Use the periodic table, to determine which element the following spin diagram represents

Use The Periodic Table, To Determine Which Element The Following Spin Diagram Represents

Answers

Answer 1
The answer is A chlorine

Related Questions

how many moles of oxygen atoms are present in 0.4 moles of oxygen gas​

Answers

Answer:

Each molecule of O2 is made up of 2 oxygen atoms. So 1 mole of O2 molecules is made up of 2 moles of oxygen atoms. Therefore 1 mole of oxygen gas contains 2 moles of oxygen atoms. And 0.4 moles of oxygen gas contains 0.8 moles of oxygen atoms.

There are 0.8 moles of oxygen atoms in 0.4 moles of oxygen gas.

Oxygen gas (O₂) consists of two oxygen atoms bonded together. Therefore, to determine the number of moles of oxygen atoms present in a given amount of oxygen gas, we can simply multiply the number of moles of oxygen gas by the number of oxygen atoms per molecule, which is 2.

Given that we have 0.4 moles of oxygen gas, we can calculate the number of moles of oxygen atoms as follows:

Number of moles of oxygen atoms = Number of moles of oxygen gas × Number of oxygen atoms per molecule

= 0.4 moles × 2

= 0.8 moles

Therefore, there are 0.8 moles of oxygen atoms present in 0.4 moles of oxygen gas.

This calculation is based on the stoichiometry of oxygen gas, which indicates that each molecule of O₂ contains two oxygen atoms. By considering the mole ratio between oxygen gas and oxygen atoms, we can determine the number of moles of oxygen atoms in a given quantity of oxygen gas.

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number is equal to 6022 x 10^23

Answers

Answer:

The Avogadro's number

Explanation:

the number is 6.02214x10 to the 23 power

Which gas will have the least collisions between its particles?
A. Argon at 265 K
B. Helium at 20 C
C. Oxygen at -45 C
D. Carbon dioxide at 80 C

Answers

Answer:

C

Explanation:

This is because oxygen has the lowest temperature, thereby collision rate is least

Draw a relative energy diagram showing a conformational analysis of 2,2-dichloropropane along C1-C2 bond. Clearly label all staggered conformations and all eclipsed conformations with the corresponding Newman projections.

Answers

Answer:

^#))(899900000)My020

A student isolated an unknown organic compound through extraction. The student measures the melting point and fins it to be 115-122 C. The student looks through the list of possible strucures and decides the comound is most likely 2-napthol. Do you believe this choice is correct?

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Hope this helps!

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The valves in the heart open and close to move blood in between heart chambers. O a) three directions O b) two directions O c) four directions d) one direction

Answers

Answer:

im not sure but i think its four directions

Hi,

The valves in the heart open and close to move blood in between heart chambers.

Answer:

d) one direction

22 SEE ** AL A large number of organic compounds have been discovered and isolated from natural sources by the first quarter of the 19th century but till then, none of the organic compounds could be prepared in the laboratory. It was believed that organic compounds followed laws of formation different from inorganic compounds and that some vital force was necessary to produce the organic compounds. Synthesis of these organic compounds in the lab was impossible due to the absence of vital force, which only known to exist in the living organisms. In 1828, Friedrich Wöhler produced the compound urea, H2N-CO-NH2 in the laboratory. Why was the result of this experiment significant in the history of Organic chemistry? (5 marks) Write equations showing the synthesis of urea from ammonium cyanate. (3 marks)​

Answers

This reaction achieved by  Friedrich Wöhler led to the birth of synthethic organic chemistry.

Prior to the successful synthesis of urea by Friedrich Wöhler in the year 1828, chemists believed that it is purely impossible to synthesize various organic substances in the laboratory owing to the absence of an imaginary "vital force". responsible for the formation of those substances.

However, the synthesis of urea by Friedrich Wöhler opened up the idea of laboratory organic synthesis which have blossomed into the present synthetic organic chemistry.

The equation for the synthesis of urea from ammonium cyanate is shown in the image attached.

Organic compounds which occur in nature could now be synthesized and studied under laboratory conditions.

Hence, this reaction achieved by  Friedrich Wöhler led to the birth of synthethic organic chemistry.

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What is the amount of heat required to change one mole of a substance from the solid to liquid state known as?
Select the correct answer below:

A) the enthalpy of fusion
B) the melting point
C) the entropy of disorder
D) none of the above

Answers

Answer:

A) the enthalpy of fusion

Explanation:

the heat of vaporization, is the amount of energy needed to change a liquid to a gas at constant temperature and pressure. The energy required to melt a solid to a liquid is called the heat of fusion,  and the heat of sublimation is the energy.

