What is 1.25 x 10^8 in standard form?

Answer:

I am not so sure but I am assuming-5 2/3 to be mixed fraction so improper fraction wud be -17/3

now 4*- 17/3 = 68/3

now divide -5/8 ÷ 12

so u must know the rule that if division we can multiply by reciprocal

so -5/(8*12) = -5/96

hope that helps

Answer:

f^-1 (-15) = -6

f^-1(4) + f(9)  = 0

Step-by-step explanation:

f^-1 (-15) =

Look where the output is -15 and  find the x value ( x=-6)

Since where are using the inverse function, the input becomes the output and  the output  and the output becomes the input

f^-1 (-15) = -6

f^-1 (4) = -11  (inverse function)

f(9) = 11  ( regular function)

f^-1(4) + f(9) = -11+11 = 0

Answer:

392

Step-by-step explanation:

1.49×10⁸/3.8×10⁵ = 392

kx + z = 3 means z = 3 - kx. Substitute this into the first two equations:

x + y + 3 (3 - kx) = 10   ==>   (1 - 3k) x + y = 1

-4x + 3y + 5 (3 - kx) = 7   ==>   (-4 - 5k) x + 3y = -8

Multiply through the first equation by -3 :

-3 ((1 - 3k) x + y) = -3 (1)   ==>   (-3 + 9k) x - 3y = -3

Add this to the second equation to eliminate y :

((-3 + 9k) x - 3y) + ((-4 - 5k) x + 3y) = -3 + (-8)

(-7 + 4k) x = -11

Normally, you would solve for x by dividing both sides by -7 + 4k. But you can't do that if this turns out to be equal to 0, which happens for

-7 + 4k = 0   ==>   k = 7/4

Answer:

k = 7/4

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

Surface area of prism is 48km^2

Answer:

Step-by-step explanation:

to find an interquartile range of the data in order to proceed with it.

ans:

53 + 1 = 54

57 - 3 = 54

24 + 30 = 54

29 + 25 = 54

The interquartile range of the data shown on the box-and-whisker plot will be 29.

IQR(inter quartile range)  is the difference between third and first quartile.

Usually, we use interquartile range along with two quartiles Q1 and Q3 to get the anomalies.

Those values who lie below Q1 - 1.5 xIQR  or above Q3 + 1.5 xIQR  are called anomalies.

But since in the case when these things are not obtainable, we check manually which point is lying away from mean or outside of usual range etc.

In order to find an interquartile range of the data in order to proceed with it.

In the box-and-whisker plot given:

Upper quartile = 54

Lower quartile = 25

Interquartile range (IQR)

54 - 25 = 29

Therefore, the interquartile range of the data shown on the box-and-whisker plot will be 29.

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Answer:

46.94 degrees (approx)

Step-by-step explanation:

Answer:

Step-by-step explanation:

Garden is two times as long as it is wide.

L = 2W

Perimeter is 120 feet

2L + 2W = 120

L +W = 60

(2W) + W = 60

3W = 60

W = 20 feet

L = 2W = 40 feet

Step-by-step explanation:

1/2 is equal to R6.

So 2 halves mean R6+R6=R12

Or

R6×2= R12

Answer:R12

Answer: x = 45

Step-by-step explanation:

Given

(2/3)x + 4 = (4/5)x - 2

Add 2 on both sides

(2/3)x + 4 + 2 = (4/5)x - 2 + 2

(2/3)x + 6 = (4/5)x

Subtract (2/3)x on both sides

(2/3)x + 6 - (2/3)x = (4/5)x - (2/3)x

6 = (12/15)x - (10/15)x

6 = (2/15)x

Divide 2/15 on both sides

6 / (2/15) = (2/15)x / (2/15)

[tex]\boxed{x=45}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

x = 45

Step-by-step explanation:

2/3 x + 4 = 4/5x - 2             Add 2 to both sides

2/3 x + 4 + 2 = 4/5x            Combine

2/3x + 6 = 4/5x                   Subtract 2/3 x from both sides.

