non-ionizing radiation and ionizing radiation.
The Washington Monument is 169.20 meters tall.
A worker assigned to the restoration of the Washington Monument is checking the condition of the stone at the very top of the monument. A nickel with a mass of 0.005 kg is in her shirt pocket. What is the kinetic energy (KE) of the nickel in her shirt pocket at the top of the monument?
Answer: K.E = 8.3 J
Explanation:
The given parameters are
Height h = 169.2 m
Mass m = 0.005kg
From conservation of energy, at the top of the monument, the total energy will be kinetic energy which is equal to the potential energy. That is,
K.E = P.E
And
P.E = mgh
Where g = 9.81 m/s^2
Substitutes all the parameters into the formula
P.E = 0.005 × 9.81 × 169.2
P.E = 8.2908 J
Therefore, the kinetic energy (KE) of the nickel in her shirt pocket at the top of the monument is approximately 8.3 Joule.
The kinetic energy (KE) of the nickel in her shirt pocket at the top of the monument is 8.2908 Joules.
Given the following data:
Mass of nickel = 0.005 kgHeight of Washington Monument = 169.20 metersScientific data:
Acceleration due to gravity = 9.8 [tex]m/s^2[/tex]To calculate the kinetic energy (KE) of the nickel in her shirt pocket at the top of the monument, we would apply the law of conservation of energy.
The law of conservation of energy.According to the law of conservation of energy, the kinetic energy (KE) of the nickel is equal to the potential energy (PE) possessed by the nickel at the top of the monument.
Mathematically, this is given by this expression:
[tex]K.E =P.E =mgh[/tex]
Substituting the given parameters into the formula, we have;
[tex]K.E = 0.005 \times 9.8 \times 169.20[/tex]
K.E = 8.2908 Joules.
Read more on kinetic energy here: https://brainly.com/question/22599382
Look at the periodic table which statement about the elements on the periodic table is true
Answer: B
Explanation:
The reactivity of alkaline metal ( example group one ) increases down the group because of the increase in atomic mass from the top to the bottom of the group. As the mass increases, the force between the nucleus and the valence electron gets weaker and the atom will easily give up the electron as a result of this which eventually increases its reactivity.
The reactivity of halogens decreases as atomic mass increases. Therefore, option B is the correct answer.
A hydrogen line in a star's spectrum
has a frequency of 6.17x10^14 Hz
when stationary. In Rigel's spectrum,
it is shifted downward by 4.26x10^10
Hz. What is Rigel's velocity relative
to us?
PLS HELP!
Answer: V = 299,958589.8 m/s
Explanation: To calculate Rigel velocity relative to us, we should use doppler effect formula.
Fo = (c + Vo) f/ ( c - Vs)
Fo/f = (c + Vo) / ( c - Vs)
If Vo = Vs = V approximately
4.26 × 10^10 = (3×10^8 + V) 6.17×10^14/(3×10^8 - V)
4.26×10^10/6.17×10^14 = (3×10^8 + V)/(3×10^8 - V)
6.9×10^-5 = (3×10^8 + V)/(3×10^8 - V)
Cross multiply
20713.13 - 6.9×10^-5V = 3×10^8 + V
Collect the like terms
6.9×10^-5V + V = 3×10^8 - 20713.13
1.000069V = 299979286.9
V = 299979286.9/1.000069
V = 299,958589.8 m/s
Therefore, Rigel's velocity relative to us is 299,958589.8 m/s
Help? 25 points and will give brainliest!
Answer: 44.89 times
Explanation:
Given that the earth's average velocity is about 6.7 times faster than that of planetoid Makemake
Given that the formula involved is:
R2/R1 = (V1/V2)^2
Let V1 = earth velocity and R1 = earth orbital distance
While R2 = Makemake velocity and R2 = orbital distance.
Since the earth's average velocity is about 6.7 times faster than that of planetoid Makemake, then,
V1/V2 = 6.7
Substitute this in the formula above
R2/R1 = (6.7)^2
R2/R1 = 44.89
Cross multiply
R2 = 44.89R1
Therefore, Makemake's orbit is about 44.89 times larger than the earth's orbit.
derive a relation between time period anf frequency of a wave
Answer:
The relation between frequency and time period is given by:
f = 1/T
Explanation:
In a wave motion, the particle move about the mean position with the passage of time. The particles rise to reach the highest point which is crest, and similarly falls to reach the lowest point which is trough. The cycle keeps on repeating.
The time period of the wave can be defined as the time taken to complete one such cycle. Time period is given by:
T = 2π/ω
Frequency can be defined as the number of cycles completed in unit time, which can be taken as the inverse of time period. frequency is given by
f = ω/2π
or
f = 1/T
Please answer as soon as possible.
