What are keyboards that include all the keys found on a typical virtual keyboard, as well as extra keys, such as function and navigation keys

Answer:

Option C: {{4, 1, 7}, {-10, -11, -12}}

Explanation:

There is a logical error in the inner loop.

for (int j = 0; j < num.length; j++)

It shouldn't be "j < num.length" as the iteration of the inner loop will be based on the length of the row number of the two dimensional array. The inner loop is expected to traverse through the every column of the same row in the two dimensional array and sum up the number. To fix this error, we can change it to

for (int j = 0; j < r.length; j++)

The sumRows method adds up all elements in each row, and prints the calculated sum.

The sumRows method would not work for input values (c) {{4, 1, 7}, {-10, -11, -12}}

In the inner loop of the sumRows method, we have

for (int j = 0; j < num.length; j++)

The above loop iterates from 0 to one less than the number of columns in the array.

Take for instance, {{10, -18}, {48, 17}} has 2 rows, and 2 columns.

So, the iteration would be for elements at indices 0 and 1.

However, the array {{4, 1, 7}, {-10, -11, -12}} has 3 rows and 2 columns

So, the iteration would be for elements at indices 0 and 1; leaving the element at index 2

Hence, the sumRows method would not work for input values (c) {{4, 1, 7}, {-10, -11, -12}}

Read more about methods at:

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Answer:

its postfix

Explanation:

Answer:

The programming language is not stated; so, I'll solve this question using Java programming language

Comments are used for explanatory purpose

//Begin of Program

import java . util.*;

import java. math . RoundingMode;

import java . text . DecimalFormat;

public class keyfreq

{

private static DecimalFormat df = new DecimalFormat("0.00");

public static void main(String [] args)

{

 Scanner input = new Scanner(System.in);

 //Declare variable

 float f0;

//Prompt user for input

System.out.print("Enter Initial Key Frequency: ");

f0 = input.nextFloat();

//Initialize number of keys

int numkey = 1;

//Print first key frequency

System.out.print("Key Frequencies: " + df.format(f0)+" ");  

while(numkey<=4)

{

 //Calculate next frequency

 f0*= Math.pow(2,(1.0/12.0));

 //Print Frequency

 System.out.print(df.format(f0)+" ");  

  //Iterate to next frequency

 numkey++;

}

}

}

//End of Program

Explanation:

See Comments in the above program

See Attachment for source file

Answer:

For me this is because, if I don't accept them they won't let me see what I came there for and my megabyte will be wasting.

Explanation:

Answer:

B. Open Source!!!!

Explanation:

Just took the test and this is the correct answer I promise!

The interviewer is referring to open-source programs.

The correct option is B.

Open-source software is a type of software that provides users with the freedom to use, modify, and distribute the program without restrictions. It typically includes the source code, allowing users to inspect, modify, and enhance the software according to their needs.

Open-source programs are developed collaboratively by a community of developers and are often available for free or at a lower cost compared to proprietary software. Users have the freedom to customize the software, fix bugs, add features, and distribute their modifications to others.

Freeware, on the other hand, refers to software that is available for free but does not necessarily provide the freedom to modify and distribute the program without restrictions. Freeware may have limitations on usage, redistribution, or access to the source code.

Software as a Service (SaaS) is a different concept where software applications are provided as a service over the internet, typically on a subscription basis. SaaS applications are not necessarily open source or freeware, as their distribution and usage terms vary depending on the specific service provider.

Learn more about Open source Program here:

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#SPJ6

Answer:

The java program for the given scenario is as follows.

import java.util.Scanner;

import java.lang.*;

public class Test

{

   //variables to hold miles per gallon and cost per gallon

   static double miles_gallon, dollars_gallon;

   public static void main(String[] args)

   {

       Scanner sc = new Scanner(System.in);

       System.out.print("Enter the car's mileage in miles per gallon: ");

       miles_gallon=sc.nextDouble();

       System.out.print("Enter the cost of gas in dollars per gallon: ");

       dollars_gallon=sc.nextDouble();

       System.out.printf("The cost of gas for 10 miles is $%.2f\n", drivingCost(10, miles_gallon, dollars_gallon));

       System.out.printf("The cost of gas for 50 miles is $%.2f\n", drivingCost(50, miles_gallon, dollars_gallon));

       System.out.printf("The cost of gas for 400 miles is $%.2f\n", drivingCost(400, miles_gallon, dollars_gallon));

   }

   //method to compute cost of gas

   public static double drivingCost(double drivenMiles, double milesPerGallon, double dollarsPerGallon)

   {

       double cost = ((drivenMiles/milesPerGallon)*dollarsPerGallon);

       return cost;

   }

}

OUTPUT

Enter the car's mileage in miles per gallon: 12

Enter the cost of gas in dollars per gallon: 23

The cost of gas for 10 miles is $19.17

The cost of gas for 50 miles is $95.83

The cost of gas for 400 miles is $766.67

Explanation:

1. Two double variables to hold user input for miles per gallon and cost of gas per gallon, are declared.

2. The variables are declared static, and at the class level (outside main()).

3. Inside main(), an object of Scanner class is created.

4. User input is taken for miles per gallon and cost of gas per gallon.

5. Next, the method, drivingCost() is called. This method takes three parameters - miles per gallon, cost of gas per gallon and miles driven. Based on these parameters and the given formula, the cost of gas is computed.

6. This value is then displayed to the user.

7. The method, drivingCost(), is called three times for 10 miles, 50 miles and 400 miles being driven.

8. The whole code is written inside a class since java is a purely object-oriented language.

9. The object of the class is not created since only a single class is used.

10. The program is saved as Test.java.

In this exercise we have to use the knowledge in computational language in JAVA to describe a code that best suits, so we have:

The code can be found in the attached image.

To make it simpler we can write this code as:

import java.util.Scanner;

import java.lang.*;

public class Test

{

  //variables to hold miles per gallon and cost per gallon

  static double miles_gallon, dollars_gallon;

  public static void main(String[] args)

  {

      Scanner sc = new Scanner(System.in);

      System.out.print("Enter the car's mileage in miles per gallon: ");

      miles_gallon=sc.nextDouble();

      System.out.print("Enter the cost of gas in dollars per gallon: ");

      dollars_gallon=sc.nextDouble();

      System.out.printf("The cost of gas for 10 miles is $%.2f\n", drivingCost(10, miles_gallon, dollars_gallon));

      System.out.printf("The cost of gas for 50 miles is $%.2f\n", drivingCost(50, miles_gallon, dollars_gallon));

      System.out.printf("The cost of gas for 400 miles is $%.2f\n", drivingCost(400, miles_gallon, dollars_gallon));

  }

  //method to compute cost of gas

  public static double drivingCost(double drivenMiles, double milesPerGallon, double dollarsPerGallon)

  {

      double cost = ((drivenMiles/milesPerGallon)*dollarsPerGallon);

      return cost;

  }

}

See more about JAVA at brainly.com/question/19705654

Answer:

Explanation:

import java.io.*;

import java.util.*;

public class GolfScores

{

    // *************************************************************

    // the purpose of this program is to read golf scores between

    // four players and figure out the winner with the lowest score

    // **************************************************************

    public static void main(String[] args) throws FileNotFoundException

    {

         final int HOLES = 28, VALUES_PER_LINE = 4;

         int hole = 0;

         int parscores[] = new int[HOLES];

         //declare a file object to handle the text file with scores

         File file1 = new File("golfscore.txt");

         int sum0=0;

         int sum1=0;

         int sum2=0;

         int sum3=0;

         int sum4=0;

         Scanner scan = new Scanner(file1);

         // total par and scores for all holes

         int scores[][] = new int[HOLES][VALUES_PER_LINE];

         //loop to store the contents of the file into arrays

         while (scan.hasNext())

         {

             int index = 0;

             parscores[hole] = scan.nextInt();

                  while (index < 4)

             {

                  scores[hole][index] = scan.nextInt();                                             // values in a line

                  index++;

             }

             //

             hole++;

         }

         for(int i=0;i<HOLES;i++)

         {

             sum0+=parscores[i];

         }

         int sumarray[]=new int[4];

         //loop to calculate the total score of each player

         for(int row=0;row<HOLES;row++)

         {

             sum1+=scores[row][0];

             sum2+=scores[row][1];

            sum3+=scores[row][2];

             sum4+=scores[row][3];

         }

         System.out.println();

         System.out.println("Par for the course"+sum0);

