we will demonstrate experimentally that light travel in staight line.​

Answers

Answer 1

OK.  

Good luck on your experimental demonstration.

It's a nice exercise.


Related Questions

Imagine two pairs of books. In the first pair, two books of mass m_1m 1 ​ m, start subscript, 1, end subscript and m_2m 2 ​ m, start subscript, 2, end subscript are separated by the distance rrr, resulting in a gravitational force F_1F 1 ​ F, start subscript, 1, end subscript. In the second pair, two books of mass 2m_12m 1 ​ 2, m, start subscript, 1, end subscript and 4m_24m 2 ​ 4, m, start subscript, 2, end subscript are separated by the distance 2r2r2, r, resulting in a gravitational force of F_2F 2 ​ F, start subscript, 2, end subscript. The relationship between these two forces can be written as F_2 = nF_1F 2 ​ =nF 1 ​ F, start subscript, 2, end subscript, equals, n, F, start subscript, 1, end subscript. In the expression F_2 = nF_1F 2 ​ =nF 1 ​ F, start subscript, 2, end subscript, equals, n, F, start subscript, 1, end subscript, what is the value of nnn?

Answers

The value of n in the relationship between F₁ and F₂, (F₂ = n·F₁), is n = 2

The reason for the above value is as follows;

The given parameters of the first pair of books are;

The masses of the books = m₁, and m₂

The distance between the two m₁ and m₂ = r

The gravitational force between the masses = F₁

The given parameters of the second pair of books are;

The masses of the books second pair = 2·m₁, and 4·m₂

The distance between the two masses in second pair = 2·r

The gravitational force between the masses in second pair = F₂

The relationship between the two forces is F₂ = n·F₁

The required parameter;

The value of n in F₂ = n·F₁

According to Newton's law of universal gravitation, we have;

[tex]\mathbf{F = G \times \dfrac{m_1 \times m_2}{r^2}}[/tex]

Therefore, we get;

[tex]F_1 = G \times \dfrac{m_1 \times m_2}{r^2}[/tex]

[tex]F_2 = G \times \dfrac{2\cdot m_1 \times 4 \cdot m_2}{(2 \cdot r)^2} = G \times \dfrac{8 \times m_1 \times m_2}{4 \times r^2} = 2 \times G \times \dfrac{ m_1 \times m_2}{r^2} = 2 \times F_1[/tex]

Therefore;

F₂ = 2·F₁

The value of n in F₂ = n·F₁ is n = 2

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Your little sister (mass 25 kg) is sitting in her little red wagon (mass
8.5 kg) at rest. You begin pulling her forward, accelerating her with a
constant force for 2.35 s to a speed of 1.8 m/s. Calculate the impulse
you imparted to the wagon and its passenger.

Answers

Answer:

p = 60.6N*s

Explanation:

v_f = v_0+a*t

a = (v_f-v_0)/t

a = (1.8m/s)/2.35s

a = 0.77m/s²

F = m*a

F = (25kg+8.5kg)*0.77m/s²

F = 25.8N

^p = F*t

p = 25.8N*2.35s

p = 60.6N*s

Why would someone choose a for-profit fitness center over a nonprofit center?


For-profits have important social missions that deserve support. For-profits have important social missions that deserve support. , ,

For-profits are more likely to be located in low-income communities.For-profits are more likely to be located in low-income communities. , ,

For-profits have services like homework support and job training. , For-profits have services like homework support and job training. , ,

For-profits usually have nicer equipment than nonprofit centers.For-profits usually have nicer equipment than nonprofit centers. , ,

Answers

Someone would choose a for-profit fitness center over a nonprofit center because for-profits usually have nicer equipment than nonprofit centers.

A for-profit institution is an institution that provides a service to society to obtain an economic profit from this service. On the other hand, non-profit institutions are those that provide a service to society and do not intend to make a profit, they are generally institutions that are part of the government, foundations, or non-governmental organizations.

Non-profit institutions can function thanks to donations, volunteers, public resources, and do not charge for providing the service they provide, while for-profit institutions charge for their service and a percentage of that charge is profit for the owner of the institution and another is reinvested in equipment, human resources or others to improve the service.

According to this, for-profits are likely to have better equipment, while non-profit are characterized by supporting missions and offering services to low-income communities.

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2.5: Một người nặng 72kg ngồi trên sàn treo nặng 12kg như hình vẽ. Hỏi người đó
phải kéo dây với một lực bằng bao nhiêu để sàn chuyển động nhanh dần đều lên cao
được 3m trong thời gian là 2s. Tính áp lực của người đó lên sàn.

