y = 2/3 x - 2
Or
y + 2 = 2/3 ( x )
Answer:
y= 2/3x - 2
hope this helps :)
b) solve by factorisation
[tex]x { }^{2} + x - 72 = 0[/tex]
QUESTION:- SOLVE EQUATION BY FACTORISATION
EQUATION:-
[tex] {x}^{2} + x - 72 = 0[/tex]
ANSWER:-
[tex] {x}^{2} + x - 72 = 0\\{x}^{2} + 9x - 8x - 72 = 0 \\ x(x + 9) - 8(x +9) = 0 \\ (x - 8)(x + 9) = 0 \\ [/tex]
NOW FOR VALUE OF X ->
[tex]x - 8 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x + 9 = 0\\ x = 8 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = - 9[/tex]
In one year the population of
Zebras in the park was 3400. In
the following year the population
reduced by 25%. What was the
size of the population after
reduction?
A basic cellular package costs $30/month for 60 minutes of calling with an additional charge of $0.40/minute beyond that time. The cost function C (2) for using x minutes would be • If you used 60 minutes or less, i.e. if if x < 60, then C (x) = 30 (the base charge). If you used more than 60 minutes, i.e. (x – 60 minutes more than the plan came with, you would pay an additional $0.40 for each of those (x – 60 minutes. Your total bill would be C (x) = 30 + 0.40 (x – 60). If you want to keep your bill at $50 or lower for the month, what is the maximum number of calling minutes you can use? minutes. The maximum calling minutes you can use is ? Number
Answer:
The maximum number of minutes to keep the cost at $50 or less is 110 minutes
Step-by-step explanation:
Given
[tex]C(x) = 30[/tex] ---- [tex]x < 60[/tex]
[tex]C(x) = 30 + 0.40(x - 60)[/tex] --- [tex]x \ge 60[/tex]
Required
[tex]C(x) = 50[/tex] ---- find x
We have:
[tex]C(x) = 30 + 0.40(x - 60)[/tex]
Substitute 50 for C(x)
[tex]50 = 30 + 0.40(x - 60)[/tex]
Subtract 30 from both sides
[tex]20 = 0.40(x - 60)[/tex]
Divide both sides by 0.40
[tex]50 = x - 60[/tex]
Add 60 to both sides
[tex]110 = x[/tex]
[tex]x =110[/tex]
please help find the solution to the system of equations
Answer:
x = 2 y = 3
Step-by-step explanation:
-2x + 7 = 5x - 7
-7x + 7 = -7
-7x = -14
x = 2
y = -2(2) + 7
y = -4 + 7
y = 3
A quality control expert at Glotech computers wants to test their new monitors. The production manager claims they have a mean life of 83 months with a variance of 81. If the claim is true, what is the probability that the mean monitor life would be greater than 81.2 months in a sample of 146 monitors? Round your answer to four decimal places.
Answer:
0.9922 = 99.22% probability that the mean monitor life would be greater than 81.2 months in a sample of 146 monitors.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
The production manager claims they have a mean life of 83 months with a variance of 81.
This means that [tex]\mu = 83, \sigma = \sqrt{81} = 9[/tex]
Sample of 146:
This means that [tex]n = 146, s = \frac{9}{\sqrt{146}}[/tex]
What is the probability that the mean monitor life would be greater than 81.2 months in a sample of 146 monitors?
This is 1 subtracted by the p-value of Z when X = 81.2. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{81.2 - 83}{\frac{9}{\sqrt{146}}}[/tex]
[tex]Z = -2.42[/tex]
[tex]Z = -2.42[/tex] has a p-value of 0.0078.
1 - 0.0078 = 0.9922.
0.9922 = 99.22% probability that the mean monitor life would be greater than 81.2 months in a sample of 146 monitors.
What is the equation
Answer:
D.) y = 2x + 2
Step-by-step explanation:
First, we need to find the slope.
Lets use the points (0, 2) and (-2, -2).
Using the formula for calculating slope, we get 2 as our slope.
Since the equation should be in slope-intercept form, we use this formula.
y = mx + b
We'll use our first point (0, 2) to substitute for x and y and use 2 to substitute for m (slope):
2 = 2(0) + b
2 x 0 = 0
2 = 0 + b
-0 = -0
= 2 = b
Now, substitute b for 2 for 2 for m.
= y = 2x + 2.
Hope this helps!
If there is something wrong, please let me know.
A credit card advertises an annual interest rate of 23%.