Answer:

A

Explanation:

Rubric #2
Forensic Science
1. Define Nucleus.
2. Define Cytoplasm.
3. Define Cell Membrane.
4. Define DNA.
5. Define Plant.
6. Define Chlorophyll.
7. Define Photosynthesis.
8. How do Plant cells and Animal cells differ?
9. Define Cell Wall.
10. Define Vacuole.
11. Why do cells differentiate in multicellular organisms?
12. Define Multicellular.
13. Complete the Eukaryotic cells and Cell Differentiation assessment.
https://clever.discoveryeducation.com/learn/techbook/units/95c20a43-6d3d-40d3-
848d-89929101140d/concepts/co0fef01-33e7-4116-8819.
143e289e15ba/tabs/6e1551ab-57b8-42d4-8e5b-25549791c760/pages/de4182af-aa 60-
454f-ae5e-28df6f4eb3ac

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Explanation:

1. Nucleus is a memberane bound organelle that contains cell,s chromosomes.

202H8(9) + 7 O2(g) > 4CO2(g) + 6 H2O(9).
AH = -1560.7 kJ/mol
Which direction with the equilibrium shift if the carbon dioxide is increased?​

Answers

since the concentration of Carbon Dioxide will increase, it would make Q > K, cause equilibrium to shift in the direction with less moles of gas to alleviate the extra pressure. In this case, the reaction will shift left because there are fewer moles of gas present.

What 2 variables are needed to calculate the percent yield?

Answers

Answer:

isn’t it reactants and products?

Explanation:

Answer: reactants and products

Explanation:

Write chemical equations for the acid-base reactions that occur when:

a. Solutions of HC₂H₃O₂ (acetic acid) and KOH are mixed.
b. Solutions of HCN (hydrocyanic acid) and Na₂CO₃ are mixed.

Answers

Acetic acid is basically known as CH_3COOH.

Chemical Equation:-

[tex]\boxed{\sf {CH_3COOH\atop Acetic\:acid}+{KOH\atop Potassium\:Hydroxide}\longrightarrow {CH_3COOK\atop Potassium\: Acetate}+{H_2O\atop Water}}[/tex]

This kinda reaction is called Neutralization Reaction.

Solution:-2

[tex]\boxed{\sf {HCN\atop Hydrogen\:Cyanate}+{Na_2CO_3\atop Sodium\:Carbonate}\longrightarrow {NaCN\atop Sodium\:Cyanate}+{H_2O\atop water}+{CO_2\atop Carbon\:dioxide}}[/tex]

Hydro cyanic acid is also called HydrogenCyanate.

what is the net charge of an ion that as 14 protons 16 electrons and 12 neutrons

Answers

Answer:

[tex]\boxed {\boxed {\sf -2}}[/tex]

Explanation:

We are asked to find the net charge of an ion.

The ion has 14 protons, 16 electrons, and 12 neutrons. Recall the charges of each subatomic particle.

Proton: +1 Electron: -1 Neutron: 0

Neutrons are neutral and have no charge, so we can ignore them while finding the net charge. There are 14 protons and 16 electrons.

14 protons and 14 electrons have a net charge of 0 because the charges balance each other out. However, we have 16 electrons, which is 2 more than 14. Each electron has a charge of -1, so the 2 electrons add a charge of -2.

The net charge of the ion is -2.

Name the following alkane molecule:
CH3
|
CH3CHCH2CHCH2CHCH3
CH
CH2CH2CH3
A. 2,4,6-trimethylheptane
B. 4-ethyl-2,6-dimethylheptane
C. 2,6-dimethyl-4-propylheptane

Answers

Answer:

2,6dimethyle-4-propylheptane

I guess!

The correct name of the compound is 4-ethyl-2,6-dimethylheptane.

What is IUPAC nomenclature?

The IUPAC nomenclature shows the correct way to name a compound this rule is established by the International Union of Pure and Applied Chemistry.

Looking at the structure of the compound as shown, the correct name of the compound is 4-ethyl-2,6-dimethylheptane.

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Which of the following substances can be used to neutralize HF?