         System.out.println("Player 1:"+sum1);

         System.out.println("Player 2:"+sum2);

         System.out.println("Player 3:"+sum3);

         System.out.println("Player 4:"+sum4);

         sumarray[0]=sum1;

         sumarray[1]=sum2;

         sumarray[2]=sum3;

         sumarray[3]=sum4;

         int min=sumarray[0];

         //Loop to find out the minimum score

         for(int j=0;j<4;j++)

         {

             if(sumarray[j]<min)

                  min=sumarray[j];

         }

         System.out.print("The winner is ");

         //condition statement to determine the winner

         if(min==sum1)

         {

             System.out.print("Player1");

         }

             else if(min==sum2)

             {

                  System.out.print("Player2");

         }

             else if(min==sum3)

             {

                  System.out.print("Player3");

         }

             else

             {

                  System.out.print("Player4");

         }

    }

}

cheers i hope this helped !!

Answer:

hardware

Explanation:

hardware is the part where we can touch and feel while software ,we cant

Answer:

keyboard

Explanation:

Answer:

a) 179 segments

b) 28 segments

Explanation:

Given data :

A) Round trip time = 100 ms, Timeout = 101 ms

number of segments  for round trip = 3000/100 = 30 segments

number of segments for timeout = 15000/100 = 150 segments

total number of segments = 150 + 30 = 180

segments that get re-transmitted under A

Total segments - timeout = 180 - 101 = 179 segments

B) Round trip = 100 ms Timeout = 152 ms

number of segments for round trip = 3000/100 = 30 segments

number of segments for timeout = 15000/100 = 150 segments

total segments = 150 + 30 = 180

segments that get re-transmitted under B

total segments - timeout = 180 - 152 = 28 segments

Answer:

1.    11.77 GHz

2.   11.11  GHz

Explanation:

1.

From the given information;

the highest resulting clock speed we could achieve in GHz is calculated as follows:

Using the formula:

highest resulting clock speed = 1/max (stage,stage,stage,stage) + register delay)

highest resulting clock speed = 1/max(65ps, 45ps, 60 ps) + 20ps)

highest resulting clock speed = 1/(65 + 20)ps

highest resulting clock speed =  1/85 ps

highest resulting clock speed = 0.01176470588  × 10¹² Hz

highest resulting clock speed = 1.17647059 × 10¹⁰ Hz

highest resulting clock speed =  1.177 × 10¹⁰ Hz

To Ghz; we have:

highest resulting clock speed = (1.177 × 10¹⁰/10⁹ )GHz

highest resulting clock speed = 11.77 Ghz

2.

Using the same formula from above;

highest resulting clock speed = 1/max(65ps, 55ps, 70 ps) + 20ps)

highest resulting clock speed = 1/(70 + 20)ps

highest resulting clock speed =  1/90 ps

highest resulting clock speed = 0.01111111111  × 10¹² Hz

highest resulting clock speed = 1.111111111  × 10¹⁰ Hz

highest resulting clock speed =  1.111 × 10¹⁰ Hz

To Ghz; we have:

highest resulting clock speed = (1.111 × 10¹⁰/10⁹ )GHz

highest resulting clock speed = 11.11 Ghz

In this exercise we have to calculate the delay time and the time to archive something, so we have that these times will be:

1) 11.77 GHz

2) 11.11  GHz

1) First we will use the knowledge to calculate the delay, so the formula can be used is:

[tex]HRCS = 1/max (stage,stage,stage,stage) + register delay)\\HRCS = 1/max(65ps, 45ps, 60 ps) + 20ps)\\HRCS = 1/(65 + 20)ps\\HRCS= 1/85 ps\\HRCS = 0.01176470588* 10^{12}Hz\\HRCS = 1.17647059 * 10^{10} Hz\\HRCS = 1.177 * 10^{10} HZ\\HRCS = 11.77 Ghz[/tex]

2) through the first formula we can also calculate the time for the speed of archiving, like this:

[tex]HRCS = 1/max(65ps, 55ps, 70 ps) + 20ps)\\HRCS = 1/(70 + 20)ps\\HRCS = 1/90 ps\\HRCS = 0.01111111111 * 10^{12} Hz\\HRCS = 1.111111111 * 10^{10} Hz\\HRCS = 11.11 Ghz[/tex]

See  more about GHZ at brainly.com/question/13112545

Answer:

Computer literacy is the correct answer and following are working of computer is given below.

