Use the points (2, 14) and (10, 22) to write the equation of the line of best fit shown
HELPPP PLEASEEEEE

Answer:

Step-by-step explanation:

1). Plane parallel to the plane WXT → Plane ZYU

2). Segments parallel to VU → ST and ZY

3). Two segments parallel to SW → VZ and TX

4). Two segments skew to XY → VS and VU

5). Two segments skew to VZ → UT and WX

Answer:

6.75, if you round it i guess 6.80

Step-by-step explanation:

Answer:

f(x) - g(x) = -x⁸ + 8x³ + 5x² - 13

General Formulas and Concepts:

Pre-Algebra

Algebra I

Step-by-step explanation:

Step 1: Define

f(x) = -5x⁹ - x⁸ + 3x³ - 8

g(x) = -5x⁹ - 5x³ - 5x² + 5

Step 2: Find f(x) - g(x)

And we have our final answer!

This question is missing some parts. Here is the complete question.

Consider the oriented path which is a straight line segment L running from (0,0) to (16,16).

(a) Calculate the line inetrgal of the vector field F = (3x-y)i + xj along line L using the parameterization B(t) = (2t,2t), 0 ≤ t ≤ 8.

Enter an exact answer.

[tex]\int\limits_L {F} .\, dr =[/tex]

(b) Consider the line integral of the vector field F = (3x-y)i + xj along L using the parameterization C(t) = [tex](\frac{t^{2}-256}{48} ,\frac{t^{2}-256}{48} )[/tex], 16 ≤ t ≤ 32.

The line integral calculated in (a) is ____________ the line integral of the parameterization given in (b).

Answer: (a) [tex]\int\limits_L {F} .\, dr =[/tex] 384

              (b) the same as

Step-by-step explanation: Line Integral is the integral of a function along a curve. It has many applications in Engineering and Physics.

It is calculated as the following:

[tex]\int\limits_C {F}. \, dr = \int\limits^a_b {F(r(t)) . r'(t)} \, dt[/tex]

in which (.) is the dot product and r(t) is the given line.

In this question:

(a) F = (3x-y)i + xj

r(t) = B(t) = (2t,2t)

interval [0,8] are the limits of the integral

To calculate the line integral, first substitute the values of x and y for 2t and 2t, respectively or

F(B(t)) = 3(2t)-2ti + 2tj

F(B(t)) = 4ti + 2tj

Second, first derivative of B(t):

B'(t) = (2,2)

Then, dot product between F(B(t)) and B'(t):

F(B(t))·B'(t) = 4t(2) + 8t(2)

F(B(t))·B'(t) = 12t

Now, line integral will be:

[tex]\int\limits_C {F}. \, dr = \int\limits^8_0 {12t} \, dt[/tex]

[tex]\int\limits_L {F}. \, dr = 6t^{2}[/tex]

[tex]\int\limits_L {F.} \, dr = 6(8)^{2} - 0[/tex]

[tex]\int\limits_L {F}. \, dr = 384[/tex]

Line integral for the conditions in (a) is 384

(b) same function but parameterization is C(t) = [tex](\frac{t^{2}-256}{48}, \frac{t^{2}-256}{48} )[/tex]:

F(C(t)) = [tex]\frac{t^{2}-256}{16}-\frac{t^{2}-256}{48}i+ \frac{t^{2}-256}{48}j[/tex]

F(C(t)) = [tex]\frac{2t^{2}-512}{48}i+ \frac{t^{2}-256}{48} j[/tex]

C'(t) = [tex](\frac{t}{24}, \frac{t}{24} )[/tex]

[tex]\int\limits_L {F}. \, dr = \int\limits {(\frac{t}{24})(\frac{2t^{2}-512}{48})+ (\frac{t}{24} )(\frac{t^{2}-256}{48}) } \, dt[/tex]

[tex]\int\limits_L {F} .\, dr = \int\limits^a_b {\frac{t^{3}}{384}- \frac{768t}{1152} } \, dt[/tex]

[tex]\int\limits_L {F}. \, dr = \frac{t^{4}}{1536} - \frac{768t^{2}}{2304}[/tex]

Limits are 16 and 32, so line integral will be:

[tex]\int\limits_L {F} \, dr = 384[/tex]

With the same function but different parameterization, line integral is the same.

Answer:

2 divided by 1/2 is 4.

