - 2
Lines l and m are parallel. When they are cut by the two transversals below, a triangle is formed.
Parallel lines l and m are intersected by lines s and t. A triangle has angles 1, 2, 40 degrees. The exterior angle to angle 1 is 74 degrees.
What is Measure of angle 2
34 degrees
40 degrees
74 degrees
146 degrees
Answer:
<2 = 34degrees
Step-by-step explanation:
Find the diagram attached below:
First we need to get <1;
<1 + 74 = 180 (angle on a straight line)
<1 = 180 - 74
<1 = 106degrees
Also, <1 + <2 + 40 = 180 (sum of angle in a triangle)
106+<2 + 40 = 180
146 + <2 = 180
<2 = 180-146
<2 = 34degrees
Answer:
34 its the right answer
Step-by-step explanation:
Find the multiples of 7 which is greater than 56 but less than 77
Answer:
63,70
Step-by-step explanation:
7 x 8 = 56
7 x 11 = 77
multiples of 7 and 9, 7 x 10
63 and 70
7×9 = 63
7×10 = 70
Answered by Gauthmath must click thanks and mark brainliest
Help anyone can help me do this question,I will mark brainlest. The question is find the area of the shaded region.
Answer:
13. 10
14. 51
Step-by-step explanation:
Answer:
13. 10
14. 51
Step-by-step explanation:
4x+3=x+9
What is the number?
X=?
Answer:x=3
Step-by-step explanation:
4x+3=x+9
4x-x=(-3)+9
3x=6
x=6:3
x=2
The graph is
function because it is symmetrical about the
Answer:
Functions can be symmetrical about the y-axis, which means that if we reflect their graph about the y-axis we will get the same graph. ... These are two types of symmetry we call even and odd functions.
Step-by-step explanation:
