Answer: Magnitude of electrical force stays the same.
Explanation:
Equation:
[tex]F_{e} =k\frac{Q_{1}Qx_{2} }{r^{2} }[/tex]
Since the magnitude of each charge is halved.
and
the separation is halved.
[tex]F_{e} =k\frac{(.5Q_{1}*.5Q_{2} }{(.5r)^{2} }[/tex]
[tex]F_{e} =k\frac{.25*Q_{1}Qx_{2} }{.25*r^{2} }[/tex]
Cancel out .25 on the numerator and denominator. Leaving the original equation.
Determine usando ecuación de Bernoulli la Presión P1 necesaria para mantener la condición mostrada dentro del sistema mostrado en la figura, sabiendo que el aceite tiene un s.g =0.45 y el valor de d=90mm.
Answer:
PlROCA
Explanation:
ASK YOUR TEACHER An oil slick on water is 99.8 nm thick and illuminated by white light incident perpendicular to its surface. What color does the oil appear (what is the most constructively reflected wavelength, in nanometers), given its index of refraction is 1.38
Answer:
There will be a phase change at the 1-1.38 interface and no phase change at the 1.38-1.33 interface.
At a thickness of lambda / 4 (y/4) one should get constructive interference for the reflected light.
y = 4 * 99.8 * 10E-9 m = 400 nm (about) = 4 * 10E-7 m
The color of this light will be violet or blue
A 150g copper bowl contains 220g of water, both at 20.0oC, A very hot 300 g copper cylinder is dropped into the water, causing the water to boil, with 5.00 g being converted to steam. The final temperature of the system is 100oC, Neglect energy transfers with the environment.
a) How much energy (in calories) is transfered to the water as heat?
b) How much to the bowl?
c) What is the original temperature of the cylinder?
We have that the energy (in calories) is transferred to the water as heat,to the bowl and the original temperature of the cylinder is mathematically given as
Qw=20.3 kcal Q= 1.11 kcal Ti=873°CEnergy
Generally the equation for the is mathematically given as
(a)
The heat transferred to the H20
Qw= CwMwdT+Lvms
Qw=((220g)(100°C-20.0T)+(539 caVg)(5.00 g)
Qw=20.3 kcal .
(b)
The heat transferred to the bowl is
Qb= CbmbdT
Q= (0.0923 cal/gC)(150g)(100°C-20.0°C)
Q= 1.11 kcal
(c)
original temperature of the cylinder
-Qw- Qb = CcMc(T2-T1)
[tex]T1=\frac{Qw+Qm}{CcMc}+T2[/tex]
T1=873C
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if C is The vector sum of A and B C = A + B What must be true about The directions and magnitudes of A and B if C=A+B? What must be tre about the directions and magnitudes of A and B if C=0?
Check attached photo
Check attached photo
Kepler's laws, satellites motion and weightlessness
Answer:
First Kepler law states that Each planet describes an ellipsoidal motion about the sun as its single focus.
Second Kepler law states that An imaginary line joining a planet to the Sun sweeps out equal areas in equal time intervals.
Third Kepler law states that The squares of period of revolution of the planet around the sun are proportional to the cubes of mean distance between the planet and the sun.
Weightlessness is the condition where the body has zero gravity ( its acceleration is equal to the acceleration due to gravity )
[tex].[/tex]
Kepler's law states that the Sun serves as the planet's center of gravity while they travel in elliptical orbits.
What is the Kepler's motion?Each planet describes an ellipsoidal motion around the sun as its sole focus, according to the first Kepler law.
According to the second Kepler law, an imaginary line between a planet and the Sun sweeps out equivalent areas at equivalent times.
According to the third Kepler law, the squares of a planet's period of revolution around the sun are proportional to the cubes of the planet's mean distance from the sun.
When the body is weightless, there is no gravitational pull on it ( its acceleration is equal to the acceleration due to gravity).
Therefore, the Sun serves as the planet's center of gravity while they travel in elliptical orbits, which is described by Kepler's law.
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A runner has a temperature of 40°c and is giving off heat at the rate of 50cal/s (a) What is the rate of heat loss in watts? (b) How long will it take for this person's temperature to return to 37°c if his mass is 90kg.
What is the connection between speed, friction, and radius of the curve when turning when driving a car.
Answer:
hhhbbbbbbbbbbbbbbnnnnnbbhb
Unit of speed is a derived unit. Give reasons
Answer:
as it 8s based upon to fundamental units distance and Time
2.5: Một người nặng 72kg ngồi trên sàn treo nặng 12kg như hình vẽ. Hỏi người đó
phải kéo dây với một lực bằng bao nhiêu để sàn chuyển động nhanh dần đều lên cao
được 3m trong thời gian là 2s. Tính áp lực của người đó lên sàn.
Answer:
english
Explanation:
What can light and sound both vary in which one of these ?
Volume
Intensity
Number or prespective?
Answer:
intensity
Explanation:
b. example, The sun is very bright and intense. and sounds can be very loud.
A resistor, an inductor, and a capacitor are connected in series to an AC source. The AC source is operating at the resonance frequency. Which of the following statements are true?
a. The peak voltage across the resistor is equal to the peak voltage across the inductor.
b. The total voltage across the inductor and the capacitor at any instant is equal to zero.
c. The peak voltage across the resistor is equal to the peak voltage across the capacitor.
d. The peak voltage across the inductor is greater than the peak voltage across the capacitor.
e. The peak voltage across the capacitor is greater than the peak voltage across the inductor.
f. The current is in phase with the driving voltage.
I believe the correct answer is a
The true statement is that, at resonance, current is in phase with the driving voltage.
Resonance occurs in an RLC circuit at the point when the inductive reactance is equal to the capacitive reactance. At the point of resonance, the voltage across the inductor and capacitor are equal.
It should noted that, at resonance, the current is in phase with the driving voltage. This is the true statement in the list.
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Can instantaneous velocity be negative
Answer:
Yes.
Explanation:
Instantaneous velocity is a vector quantity and thus can be negative.
Unlike, Instantaneous speed which is found by taking the absolute value of the magnitude of instantaneous velocity, and thus always positive.
How does the capacitance of capacitor vary with the dielectric resistant of a medium
Answer:
Every dielectric medium will have a dielectric (strength) constant.
For space / vacuum it is 1. For rest of the dielectric media, it is greater than 1. The capacitance of a capacitor filled with a material of dielectric constant k, is given by the relation:
C = k . C0 (where C0 is the capacitance with space / vacuum as the dielectric material in that capacitor which means no dielectric between the plates)
So, it clearly states that the higher the dielectric constant, the more the capacitance i.e. it is directly proportional to the dielectric strength.
Dielectric constant varies with temperature.
Explanation:
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Answer:
1.84 hours
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A spring whose stiffness is 3500 N/m is used to launch a 4 kg block straight up in the classroom. The spring is initially compressed 0.2 m, and the block is initially at rest when it is released. When the block is 1.3 m above its starting position, what is its speed
Answer:
the speed of the block at the given position is 21.33 m/s.
Explanation:
Given;
spring constant, k = 3500 N/m
mass of the block, m = 4 kg
extension of the spring, x = 0.2 m
initial velocity of the block, u = 0
displacement of the block, d =1.3 m
The force applied to the block by the spring is calculated as;
F = ma = kx
where;
a is the acceleration of the block
[tex]a = \frac{kx}{m} \\\\a = \frac{(3500) \times (0.2)}{4} \\\\a = 175 \ m/s^2[/tex]
The final velocity of the block at 1.3 m is calculated as;
v² = u² + 2ad
v² = 0 + 2ad
v² = 2ad
v = √2ad
v = √(2 x 175 x 1.3)
v = 21.33 m/s
Therefore, the speed of the block at the given position is 21.33 m/s.
The speed of the block at a height of 1.3 m above the starting position is 21.33 m/s
To solve this question, we'll begin by calculating the acceleration of the block.
How to determine the acceleration Spring constant (K) = 3500 N/m Mass (m) = 4 KgCompression (e) = 0.2 mAcceleration (a) =?F = Ke
Also,
F = ma
Thus,
ma = Ke
Divide both side by m
a = Ke / m
a = (3500 × 0.2) / 4
a = 175 m/s²
How to determine the speed Initial velocity (u) = 0 m/sAcceleration (a) = 175 m/s²Distance (s) = 1.3 mFinal velocity (v) =?v² = u² + 2as
v² = 0² + (2 × 175 × 1.3)
v² = 455
Take the square root of both side
v = √455
v = 21.33 m/s
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What is Matter? write its types
According to definition of general chemistry matter is any substance which has atleast a mass and occupies a volume.
Matter is of three types
SolidLiquidGasTwo students are applying a force on a desk on the same side causing it to move to the right what were the forces acting on it?
Answer:
contact force because they were pushing it and it moved
A cycle track is 500 metres long. A cyclist completes 10 laps (that is, he rides completely round the track 10 times).
a) How many kilometres has the cyclist travelled?
b) On average it took the cyclist 50 second to complete one lap (that it, to ride round just one).
(i) What was the average speed of the cyclist?
