What are three types of land reform ​

Answers

Answer 1

Answer:

Abolition of intermediaries (rent collectors under the pre-Independence land revenue system); Tenancy regulation (to improve the contractual terms including the security of tenure); A ceiling on landholdings (to redistributing surplus land to the landless);

Answer 2

Types of Land Reform

Abolition of Intermediaries

The first step taken by the Indian government under land reforms post-independence was passing the Zamindari Abolition Act. The primary reason of a backward agrarian economy was the presence of intermediate entities like, jagirdars and zamindar who primarily focussed on collecting sky-rocketing rents catering to their personal benefits, without paying attention to the disposition of farms and farmers. Abolition of such intermediaries not only improved conditions of farmers by establishing their direct connection with the government but also improved agricultural production.

Regulation of Rents

This was in direct response to the unimaginably high rents which were charged by intermediaries during British rule, which resulted in a never-ending cycle of poverty and misery for tenants. Indian government implemented these regulations to protect farmers and labourers from exploitation by placing a maximum limit on the rent that could be charged for land.

Tenure Security

Legislations were passed in all states of the country to grant tenants with permanent ownership of lands and protection from unlawful evictions on expiry of the lease. This law protects tenants from having to vacate a property immediately after their tenure is over unless ordered by law. Even in that case, ownership can be regained by tenants with the excuse of personal cultivation.


Related Questions

Uses of P-N junction

Answers

Answer:

Explanation:

Two that come to mind:

a semiconductor diode is essentially a PN junctiona transistor is made of two pn junctions.

A bird is flying in air. It is stretching its wings all along the sky and is flying in a certain direction Flying a bird is an example of: a. Composition of vector b. Collinear vector c. Addition of vector d. Multiplication of vector

Answers

Answer:

a. Composition of Vector.

Explanation:

When a bird flies in the air, it stretches its wings into air and this movement helps it move in a certain direction. This is an example of composition of vector. Air strikes the wings in opposite direction and bird wing movement helps it move against the wind.

beacuse thye want them to hav egoood and thye wn thme tto

Answers

Answer:

I don't understand the question

I don’t understand what your asking

Rafel knows that lessons learned is a valuable aid to future projects. When should he and his team address
lessons learned on a project?
Select an answer:
Add lessons learned as a topic in status meetings
Review past lessons learned so a new one does not have to be created,
Create lessons learned at the end of the project.
Brainstorm lessons learned at the beginning of a project

Answers

Answer: Create lessons learned at the end of the project.

Explanation:

Lessons learned are the experiences that are gotten from a project which should be taken into account for the future projects. Lesson learned are created at the end of the project.

The main objective of the lessons learned is that they show both the positive experience and the negative experience of a project and this will help the future projects that will be undertaken.

can you guys please introduce yourself​

Answers

Answer: why?

Explanation:

hi i’m kira and i need points so i can pass this class. i hope you’re having a good day

Which statement describes the relay between minerals and rocks ?

Answers

Answer:

•○●□■hey hi!■□●○•

Explanation:

Minerals and rocks are the same. Aggregates of minerals form rocks. Minerals determine the texture of a rock. Most rocks are made of a single mineral type.

☆♡hope this helps♡☆

You are given a pot of hot tea (350 mL) at a temperature of 85°C and a quantity of ice at -12°C. Determine the absolute minimum amount of ice you can add to the hot tea so that at equilibrium you have iced tea (ie. a very, very small amount of ice and some water). You can assume tea has the same density (1.00 g/mL) and specific heat (4190 J/kgK) as liquid water. The heat of fusion of H2O is 3.33x10^5 J/kg. The specific heat of ice is 2090 J/kgK.

Answers

Answer:

348 g

Explanation:

The heat gained by the ice equals the heat lost by the hot tea.

Also, since we require a very, very small amount of ice and some water, to still have some ice, the temperature of the hot tea has to decrease to the melting point of ice which is 0°C. So, the final temperature of the mixture is 0 °C.

So, mc(T - T') + mL = -MC(T - T") where m = mass of ice, c =  specific heat of ice = 2090 J/kgK., T = final temperature of mixture = 0 °C, T' = initial temperature of ice = -12 °C, L = heat of fusion of H2O = 3.33 × 10⁵ J/kg, M = mass of hot tea = ρV where ρ = density of tea = 1.00 g/mL and V = volume of hot tea = 350 mL. So, M = ρV = 1.00 g/mL × 350 mL = 350 g = 0.350 kg, C = specific heat of tea = 4190 J/kgK and T" = initial temperature of tea = 85 °C.