Answers

Answer:

english

Explanation:

A cycle track is 500 metres long. A cyclist completes 10 laps (that is, he rides completely round the track 10 times).
a) How many kilometres has the cyclist travelled?
b) On average it took the cyclist 50 second to complete one lap (that it, to ride round just one).
(i) What was the average speed of the cyclist?
(ii) How long in minutes and seconds dit it take the cyclist to complete the 10 laps?
c) Near the end of the run the cyclist put on a spurt. During this spurt it took the cyclist 2 seconds to increase speed from 8 m/s to 12 m/s. What was the cyclist's acceleration during this spurt?

Answers

Explanation:

a) D_t = 500m*10laps

D_t = 5000m or 5km

b)

I) v = d/t

v = 500m/50s

v = 10m/s

ii) 10m/s = 5000m/t

t = 5000m/10m/s

t = (500s)*(1min/60s)

t = 8'20" or 8 mins and 20 sec

c) v_f = v_0 + a*t

v_f-v_0 = a*t

a = (v_f-v_0)/t

a = (12m/s-8m/s)/2s

a = (4m/s)/2s

a = 2m/s²

Part(a),

The distance travelled by the cyclist is 5 km.

Part(b),

(i) The average speed is 10 m/s

(ii) The time taken to cover 10 laps is 8 minutes and 20 seconds.

Part(c),

The acceleration is 2 m/s²

What is speed?

Speed is defined as the ratio of the time distance travelled by the body to the time taken by the body to cover the distance. Speed is the ratio of the distance travelled by time. The unit of speed in miles per hour.

a) The distance will be calculated as

D = 500m*10laps

D = 5000m or 5km

b) The average speed is calculated as,

I) v = d/t

v = 500m/the 50s

v = 10m/s

The time will be calculated as,

ii) 10m/s = 5000m/t

t = 5000m/10m/s

t = (500s)*(1min/60s)

t = 8'20" or 8 mins and 20 sec

The acceleration is calculated as,

c) vf = v0 + at

vf-v0 = at

a = (vf-v0)/t

a = (12m/s-8m/s)/2s

a = (4m/s)/2s

a = 2m/s²

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A resistor, an inductor, and a capacitor are connected in series to an AC source. The AC source is operating at the resonance frequency. Which of the following statements are true?
a. The peak voltage across the resistor is equal to the peak voltage across the inductor.
b. The total voltage across the inductor and the capacitor at any instant is equal to zero.
c. The peak voltage across the resistor is equal to the peak voltage across the capacitor.
d. The peak voltage across the inductor is greater than the peak voltage across the capacitor.
e. The peak voltage across the capacitor is greater than the peak voltage across the inductor.
f. The current is in phase with the driving voltage.

Answers

I believe the correct answer is a

The true statement is that, at resonance, current is in phase with the driving voltage.

Resonance occurs in an RLC circuit at the point when the inductive reactance is equal to the capacitive reactance. At the point of resonance, the voltage across the inductor  and capacitor are equal.

It should noted that, at resonance, the current is in phase with the driving voltage. This is the true statement in the list.

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I need help with this please!!!!

Answers

Answer:

1.84 hours

I hope it's helps you

Which is a rule of boundary plates colliding or sliding past each other?

A. valleys form
B. volcanoes erupt
C. earthquakes occur*
D. mountains form

Answers

Explanation:

C...earthquakes occur

C. Earthquakes occur

What is a measure of how hard it is to stop a moving object?
25.
A. gravity
B. weight
C.
inertia
D. momentum

Answers

Answer:

C. inertia

Explanation:

inertia describes an object’s resistance to change in motion (or to get in motion due to a lack of motion), and momentum describes how much motion it has.

both are connected, as inertia depends on the object's momentum, but the answer here is inertia.

A metal blade of length L = 300 cm spins at a constant rate of 17 rad/s about an axis that is perpendicular to the blade and through its center. A uniform magnetic field B = 4.0 mT is perpendicular to the plane of rotation. What is the magnitude of the potential difference (in V) between the center of the blade and either of its ends?

Answers

We are being given that:

The length of a metal blade = 300 cmThe angular velocity at which the metal blade is rotating about its axis is ω = 17 rad/sThe magnetic field (B) = 4.0 mT

A pictorial view showing the diagrammatic representation of the information given in the question is being attached in the image below.

From the attached image below, the potential difference across the conducting element of the length (dx) moving with the velocity (v) appears to be perpendicular to the magnetic field (B).

The magnitude of the potential difference induced between the center of the blade in relation to either of its ends can be determined by using the derived formula from Faraday's law of induction which can be expressed as:

[tex]\mathsf{E = B\times l\times v}[/tex]

where;

B = magnetic fieldl = lengthv = relative speed

From the diagram, Let consider the length of the conducting element (dx) at a distance of length (x) from the center O.