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

did it on edge

Answer:

The figure is translating right 5 and down 6

Step-by-step explanation:

X and Y both represent axis on a coordinate grid. x+5 simply means adding 5 to a value. In other words, on a coordinate grid, an increase in the value means you are going right, the lower the farther left. Same for the y axis, the higher the more you are increasing vertically, the lower the value the lower the point is.

Answer:

center of mass

X = [tex]\frac{my}{m} = \frac{28}{19}[/tex]

Y = [tex]\frac{mx}{m} = \frac{872}{95}[/tex]

Step-by-step explanation:

y = x and x = 0

parabola ; y = 20 - x^2

attached below is the detailed solution

M = [tex]\frac{152}{3}[/tex]б

Mx =  [tex]\frac{6976}{15}[/tex]б

My = [tex]\frac{224}{3}[/tex]б

X = [tex]\frac{my}{m} = \frac{28}{19}[/tex]

Y = [tex]\frac{mx}{m} = \frac{872}{95}[/tex]

Answer:

AC = 4.6

Step-by-step explanation:

since AX and XC are equal amd XC= 2.3

so AC = 2*2.3

Answer:

4.6

Step-by-step explanation:

Total weight, w = 10 lbs.

Height of the bucket, h = 2 feet.

Distance walked, d = 100 ft.

Now, work done in moving the bucket at a height of 2 feet.

W = mgh

W = 2× 32.17×100

W = 6434  lbs ft²/s²

Work done in moving bucket in horizontal direction is zero because it is perpendicular to the force.

Therefore, work done is 6434  lbs ft²/s² .

Hence, this is the required solution.

Answer:

C

Step-by-step explanation:

She spent $80

Answer:

eek, m/5+120??

Step-by-step explanation:

Answer:

I cant find the answer

Step-by-step explanation:

I searched and searched but no answer

Answer:

11 or I'm just bad at math

Answer:

The answer is x= 3

Step-by-step explanation:

hope this helps

Answer:

i think 48

Step-by-step explanation:

Answer:

Step-by-step explanation:

Use the half life formula

[tex]N=N_0e^{kt}[/tex] where N is the amount after decay, No is the initial amount, e is Euler's number, k is the decay constant, and t is the time in minutes. For us, the first equation looks like this:

[tex]7=12e^{k(70)}[/tex] and we will solve that for k and then use that value of k in the second equation to find time.

Begin by dividing 7 by 12 to get

[tex]\frac{7}{12}=e^{k(70)}[/tex] Now take the natural log of both sides since the natural log and that e are inverses. The e then disappears:

[tex]ln(\frac{7}{12})=k(70)[/tex]

Plug the left side into your calculator and then set it equal to the right side, giving us:

[tex]-.5389965007=70k[/tex]

Divide both sides by 70 to get the k value of

k = -.00769995

Now the second equation looks like this:

[tex]2=12e^{(-.00769995)t[/tex] where t is our only unknown now that we know k.

Begin by dividing both sides by 12 to get

[tex]\frac{1}{6}=e^{-.00769995t[/tex] and take the natural log of both sides again to eliminate the e:

[tex]ln(\frac{1}{6})=-.00769995t[/tex]

Take care of the left side on your calculator to get

-1.791759469 = -.00769995t and divide both sides by -.00769995 to get

t = 232.697 minutes

Answer:

μ₁`= 1/6

μ₂=  5/36

Step-by-step explanation:

The rolling of a fair die is described by the binomial distribution, as  the

The moment generating function of the binomial distribution is derived as below

M₀(t) = E (e^tx)

        = ∑ (e^tx) (nCx)pˣ (q^n-x)

        = ∑ (e^tx) (nCx)(pe^t)ˣ (q^n-x)

        = (q+pe^t)^n

the expansion of the binomial is purely algebraic and needs not to be interpreted in terms of probabilities.

We get the moments by differentiating the M₀(t) once, twice with respect to t and putting t= 0

μ₁`= E (x) = [ d/dt (q+pe^t)^n]  t= 0

            = np

μ₂`=  E (x)² =[ d²/dt² (q+pe^t)^n]  t= 0

              = np +n(n-1)p²

μ₂=μ₂`-μ₁` =npq

in similar way the higher moments are obtained.

