Answer:
c² = 3² +6² - 2⋅3⋅6⋅cos 60
c = 27ft
Step-by-step explanation:
Since the angle is located in between the sides of the sides, we will use the cosine rule to get the unknown sides
Let c be the missing sides
According to the cosine rule;
c² = a²+ b² - 2abcosC
c² = 3² +6² - 2⋅3⋅6⋅cos 60
c² = 9 + 36 - 36cos60
c² = 45 - 36cos60
c² = 45 - 36(0.5)
c² = 45 - 18
c² = 27ft
Hence the missing attribute is 27ft and the required expression is c² = 3² +6² - 2⋅3⋅6⋅cos 60
A $550 T.V is discounted by 30%. It is then discounted another 10%
Answer:
346.50
Step-by-step explanation:
550 discounted by 30% is 385.00.
385.00 discounted by 10% is 346.50
What is the measure of 4? Please and thank you :)
Answer:
[tex]\angle 2 = 48[/tex]
Step-by-step explanation:
Given
[tex]\angle 1 = 48[/tex]
Required
Find [tex]\angle 2[/tex]
[tex]\angle 1[/tex] and [tex]\angle 2[/tex] are vertically opposite angles.
So:
[tex]\angle 2 = \angle 1[/tex]
Substitute [tex]\angle 1 = 48[/tex]
[tex]\angle 2 = 48[/tex]
PLS HWLP ME, I REALLY NEED IT
Answer:
E. 3×3×3×3
part b:
3×3×3×3
9×9
81
Find the length of side x in simplest radical form with a rational denominator.
Answer:
8
Step-by-step explanation:
sin Θ = opp / hyp
Θ = 60
opp = 4
hyp = x
sin 60 = 4 / x sin 60 = 0.5 or 1/2
1/2 = 4 / x
x/2 = 4
x = 8
Starting salaries of 135 college graduates who have taken a statistics course have a mean of $42,650. Suppose the distribution of this population is approximately normal and has a standard deviation of $8,988. Using a 93% confidence level, find both of the following:
(NOTE: Do not use commas nor dollar signs in your answers.)
(a) The margin of error:
(b) The confidence interval for the mean μ:
Answer:
Hence, the margin error is [tex]1415.62189[/tex] and the confidence interval for the mean is [tex](41234.38,44065.62)[/tex].
Step-by-step explanation:
Given :
Sample size [tex]n=135[/tex]
Sample mean [tex]\bar{x}=\$42,650[/tex]
Standard deviation [tex]\sigma =\$8,988[/tex]
Confidence level is [tex]93\%[/tex]
(a)
The margin error [tex]=Z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n}}[/tex]
[tex]\because \alpha =1-[/tex]confidence level
[tex]\Rightarrow \alpha=1-93\%=1-0.93[/tex]
[tex]\Rightarrow \alpha=0.07\Rightarrow \frac{\alpha}{2}=0.035[/tex]
[tex]Z_{\frac{\alpha}{2}}=Z_{0.035}=1.83[/tex] from the [tex]z-[/tex]table
Now, the margin error[tex]=1.83\times \frac{8988}{\sqrt{135}}[/tex]
[tex]=1415.62189[/tex]
(b)
The confidence interval for the mean [tex]\mu\\[/tex] :
[tex](\bar{x}-\text{margin error},\bar{x}+\text{margin error})[/tex]
[tex]\Rightarrow (\bar{x}-1415.62189,\bar{x}+1415.62189)[/tex]
[tex]\Rightarrow (42650-1415.62189,42650+1415.62189)\\\Rightarrow (41234.38,44065.62)[/tex]
A coin collection consists of nickels, dimes and quarters, and has a total value of $3.30. There are three times as many nickels as quarters. How many coins of each kind are there if the numbers of dimes is three less than the average of the number of nickels and number of quarters
Answer:
18 nickels, 9 dimes, and 6 quarters.
Step-by-step explanation:
Answer:
18 nickels, 9 dimes, and 6 quarters
Step-by-step explanation:
Find the probability of rolling a number greater than 2 on a number cube labeled 1-6 write your answers as a decimal
Answer: Approximately 0.667
================================================================
Explanation:
Here are all the possible outcomes to roll on the number cube: {1,2,3,4,5,6}
Here are the outcomes which are greater than two: {3,4,5,6}
There are 4 outcomes we want (rolling a 3 through 6) out of 6 outcomes total, so we end up with the probability 4/6 = 0.667 which is approximate
In reality, the 6's go on forever in the decimal value, but we can't write the number forever. Round that value in bold however you need to or however your teacher instructs.
geometry help pleaseeee
Answer: 11
Step-by-step explanation:
[tex]48=4x+4[/tex] (angles opposite congruent sides in a triangle are congruent)
This gives that x = 11
The average annual precipitation in Berkeley, CA is 26.8 inches. Albany, NY has an average precipitation of 39.4 inches. What is the difference in two cities average annual precipitation.
Equation:
Solution:
Answer:
The equation is 39.4 - 26.8
The solution is: 12.6 inches.
Step-by-step explanation:
To find the difference in average precipitation between Albany and Berkeley, we subtract the average annual precipitation in each city.
We have that:
Albany: 39.4 inches
Berkeley: 26.8 inches.
So the equation is:
39.4 - 26.8
And the solution is:
39.4 - 26.8 = 12.6 inches.
3) 40% of the class of 30 students are boys.
How many are girls?
Answer:
there 18 girls
Step-by-step explanation:
40% of 30 = 12
this means there are 12 boys
30-12 = 18
there 18 girls
HELP ASAP!!!!!!!!!!!!!!!!!!!!
I think that it might be the third one. I hope this helped
What is the weight (in grams) of a liquid that exactly fills a 465.0 milliliter container if the density of the liquid is 0.982 grams over milliliter? Round to the nearest hundredth when necessary and only enter numerical values, which can include a decimal point.
Answer:456.63
Step-by-step explanation:
The weight (in grams) of a liquid is 456.63 grams.
What is weight?Weight is a quantity representing the force exerted on a particle or object by an acceleration field, particularly the gravitational field of the Earth at the surface.
V = Volume of liquid = 182.8 milliliter
[tex]\rho[/tex] = Density of liquid = 0.135 grams over milliliter
We know that,'
mass= volume x density
= 465 x 0.982
= 456.63 grams
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Solve for x. Round to the nearest tenth. *
9.8
5.3
61.2
8.6
Answer:
9.85
that is 9.8
Step-by-step explanation:
16sin38=x
x= 9.85
Find all solutions of sin x - sqr3-3sin^2x =0
Answer:
sqr3 sin x/2
+ cos x = 1 if 0º< < 360°.
Step-by-step explanation:
PLease Help help Help
Answer:
98.1 square units
Step-by-step explanation:
know you need it quick
Does the quadratic function
f(x) = 3x2 + 5x + 17 have one,
two, or no real zeros? Utilize the
quadratic formula to determine
the answer
[?] real zero(s)
Answer:
[0] real zeros
Step-by-step explanation:
You can use the discriminant of the quadratic formula which is b² – 4ac to determine the # of real zeros by knowing that:
2 real zero(s) occur when b² – 4ac > 0.1 real zero(s) occur when b² – 4ac = 0.0 real zero(s) occur when b² – 4ac < 0.Taking into account the definition of zeros of a function, the function has no real roots and its graph does not intersect the x-axis.
Zeros of a functionThe function f(x) = ax² + bx + c
with a, b, c real numbers and a ≠ 0, is a function quadratic expressed in its polynomial form (It is so called because the function is expressed by a polynomial).
The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.
That is, the zeros represent the roots of the polynomial equation that is obtained by making f(x)=0.
In summary, the roots or zeros of the quadratic function are those values of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.
The following expression is called discriminant:
Δ= b²- 4×a×c
The discriminant determines the amount of roots of the function. Then:
If Δ <0 the function has no real roots and its graph does not intersect the x-axis.If Δ> 0 the function has two real roots and its graph intersects the x-axis at two points .If Δ = 0 the function has a real root and its graph intersects the x-axis at a single point that coincides with its vertex. In this case the function is said to have a double root.Amount of roots in this caseIn this case, the function is f(x) = 3x² + 5x + 17, where:
a= 3b= 5c= 17Replacing in the definition of discriminant:
Δ= 5²- 4×3×17
and solving you get:
Δ= 25- 204
Δ= -179
Since Δ< 0, the function has no real roots and its graph does not intersect the x-axis.
Learn more about the zeros of a quadratic function:
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Julie is solving the equation 3x2 + 5x + 15 = 0 and notices that the discriminant b2 - 4ac has a value of -155. This tells her that the
equation has
Answer: A
Step-by-step explanation:
In an examination a candidate scored 5 marks for a correct answer, -2 for an incorrect answer and 0 marks for a question that has not been attempted. The examination comprises 20 questions. Ananya has answered 12 correct answer and 5 incorrect answers . Find her total score.
Answer:
Ananya's total score was 50 marks.
Step-by-step explanation:
Given that in an examination a candidate scored 5 marks for a correct answer, -2 for an incorrect answer and 0 marks for a question that has not been attempted, and the examination comprises 20 questions, and Ananya has answered 12 correct answer and 5 incorrect answers, to find her total score the following calculation must be performed:
(12 x 5) + ((20 -12 - 5) x 0) + (5 x -2) = X
60 + (3 x 0) + (-10) = X
60 + 0 - 10 = X
50 = X
Therefore, Ananya's total score was 50 marks.
I need help please.
5x-1-3x≥4x+5
Someone help please
Answer:
-3≥x
Step-by-step explanation:
5x-1-3x≥4x+5
Combine like terms
2x-1≥4x+5
Subtract 2x from each side
2x-1-2x≥4x+5-2x
-1≥2x+5
Subtract 5 from each side
-1-5≥2x+5-5
-6≥2x
Divide by 2
-6/2≥2x/2
-3≥x
Answer:
See Image below for the steps:)
Step-by-step explanation:
IF THE TWO ANGLES IN A LINEAR PAIR HAVE EQUAL MEASURES THEN EACH IS A RIGHT ANGLE
TRUE OR FALSE
HELP PLS!!! WILL MARK BRAINLIEST
what percent of the runners ran 75 seconds or lower?
In the figure below, j || n. Find the values of y and x.
What is the solution of the system of equations
y-x=5 and y=x² +5?
1) (0,5) and (1,6)
2) (0,5) and (-1,0)
3) (2.9) and (-1,4)
4) (-2,9) and (-1.4)
The following list shows three factors that can either increase or decrease the probability of a Type II error. The sample size is increased. The significance level is increased. The standard error is increased. Which factors alone will cause the probability of a Type II error to increase?
Answer:
Standard Error is increased.
Step-by-step explanation:
Type 2 error is failure to reject a false null hypothesis. This is a 'false negative' result of hypothesis testing, represented by beta 'β'.
Power of test is 1 - β, which shows probability of accurately stating a null hypothesis false, when it is actually false.
Increased sample size increases the power of test accuracy, hence reduces type 2 error. Increased level of significance implies higher probability of rejecting a true null hypothesis, ie type 1 (false positive) error. So, it decreases type 2 error.
Standard Error increase implies lower level of t statistic , ie = (x - u) / (s / √ n) Lower the t value, higher is the probability of not rejecting null hypothesis, which implies higher chance of type 2 error.
Type II error is 1 - power of the test. The factor that can alone make the type II error to increase is: Option C: The standard error is increased.
Firstly the whole story starts from hypotheses. The null hypothesis is tried to reject and we try to accept the alternate hypothesis.
The type 1 error occurs if we get false positive conclusion (false positive means we accuse null hypothesis being wrong when it was actually correct).The type 2 error occurs if we get false negative conclusion (false negative means we accept null hypothesis when it was actually false). It is 1 - statistical power of the test. Thus, increasing power of the test decreases this error.How are the type I error and type II error are related to level of significance?The probability of committing the type I error is called the significance level of the hypothesis test.