Explanation:

Computer literacy is characterized as the awareness and capacity to make the effective use through the software as well as the computer technology, The computer literacy including the skill sets of varying from simple use to the computer science as well as the specialized solving problems.

 Working of computer

What is computer knowledge called?

Computer literacy

Computer literacy is defined as the knowledge and ability to use computers and related technology efficiently, with skill levels ranging from elementary use to computer programming and advanced problem solving.

Answer:

Explanation:

The solution code is written in Python.

Firstly, prompt user to input three numbers for red, green and blue (Line 1-3).

Next, create three similar if statements to check if the red, green and blue are within the range 0-255 by using logical operator "or" to check if the number is smaller than 0 or bigger than 255. If either one condition is met, display a message to indicate a particular color number is not correct (Line 5-12).

The program written in python 3 which displays the whether the range of RGB values inputted by the user is in range goes thus :

r = int(input('Enter red value between 0 - 255'))

g = int(input('Enter green value between 0 - 255'))

b = int(input('Enter blue value between 0 - 255'))

#accepts inputs for red, green and blue values from the user

vals = {'red':r, 'green':g, 'blue':b}

#read the values into a dictionary and assign the values inputted by the user as the values

for k, v in vals.items():

#iterate through the dictionary as key-value pairs

if(v < 0) or (v > 255):

#Check of the values inputted is within range (0 - 255)

print('%s is not correct' %k)

#for any value which is out of range, display the name of the color and state that it is incorrect.

A sample run of the program ls attached below.

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Answer:

C.

Explanation:

The component that t provides WiFi access for employees in home offices, branch offices, and on the corporate campus is Wireless access points (APs).

APs are generally a networking hardware device that allows other wifi devices to connect to wired network. It creates a wireless local area network, usually in offices or large buildings.

Answer:

2 MBPS.

Explanation:

The Bluetooth 5 raises the data transmission of information throughput from 1 Mbps to the 2 Mbps. The main advantage of Bluetooth 5 do not increasing the energy  utilization.The Bluetooth 5 increasing the volume of information that technologies can be distribute.

Answer:

#include<iostream>

#include<stdio.h>

using namespace std;

class Node

{

public:

string name;

int waittime;

Node *next;

Node(string n,int w)

{

name=n;

waittime=w;

next=NULL;

}

};

Node *insert(Node *head,string name,int waittime)

{

Node *temp=new Node(name,waittime);

if(head==NULL||head->waittime>waittime)

{

temp->next=head;

head=temp;

}

else

{

Node *p=head;

while(p->next!=NULL)

{

if(p->next->waittime>waittime)

{

temp->next=p->next;

p->next=temp;

break;

}

p=p->next;

}

if(p->next==NULL)

{

p->next=temp;

}

}

return head;

}

Node *remove(Node *head)

{

if(head==NULL)

return NULL;

string name=head->name;

int waittime=head->waittime;

cout<<name<<" with wait time "<<waittime<<" landed"<<endl;

head=head->next;

return head;

}

void print(Node *head)

{

if(head==NULL)

return;

Node *temp=head;

cout<<"All the landing requests: "<<endl;

while(temp!=NULL)

{

cout<<temp->name<<" with waiting time "<<temp->waittime<<endl;

temp=temp->next;

}

}

int main()

{

Node *head=NULL;

cout<<" Welcome to plane landing system\n"<<endl;

int exit=0;

while(1)

{

cout<<"1. Make a landing request"<<endl;

cout<<"2. Land a plane"<<endl;

cout<<"3. List all the landing requests"<<endl;

cout<<"4. Exit\n"<<endl;

cout<<"Select your option: ";

int i;

cin>>i;

string name;

int waittime;

switch(i)

{

case 1:

cout<<"Enter plane name: ";

cin>>name;

cout<<"Enter wait time before landing: ";

cin>>waittime;

head=insert(head,name,waittime);

cout<<"Landing request made"<<endl;

break;

case 2:

head=remove(head);

break;

case 3:

print(head);

break;

case 4:

exit=1;

break;

default:

cout<<"Invalid option...Try again"<<endl;

break;

}

if(exit==1)

break;

}

return 0;

}

Explanation:

Input the code and see the output.

