Answer:
Television,video game consoles
Answer:
A toaster
Explanation:
Since it heats up with heat waves of radiant energy
You are building a house of cards. Explain how you know if the forces
acting on the cards are not balanced
Answer:
Equilibrium
Explanation:
For something to be balanced like a house of cards all forces acting on it have to be in equilibrium.
All the cards will fall down if they the forces acting on them aren't balances. That's how, it can be known that the forces acting on the cards are not balanced.
What are balanced force and unbalanced force?The forces acting on a body are said to be balanced if the total force of all the forces acting on it equals zero. Let's examine a few instances of balanced forces to better comprehend how the motion of the body is unaffected.
Unbalanced forces are those acting on a body when the net force acting on the body is greater than zero. The body alters its state of motion when unbalanced forces act on it.
If the forces acting on the cards are not balanced, every card will fall. It is possible to determine that the forces affecting the cards are not balanced in this way.
Learn more about force here:
https://brainly.com/question/13191643
#SPJ2
1000-kg car travelling down on a steepest road, which has inclined angle of 18
degree. Coefficient of kinetic friction is 0.3.
Calculate
1. Weight (force due to gravity).
2.Horizontal and vertical component of the weight
3. Normal force
4.Friction force
5. Net force along the plane down
6. Acceleration
Answer:
1
Explanation:
it was thinking about how much and then the other than you can get it would be able to ask her to be able and then the way you have been sent from your browser
A 40g bullet traveling at 450 m/s passed through a board and comes out traveling 300m/s. The board is 7.6cm thick. What is the force of friction applied by the wood to the bullet?
Answer:
f = 29605.2 [N]
Explanation:
To solve this problem we must use the following equation of kinematics, then use Newton's second law.
[tex]v_{f}^{2} =v_{o}^{2} -2*a*x[/tex]
where:
Vf = final velocity = 300 [m/s]
Vo = initial velocity = 450 [m/s]
a = acceleration [m/s²]
x = distance = 7.6 [cm] = 0.076 [m]
Now replacing and clearing a
2*a*0.076 = (450² - 300²)
a = 740131.57 [m/s²]
Now using Newton's second law which tells us that the force on a body is equal to the product of mass by acceleration.
f = m*a
where:
f = friction force [N]
m = mass = 40 [g] = 0.04 [kg]
f = 0.04*740131.57
f = 29605.2 [N]
will be required to accelerate a 1100kg car to .5 m/s
Answer:
550 N
Explanation:
Use Newton's second law:
F = ma
F is the force required to accelerate the car
m is the mass of the car
a is the acceleration of the car
In this problem, the mass is m=1100 kg, while the acceleration is a=0.5 m/s^2, therefore the force required to accelerate the car is 550 N
Hi I need the answer to this please
Answer:
its A
Explanation:
because that's how reality works
Answer:
B
Explanation:
thermal energy (heat) flows from a highest to lowest
NEED HELP
If a 6 volt battery is connected in series to resistances of 2 ohms, 8 ohms, and 14 ohms, what is the amount of the current that is flowing?
Answer:
I = 0.25 [amp]
Explanation:
To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the current by the resistance.
V = I*R
where:
V = voltage [Volt]
I = amperage or current [amp]
R = resistance [ohm]
Since all resistors are connected in series, the total resistance will be equal to the arithmetic sum of all resistors.
Rt = 2 + 8 + 14
Rt = 24 [ohm]
Now clearing I for amperage
I = V/Rt
I = 6/24
I = 0.25 [amp].
What features will your car have to reduce the forces of friction and drag?
please help , i’m doing online class & my teacher doesn’t teach, we just read and try our best & i have no idea what this even means
Answer:
To decrease friction in machinery, low-friction materials such as Teflon and other plastics are used. Contact surfaces are designed to be smooth as possible. Lubricants are introduced to reduce friction. To decrease drag on an airplane, smooth surfaces and a streamlined design are used.
Describe the agronomic significance of the upper and lower plastic limits, and of the plasticity index?
Answer:It shows the size of the range of the moisture contents at which the soil remains plastic. In general, the plasticity index depends only on the amount of clay present. It indicates the fineness of the soil and its capacity to change shape without altering its volume.