6 = 4/5x - 2/3 x                  Multiply both sides by 15

6*15 = 4/5 x * 15 - 2/3x * 15

6*15 = 12x - 10x                   Combine the left and right

90 = 2x                               Divide by 2

x = 45

Let's see if it works.

LHS = 2/3 * 45 + 4

LHS = 2*15 + 4

LHS = 30 + 4

LHS = 34

RHS

Right hand side = 4/5 * 45 - 2

RHS = 36 - 2

RHS = 34 which is the same as the LHS

The answer is the population grew over the hundred-year span by [tex]6.481*(10)^6[/tex]

Given that in 2014, the population of people in Ohio = [tex]11.59[/tex] million

Also given that One-hundred years earlier of the year 1914, the population =  [tex]5.109[/tex] million people

One-hundred years earlier in the year 2014 = 2014 [tex]- 100[/tex] years

One-hundred years earlier in the year 2014 = Year 1914

The scientific notation of the year 2014 population is [tex]11.59*(10)^6[/tex]

The scientific notation of the year 1914 population is [tex]5.109*(10)^6[/tex]

How much did the population grow over the hundred-year span?

Growth of the population from 1914-2014 = [tex]11.59*(10)^6 - 5.109*(10)^6[/tex]

Growth of the population from 1914-2014 = [tex]6.481*(10)^6[/tex]

Conclusion: The population grew over the hundred-year span by [tex]6.481*(10)^6[/tex]

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Answer:

This is not a function graph as no variables are present.

Answer:

10

Step-by-step explanation:

-3 = 7 - 10

-3 = -3

Step-by-step explanation:

Part A, Option 1 is a exponential function while option is a linear equation.

Part B, Let y=b*a^(x) be the function for option 1. At x=1, y=1100 and at x=2, y=1210. 1100=b*a and 1210=b*a^2. Dividing them both we get, b=1.1 and a=1000. y=1000*(1.1)^(x). For option 2, it's a linear equation with a function y(x)=1000+100x.

The 20 year difference would be immense. With option 1, Belinda will get $6727.5 whereas with option 2, they will end up with $3000

9514 1404 393

Answer:

  A

Step-by-step explanation:

Vertical multiplication of polynomials is virtually identical to vertical multiplication of integers. The "place value" associated with a column is the power of the variable. When adding within a column, there is no "carry" to the next column the way there is with integers.

Here, the correct answer choice can be found by looking at the coefficients of x^2 and of x.

Step-by-step explanation:

can't c please type the question..

Answer: 1 day

Step-by-step explanation:

i took the test lol...

[tex] \begin{cases}\large\bf{\blue{ \implies}} \tt \: \frac{4}{9} \sf \: w \: = \: - 8 \\ \\ \large\bf{\blue{ \implies}} \tt \: \frac{4 \sf \: w}{9} \: = \: 8 \\ \\ \large\bf{\blue{ \implies}} \tt 4 \sf \: w \: = \: 9 \: \times \: 8 \\ \\ \large\bf{\blue{ \implies}} \tt 4 \sf \: w \: = \: 72 \\ \\ \large\bf{\blue{ \implies}} \tt \sf \: w \: = \: \cancel\frac{72}{4} \\ \\ \large\bf{\blue{ \implies}} \tt \sf \: w \: = \: 18 \end{cases}[/tex]

Answer:

50

Step-by-step explanation:

The amount of 4​% butterfat milk  is equal to x quarts , When 1​% butterfat milk  is equal to 75-x. The amount of butterfat in 4​% butterfat milk is x/100*4=0.04x

The amount of butterflat in 1​% butterfat milk is (75-x)/100= 0,75-0.01x

1​The amount of butterflat in 75 quarts of 3​% butterfat milk (our desired mixture) is 75/100*3= 2.25