Then, the velocity (v) = ωx

The potential difference across it can now be expressed as:

[tex]\mathsf{dE = B*(dx)*(\omega x)}[/tex]

For us to determine the potential difference, we need to carry out the integral form from center point O to L/2.

[tex]\mathsf{E = \int ^{L/2}_{0}* B (\omega x ) *(dx)}[/tex]

[tex]\mathsf{E = B (\omega ) \times \Big[ \dfrac{x^2}{2}\Big]^{L/2}_{0}}[/tex]

[tex]\mathsf{E = B (\omega ) * \Big[ \dfrac{L^2}{8}\Big]}[/tex]

Recall that,

magnetic field (B) = 4 mT = 4 × 10⁻³  TLength L = 300 cm = 3mangular velocity (ω) = 17 rad/s

[tex]\mathsf{E = (4\times 10^{-3}) * (17) \Big[ \dfrac{(1.5)^2}{8}\Big]}[/tex]

[tex]\mathsf{E = 19.13 mV}[/tex]

Thus, we can now conclude that the magnitude of the potential difference as a result of the rotation caused by the metal blade from the center to either of its ends is 19.13 mV.

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if C is The vector sum of A and B C = A + B What must be true about The directions and magnitudes of A and B if C=A+B? What must be tre about the directions and magnitudes of A and B if C=0? ​

Answers

Check attached photo

Check attached photo

A 500 kg rocket sled is coasting in reverse at 10 m/s (to the left). It then turns on its rocket engines for 10.0 s, with a thrust of 1500 N (to the right). What is its final velocity? (Remember velocity has magnitude and direction)

Answers

Explanation:

F = ma

[tex]a = \frac{f}{m} [/tex]

[tex]a = \frac{1500}{500} = 3[/tex]

[tex]a = \frac{v2 - v1}{t} [/tex]

[tex]3 = \frac{v2 - 10}{10} [/tex]

v2 (final) = 40 m/s to the right direction

What can light and sound both vary in which one of these ?

Volume
Intensity
Number or prespective?

Answers

Answer:

intensity

Explanation:

b. example, The sun is very bright and intense. and sounds can be very loud.

​Determine usando ecuación de Bernoulli la Presión P1 necesaria para mantener la condición mostrada dentro del sistema mostrado en la figura, sabiendo que el aceite tiene un s.g =0.45 y el valor de d=90mm.

Answers

Answer:

PlROCA

Explanation:

ASK YOUR TEACHER An oil slick on water is 99.8 nm thick and illuminated by white light incident perpendicular to its surface. What color does the oil appear (what is the most constructively reflected wavelength, in nanometers), given its index of refraction is 1.38

Answers

Answer:

There will be a phase change at the 1-1.38 interface and no phase change at the 1.38-1.33 interface.

At a thickness of lambda / 4       (y/4) one should get constructive interference for the reflected light.

y = 4 * 99.8 * 10E-9 m = 400 nm (about)  = 4 * 10E-7 m

The color of this light will be violet or blue

Can instantaneous velocity be negative

Answers

Answer:

Yes.

Explanation:

Instantaneous velocity is a vector quantity and thus can be negative.

Unlike, Instantaneous speed which is found by taking the absolute value of the magnitude of instantaneous velocity, and thus always positive.

Understanding Heisenberg's uncertainty principle is one of the keys to understanding quantum mechanics.

a. True
b. False

Answers

Answer:

Very TRUE

Option A is legit

two bodies A and B with some asses 20 kg and 30 kg respectively above the ground which have greater potential​

Answers

Answer:

B has greater potential

Explanation:

We know;

Potential Energy (PE) = mgh

where, m=mass of body

g=acceleration due to gravity

h=height of body

From the formula,

PE is directly proportional to the mass of the body

so the body with greater mass has greater potential.

A velocity selector is a device with an electric and magnetic field perpendicular to one another.

a. True
b. False

Answers

Answer:

a. True

Explanation:

It's commonly used in the bain bridge diagram determining positive rays

true

step by step:
bec ik i’m in hs

A runner has a temperature of 40°c and is giving off heat at the rate of 50cal/s (a) What is the rate of heat loss in watts? (b) How long will it take for this person's temperature to return to 37°c if his mass is 90kg.

Answers

TRY USING PHOTO MATH IT HELPS ME OUT A LOT

Electron A is fired horizontally with speed 1.00 Mm/s into a region where a vertical magnetic field exists. Electron B is fired along the same path with speed 2.00 Mm/s. (i) Which electron has a larger magnetic force exerted on it

Answers

B will have the greater force

Fc=MV2 /R=Fm

The A particle has less centipetal force and larger radius so larger curve

A 150g copper bowl contains 220g of water, both at 20.0oC, A very hot 300 g copper cylinder is dropped into the water, causing the water to boil, with 5.00 g being converted to steam. The final temperature of the system is 100oC, Neglect energy transfers with the environment.
a) How much energy (in calories) is transfered to the water as heat?
b) How much to the bowl?
c) What is the original temperature of the cylinder?