What is the equivalent monthly interest rate?
Given:
A credit card advertises an annual interest rate of 23%.
To find:
The equivalent monthly interest rate.
Solution:
We know that,
1 year = 12 months
It is given that, the credit card advertises an annual interest rate of 23%. So, the equivalent monthly interest rate is:
[tex]\dfrac{23\%}{12}=1\dfrac{11}{12}\%[/tex]
[tex]\dfrac{23\%}{12}\approx 1.9167\%[/tex]
Therefore, the equivalent monthly interest rate is [tex]1\dfrac{11}{12}\%[/tex] and the approximate equivalent monthly interest rate is 1.9167%.
Using the applet, explore the results for simulating a group of 30 people and noting whether there is a duplicated birthday (whether at least two people have a matching birthday). Run at least 40 trials. What is the relative frequency of trials that had at least two people with the same birthday
Answer:I just need points
Step-by-step explanation:
Hey
if for men working for hours for 4 days complete for unit of work then how many unit of work will be completed by two men working for two hours per day?
The 2 men working for 2 hours per 2 days will complete 1/2 unit of work. This is calculated by using the proportions formula.
What is the formula for calculating equal proportions?The formula for the given proportions is,
a: b = c: d
⇒ a/b = c/d
⇒ ad = bc
In this way, the required variable is calculated.
Calculation:For the given question, the proportion we can write
M1 × H1 × D1: M2 × H2 × D2 = W1: W2
⇒ M1 × H1 × D1 × W2 = M2 × H2 × D2 × W1
Where M1 = 4; H1 = 4; D1 = 4; M2 = 2; H2 = 2; D2 = 2 and W1 = 4
We need to calculate W2 - required units of work
So, on substituting,
M1 × H1 × D1 × W2 = M2 × H2 × D2 × W1
⇒ 4 × 4 × 4 × W2 = 2 × 2 × 2 × 4
⇒ 64 × W2 = 32
⇒ W2 = 32/64
∴ W2 = 1/2
Thus, the required units of work are 1/2.
So, 2 men working for 2 hours for 2 days will complete 1/2 unit of work.
Learn more about proportions here:
https://brainly.com/question/1781657
#SPJ1
Disclaimer: The given question is incomplete. Here is the complete question.
Question: If 4 men working for 4 hours for 4 days complete 4 units of work then how many unit of work will be completed by two men working for two hours per 2 days?
Which expression is equivalent to
-32 3/5
-8
-3/325
3/325
1/8
Answer:
[tex]-32^\frac{3}{5} = -8[/tex]
Step-by-step explanation:
Given
[tex]-32^\frac{3}{5}[/tex]
Required
The equivalent expression
We have:
[tex]-32^\frac{3}{5}[/tex]
Rewrite as:
[tex]-32^\frac{3}{5} = (-32)^\frac{3}{5}[/tex]
Expand
[tex]-32^\frac{3}{5} = (-2^5)^\frac{3}{5}[/tex]
Remove bracket
[tex]-32^\frac{3}{5} = -2^\frac{5*3}{5}[/tex]
[tex]-32^\frac{3}{5} = -2^3[/tex]
[tex]-32^\frac{3}{5} = -8[/tex]
bHhHshsbsnsnsnsnsnsbsbsbckclccllcxldkdldkdkdk HELP
Answer:
Step-by-step explanation:
The reasons for each statement are inside the parentheses
1. <1 and <2 are complementary (given)
2. m<1 + m<2 = 90° (definition of complementary angles)
3. m<2 = 74° (given)
4. m<1 + 74° = 90° (Substitution)
5. m<1 = 16° (Subtraction property of equality)
This is gotten by subtracting 74° from both sides as follows:
m<1 + 74° - 74° = 90° - 74°
m<1 = 16°
Determine the value of X. Please explain the answer
We have two lines from the same point.
These two lines are also tangents to same circle which implies that they are of the same length.
That is 2x - 1 = 9
2x = 9 +1 = 10
x =10/2
x = 5
*20 points*
how do you get the weighted average from this table?
Answer:
it is
[(2+3+4+6)-2*4]:4=1.75
I THINK
Step-by-step explanation:
For this problem I thought the answer would be 1.3 for part C since it said to find the mean. However, I am wrong. Can someone help me with the problem please? Thank you for your help!
Answer:
Step-by-step explanation:
the mean is
{(12x1)+(13x1)+(14x2)+(15x2)+(17)+(18)+(19x2)+(20)+(21x2)+(22)+(24)}/11
mean=264/11
mean=24
2.WHICH OF THE FOLLOWING IS A NON- NUMERIC DATA ? Required to answer. Single choice.
