What are the ways that energy
conversion can occur?

The amino acid coded by the sequence code UUC is phenylalanine.

An amino acid is an organic compound made up of an amine group and carboxylic group. There are total 20 amino acids are present.

Phenylalanine is coded by two code sequence UUU and UUC. It is not an essential acid, and its role in the body is not confirmed.

Thus, the amino acid coded by the sequence code UUC is phenylalanine.

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Answer:

they send signals through the nerves. through sensory receptors to be specific

The number of particles of 285 grams of   aluminum oxide  (Al2O3) is  1.68 x 10²⁴ particles.

The number of moles of the given aluminum oxide is calculated as follows;

Al2O3 = 101.96 g/mol

moles = 285/101.96

moles = 2.795 moles

1 mole = 6.02 x 10²³ particles

2.795 moles = ?

= 2.795  x  6.02 x 10²³ particles

= 1.68 x 10²⁴ particles.

Thus, the number of particles of 285 grams of   aluminum oxide  (Al2O3) is  1.68 x 10²⁴ particles.

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Answer:

V=10 l H2O

VM=22.4 l/mole

n=V/Vm=0.446 moles H2O

the ratio 1:2

x:0.446

x=0.223 moles O2

Answer:

It means there are 6 O2 molecules

Explanation:

Answer:

.371 mole of NaCl

Explanation:

Na Cl Mole weight = 22.989   + 35.45 = 58.439 g/mole

21.7 g / 58.439 g/mole = .371 mole

Answer:

Las Vegas is expected to recieve less precipitation

Answer: When this atom loses an electron, the result is a positive ion.

Explanation:

Answer:

.3422 M

Explanation:

Mole weight of NaCl ( from periodic table) = 58.439 gm/mole

20 g is how many moles ?      20 g / 58.439 gm/mole=.3422 mole

.3422 mole / 1 liter .3422 M

Answer:

T = (Z x 10) + 50

Explanation:

The total pressure of the gas is calculated as 849 mmHg.

The term partial pressure is the pressure that is exerted by an individual gas in a mixture of gases.

In this case, the partial pressures of hydrogen and water are 789 mmHg and  60 mmHg respectively.

Thus, the total pressure of the gas =  60 mmHg +  789 mmHg = 849 mmHg.

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The molar solubility of AuCl₃ in 0.010M MgCl₂ is 4 ×10⁻²⁰M.

The solubility product constant, Ksp, is the equilibrium constant for a solid substance dissolving in an aqueous solution. And for the AuCl₃ Ksp will be written as: Ksp = [Au³⁺][Cl⁻]³

AuCl₃(aq) ⇄ Au³⁺(aq) + 3Cl⁻(aq)

Let the solubility of the AuCl₃ in 0.013m solution of magnesium chloride is x, of Au³⁺ is x and of Cl⁻ is 3x. But we know that MgCl₂ is a strong electrolyte and it completely dissociates into its ion and will produce 2 moles of chloride ions. For this solution let we consider the volume is 1 litre then the concentration of chloride ions in MgCl₂ is 2(0.010) = 0.020M.

So, in MgCl₂ solution concentration of Cl⁻ becomes = 3x + 0.020.

Value of Ksp for AuCl₃ = 3.2 × 10⁻²⁵

On putting all values on the Ksp equation, we get

Ksp = (x)(3x + 0.020)³

Value of 3x is negligible as compared to the 0.020, so the equation becomes

3.2 × 10⁻²⁵ = (x)(0.020)³

x = 3.2×10⁻²⁵ / (0.020)³

x = 4 ×10⁻²⁰M

Hence the molar solubility of AuCl₃ in 0.010M MgCl₂ is 4 ×10⁻²⁰M.

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The answer is "Location E, because Earth's axis is tilted towards the sun" :D

Answer:

C. Location E, because earth's axis is tilted towards the sun

Explanation:

Geometric progression is a sequence that can be found by multiplying the same value by the preceding number. The next term in the sequence is 8 / 81.

A geometric progression is a sequence of numbers other than 0 and can be estimated by multiplying a specific digit by the prior number. It is given as,

an = a₁rⁿ⁻¹

Where r is the common ratio or the number.

For the given sequence the common ratio (r) is 2/3.

Substituting values:

an = (1/2) ×  (2/3)ⁿ⁻¹

Applying r:

an=2ⁿ⁻¹ / 2 × 3ⁿ⁻¹

Substitute n to find the nth term as:

a₅=2⁽⁵⁾⁻²/ 3⁽⁵⁾⁻¹

a₅=8/ 3⁽⁵⁾⁻¹

a₅ = 8/ 81

Therefore, the next number on the sequence is 8/81.

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The oxidation number of chromium (Cr) in CrO₂, Cr₂O₇²⁻ and Cr₂(SO₄)₃³⁻ is +4, +6 and +1.5 respectively.

Oxidation number of any compound gives idea about the number of exchangeable electrons from the outer most shell of an atom.