Making m subject of the formula, we have

mc(T - T') + mL = -MC(T - T")

m[c(T - T') + L] = -MC(T - T")  

m = -MC(T - T")/[c(T - T') + L]

substituting the values of the variables into the equation, we have

m = -MC(T - T")/[c(T - T') + L]

m = -0.350 kg × 4190 J/kgK(0 °C - 85 °C.)/[2090 J/kgK(0 °C. - (-12 °C)) + 3.33 × 10⁵ J/kg]

m = -1466.5 J/kK(- 85 °C)/[2090 J/kgK(0 °C + 12 °C)) + 3.33 × 10⁵ J/kg]

m = 124652.5 J/[2090 J/kgK(12 °C) + 3.33 × 10⁵ J/kg]

m = 124652.5 J/[25080 J/kg + 3.33 × 10⁵ J/kg]

m = 124652.5 J/358080 J/kg

m = 0.3481 kg

m = 348.1 g

m ≅ 348 g

So, the minimum amount of ice to be added is 348 g.

if a person is injured at the hospital during a natural disaster a correct action to take is ​

Answers

first check that you and the casualty aren't in any danger. If you are, make the situation safe. When it's safe to do so, assess the casualty and, if necessary, dial 999 or 112 for an ambulance. You can then carry out basic first aid and shift to another hospital




That’s what I learnt sooo..

The purification of hydrogen gas is possible by diffusion through a thin palladium sheet. Calculate the number of kilograms of hydrogen that pass per hour (in kg/h) through a 4.0-mm thick sheet of palladium having an area of 0.25 m^2 at 500°C. Assume a diffusion coefficient of 6.0 x 10^-8 m^2/s, that the concentrations at the high- and low-pressure sides of the plate are 3.5 and 0.25 kg/m^3 (kilogram of hydrogen per cubic meter of palladium), and that steady-state conditions have been attained. (clearly show your solution step by step, pay attention to units otherwise you will lose points!)

Answers

Man I don't have a clue, but this stuff sounds interesting

In a major human artery with an internal diameter of 5mm, the flow of blood, averaged over the cardiac cycle is 5cm3·s−1. The artery bifurcates (splits) into two identical blood vessels that are each 3mm in diameter. What are the average velocity and the mass flow rate upstream and downstream of the bifurcation? The density of blood is 1.06g·cm−3

Answers

9514 1404 393

Answer:

  see attached

Explanation:

Assuming flow is uniform across the cross section of the artery, the mass flow rate is the product of the volumetric flow rate and the density.

  (5 cm³/s)(1.06 g/cm³) = 5.3 g/s

If we assume the blood splits evenly at the bifurcation, then the downstream mass flow rate in each artery is half that:

  (5.3 g/s)/2 = 2.65 g/s

__

The average velocity will be the ratio of volumetric flow rate to area. Upstream, that is ...

  (5 cm³/s)/(π(0.25 cm)²) ≈ 25.5 cm/s

Downstream, we have half the volumetric flow and a smaller area.

  (2.5 cm³/s)/(π(0.15 cm)²) ≈ 35.4 cm/s

8.50 nC of charge is uniformly distributed along a thin rod of length L = 9.20 cm, which is then bent into a semicircle. What is the magnitude of the electric field at the center of the circle​

Answers

The answer would be 8.65

A 35kg block of mass is subjected to forces F1=100N and F2=75N at agive angle thetha= 20° and 35° respectively.find the distance it slides in 10seconds if the kinetic coefficient is 0.4.

Answers

Answer:

21 m

Explanation:

Since F₁ = 100 N and acts at an angle of 20° to the horizontal, it has horizontal component F₁' = 100cos20° = 93.97 N and vertical component F₁" = 100sin20° = 34.2 N.

Also, F₂ = 75 N and acts at an angle of -35° to the horizontal, it has horizontal component F₂' = 75cos(-35°) = 75cos35° = 61.44 N and vertical component F₂" = 75sin(-35°) = -75sin35° = -43.02 N

The resultant horizontal force F₃' = F₁' + F₂' = 93.97 N + 61.44 N = 155.41 N

The resultant vertical force F₃" = F₁" + F₂" = 34.2 N - 43.02 N = -8.82 N

If f is the frictional force on the block, the net horizontal force on the block is F = F₃' - f.

Since f = μN where μ = coefficient of kinetic friction = 0.4 and N = normal force on the block.

For the block to be in contact with the surface, the vertical forces on the block must balance.

Since the normal force, N must equal the resultant vertical force F₃" and the weight, W = mg of the object for a zero net vertical force,

N = mg + F₃" (since both the weight and the resultant vertical force act downwards)

N = mg + F₃"

Since m = mass of block = 35 kg and g = acceleration due to gravity = 9.8 m/s² and F₃" = 8.82 N

So,

N = mg + F₃"

N = 35 kg × 9.8 m/s² + 8.82 N

N = 343 N + 8.82 N

N = 351.82 N

So, the net horizontal force F = F₃' - f.