(1) 1,2,3,4,5,6
(2) 2,8,4,5,8
(3) A,B,AB,O
(4) NONE OF THE ABOVE
Answer:
3.) A,B,AB,O
Step-by-step explanation:
Non-numeric data refers to categorical data, or data that is not expressed quantitatively. Answers (1) and (2) contain quantitative data, so they would be eliminated as potential answer choices and therefore (4) would also be eliminated. This leaves answer (3), which does not have quantitative data and is therefore non-numeric.
PLEASE HELPPPPPPPPPP
Answer: SORRY NEED AN ACCOUNT ON - 10
Step-by-step explanation:
To resolve the proposed issue, an explanation is needed in which the subject is addressed
Nadira owns a clothes shop.
The pictogram shows the number of skirts that were sold each day in one week.
On which day were most skirts sold?
Answer:
Friday
Step-by-step explanation:
you need to count the number of circles, the half circle represents 5 skirts
Answer by Gauthmath
A survey of 30-year-old males provided data on the number of auto accidents in the previous 5 years. The sample mean is 1.3 accidents per male. Test the hypothesis that the number of accidents follows a Poisson distribution at the 5% level of significance.
No. of accident No. of males
0 39
1 22
2 14
3 11
>=4 4
Required:
a. What's the Expected probability of finding males with 0 accidents?
b. What's the Expected probability of finding males with 4 or more accidents?
Answer:
0.2725
0.0431
Step-by-step explanation:
The distribution here is a poisson distribution :
λ = 1.3
The poisson distribution :
p(x) = [(e^-λ * λ^x)] ÷ x!
Expected probability of finding male with 0 accident ; x = 0
p(0) = [(e^-1.3 * 1.3^0)] ÷ 0!
p(0) = [0.2725317 * 1] ÷ 1
p(0) = 0.2725317
= 0.2725
2.)
P(x ≥ 4) = 1 - P(x < 4)
P(x < 4) = p(x = 0) + p(x. = 1) + p(x = 2) + p(x = 3)
p(x = 0) = p(0) = [(e^-1.3 * 1.3^0)] ÷ 0! = 0.2725
p(x = 1) = p(1) = [(e^-1.3 * 1.3^1)] ÷ 1! = 0.35429
p(x = 2) = p(2) = [(e^-1.3 * 1.3^2)] ÷ 2! = 0.23029 p(x = 3) = p(3) = [(e^-1.3 * 1.3^3)] ÷ 0! = 0.09979
P(x < 4) = 0.2725 + 0.35429 + 0.23029 + 0.09979 = 0.95687
P(x ≥ 4) = 1 - 0.95687 = 0.0431
Find the value of the trigonometric ratio. sin A
Answer:
sin A = 4/5
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
sin A = opp / hyp
sin A = 24/ 30
Dividing the top and bottom by 6
sin A = 4/5
sinØ=Perpendicular/Hypotenuse
sinA=BC/ACsinA=24/30sinA=4/5If one ruler and three pencils cost N120 and two
rulers and one pencil cost N140. Find the cost of
one ruler and one pencil
Answer:
N80
Step-by-step explanation:
One ruler is N60 and one pencil is N20.
How much wrapping is needed to cover a cubed gift box that is 9 inches high? (Include the bow which takes 115 sq. inches.)
Answer:
601 in²
Step-by-step explanation:
To obtain the amount of wrapping needed to cover the cube shaped gift box, including the bow
Area of bow = 115 in²
Surface area of cube shaped box = 6a²
a = side length of cube = 9
Hence,
Surface area of gift box = 6 * 9²
Surface area = 6 * 81 = 486 in²
Total wrapping required = area of gift box + area of bow = (486 in² + 115 in²) = 601 in²
The population of City A in 2000 was 40 thousand people and the population increased by 13% each year. The function f determines the population of this city (in thousands of people) in terms of x . Write a function formula for f .
Answer:
f(x) = 40(1 + 0.13)^x
Step-by-step explanation:
The general formula for an exponential growth function is;
f(x) = a(1 + r)^x
Where;
a= initial population of the city
r= population growth rate
x = number of years
Given that;
a= 40,000
r= 0.13
The population of the city in thousands of people in terms of x is;
f(x) = 40(1 + 0.13)^x
Solve the following equation for
g
g. Be sure to take into account whether a letter is capitalized or not.