Answer:

Explanation:

Agile testing is software testing that follows the best practices of Agile development. For example, Agile development takes an incremental approach to design. Similarly, Agile testing includes an incremental approach to testing. In this type of software testing, features are tested as they are developed.

Answer: Provided in the explanation segment

Explanation:

CODE:-

import java.util.*;

class UserName{

  ArrayList<String> possibleNames;

  UserName(String firstName, String lastName){

      if(this.isValidName(firstName) && this.isValidName(lastName)){

          possibleNames = new ArrayList<String>();

          for(int i=1;i<firstName.length()+1;i++){

              possibleNames.add(lastName+firstName.substring(0,i));

          }  

      }else{

          System.out.println("firstName and lastName must contain letters only.");

      }

  }

  public boolean isUsed(String name, String[] arr){

      for(int i=0;i<arr.length;i++){

          if(name.equals(arr[i]))

              return true;

      }

      return false;

  }

  public void setAvailableUserNames(String[] usedNames){

      String[] names = new String[this.possibleNames.size()];

      names = this.possibleNames.toArray(names);

      for(int i=0;i<usedNames.length;i++){

          if(isUsed(usedNames[i],names)){

              int index = this.possibleNames.indexOf(usedNames[i]);

              this.possibleNames.remove(index);

              names = new String[this.possibleNames.size()];

              names = this.possibleNames.toArray(names);

          }

      }

  }

  public boolean isValidName(String str){

      if(str.length()==0) return false;

      for(int i=0;i<str.length();i++){

          if(str.charAt(i)<'a'||str.charAt(i)>'z' && (str.charAt(i)<'A' || str.charAt(i)>'Z'))

              return false;

      }

      return true;

  }

  public static void main(String[] args) {

      UserName person1 = new UserName("john","smith");

      System.out.println(person1.possibleNames);

      String[] used = {"harta","hartm","harty"};

      UserName person2 = new UserName("mary","hart");

      System.out.println("possibleNames before removing: "+person2.possibleNames);

      person2.setAvailableUserNames(used);

      System.out.println("possibleNames after removing: "+person2.possibleNames);

  }

}

cheers i hope this helped !!

Answer: Provided in the explanation section

Explanation:

class philosopher extends Thread

{

public void run()

{

diningps.count++;

philosopher(diningps.count);

}

public void philosopher(int i)

{

take_forks(i);

System.out.println(i+"philosopher Eating");

put_forks(i);

}

public void take_forks(int i)

{

while(diningps.mutex<=0)

{

System.out.println(i+"philosopher has to be wait while other philosopher in testing");

}

diningps.state[i]="HUNGRY";

test(i);

diningps.mutex=1;

while(diningps.S[i]<=0)

{

System.out.println(i+"philosopher has to be wait while his left or right side philosopher eating.");

}

}

public void put_forks(int i)

{

while(diningps.mutex<=0)

{

System.out.println(i+"philosopher has to be wait while other philosopher in testing");

}

diningps.state[i]="THINK";

test((i+4)%5);

test((i+1)%5);

diningps.mutex=1;

}

public void test(int i)

{

if(diningps.state[i]=="HUNGRY" && diningps.state[(i+4)%5]!="EAT" && diningps.state[(i+1)%5]!="EAT")

{

diningps.state[i]="EAT";

diningps.S[i]=1;

}

}

}

class diningps

{

static int mutex=1;

static int S[]={0,0,0,0,0};

static String state[]={"THINK","THINK","THINK","THINK","THINK"};

static int count=-1;

public static void main(String ar[])

{

philosopher ob=new philosopher();

philosopher ob1=new philosopher();

philosopher ob2=new philosopher();

philosopher ob3=new philosopher();

philosopher ob4=new philosopher();

ob.start();

ob1.start();

ob2.start();

ob3.start();

ob4.start();

}

}

cheers i hope this helped !!

Answer:

Following are the program in python language

def prob3_6(k): #function definition

  c = 0 #variable declaration

  while k != 1: #iterating the while loop

      print(k) #print k

      if k % 2 == 0:#check if condition  

          k= k // 2 #divisible by 2

      else: #else condition

          k = k * 3 + 1  

      c = c + 1

  print(k) #print k

  print c #print count

prob3_6(3)#function call

Output:

3

10

5

16

8

4

2

1

7

Explanation:

Following are the description of program

Answer:

Explanation:

The solution code is written in Python 3.