A block of wood weighs 160 N and has a specific gravity of 0.60. To sink it in fresh water requires an additional downward force of:_______A. 54N B. 64N C. 96N D. 110N E. 240N
Answer:
Your answer is: D) 110N
Hope this helped : )
Explanation:
In order for the wood to sink, it's specific gravity must equal 1 (or greater).
Specific gravity = .6 kg/m^3= Mass/volume
F (Newtons or kg x m/s^2) = Mass*9.8m/s^2.
Therefore, Mass = 160 N / 9.8 m/s^2= 16.32 kg
Volume = Mass/Specific Gravity = 16.32kg/.6 kg/m^3 = 27.2 m^3
Desired Specific gravity = 1 = (Mass + additional force/9.8m/s^2)/Volume = (16.32 kg +X / 9.8m/s^2)/27.2m^3
Solving for the additional force: X = 106.66...N
The answer is D, 110 N will be required to sink the block of wood.
A baseball is hit with an initial velocity of 49 meters per second at an angle of 30 degrees. What is the velocity of the ball in the X direction and what is the velocity of the ball in the y direction?
Answer:
Higher launch angles have greater times in the air
The time in air is determined by the initial vertical velocity. Since steeper launch angles have a larger vertical velocity component, increasing the launch angle increases the time in air.
Explanation:
Higher launch angles have greater times in the air
The time in air is determined by the initial vertical velocity. Since steeper launch angles have a larger vertical velocity component, increasing the launch angle increases the time in air.
How much work does a supermarket checkout attendant do on a can of soup he pushes 0.600 m horizontally with a force of 5.00 N?
Which statement does not describe brainstorming?
A Keep a record of ideas.
B Keep criticism of other's ideas to yourself.
C Collect only a few ideas.
D Use all of the information found when researching
Answer:
d
Explanation:
i just know (pls check out my question pls i will give nayone who answers brainiest)
When a 5.0 kg box is hung from a spring, the spring stretches to 50 mm beyond its relaxed length. (a) In an elevator accelerating upward at 2.0 m/s2 , how far does the spring stretch with the same box attached? (b) How fast and in which direction should the elevator accelerate for the spring stretch to be zero (that is, the spring returns to its relaxed length)?
Answer:
a) the spring will stretch 60.19 mm with the same box attached as it accelerates upwards
b) spring will be relaxed when the elevator accelerates downwards at 9.81 m/s²
Explanation:
Given that;
Gravitational acceleration g = 9.81 m/s²
Mass m = 5 kg
Extension of the spring X = 50 mm = 0.05 m
Spring constant k = ?
we know that;
mg = kX
5 × 9.81 = k(0.05)
k = 981 N/m
a)
Given that; Acceleration of the elevator a = 2 m/s² upwards
Extension of the spring in this situation = X1
Force exerted by the spring = F
we know that;
ma = F - mg
ma = kX1 - mg
we substitute
5 × 2 = 981 × X1 - (5 ×9.81 )
X1 = 0.06019 m
X1 = 60.19 mm
Therefore the spring will stretch 60.19 mm with the same box attached as it accelerates upwards
B)
Acceleration of the elevator = a
The spring is relaxed i.e, it is not exerting any force on the box.
Only the weight force of the box is exerted on the box.
ma = mg
a = g
a = 9.81 m/s² downwards.
Therefore spring will be relaxed when the elevator accelerates downwards at 9.81 m/s²
The extension of the spring in the elevator is 60 mm.
For the extension of the spring to be zero, the elevator must be moving downwards under free fall.
The given parameters;
mass of the box, m = 5 kgextension of the spring, x = 50 mm = 0.05 mThe spring constant is calculated as follows;
F = kx
mg = kx
[tex]k = \frac{mg}{x} \\\\k = \frac{5 \times 9.8}{0.05} \\\\k = 980 \ N/m[/tex]
The tension on the spring in an elevator accelerating upwards is calculated as follows;
T = mg + ma
T = m(g + a)
T = 5(9.8 + 2)
T = 59 N
The extension of the spring is calculated as follows;
[tex]T = kx\\\\x = \frac{T}{k} \\\\x = \frac{59}{980} \\\\x = 0.06 \ m\\\\x = 60 \ mm[/tex]
For the extension of the spring to be zero, the elevator must be under free fall, such that the tension on the spring is zero.