Let the oxidation state of chromium is x and charge on the whole molecule is zero, so it will be calculated as:

x + 2(-2) = 0

x - 4 = 0

x = +4

Let the oxidation state of chromium is x and charge on the whole molecule is -2, so it will be calculated as:

2x + 7(-2) = -2

2x - 14 = -2

2x = 12

x = +6

Let the oxidation state of chromium is x and charge on the whole molecule is -3, so it will be calculated as:

2x + 3(-2) = -3

2x - 6 = -3

2x = 3

x = +1.5 (which is impossible)

Hence oxidation state of chromium atom in CrO₂, Cr₂O₇²⁻ and Cr₂(SO₄)₃³⁻ is +4, +6 and +1.5 respectively.

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Ionization reaction gives the ionization state of the chemical species. Its ionization will result in a conjugate base of the formic acid and release a hydrogen ion.

The acid dissociation constant is the concentration of the acid that has been dissociated into its constituents ions in the solution.

The ionization equation of the formic acid is:

[tex]\rm HCOOH \rightleftharpoons HCOO^{-} + H^{+}[/tex]

The acid dissociation constant (Ka) for formic acid is given as,

[tex]\rm Ka = \rm \dfrac {[H^{+}][HCOO^{-}]}{[HCOOH]}[/tex]

Anions are negatively charged ions and formate ions generated in the dissociation of the formic acid.

Therefore, the formate ion is an anion.

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Synthesis reaction

It is a reaction in which 2 or more reactants combine with each other to form one product .

Check option C

Sulphate and water are combining to form sulfuric acid .

Hence option C is correct

Answer:

SO3 + H2O => H2SO4

Explanation:

I took the test :)

Answer:

Here is the solution....hope it helps :)

Answer:

A

Explanation:

Banana ripening in air is an example of oxidation reaction.

Nitrogen has a normal boiling point of 77.4 K and a melting point (at 1 atm) of 63.2 K. Its critical temperature is 126.2 K, and its critical pressure is 2.55 * 104 torr. It has a triple point at 63.1 K and 94.0 torr.

The temperature and pressure at which the solid, liquid, and vapour phases of a pure substance can coexist in equilibrium.

- Normal melting point: 63.2 K.

- Normal boiling point: 77.4 K.

- Triple point: 0.127 atm and 63.1 K.

- Critical point: 33.5 atm and 126.0 K.

In such a way:

- N2 does not exist as a liquid at pressures below 0.127 atm: that is because below this point, solid N2 exists only (triple point).

- N2 is a solid at 16.7 atm and 56.5 K: that is because it is above the triple point, below the critical point and below the normal melting point.

- N2 is a liquid at 1.00 atm and 73.9 K: that is because it is above the triple point, below the critical point and below the normal boiling point.

- N2 is a gas at 0.127 atm and 84.0 K: that is because it is above the triple point temperature at the triple point pressure.

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If there are equal moles of each gas, what is the partial pressure of H₂ is 0.362.

The pressure that one of the gases in a mixture would exert if it were in the same volume on its own.

According to the Dalton's law of partial pressure

The Partial pressure of a gas = (Total pressure × mole fraction of the particular gas)

Partial pressure of H₂ is

[tex]\dfrac{1.81}{5.00} = 0.362[/tex]

Thus, the partial pressure of H₂ is 0.362.

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The concentration required to begin to precipitate PbCl2 for PbCl2 is 0.0216 M.

Molarity is the measure of the concentration of any solute in per unit volume of the solution.

The reaction is [tex]\rm Pb^2^+(aq) + 2Cl^-(aq) \rightarrow PbCl_2(s).[/tex]

The molarity of lead is 0.025 M

The ksp is given 17×10⁻⁵

Now, calculating the concentration

[tex][Pb^2^+] = 0.025 M.\\Ksp = 1.17 \times 10^-^5\\Ksp = [Pb^2^+] \times [Cl^-]^2\\[Cl^-] = \dfrac{\sqrt{ Ksp}}{[Pb^2^+]} \\\\[Cl^-] = \dfrac{\sqrt{ 0.0000117}}{0.025} \\[Cl^-] = 2.16 \times 10^-^2M.[/tex]

Thus, the concentration required to begin to precipitate PbCl2 for PbCl2 is 0.0216 M.

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Answer:

0.371

Explanation:

number of moles = mass / Ar

= 23.8g / 32.1 + (16.0 × 2)

= 0.37129485179 = 0.371 (3 s.f).

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The SN₁ substitution reaction, in which the halogen is released from the haloalkane, and the nucleophile attacks the carbon's positive charge. SN₂ in which the nucleophile attacks the halogen's carbon, causing the halogen to be replaced in which nucleophile attack.

Substitution reactions are those reactions in which one functional group is replaced by another functional group.

Two types of substitution reactions can occur in haloalkanes: SN1  and SN2.

Thus, the SN₁ substitution reaction, in which the halogen is released from the haloalkane, and the nucleophile attacks the carbon's positive charge. SN₂ in which the nucleophile attacks the halogen's carbon, causing the halogen to be replaced in which nucleophile attack.

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Answer:

yesss

Explanation:

hehhehehhehe