A Physics question about electricity and circuits.
Answer:
Explanation:
The formula P=VI, just rearrange to find I
So
I=P/V
=75/120
=0.625amps
625mA
Non-living factors in an ecosystem are
biotic
abiotic
antibiotic
Answer:
Abiotic
Explanation:
The non living factors of the ecosystem which is essential for the survival of living factors of the ecosystem are abiotic factors.
Examples for abiotic factors include temperature, sunlight, water, wind etc....
Answer:
B
Explanation:
is the correct answer
True or false: it is legal for a goalie to jump forward or come off his line during a penalty kick
Answer:
no
Explanation:
the goalie can move side to side but cant go out of the goalie box.
pls mark me brainliest
1. An automobile traveling at 25 km/hour has kinetic energy equal to 1x 10^4J.
a What is the mass of the car?
b. If the velocity of the car is increased to 45 km/hour, what is its kinetic energy?
c. If the velocity is increased to 80 km/hour, what is its kinetic energy?
Explanation:
It is given that,
Speed of an automobile is 25 km/h or 6.95 m/s
Kinetic energy of the automobile is [tex]10^4\ J[/tex]
(a) Kinetic energy of automobile s given by :
[tex]K=\dfrac{1}{2}mv^2\\\\m=\dfrac{2K}{v^2}\\\\m=\dfrac{2\times 10^4}{(6.95)^2}\\\\m=414\ kg[/tex]
(b) If the velocity of the car is increased to 45 km/hour or 12.5 m/s, new kinetic energy becomes :
[tex]K=\dfrac{1}{2}\times 414\times (12.5)^2\\\\K=32343.75\ J[/tex]
(c) If the velocity is increased to 80 km/hour, 22.23 m/s, So
[tex]K=\dfrac{1}{2}\times 414\times (22.23)^2\\\\K=102293.79\ J[/tex]
Hence, this is the required solution.
Luis and Aisha conducted an experiment. They exerted different forces on four objects. Their results are shown in the table.
A 3-column table with 4 rows. The first column labeled Object has entries 1, 2, 3, 4. The second column labeled Mass has entries 10 kilograms, 100 grams, 10 grams, 1 kilogram. The third column labeled Force (Newtons) has entries 4 Newtons, 20 Newtons, 4 Newtons, 20 Newtons.
Based on the data, which object has the greatest acceleration?
Object 1
Object 2
Object 3
Object 4
Answer:
Object 3
Explanation:
The object has the greatest acceleration is Object 2.
The following information should be considered;
The option 2 should be considered becasue 100 grams is lighter than 1 kilogram and therefore it has the greater amount of force that being applied to it, Due to this, it will have the greater acceleration.learn more: https://brainly.com/question/5303391?referrer=searchResults
assuming that voltage remains constant, what happpens to the current in a wire as its diameter decreases?
Jake has a car that accelerates at 10 m/s2. If the car has a mass of 1000 kg, how much force does the car produce?
Answer:
10,000 N
Explanation:
Force = mass · acceleration
F = m · a
Jake's car:
Accelerates at 10 m/s²
Weighs 1000 kg
F = 1000 · 10
F = 10000 N
Answer:
10,000 Newtons
Please mark my answer.
Cheers, Jake
how do radios work?
music has 3 things that make them pleasing to hear..
ANSWERS ASAP
Answer:
radios work when electrons are speeding up and dow the attena, patters structure and shape make music pleasing to hear. (more info below)
Explanation:
a radio works when electrons are speeding up and down the antenna, sending out electromagnetic waves. Radiation waves travel through the air at the speed of light. When the radio waves reach the antenna, the electrons vibrate within the antenna and reproduce the initial signal. to make music pleasing to hear it has to have patterns, structure, shape.
hope this helped!
The table gives some information about the orbits of Mars and Saturn.
Mars completes a number of orbits in the time it takes for Saturn to complete one orbit.
I will rate you brainliest if you answer!