For free fall, a = g
T = m(g - a) = 0
Learn more here:https://brainly.com/question/4404276
In physics, a is a group of related objects that interact with each other and form a complex whole.
Answer: a system
Explanation: just did the test
Answer:
system is correct
Explanation:
A satellite is a large distance from a planet, and the gravitational force from the planet is the only significant force exerted on the
satellite. The satellite begins falling toward the planet, eventually colliding with the surface of the planet. As the satellite falls,
which of the following claims is correct about how the force that the planet exerts on the satellite Fps changes and how the force
that the satellite exerts on the planet Fsp changes, if at all? What reasoning supports this claim?
A
Fps and Fs both increase. The gravitational forces that two objects exert on one another decrease as the
separation between the objects increases, and these forces are always equal in magnitude.
B
Fps increases while Fsp remains constant. The gravitational force exerted by a planet on a satellite decreases
as the separation between the two objects increases, and the force exerted by the satellite on the planet remains
negligibly small.
с
Fps remains constant while Fgp increases. The gravitational force exerted by a planet on a satellite is a constant
equal to the weight of the satellite, and the gravitational force exerted by the satellite on the planet decreases as
the separation between the two objects increases.
D
Fps and Fs both remain constant
. The gravitational forces that a planet and a satellite exert on one another is a
constant equal to the weight of the satellite.
Answer:
None of the provided reasoning correct.
Explanation:
Let d be the distance between the center of the planet having mass M and the satellite having mass m.
The gravitational force acting between the planet and the satellite is
[tex]F= \frac {GMm}{d^2}\cdots(i)[/tex]
where G is the universal gravitational constant, d is the distance between the center of two bodies having masses M and m.
This gravitational force, F, is the mutual force between both the objects, so
[tex]F=F_{ps}=F_{sp}[/tex]
Where [tex]F_{ps}[/tex]: the force that the planet exerts on the satellite and
[tex]F_{sp}[/tex] the force that the satellite exerts on the planet.
So, from equation (i),
[tex]F_{ps}=F_{sp}=\frac {GMm}{d^2}\cdots(ii)[/tex]
As the satellite is falling towards the planet, to the distance, d, between the center of the planet and satellite is decreasing.
Now, from equation (ii), as [tex]F_{ps}[/tex] and [tex]F_{sp}[/tex]are inversely proportional to [tex]d^2[/tex]. So, both [tex]F_{ps}[/tex] and [tex]F_{sp}[/tex] increase on decreasing d.
Hence, both [tex]F_{ps}[/tex] and [tex]F_{sp}[/tex] increase as the gravitational forces that two objects exert on one another increases as the separation between the objects decreases, and these forces are always equal in magnitude.
None of the provided reasoning correct.
Can someone help me?
Answer: (1, 30), (2,10), (3,40), (4,20)
Explanation:
in a distance vs time graph what does the slope represent
Which substance is the stronger base?
Milk of Magnesia
Sodium Bicarbonate
Ferrous Hydroxide
Distilled Water
Answer:
Ferrous Hydroxide
Explanation:
A 5100 kg rocket almost in orbit and traveling horizontally is propelled by a thrust force of 7450 Newtons. How fast is it accelerating while the force is applied? ROUND YOUR ANSWER TO THE NEAREST TENTH DECIMAL PLACE (TEKS 4D)
Answer:
[tex]a=1.46\ m/s^2[/tex]
Explanation:
Given that,
Mass of a rocket, m = 5100 kg
Thrust force acting on the rocket, F = 7450 N
We need to find the acceleration of the rocket. The net force acting on an object is given by the formula as follows :
F = ma
a is acceleration of the rocket
[tex]a=\dfrac{F}{m}\\\\a=\dfrac{7450}{5100}\\\\a=1.46\ m/s^2[/tex]
So, the acceleration is [tex]1.46\ m/s^2[/tex].