This quantity (2.25) is the sum of butterfat from  4​% butterfat milk and 1​% butterfat milk(the sum of 0.04x and 0.75-0.01x)

the equation is

0.04x+0.75-0.01x=2.25

0.03x=1.5

x=50

[tex]5 \frac{2}{3} + 3 \frac{1}{5} \\ \frac{17}{3} + \frac{16}{5} \\ \frac{(17 \times 5) + (16\times 3)}{5 \times 3} \\ \frac{85 + 48}{15} \\ \frac{133}{15} = 8\frac{13}{15} [/tex]

Answer:

Answer:×(-2)

Answer:×(-2)Step-by-step explanation:

-2/1 = -2

4/-2 = -2

-8/2 = -2

Next two: 16, -32

Answer:

x = -16/7​

Step-by-step explanation:

7x+25=9​

Subtract 25 from each side

7x+25-25=9-25

7x = -16

Divide each side by 7

7x/7 = -16/7

x = -16/7​

Answer:

[tex]7x + 25 = 9 \\ 7x = 9 - 25 \\ 7x = - 16 \\ x = \frac{ - 16}{7} \\ x = - 2.29[/tex]

Step-by-step explanation:

I hope it helped U

stay safe stay happy

From the formula R(300) - C(300) we understand that is loss of 7500 for the company.

The given functions are R(x) = 55x and C(x) = 15,000 + 30x.

Functions are the fundamental part of the calculus in mathematics. The functions are the special types of relations. A function in math is visualized as a rule, which gives a unique output for every input x.

The given function is R(300) - C(300).

Now, R(300) = 55 × 300 = 16500

C(300) = 15,000 + 30 × 300

=15,000 + 9000

= 24,000

Now, R(300) - C(300) = 16500-24000

= -7,500

Therefore, from the formula R(300) - C(300) we understand that is loss of 7500 for the company.

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Answer:

Its 2714

Step-by-step explanation:

Khan Academy

The volume of the material that would be needed for each cylindrical cracker is approximately: 2,714 mm³ mm³.

Volume of a cylinder = πr²h

The volume of the material used for each cylindrical cracker = Volume of entire cylindrical cracker - volume of cylindrical hole

Radius of entire cracker (r) = 16/2 = 8 mm

Height (h) = 18 mm

Volume of the entire cracker = π(8²)(18) ≈ 3,619 mm³

Radius of hole (r) = 8/2 = 4 mm

Height (h) = 18 mm

Volume of the entire cracker = π(4²)(18) ≈ 905 mm³

The volume of the material used for each cylindrical cracker = 3,619 - 905 = 2,714 mm³

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Answer:

0.25meters

As 100cm=1metre

so, 25cm=25/100meter

=0.25metre

Step-by-step explanation:

If you like my answer than please mark me brainliest

The answer is 0.25 meters

Answer:

2x³ - x² - 10x + 5

Step-by-step explanation:

Use FOIL method.

(x² - 5) (2x - 1) = x²*2x +(x²)*(-1) + (-5)*(2x) + (-5)*(-1)

                       = 2x³ - x² - 10x + 5

Answer:

4842.24 cubic feet

Step-by-step explanation:

Use the formula for the volume of a cone, V = [tex]\pi[/tex]r²[tex]\frac{h}{3}[/tex]

The diameter of the cone is 34 ft, so the radius is 17 ft.

Plug in the radius and height into the formula, and solve for the volume:

V = [tex]\pi[/tex]r²[tex]\frac{h}{3}[/tex]

V = [tex]\pi[/tex](17)²[tex]\frac{16}{3}[/tex]

V = [tex]\pi[/tex](289)[tex]\frac{16}{3}[/tex]

V = 4842.24

So, the volume of the cone is 4842.24 cubic feet

Answer:

4,841.32 ft³.

Step-by-step explanation:

Let’s assume that this is a right circular cone and that the radius of the cone is r.

For our problem, r = (1/2)d = (1/2)34 = 17.

The volume of the cone is:

V = (1/3)pi r^2 h, where r is the radius and h is the height.

So, V = (1/3)pi(17^2)16 = 4,841.32 ft³.