A: HF
B: SO2
C: HCI
D: NaOH

Answers

Answer:

option (D) NaOH is right answer

A neutralization reaction is "a reaction in which an acid and a base react to form water and a salt and involves H+ ions and OH- ions to produce water.

What is an acid?

An acid is "any hydrogen-containing substance that is capable of donating a proton or hydrogen ion to another substance".

What is base?

Base is "a substance that gets dissociated in an aqueous solution to form hydroxide ions OH-".

Hence, NaOH can be used to neutralize HF.

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The conversion of CICH=CHCI to CI2C=CC12 can be carried out with:
C12 / H20
C12
C12/ hv
C12 / aq. NaOH​

Answers

Answer:

I think third C12/hv is right answer

What makes it possible
for a vascular plant to
be a long distance from
a water source?
A. long leaves
B. flowers
C. long roots
D. long stems

Answers

Answer:

I think long roots

Explanation:

Answer :
long roots

Explanation :
the roots allow the plant to absorb nutrients from the soil

Write any four difference between metals and non metals.​

Answers

Answer:

metals are malleable and ductile.

Non metals are non malleable and ductile.

Metals are good conductor of heat and electricity.

Non metals are bad conductor of heat and electricity.

Metals are lustrous.

Non metals are non lustrous.

Metals are strong and tough.

Non metals are not strong or tough.

Hope it helps you.Thank you

Answer:

1metal are good conductor of heat and electricity

2metal are ductile and mellability .

3it doesnot get brittle .

4metal are hard .

and for nonmetle you can just add

Calculate the no. of moles in 15g of CaCl2

Answers

Answer:

[tex]\boxed {\boxed {\sf 0.14 \ mol \ CaCl_2}}[/tex]

Explanation:

We are asked to calculate the number of moles of 15 grams of calcium chloride (CaCl₂).

To convert from grams to moles, we use the molar mass, or the mass of 1 mole of a substance. Molar masses are found on the Periodic Table because they are equivalent to the atomic masses, but the units are grams per mole instead of atomic mass units.

Look up the individual elements in the compound: calcium and chloride.

Ca: 40.08 g/mol Cl: 35.45 g/mol

Notice the chemical formula has a subscript of 2 after Cl or chlorine. There are 2 moles of chlorine in every 1 mole of calcium chloride. We must multiply chlorine's molar mass by 2 before adding calcium's molar mass.

Cl₂: 35.45 * 2 = 70.9 g/mol CaCl₂= 40.08 + 70.9 = 110.98 g/mol

We will convert using dimensional analysis, so we must create a ratio using the molar mass.

[tex]\frac {110.98 \ g \ CaCl_2}{ 1 \ mol \ CaCl_2}[/tex]

We are converting 15 grams of calcium chloride to moles, so we must multiply the ratio by this value.

[tex]15 \ g \ CaCl_2 *\frac {110.98 \ g \ CaCl_2}{ 1 \ mol \ CaCl_2}[/tex]

Flip the ratio so the units of grams of calcium chloride cancel.

[tex]15 \ g \ CaCl_2 *\frac { 1 \ mol \ CaCl_2}{110.98 \ g \ CaCl_2}[/tex]

[tex]15 *\frac { 1 \ mol \ CaCl_2}{110.98}[/tex]

[tex]\frac { 15}{110.98} \ mol \ CaCl_2[/tex]

[tex]0.1351594882\ mol \ CaCl_2[/tex]

The original measurement of grams (15) has 2 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place. The 5 in the thousandth place tells us to round the 3 up to a 4.

[tex]0.14 \ mol \ CaCl_2[/tex]

15 grams of calcium chloride is approximately 0.14 moles of calcium chloride.

The functional groups in an organic compound can frequently be deduced from its infrared absorption spectrum. A compound, C5H10O2, exhibits strong, broad absorption across the 2500-3200 cm^1 region and an intense absorption at 1715 cm'^-1. Relative absorption intensity: (s)=strong, (m)-medium, (w) weak. What functional class(cs) docs the compound belong to List only classes for which evidence is given here. Attach no significance to evidence not cited explicitly. Do not over-interpret exact absorption band positions. None of your inferences should depend on small differences like 10 to 20 cm^1. The functional class(es) of thla compound is(are) alkane (List only if no other functional class applies.) alkene terminal alkyne internal alkyne arene alcohol ether amine aldehyde or ketone carboxylic acid ester nitrile