Calculate the number of orbits that Mars completes in the time it takes for Saturn to complete one orbit.Immersive Reader
(5 Points)
Answer: 15 orbits
Explanation:
Given that the
Radius of Mars = 2.28 × 10^8 km
Radius of Saturn = 1.43 × 10^9 km
For a linear speed,
One revolution = 2πR
One revolution of Mars = 2 × π 2.28×10^8
And
One revolutionary of Saturn = 2 × π × 1.43 × 10^9
Since the relationship between angular speed and linear speed is
V = wr
Or
W = V/2πR
The number of orbits that Mars completes in the time it takes for Saturn to complete one orbit will be
(Vs/2π × 1.43 × 10^9) ÷ (Vm/2π × 2.28×10^8)
Where
Vm = linear speed of Mars = 24.1 km/s
Vs = linear speed of Saturn = 9.7km/s
(24.1/2π × 2.28×10^8) ÷ (9.7/2π × 1.43 × 10^9)
(24.1/2π × 2.28×10^8) × ( 2π × 1.43 × 10^9/9.7)
2π Will cancel each other
(24.1/2.28 × 10^8) × (1.43×10^9/9.7)
(24.1 × 1.43×10^9)/(2.28×10^8 × 9.7)
3.4463×10^10 / 2.2116×10^9
15.58 times
Therefore, Mars will complete 15 orbits in the time it takes for Saturn to complete one orbit.
critical mass depends on ___. Check all that apply.
A. the polarity
B. the purity
C. the density
D. the shape
What happens when a light bulb is disconnected in a series circuit?
Answer:
it will most likely turn off?
At the beginning of a bobsled race, teammates push their bobsled along the track before jumping
into it.
a. Before the teammates jump in, they push the bobsled (m= 100 kg) from rest to a speed of 6
m/s. How much kinetic energy does the bobsled gain
I’ll give brainliest to whoever answers first
KE=1/2mv^2
1/2(100)6^2
1800 J
PLEASE HELP ME SOLVE THIS!! PLZ
Banpo Bridge fountain is 60 metres above the water.
The water is projected with a horizontal speed of 6m/s
-Calculate:
1. The time taken to hit the river for a single droplet of water.
2. The range of the projectile for a single droplet of water.
3. The velocity (diagonal) when it hits the water.
Answer:
1.) Time = 3.5 seconds
2.) Range = 21 m
3.) Velocity = 34.8 m/s
Explanation:
Given that the
Height h = 60 m
Initial velocity U = 6 m/s
1.) The time taken to hit the river for a single droplet of water can be achieved by using second equation of motion
h = Ut + 1/2gt^2
Let assume that the water drops from rest. Therefore, U = 0
60 = 1/2 × 9.8t^2
60 = 4.9t^2
t^2 = 60/4.9
t^2 = 12.24
t = sqrt (12.24)
t = 3.5s
2.) The range of the projectile for a single droplet of water will be calculated by using the formula
R = Ut
Range R = 6 × 3.5 = 20.99
Range = 21 m
3.) The velocity (diagonal) when it hits the water.
Using third equation of motion
V^2 = U^2 + 2gH
Substitute values into the equation
V^2 = 6^2 + 2 × 9.8 × 60
V^2 = 36 + 1176
V^2 = 1212
V = sqrt (1212)
V = 34.8 m/s
Early in the twentieth century, a group of German psychologists noticed that people tend to organize a cluster of sensations into a(n) Group of answer choices parallel process. monocular cue. afterimage. gestalt.
Answer:
The correct option is D
D) Gestalt
Explanation:
In the earlier 20th century, a group of German scientists named Max Wertheimer, Wolfgang Köhler and Kurt Koffka, noticed that people tend to organzie a cluster of information into a Gestalt.
Gestalt is a German word which means the way things are placed or put together as a whole. In the field of phychology, it can be defined as a pattern or configuration. In this context, it included the human mind and its behavior as a whole.
The Gestalt theory states that:
"The whole of anything is greater than its parts and that attributes of the whole can't be deduced by analyzing any of the parts on their own accord"
There are 200 turns of wire around an electromagnet. The current in the wire is 6 amp. You want to increase the strength of the magnet to 1.5 times its present strength. What are two changes you can make to achieve your goal? Show all your calculations.
Answer:
i. increasing the number of turns of the wire by half, so that it equals 300.
OR
ii. increasing the value of the current by half of its initial value, so that it equals 9 amp.
Explanation:
An electromagnet consists of a coil of wire wound around a conductor which becomes induced with magnetism when current flows through the coil.
The magnetic strength of the electromagnet can be increased to 1.5 of its initial strength either by;
i. increasing the number of turns by half of its initial value
OR
ii. increasing the current by half of its initial value
The magnetic strength of an electromagnet = I × N
where; I is the amount of current and N the number of turns.
Given that: I = 6 A, N = 200, then;
magnetic strength = 6 ×200
= 1200 Ampere turns
i. Increasing the number of turns to 300 and I = 6 A, we have;
magnetic strength = 6 × 300
= 1800 Ampere turns
OR
ii. increasing the value of current by half of its initial value, so that N = 200 and I = 9 A;
magnetic strength = 9 ×200
= 1800 Ampere turns
An electric motor has an operating resistance of 25 Ω when a 4.8 A current is flowing through it. What is the potential difference of the outlet the motor is plugged into?