F = 155.41 N - 0.4 × 351.82 N

F = 155.41 N - 140.728 N

F = 14.682 N

Since F = ma, where a = acceleration of block,

a = F/m = 14.682 N/35 kg = 0.42 m/s²

To find the distance the block moved, x we use the equation

x = ut + 1/2at² where u = initial speed of block = 0 m/s, t = time = 10 s and a = acceleration of block = 0.42 m/s²

Substituting the values of the variables into the equation, we have

x = ut + 1/2at²

x = 0 m/s × 10 s + 1/2 × 0.42 m/s² × (10 s)²

x = 0 m + 1/2 × 0.42 m/s² × 100 s²

x = 0.21 m/s² × 100 s²

x = 21 m

So, the distance moved by the block is 21 m.

A glass tube is inserted into a flowing stream of water with one opening directed upstream and the other end vertical. If the water velocity is 3 m/s, how high will the water rise in the vertical leg relative to the level of the water surface of the stream?

Answers

Answer:

[tex]h=0.46m[/tex]

Explanation:

From the question we are told that:

Velocity of water [tex]V=3m/s[/tex]

Height=?

Generally, the equation for Water Velocity is mathematically given by

[tex]V=\sqrt{2gh}[/tex]

Therefore Height h is given as

[tex]h=\frac{v}{2g}[/tex]

[tex]h=\frac{3^2}{2*9.81}[/tex]

[tex]h=0.46m[/tex]

Suppose that you have a block of copper which is 300 g. Relevant material parameters follow.

Material atomic weight Density
Copper 63.5 g/mol 8.96 g/cm^3

Using equipartition, compute the molar heat capacity in J/mol K.

Answers

Answer:

[tex]C_v= 24.942[/tex] J / mol K

Explanation:

Molar Heat Capacity

using the equipartition, the equation :

[tex]$C_v=\frac{d}{2} R$[/tex]

Here, [tex]C_v[/tex] = molar heat capacity

          d = degree of freedom

          R = Universal gas constant

Degree of freedom, d is 6          

Universal gas constant, R = 8.317 J/ mol K

Therefore, the molar heat capacity is :

[tex]$C_v=\frac{d}{2} R$[/tex]

[tex]$C_v=\frac{6}{2} \times 8.314$[/tex]

[tex]C_v= 24.942[/tex] J / mol K

the heat treatment process depends on 3 steps according to the time-temperature cycle. Name and Briefly describe each one​

Answers

Explanation:

there are three stages of heat treatment

1.hit the metal slowly to ensure that the metal maintains a uniform temperature

2.soak or hold the metal at a specific temperature for a alloted period of time

3.cool the metal to room temperature

To avoid a possible collision with a manned airplane, you climb your unmanned aircraft to yield the right of way. In doing so, your unmanned aircraft reached an altitude greater than 600 feet AGL. To whom must you report the deviation?

Answers

Answer:

you have to report to the federal aviation administration upon request

Explanation:

An unmanned aircraft can also be a drone it is an aircraft that does not have passengers or a human pilot.

Such an aircraft could be fully autonomous but most times they have a human pilot who controls it remotely.

Now you have to report this deviation to the federal aviation administration. This body is responsible for the enforcement of regulations that have to do with the manufacture, operation and maintenance of aircrafts. The body makes sure there is an efficient and safe system for a navigation and they also control air traffic.

deep invasion lead to???

Answers

Answer:

2

Explanation:

usjshshshjeoeieieiiekeiekeiekekekekekkske

Answer:

2

Explanation:

High separation between deep...........

what is tracer lathe machine​

Answers

Answer: The tracer lathe is a roughing operation for the output shaft on rear wheel drive transmissions.

Explanation:

The load on a bolt consists of an axial pull of 10 KN together with a transverse shear force of 5 KN. Find the diameter of bolt required according to I. Maximum principal stress theory; 2. Maximum shear stress theory; 3. Maximum principal strain theory, 4. Maximum strain energy theory, and 5 Maximum distortion energy theory. Take permissible tensile stress at elastic limit = 100 MPa and poisson's ratio = 0.3​

Answers

Answer:

hey. its a big question. solved from *c hegg

Explanation:

hỗ trợ mình với được không các bạn

Answers

Answer:

Explanation:

Be bop

I want to explain what 2000 feet looks like to young children so that they can imagine it in class

Answers

Answer:

maybe take a really common toy kids play with or often see, find the average height for the toy and do the math to see how many of those toys stacked ontop of eachother would make up 2000 feet. For example (this isn't accurate btw just an idea of what it would sound like but) "Have you ever seen a barbie doll? well if you stack 400 barbie dolls ontop of their head it would be equal to 2000 feet."

Explanation:

sometimes taking common or beloved objects children have into your examples makes them have a better image of how small or how big something is.

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