A 120-kg roller coaster cart is being tested on a new track, and a crash-test dummy is loaded into it. The roller coaster starts from rest at point A which is 35 m above the ground. The cart is observed to roll down the track to point B, which is 10 m above the ground. In your own words, what physics ideas would you be able to use to predict how fast the cart is moving at point B? What calculations would you use, what things would you be measuring, and what physics principles or laws would you use to make this calculation?
Answer:
v₂ = 22.13 m/s
We need to measure heights of both points and the law of conservation of energy is applied to measure this speed.
Explanation:
In order to find the speed at the point B, we will use the Law of conservation of energy between points A and B to get the required results, as follows:
Total Energy of Cart at Point A = Total Energy of Cart Point B
K.E at A + P.E at A = K.E at B + P.E at B
(1/2)mv₁² + mgh₁ = (1/2)mv₂² + mgh²
(1/2)m(v₁² - v₂²) = mg(h₂ - h₁)
(1/2)(v₁² - v₂²) = g(h₂ - h₁)
where,
v₁ = velocity of cart at Point A = 0 m/s
v₂ = Velocity of Cart at Point B = ?
h₁ = height of point A relative to the ground = 35 m
h₂ = height of point B relative to the ground = 10 m
g = 9.8 m/s²
Therefore,
(1/2)[(0 m/s)² - v₂²] = (9.8 m/s²)(10 m - 35m)
- v₂² = - (2)(245 m²/s²)
v₂ = √(490 m²/s²)
v₂ = 22.13 m/s
We need to measure heights of both points and the law of conservation of energy is applied to measure this speed.
state newton's three laws of motion
I. Every object in a state of uniform motion tends to remain in that state of motion unless an external force is applied to it.
Ex: You roll a ball. It slows down by friction.
II. Acceleration is produced when a force acts on a mass. The greater the mass (of the object being accelerated) the greater the amount of force needed (to accelerate the object).
Ex: You cannot kick a brick wall down, but you can kick a soccer ball because the brick wall is more massive.
III. For every action there is an equal and opposite re-action.
Ex:when a rocket lifts off, the rocket's action is to push down on the ground with the force of its engines, and the reaction is that the ground pushes the rocket upwards with an equal force.
If a leaf falls from a tree, has work been done on the leaf? Explain.
Answer:
Hope this helps!
If a leaf falls from a tree, has work been done on the leaf, yes gravity do positive work and restive force do negative work.
What is work?
Work in physics is the energy that is transferred to or from an item when a force is applied along a displacement. In its simplest form, it equals the product of the force's magnitude and the distance travelled for a constant force directed in the direction of motion.
When the force has a component that is parallel to the displacement, positive work results. A system gains energy via constructive effort. When the force contains a component that is opposed to or against the displacement, negative work results. Energy is removed from the system or lost through negative labor.
If a leaf falls from a tree, has work been done on the leaf, yes gravity do positive work and restive force do negative work.
To learn more about work refer to the link:
brainly.com/question/18094932
#SPJ5
Nicole is making smoothies. She uses 1.2 kilograms of
apples and 600 grams of strawberries. How many
kilograms of fruit does Ann use in all?
I
Answer:
1.8 kg
Explanation:
Nicole is making smoothies. She uses 1.2 kilograms of apples and 600 grams of strawberries.
1.2 kg = 1200 gram
600 grams
Now,
1200 + 600 = 1800 gram
1800 gram = 1.8 kg
Thus, 1.8 kilograms of fruit does Ann use in all
-TheUnknownScientist
FLAMING OR ALBERT .........
Answer:
Albert
Explanation:
check the correctness of formula t=2π √m/k, dimensionally
Hi there! Lets see!
m is mass, and its units are kgk is the elastic constant measured in newtons per meter (N/m), or kilograms per second squared kg/s²Therefore:
[tex]\sqrt{\dfrac{m}{k}} =\sqrt{\dfrac{[kg]}{[\dfrac{kg}{s^2}]}} =\sqrt{\dfrac{[kg]}{[kg]}\cdot s^2} = \sqrt{[s]^2} = s[/tex]
The period is given in seconds so the formula is dimensionally correct.
The acceleration of gravity on the
Moon is 1.62 m/s2. The mass of the
Moon is 7.35 x 10^22 kg. From this
information, what is the radius of the
Moon?