WILL MARK BRAINLIEST
Using the fact that pressure is defined as force : area, what is the pressure
exerted by 1 book in N/m??
Answer:
Pressure= force/ area
12/ 2033.33= 24400 N/m2.
i believe this is it :)
how is energy transformed using a wheel and axle
Answer:
The mechanical advantage of the wheel and axle is the ratio of the distances from the fulcrum to the applied loads, or what is the same thing the ratio of the diameter of the wheel and axle
Explanation:
i looked on Google
The wheel and axle simple machine is closely related to gears. Like all other simple machines the wheel and axle system changes the force by changing the distance over which the force must be applied; if the input force is reduced to the output force, then the force must be applied over five times the distance.
Which of the following are features of the nucleus of an atom?
Assertion: A normal human eye can see clearly all the objects below and above 25 cm
Reason: The human eye has the capacity to suitable adjust the focal length of its lens to a certain extent.
(a) Both Assertion and Reason are true and the Reason is the correct explanation of the Assertion.
(b) Both Assertion and Reason are true but Reason is not a correct explanation of the Assertion.
(c) The assertion is true but the Reason is false.
(d) Both Assertion and Reason are false.
Answer: d)
Both Assertion and Reason are false
Explanation:
The least distance of distinct vision for normal human beings is 25 cm. That is,
normal eye can not be able to see clearly the objects placed closer than 25 Centimetre.
Havong an Assertion that normal human eye can see clearly all the objects below and above 25 cm is false. And since the assertion is false, the reason behind it is invalid. Therefore, having a reason that the human eye has the capacity to suitable adjust the focal length of its lens to a certain extent is also false.
Sasha sits on a horse on a carousel 3.5 m from the center of the circle. She makes a revolution once every 8.2
seconds. What is Sasha's tangential speed?
O 0.9 m/s
O 1.3 m/s
O 2.7 m/s
Answer:
tangential speed ≈ 2.7 m/s
Explanation:
formula: Vt = 2r / t
r = 3.5 m
t = 8.2 s
Vt = 2(3.5) / 8.2
Vt = 2.68184 m/s
Vt ≈ 2.7 m/s
correct on edge
Find the electric field at the center of square. Assume that q1=11.8nC, q2=-11.8nC, q3=23.6nC, q4=-23.6nC and a=5.2cm. Such that 'a' is the distance between any two charges. The charge q1 and q3 are along two sides of a diagonal.
Answer:
[tex]E_T=[-27739.6\hat{i}-55479\hat{j}]\frac{N}{C}[/tex]
Explanation:
You have four charges at the corners of a square of side a=5.2cm
In order to calculate the electric field at the center of the square, you sum the contribution of the electric field generated by each charge.
The total electric field is given by:
[tex]E_T=E_1+E_2+E_3+E_4\\\\[/tex] (1)
each contribution to the total electric field has two components x and y. The signs of the components depends of the direction of the field, which is given by the sign of the charge that produced the electric field. Then, you have
[tex]E_1=k\frac{q_1}{r^2}cos\theta\hat{i}-k\frac{q_1}{r^2}sin\theta\hat{j}\\\\E_1=k\frac{q_1}{r^2}(cos\theta \hat{i}-sin\theta \hat{j})[/tex] (2)
q1 = 11.8*10^-9 C
k: Coulomb's constant = 8.98*10^9 Nm^2/C^2
For a square you obtain that
[tex]r=\sqrt{2}a=\sqrt{2}(5.2cm)=7.35cm=7.35*10^{-2}m[/tex]
and the angle is 45°
Then, you have in the equation (2):
[tex]E_1=(8.98*10^9Nm^2/C^2)\frac{11.8*10^{-9}C}{(7.35*10^{-2}m)^2}(cos45\° \hat{i}-sin45\° \hat{j})=[13869.7\hat{i}-13869.7\hat{j}]\frac{N}{C}[/tex]
In the same way you obtain for the other contributions to the total electric field:
For E2:
[tex]E_2=k\frac{q_2}{r^2}(cos45\°\hat{i}+sin45\° \hat{j})\\\\E_2=[13869.7\hat{i}+13869.7\hat{j}]\frac{N}{C}[/tex]
For E3:
[tex]E_3=k\frac{q_3}{r^2}(-cos45\°\hat{i}+sin45\°\hat{j})\\\\E_3=(8.98*10^9Nm2/C^2)\frac{23.6*10^{-9}C}{(7.35*10^{-2}m)^2}(-cos45\°\hat{i}+sin45\°\hat{j})\\\\E_3=39229.58(-cos45\°\hat{i}+sin45\°\hat{j})\frac{N}{C}\\\\E_3=[-27739.5\hat{i}+-27739.5\hat{j}]\frac{N}{C}[/tex]
for E4:
[tex]E_4=k\frac{q_4}{r^2}(-cos45\°\hat{i}-sin45\°\hat{j})\\\\E_4=[-27739.5\hat{i}-27739.5\hat{j}]\frac{N}{C}[/tex]
Finally, you sum component by component the four contributions to the total electric field (equation (1)):
[tex]E_T=[-27739.6\hat{i}-55479\hat{j}]\frac{N}{C}[/tex]
There still are four chargers in the corners of a square with side a=5.2cm. To compute the electric field just at the center of the composition, add the contributions of each shield's electromagnetic current.