Firstly, prompt user to input a mileage (Line 1).

Next, create an if statement to check if a mileage greater than 100 (Line 3). If so, apply the formula to calculate amount with mileage above 100 (Line 4) otherwise,  calculate the amount just by multiplying the mileage by 0.25.

At last, print the total amount (Line 8).

Answer:

6 yards

Explanation:

if to convert 15 feet into yards it would 15/3 = 5

Answer:

hardware-initiated reset

Explanation:

In order to properly switch it back to real address mode operations you need to perform a hardware-initiated reset. This is because once in protected mode the 80286 will remain there until the hardware itself is reset. Therefore manually reseting the hardware will allow the user to switch back the microprocessor into a real address mode operations.

Answer:

Option B:

Some people have a difficulty in managing risks

Explanation:

Riding a motorcycle is a lot riskier than driving a car. This is because motorcyclists are exposed, and any accident that occurs will most likely lead to bodily harm to the rider.

Some individuals, have problems managing such risks, and cannot comfortably control the motorbike on the highway because of the number of cars speeding by.

Such individuals are not expected to be riding as this lack of confidence when riding on the highways can lead to accidents.

Answer:

[tex]L=2^{25830}[/tex] is the correct answer .

Explanation:

bandwidth = 3000 Hz

SNR =3162

We know that

[tex]bitrate = bandwidth * log2(1 + SNR)[/tex]

Putting the value of bandwidth and SNR in the given equation .

[tex]bitrate = 3000 * log_{2} ^\ (1 + 3162) \\\\birate = 3000 * log_{2} ^\ {3163} \\\\birate =3000 * 11.\ 6\\\\bitrate=\ 34860 bps[/tex]

Now using the formula

[tex]BitRate = 2 * Bandwidth * log_{2} (L)[/tex]

Putting the value of bitRate and bandwidth we get

[tex]34860=2\ * 3000\ * \ log_{2} (L)\\34860=6000 * \ log_{2} (L)[/tex]

[tex]31860-6000=log_2L\\25830=log_2L\\L=2^{25830}[/tex]

Answer:

c

Explanation:

because its inportant



Answer: Provided in the explanation section

Explanation:

Programs:

IncomeTax.java

import java.util.Scanner;

public class IncomeTax {

  // Method to get a value from one table based on a range in the other table

  public static double getCorrespondingTableValue(int search, int [] baseTable, double [] valueTable) {

  int baseTableLength = baseTable.length;

  double value = 0.0;

  int i = 0;

  boolean keepLooking = true;

  i = 0;

  while ((i < baseTableLength) && keepLooking) {

  if (search <= baseTable[i]) {

  value = valueTable[i];

  keepLooking = false;

  }

  else {

  ++i;

  }

  }

  return value;

  }

  public static int readInput(Scanner scan){

      System.out.println("\nEnter annual salary (0 to exit): ");

      int annualSalary = scan.nextInt();

      return annualSalary;

  }

  public static void main (String [] args) {

  Scanner scnr = new Scanner(System.in);

  int annualSalary = 0;

  double taxRate = 0.0;

  int taxToPay = 0;

  int [] salaryBase = { 20000, 50000, 100000, 999999999 };

  double [] taxBase = { .10, .20, .30, .40 };

  // FIXME: Change the input to come from a method

  annualSalary = readInput(scnr);

  while (annualSalary > 0) {

  taxRate = getCorrespondingTableValue(annualSalary, salaryBase, taxBase);

  taxToPay= (int)(annualSalary * taxRate); // Truncate tax to an integer amount

  System.out.println("Annual salary: " + annualSalary +

  "\tTax rate: " + taxRate +

  "\tTax to pay: " + taxToPay);

  // Get the next annual salary

  // FIXME: Change the input to come from a method

  annualSalary = readInput(scnr);

  }

  return;

  }

  }

Output:

Enter annual salary (0 to exit):

10000

Annual salary: 10000   Tax rate: 0.1   Tax to pay: 1000

Enter annual salary (0 to exit):

50000

Annual salary: 50000   Tax rate: 0.2   Tax to pay: 10000

Enter annual salary (0 to exit):

0