And the more we increase the level of significance, the less area the test statistic gets to fall in, and its chances of falling in region outside level of significance increases, which makes us to reject the null hypothesis more probable, thus, decreasing its chance of tagging as negative, not mattering if true or false.
Thus, increasing level of significance increases the type I error but decreases the type II error.
If it is increases, the likely area for test statistic falling increases, thus, increasing probability of tagging the null hypothesis tagging to be true, so increasing result of test being declared negative, thus, increasing type II error.
How is type II error and sample size related?Increasing sample size increases statistical power, thus, decreasing the type II error.
Thus, for the given case, as the sampling size is increased, the type II error will decrease, as the significance level is increased, the type II error will decrease, and as the standard error is increased, the type II error will increase with it.
Thus, out of the given factors, only the last factor (increasing the standard error) makes the type II error to get increased.
Thus, the factor that can alone make the type II error to increase is: Option C: The standard error is increased.
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Please I need help as soon as possible
Answer:
47. C. 30
48. D. 50
49. A. 10
50. A. 10
Step-by-step explanation:
47. The point in the middle of the box is the median, 30
48. The range is the last dot - the first dot outside of the box, 50 - 0 = 50
49. The interquartile range is the range inside the box, the first dot in the box is between 20 and 30, 25. The last dot in the box is between 30 and 40, 35.
35 - 25 = 10
50. Test A's median is 30, Test B's median is 40. 40 - 30 = 10
Hope this helps ^^
marquis cut a 33 inch roll of wire into 7 equal sized pieces for a science experiment WHAT is th3 length of each piece of wire
Answer:
4
Step-by-step explanation:
33÷7
A recent study in a small city stated that the average age of robbery victims was 63.5 years. A random sample of 20 recent victims had a mean of 63.7 years and a standard deviation of 1.9 years. At = 0.05, is the average age higher than originally believed?
Answer:
The p-value of the test is of 0.3219 > 0.05, which means that at [tex]\alpha = 0.05[/tex], the average age is not higher than originally believed.
Step-by-step explanation:
A recent study in a small city stated that the average age of robbery victims was 63.5 years. Test if the average age higher than originally believed.
At the null hypothesis, we test that the mean is the believed mean age of 63.5 years, that is:
[tex]H_0: \mu = 63.5[/tex]
At the alternate hypothesis, we test if this mean is higher, that is:
[tex]H_1: \mu > 63.5[/tex]
The test statistic is:
[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.
63.5 is tested at the null hypothesis:
This means that [tex]\mu = 63.5[/tex]
A random sample of 20 recent victims had a mean of 63.7 years and a standard deviation of 1.9 years.
This means that [tex]n = 20, X = 63.7, s = 1.9[/tex]
Test statistic:
[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]
[tex]t = \frac{63.7 - 63.5}{\frac{1.9}{\sqrt{20}}}[/tex]
[tex]t = 0.47[/tex]
P-value of the test and decision:
The p-value of the test is the probability of finding a sample mean above 63.7, which is a right-tailed test, with t = 0.47 and 20 - 1 = 19 degrees of freedom.
With the help of a calculator, this probability is of 0.3219.
The p-value of the test is of 0.3219 > 0.05, which means that at [tex]\alpha = 0.05[/tex], the average age is not higher than originally believed.
What is the answer for the four at the bottom?
What is the volume of this triangular prism
9514 1404 393
Answer:
153.6 mm³
Step-by-step explanation:
The volume of a prism is given by the formula ...
V = Bh . . . . . . where B is the area of the base, and h is the height
The area of the triangular base is given by the formula ...
A = 1/2bh . . . . where b and h are the base and height of the triangle
For a right triangle, the lengths of the legs can be used for the base and height.
The base area is ...
A = (1/2)(6 mm)(8 mm) = 24 mm²
Then the volume is ...
V = (24 mm²)(6.4 mm) = 153.6 mm³