μ₁`=1(1/6)= 1/6

μ₂= 1(1/6)5/6

   = 5/36

Answer:

Step-by-step explanation:

3/8=0.375

11/16=0.6875

0.375+0.6875=1.0625

Answer:

Horizontal component = 9.6

Step-by-step explanation:

Recall that the horizontal component is given by the cosine projection;

[tex]v_x=|v_0| * cos(\theta)[/tex]

which in our case (using the fact that in each degree of angle one has 60 minutes of angle, and therefore 30 minutes of angles is the same as 0.5 degrees) becomes:

[tex]v_x=12.6 * cos(40.5^o)=9.5811[/tex]

And rounding to the nearest tenth as requested, we have:

[tex]v_x=9.6[/tex]

Answer:

19

Step-by-step explanation:

1. y= -5x + 12

  y= -5x – 7

2. -5x + 12

   -(-5x – 7)

3. -5x + 12

    5x + 7

    0   +19

4. 19

Answer:

Equivalent, equivalent, not equivalent.

Step-by-step explanation:

The answers for the first two are equal, but the last one doesn't have equal answers.

Answer:

dont get it

Step-by-step explanation:

The question is specific enough for an answer.

Answer:

So now D would be at (-4 , 2)

Step-by-step explanation:

From D, you can calculate every other letter’s location. Yeah.

Answer:

Please mark me as brainliest!

Step-by-step explanation:

The coordinates:

D: ( 2,6 )

A: ( 2, 1 )

B: ( 5, 1 )

C: ( 5, 6 )

You want to translate this down 4 units and left 6 units.

So what you would do is this:

Formula = ( x - 6 , y - 4 )

D: ( -4, 2 )

A: ( -4, -3 )

B: ( -1, -3 )

C: ( -1, 2 )

Answer:

The AP is 6, 11, 16, 21, 26, 31, 36, 41, 46, 51, 56, 61 ....

Step-by-step explanation:

The nth term = a1 + d(n - 1)

Sum of 5th and 9th terms

= a1 + 4d + a1 + 8d = 72

2a1 + 12d = 72.............(1)

Similarly:

a1 + 6d + a1 + 11d = 97

2a1 + 17d = 97..............(2)

Subtracting equation (1) from equation (2):

5d = 25

d = 5.

and , using equation (1), the first term

a1 = (72 - 12(5)) / 2

= 12/2

= 6.

Answer:

1st and 4th

Step-by-step explanation:

goodluck!

Answer:

Quotient=306

Step-by-step explanation:

2449÷8

Quotient=306 remainder=1

Answer:

The answer for height is 20

Step-by-step explanation:

Answer

(-6. 3) (-6, 6) (-4, 2)

Step-by-step explanation:

the solution is the dark area between the two lines.

the only trick would be if one of the points fell on the dotted line.

all points on the dotted line are not included but all points on the solid line are included.

Answer:

12x +4y + 3z=36

Step-by-step explanation:

The equation of plane is given by

z-zo = a(x-xo) + b(y-yo)

pass through (1,3,4)

Z -4 = a(x -1) +b(y-3)

The question is asking us to optimize a and b. To minimize the volume V both a and b should be negative as the normal vector should be towards the negative x and y direction so that a finite tetrahedron can be formed in the first octant.

we need x , y and z intercepts o define volume

x intercept( y, z =0) = [tex]\frac{a+3b-4}{a}[/tex]

y intercept (x, z =0) = [tex]\frac{a+3b-4}{b}[/tex]

z intercept ( x, y =0) = -(a+3b-4)

Base = [tex]\frac{(a+3b-4)^2}{2ab}[/tex]

Volume = [tex]\frac{1}{3}*base*height[/tex]

Volume(a, b) = [tex]\frac{-(a+3b-4)^3}{6ab}[/tex]

now we differentiate partially in terms to a and b the volume to minimize and get a and b.

ΔV(a, b) = [tex]\frac{-1}{6}(\frac{3(a+3b-4)^2ab-b(a+3b-4)^3}{a^2b^2}[/tex] ,[tex]\frac{-1}{6}(\frac{9(a+3b-4)^2ab-a(a+3b-4)^3}{a^2b^2}[/tex]  = 0

Taking the first part of differential it will give

b(a+3b-4) [3a -(a+3b -4)] =0

(a+3b-4) [tex]\neq 0[/tex] because the volume will become zero if this becomes true

2a -3b = -4  ..................(1)

similarly the second part of the differential will give

a-6b=4 ................(2)

on solving 1 and 2 we get

a = -4 and b = -4/3

so the equation will be

Z -4 = -4(x -1) - 4/3*(y-3)

final equation

12x +4y + 3z=36

Answer:

5:15

Step-by-step explanation:

Quater means 15 and passed means 15 passed 5