Answers

Answer:The functional groups in an organic compound can frequently be deduced from its infrared absorption spectrum. A compound, C5H10O2, exhibits strong, broad absorption across the 2500-3200 cm^1 region and an intense absorption at 1715 cm'^-1. Relative absorption intensity: (s)=strong, (m)-medium, (w) weak. What functional class(cs) docs the compound belong to List only classes for which evidence is given here. Attach no significance to evidence not cited explicitly. Do not over-interpret exact absorption band positions. None of your inferences should depend on small differences like 10 to 20 cm^1. The functional class(es) of thla compound is(are) alkane (List only if no other functional class applies.) alkene terminal alkyne internal alkyne arene alcohol ether amine aldehyde or ketone carboxylic acid ester nitr

The half life of radium-226 is 1600 years. If you have 200 grams of radium today how many grams would be present in 8000 years?

Answers

Answer:

Half life is the time taken by a radio active isotope to reduce by half of its original amount. Radium-226 has a half life of 1602 years meaning that it would take 1602 years for a mass of radium to reduce by half.

Number of half lives in 9612 years = 9612/1602 = 6 half lives

New mass = Original mass x (1/2)n where n is the number of half lives.

Therefore, New mass= 500 x (1/2)∧6

                                 = 500 x 0.015625

                                 = 7.8125 g

Hence the mass of radium after 9612 years will be 7.8125 grams.

Explanation:

Answer:

[tex]\boxed {\boxed {\sf 6.25 \ grams}}[/tex]

Explanation:

We are asked to find the mass of a sample of radium-226 after half-life decay. We will use the following formula:

[tex]A= A_o *\frac{1}{2}^{\frac{t}{h}}[/tex]

In this formula, [tex]A_o[/tex] is the initial amount, t is the time, and h is the half-life.

For this problem, the initial amount is 200 grams of radium-226, the time is 8,000 years, and the half-life is 1,600 years.

[tex]\bullet \ A_o= 200 \ g \\\\bullet \ t= 8,000 \ \\\bullet \ h= 1,600[/tex]

Substitute the values into the formula.

[tex]A= 200 \ g * \frac{1}{2} ^{\frac{8.000}{1,600}[/tex]

Solve the fraction in the exponent.

[tex]A= 200 \ g * \frac{1}{2}^{5}[/tex]

Solve the exponent.

[tex]A= 200 \ g *0.03125[/tex]

[tex]A= 6.25 \ g[/tex]

In addition, we can solve this another way. First, we find the number of half-lives by dividing the total time by the half-life.

8,000/1,600= 5 half-lives

Every half-life, 1/2 of the mass decays. Divide the initial mass in half, then that result in half, and so on 5 times.

1.  200 g/2= 100 g2. 100 g / 2 = 50 g3. 50 g / 2 = 25 g 4. 25 g / 2 = 12.5 g5. 12.5 g / 6.25 g

After 8,000 years, 6.25 grams of radium-226 remains.

what is a compound?And what are some common examples of a compound?​

Answers

Answer:

Compounds are substances made from atoms of different elements joined by chemical bonds. Common examples are water (H2O), salt (sodium chloride, NaCl), methane (CH4).

How does a smoke detector utilize radiation?

A. Beta radiation creates a stead stream of electrons. When the stream is broken by smoke particles, it sets off the alarm.
B. Alpha radiation ionizes the air. When smoke interacts with the ionized particles it causes the alarm to sound.
C. Gamma radiation creates a stead stream of electrons. When the stream is broken by smoke particles, it sets off the alarm.
D. Beta radiation ionizes the air. When smoke interacts with the ionized particles it causes the alarm to sound.

Answers

D. Beta radiation ionizes the air. When smoke
interacts with the ionized particles it causes the
alarm to sound.

why is repetition important in science?

Answers

Answer:

the repetition principle is important in scientific research, because the observational indexes are random variables,which requires a certain amount of samples to reveal their changing regularity

repeating something as in a meaning of a word helps us not only remember but have it stuck in our brain. My science teacher in 10th made us rewrite our vocab everyday until all of us knew it. When it came to test taking it was so much easier when I thought of the word. Repetition is so important in science to not only get you to understand the meaning of something but help you remember it.

Spinocerebellar Ataxia

Answers

Spinocerebellar ataxia (SCA) is a term referring to a group of hereditary ataxias that are characterized by degenerative changes in the part of the brain related to the movement control (cerebellum), and sometimes in the spinal cord.