Answer:
q/N = g
Step-by-step explanation:
q = Ng
Divide each side by N
q/N = Ng/N
q/N = g
If the white rod is 1/3, what color is the whole??
Answer:
brown
Step-by-step explanation:
it might be brown because it compelled
State and prove the Cantor Intersection Theorem.
Answer:
Cantor's intersection theorem refers to two closely related theorems in general topology and real analysis, named after Georg Cantor, about intersections of decreasing nested sequences of non-empty compact sets.
calculate the effective yearly rate if an investment offers a nominal interest rate of 9.5% compounded quarterly
Answer:
9.725%
Step-by-step explanation:
(1.0475)^2 =1.09725
one year 2 periods 4.75% per period
The perimeter of a triangle is 83 centimeters. If two sides are equally long and the third side is 8 centimeters longer than the others, find the lengths of the three sides.
Answer:
25, 33
Step-by-step explanation:
let the length of the one with equal sides be x
third side = x+8
x+x+x+8 = 83
3x+8 = 83
3x = 75
x = 25
x+8 = 25+8 = 33
Which expression is the best estimate of the product of 7/8and 8 1/10?
Answer:
7 7/80 or 7.0875
Step-by-step explanation:
product is the result of multiplication
7/8 * 81/10 = 567/80 = 7 7/80 or 7.0875
The 90% confidence interval for the mean one-way commuting time in New York City is
5.22 < < 5.98 minutes. Construct a 95% confidence interval based on the same data.
Which interval provides more information?
Answer:
95% provides more information
Step-by-step explanation:
The confidence interval is obtained by using the relation :
Xbar ± Zcritical * σ/√n
(Xbar - (Zcritical * σ/√n)) = 5.22 - - - (1)
(Xbar + (Zcritical * σ/√n)) = 5.98 - - (2)
Adding (1) and (2)
2xbar = 5.22 + 5.98
2xbar = 11.2
xbar = 11.2 / 2 = 5.6
Margin of Error :
Xbar - lower C.I = Zcritical * σ/√n
Zcritical at 90% = 1.645
5.6 - 5.22 = 1.645 * (σ/√n)
0.38 = 1.645 * (σ/√n)
(σ/√n) = 0.38 / 1.645 = 0.231
Therefore, using the se parameters to construct at 95%
Zcritical at 95% = 1.96
Margin of Error = Zcritical * σ/√n
Margin of Error = 1.96 * 0.231 = 0.45276
C.I = xbar ± margin of error
C. I = 5.6 ± 0.45276
C.I = (5.6 - 0.45276) ; (5.6 + 0.45276)
C. I = (5.147 ; 6.053)
Hence, 95% confidence interval provides more information as it is wider.
At a local company, 15% of the employees are women. every day, 9% of them bring their lunch to work, while only 3% of the men bring lunch. Find the probability that a randomly selected employee
a. is a woman goven that the person brings their lunch to work.
b. brings their lunch to work given that person is a woman.
c. is a woman given that the person brings their lunch to work.
Answer:
a) 0.3462 = 34.62% that a randomly selected employee is a woman given that the person brings their lunch to work.
b) 0.09 = 9% probability that a randomly selected employee brings their lunch to work given that person is a woman.
c) 0.3462 = 34.62% that a randomly selected employee is a woman given that the person brings their lunch to work.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
Questions a/c:
Questions a and c are the same, so:
Event A: Brings lunch to work.
Event B: Is a woman.
Probability of a person bringing lunch to work:
9% of 15%(woman)
3% of 100 - 15 = 85%(man). So
[tex]P(A) = 0.09*0.15 + 0.03*0.85 = 0.039[/tex]
Probability of a person bringing lunch to work and being a woman:
9% of 15%, so:
[tex]P(A \cap B) = 0.09*0.15[/tex]
Desired probability:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.09*0.15}{0.039} = 0.3462[/tex]
0.3462 = 34.62% that a randomly selected employee is a woman given that the person brings their lunch to work.
Question b:
Event A: Woman
Event B: Brings lunch
15% of the employees are women.
This means that [tex]P(A) = 0.15[/tex]
Probability of a person bringing lunch to work and being a woman:
9% of 15%, so:
[tex]P(A \cap B) = 0.09*0.15[/tex]
Desired probability:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.09*0.15}{0.15} = 0.09[/tex]
0.09 = 9% probability that a randomly selected employee brings their lunch to work given that person is a woman.