Answer:
Near the Earth's surface, the acceleration due to gravity is approximately constant. ... Its value is = 6.673 x 10-11 N·m2/kg2. ... The mass of the moon is 7.35 x 1022 kg. ... moon, the distance to the center of mass is the same as the radius: r = 1.74 x ... Handwriting · Spanish · Facts · Examples · Formulas · Difference Between ...
Explanation:
The acceleration of gravity on the Moon is 1.62 m/s2. The mass of the Moon is 7.35 x 10^22 kg. From this information, then the radius of the Moon is 3 * 10¹² m.
What is moon ?The sole natural satellite of Earth is the Moon. With a diameter around one-quarter that of Earth (equivalent to the breadth of Australia), it is the largest and most massive compared to its home planet and the fifth largest satellite in the Solar System. The Moon is bigger than any known dwarf planets of the Solar System and is a planetary-mass object with a distinct rocky body, making it a satellite planet according to geophysical definitions of the word. There isn't much of an atmosphere, hydrosphere, or magnetic field there. With a surface gravity of 0.1654 g, it has a gravity that is around one-sixth that of Earth. Jupiter's moon Io is the only satellite in the Solar System that is known to have a greater gravity and density.
The Moon travels an average distance around Earth.
Given,
g = 1.62 m/s²
m = 7.35*10²² kg
according to formula,
g = GM/r²
1.62 = 6.67× 10⁻¹¹ m³ kg⁻¹ s⁻²*7.35*10²² kg/r²
solving this for r we get
r = 1.7 * 10⁶ m
To know more about Gravity :
https://brainly.com/question/31321801
#SPJ2.
1. A 500 N force applied to a box at a 50 degree angle above the horizontal surface. Find the x and y
components. Use the cheat sheet located in your blue resource folder, and show all work.
Answer:
The x and y components of the 500 N-force are 321.394 newtons and 383.023 newtons, respectively.
Explanation:
At first we present a figure describing the situation explained on statement, the x and y components of the force are determined by the following trigonometric expressions:
[tex]F_{x} = F\cdot \cos \alpha[/tex] (1)
[tex]F_{y} = F\cdot \sin \alpha[/tex] (2)
Where:
[tex]F[/tex] - Magnitude of the force, measured in newtons.
[tex]\alpha[/tex] - Direction of the force above the horizontal surface, measured in sexagesimal degrees.
If we know that [tex]F = 500\,N[/tex] and [tex]\theta = 50^{\circ}[/tex], then the components of the force is:
[tex]F_{x} = (500\,N)\cdot \cos 50^{\circ}[/tex]
[tex]F_{x} = 321.394\,N[/tex]
[tex]F_{y} = (500\,N)\cdot \sin 50^{\circ}[/tex]
[tex]F_{y} = 383.023\,N[/tex]
The x and y components of the 500 N-force are 321.394 newtons and 383.023 newtons, respectively.
explain the Kepler s law of planetary motion
A mason stretches a string between two points 70 ft apart on the same level with a tension of 20 lb at each end. If the string weighs 0.18 lb, determine the sag h at the middle of the string.
Answer:
Explanation:
Let tension be T in each string . Let angle with horizontal be θ in the middle
The sum of vertical components of tension of two string will balance the weight
2Tsinθ = mg
2 x 20 sinθ = .18
sinθ = .18 / 40 = .0045
θ = .25783 degree
If sag be y
y / 70 = tan .25783
y = 70 x tan.25783
= .3150 m
= 31.50 cm .
A car accelerates at a rate of 8.8 m/s2 with a force from the tires of 11,968 N.
What is the mass of the car?
Answer:
1360 kgExplanation:
The mass of the car can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question we have
[tex]m = \frac{11968}{8.8} \\ [/tex]
We have the final answer as
1360 kgHope this helps you
Answer:
[tex]\displaystyle 1360\:kg.[/tex]
Explanation:
[tex]\displaystyle am = F_{net} \\ \\ \frac{11968}{8,8} = \frac{8,8m}{8,8} \\ \\ \boxed{1360 = m}[/tex]
I am joyous to assist you at any time.