The density of toluene (C7H8) is 0.867 and that of thiophene (C4H4S) is 1.065 g/ml. A solution is made by dissolving 10.00g thiophene in 250.00ml of toluene. a)Calculate the molarity of the solution
b)Assuming the volume are addictive ,calculate the molarity of the solution

Answers

Answer:

Calcular la molaridad de una solución que se preparó disolviendo 14 g de KOH en suficiente  

agua para obtener 250 mL de solución. (masa molar del KOH = 56 g/mol).

Resolución: de acuerdo a la definición de “molaridad” debemos calcular primero, el número de mol de soluto (KOH) que  

se han disuelto en el volumen dado, es decir, “se transforma g de soluto a mol de soluto” por medio de la masa molar,  

así:

56 g de KOH 14 g de KOH

----------------- = ------------------- X = 0,25 mol de KOH

1 mol X

Ahora, de acuerdo con la definición de molaridad, el número de mol debe estar contenido en 1000 mL (o 1 L) de  

solución, que es el volumen estándar para esta unidad de concentración, lo que se determina con el siguiente planteamiento:

0,25 mol X

----------------------- = ------------------------- X = 1 mol de KOH

250 mL de solución 1000 mL de solución

Explanation:

Explain why you get a basic solution when you dissolve NaF in water.

Answers

Answer:

The fluoride ion is capable of reacting, to a small extent, with water, accepting a proton. The fluoride ion is acting as a weak Brønsted-Lowry base. The hydroxide ion that is produced as a result of the above reaction makes the solution slightly basic.

So

we get a basic solution when you dissolve NaF in water.

Na is a alkaline earth metal

Metallic compound dissolved in water acts as base

Also there is another reason

Na F is ioniC

Fluorine is known as having highest electron affinity in world

It can accept a line pair of OH-

So it's Bronsted Lowry base .

It can also acts as Arrhenius base

Hence its basic

write anode and cathode in Zn-Ag galvanic cell​

Answers

Explanation:

Zinc is the anode (solid zinc is oxidised). Silver is the cathode (silver ions are reduced).

By convention in standard cell notation, the anode is written on the left and the cathode is written on the right. So, in this cell: Zinc is the anode (solid zinc is oxidised). Silver is the cathode (silver ions are reduced).

Q1: A stock solution containing Mn+2 ions was prepared by dissolving 1.584 g pure manganese metal in nitric acid and diluting to a final volume of 1.000 L. The following solutions were then prepared by dilution: For solution A, 50.00 mL of stock solution was diluted to 1000.0 mL. For solution B, 10.00 mL of solution A was diluted to 250.0 mL. For solution C, 10.00 mL of solution B was diluted to 500.0 mL. Calculate the concentrations of the stock solution and solutions A, B, and C.

Answers

The concentration of a solution is the amount of solute in a solution.

We have from the question that he mass of manganese = 1.584 g

Hence;

Amount of [tex]Mn^2+[/tex] = 1.584 g/55g/mol = 0.0288 moles

Recall that;

Number of moles = concentration * volume

Let the concentration of the solution be C

0.0288 moles = C * 1 L

C = 0.0288 moles/ 1 L

C= 0.0288 mol/L

Hence concentration of stock solution = 0.0288 mol/L

For solution A

From the dilution formula;

C1V1 = C2V2

where;

C1 = initial concentration

C2 = final concentration

V1 =  initial volume

V2= final volume

C1 = 0.0288  mol/L

V1 = 50.00 mL

C2 = ?

V2 = 1000.0 mL

C2 = 0.0288  mol/L * 50.00 mL/1000.0 mL

C2 = 0.00144 mol/L

Hence, concentration of solution A is 0.00144 mol/L

For solution B

C1V1 = C2V2

C1 = 0.00144 mol/L

V1 = 10.00 mL

C2 = ?

V2 = 250.0 mL

C2 = 0.00144 mol/L * 10.00 mL/250.0 mL

C2 = 0.0000576 mol/L

Hence, concentration of solution B is 0.0000576 mol/L

For solution C

C1 = 0.0000576 mol/L

V1 = 10.00 mL

C2 = ?

V2 = 500.0 mL

C2 = 0.0000576 mol/L * 10.00 mL/500.0 mL

C2= 0.000001152 mol/L

Hence, concentration of solution C is 0.000001152 mol/L

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Hello, I am a bit stuck on this. Could someone help?

Answers

There is no picture or question. What am I supposed to answer to?
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