entire electric field
[tex]\to E_T=E_1+E_2+E_3+E_4\ \ \ \ \ \ \ (1)[/tex]
Every contribution to the total electric field is comprised of two components, x, and y. These components' signs were determined by the direction of the field, which is determined by the sign of the charge that produced the electric field. There's
[tex]\to E_1=k\frac{q_1}{r^2}\cos\theta\hat{i}-k\frac{q_1}{r^2}\sin\theta\hat{j}\\\\\to E_1=k\frac{q_1}{r^2}(\cos\theta \hat{i}-\sin\theta \hat{j}) \ \ \ \ (2)\\\\\to q_1 = 11.8\times 10^{-9}\ C\\\\[/tex]
Coulomb’s constant (K) [tex]= 8.98\times 10^9\ \frac{Nm^2}{C^2}[/tex]
square, you obtain that
[tex]\to r=\sqrt{2}\\\\\to a=\sqrt{2}(5.2\ cm)=7.35\ cm=7.35\times 10^{-2}\ m[/tex]
angle= [tex]45\°[/tex] then, you have in the equation (2):
[tex]\to E_1=(8.98\times 10^9\ \frac{Nm^2}{C^2})\frac{11.8 \times 10^{-9}\ C}{(7.35 \times 10^{-2}m)^2}(\cos 45^{\circ} \hat{i}-\sin 45^{\circ} \hat{j})[/tex]
[tex]=[13869.7\hat{i}-13869.7\hat{j}]\ \frac{N}{C}[/tex]
Similarly, for other components to the overall electric field, you get:
For E2:
[tex]\to E_2=k\frac{q_2}{r^2}(\cos45^{\circ}\hat{i}+\sin45^{\circ} \hat{j})\\\\ \to E_2=[13869.7\hat{i}+13869.7\hat{j}]\ \frac{N}{C}[/tex]
For E3:
[tex]\to E_3=k\frac{q_3}{r^2}(-\cos45^{\circ}\hat{i}+\sin45^{\circ} \hat{j})\\\\\to E_3=(8.98\times 10^9 \ \frac{Nm^2}{C^2}) \ \frac{23.6 \times 10^{-9}\ C}{(7.35\times 10^{-2}\ m)^2}(-\cos45^{\circ} \hat{i}+\sin45^{\circ} \hat{j})\\\\\to E_3=39229.58(-\cos45^{\circ} \hat{i}+\sin45^{\circ} \hat{j})\frac{N}{C}\\\\\to E_3=[-27739.5\hat{i}+-27739.5\hat{j}]\ \frac{N}{C}\\[/tex]
For E4:
[tex]\to E_4=k\frac{q_4}{r^2}(-\cos45^{\circ}\hat{i}-\sin45^{\circ}\hat{j})\\\\ \to E_4=[-27739.5\hat{i}-27739.5\hat{j}]\ \frac{N}{C}[/tex]
Finally, we add up the four contributions to the total electric field (equation (1)):
[tex]E_T=[-27739.6\hat{i}-55479\hat{j}]\frac{N}{C}[/tex]
Learn more:
brainly.com/question/14696059
True or false when a person swims through water no work is done
Answer:
False
Explanation:
First we need to know the definition of work.
Work is done when a body moves through a distance with an applied force.
When swimming in water, you exert a force while moving through a distance. Therefore, work is done!
A man climbs a ladder. Which two quantities can be used to calculate the energy stored of the man at the top of the ladder.
A. The Weight of the man and the time taken only
B. The Weight of the man and the vertical distance moved only
C. The work don't by the man and the time taken only
D. The work don't by the man and the vertical distance moved only
Answer:The answer must be The weight of the man and the vertical distance moved.
Explanation: you calculate it by the force you applied times the distance you moved
Skin sensitivity may not include:
a. Touch
b. Hearing
c. Pain
d. Temnerature