Answers

We have that the  energy (in calories) is transferred to the water as heat,to the bowl and  the original temperature of the cylinder  is mathematically given as

Qw=20.3 kcal Q= 1.11 kcal Ti=873°C

Energy

Generally the equation for the   is mathematically given as

(a)

The heat transferred to the H20

Qw= CwMwdT+Lvms

Qw=((220g)(100°C-20.0T)+(539 caVg)(5.00 g)

Qw=20.3 kcal .

(b)

The heat transferred to the bowl is

Qb= CbmbdT

Q= (0.0923 cal/gC)(150g)(100°C-20.0°C)

Q= 1.11 kcal

(c)  

original temperature of the cylinder

-Qw- Qb = CcMc(T2-T1)

[tex]T1=\frac{Qw+Qm}{CcMc}+T2[/tex]

T1=873C

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A spring whose stiffness is 3500 N/m is used to launch a 4 kg block straight up in the classroom. The spring is initially compressed 0.2 m, and the block is initially at rest when it is released. When the block is 1.3 m above its starting position, what is its speed

Answers

Answer:

the speed of the block at the given position is 21.33 m/s.

Explanation:

Given;

spring constant, k = 3500 N/m

mass of the block, m = 4 kg

extension of the spring, x = 0.2 m

initial velocity of the block, u = 0

displacement of the block, d =1.3 m

The force applied to the block by the spring is calculated as;

F = ma = kx

where;

a is the acceleration of the block

[tex]a = \frac{kx}{m} \\\\a = \frac{(3500) \times (0.2)}{4} \\\\a = 175 \ m/s^2[/tex]

The final velocity of the block at 1.3 m is calculated as;

v² = u² + 2ad

v² = 0 + 2ad

v² = 2ad

v = √2ad

v = √(2 x 175 x 1.3)

v = 21.33 m/s

Therefore, the speed of the block at the given position is 21.33 m/s.

The speed of the block at a height of 1.3 m above the starting position is 21.33 m/s

To solve this question, we'll begin by calculating the acceleration of the block.

How to determine the acceleration Spring constant (K) = 3500 N/m Mass (m) = 4 KgCompression (e) = 0.2 mAcceleration (a) =?

F = Ke

Also,

F = ma

Thus,

ma = Ke

Divide both side by m

a = Ke / m

a = (3500 × 0.2) / 4

a = 175 m/s²

How to determine the speed Initial velocity (u) = 0 m/sAcceleration (a) = 175 m/s²Distance (s) = 1.3 mFinal velocity (v) =?

v² = u² + 2as

v² = 0² + (2 × 175 × 1.3)

v² = 455

Take the square root of both side

v = √455

v = 21.33 m/s

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Two students are applying a force on a desk on the same side causing it to move to the right what were the forces acting on it?

Answers

Answer:

contact force because they were pushing it and it moved

If weight is an answer i think it would make most sense.

What is Matter? write its types​

Answers

According to definition of general chemistry matter is any substance which has atleast a mass and occupies a volume.

Matter is of three types

SolidLiquidGas

intial velocity is 45km/h, final velocity is 0, time taken is 3 seconds,calculate the retradation of the vehicle and distance travelled​

Answers

Answer:

Acceleration=12.5/3m/s^2=4.17m/s^2

Explanation:

Initial velocity u = 45 km/h = 12.5 m/s; Final velocity v = 0 m/s; time t = 3 s, acceleration a.

[a=v-u/t] : a=0-12.5/3=-12/3m/s^2

(Retaradation=-(-12.5/3)=12.5/3.

Convierta 164 decimetros a hectometros

Answers

Answer:

sinco

Explanation:

The valves in the heart open and close to move blood in between heart chambers. O a) three directions O b) two directions O c) four directions d) one direction

Answers

Hi,

The valves in the heart open and close to move blood in between heart chambers.

Answer:

d) one direction

A sinusoidal voltage is displayed on an oscilloscope screen. The separation on the screen between two adjacent peaks is 5.5 divisions, and you notice that the sweep speed is set to 1 ms per division. What is the frequency of the sinusoidal voltage

Answers

Answer:

f = 1.8 10² Hz

Explanation:

With the readings of the oscilloscope screen we can calculate the period of the wave

       T = #_divisions    time_base  

       T = 5.5  1 10⁻³

       T = 5.5 10⁻³ s

the period and frequency are related

        f = 1 / T

        f = 1 / 5.5 10⁻³

        f = 1.8 10² Hz

Unit of speed is a derived unit. Give reasons​

Answers

Answer:

as it 8s based upon to fundamental units distance and Time

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