(ii) How long in minutes and seconds dit it take the cyclist to complete the 10 laps?
c) Near the end of the run the cyclist put on a spurt. During this spurt it took the cyclist 2 seconds to increase speed from 8 m/s to 12 m/s. What was the cyclist's acceleration during this spurt?
Explanation:
a) D_t = 500m*10laps
D_t = 5000m or 5km
b)
I) v = d/t
v = 500m/50s
v = 10m/s
ii) 10m/s = 5000m/t
t = 5000m/10m/s
t = (500s)*(1min/60s)
t = 8'20" or 8 mins and 20 sec
c) v_f = v_0 + a*t
v_f-v_0 = a*t
a = (v_f-v_0)/t
a = (12m/s-8m/s)/2s
a = (4m/s)/2s
a = 2m/s²
Part(a),
The distance travelled by the cyclist is 5 km.
Part(b),
(i) The average speed is 10 m/s
(ii) The time taken to cover 10 laps is 8 minutes and 20 seconds.
Part(c),
The acceleration is 2 m/s²
What is speed?Speed is defined as the ratio of the time distance travelled by the body to the time taken by the body to cover the distance. Speed is the ratio of the distance travelled by time. The unit of speed in miles per hour.
a) The distance will be calculated as
D = 500m*10laps
D = 5000m or 5km
b) The average speed is calculated as,
I) v = d/t
v = 500m/the 50s
v = 10m/s
The time will be calculated as,
ii) 10m/s = 5000m/t
t = 5000m/10m/s
t = (500s)*(1min/60s)
t = 8'20" or 8 mins and 20 sec
The acceleration is calculated as,
c) vf = v0 + at
vf-v0 = at
a = (vf-v0)/t
a = (12m/s-8m/s)/2s
a = (4m/s)/2s
a = 2m/s²
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Understanding Heisenberg's uncertainty principle is one of the keys to understanding quantum mechanics.
a. True
b. False
Answer:
Very TRUE
Option A is legit
A metal blade of length L = 300 cm spins at a constant rate of 17 rad/s about an axis that is perpendicular to the blade and through its center. A uniform magnetic field B = 4.0 mT is perpendicular to the plane of rotation. What is the magnitude of the potential difference (in V) between the center of the blade and either of its ends?
We are being given that:
The length of a metal blade = 300 cmThe angular velocity at which the metal blade is rotating about its axis is ω = 17 rad/sThe magnetic field (B) = 4.0 mTA pictorial view showing the diagrammatic representation of the information given in the question is being attached in the image below.
From the attached image below, the potential difference across the conducting element of the length (dx) moving with the velocity (v) appears to be perpendicular to the magnetic field (B).
The magnitude of the potential difference induced between the center of the blade in relation to either of its ends can be determined by using the derived formula from Faraday's law of induction which can be expressed as:
[tex]\mathsf{E = B\times l\times v}[/tex]
where;
B = magnetic fieldl = lengthv = relative speedFrom the diagram, Let consider the length of the conducting element (dx) at a distance of length (x) from the center O.
Then, the velocity (v) = ωx
The potential difference across it can now be expressed as:
[tex]\mathsf{dE = B*(dx)*(\omega x)}[/tex]
For us to determine the potential difference, we need to carry out the integral form from center point O to L/2.
∴
[tex]\mathsf{E = \int ^{L/2}_{0}* B (\omega x ) *(dx)}[/tex]
[tex]\mathsf{E = B (\omega ) \times \Big[ \dfrac{x^2}{2}\Big]^{L/2}_{0}}[/tex]
[tex]\mathsf{E = B (\omega ) * \Big[ \dfrac{L^2}{8}\Big]}[/tex]
Recall that,
magnetic field (B) = 4 mT = 4 × 10⁻³ TLength L = 300 cm = 3mangular velocity (ω) = 17 rad/s[tex]\mathsf{E = (4\times 10^{-3}) * (17) \Big[ \dfrac{(1.5)^2}{8}\Big]}[/tex]
[tex]\mathsf{E = 19.13 mV}[/tex]
Thus, we can now conclude that the magnitude of the potential difference as a result of the rotation caused by the metal blade from the center to either of its ends is 19.13 mV.
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What frequency is received by a person watching an oncoming ambulance moving at 110 km/h and emitting a steady 800-Hz sound from its siren? The speed of sound on this day is 345 m/s. Group of answer choices
Answer:
check photo for solve
Explanation:
Suppose that you release a small ball from rest at a depth of 0.700 m below the surface in a pool of water. If the density of the ball is 0.200 that of water and if the drag force on the ball from the water is negligible, how high above the water surface will the ball shoot as it emerges from the water? (Neglect any transfer of energy to the splashing and waves produced by the emerging ball.)
Number________
Units ________
Answer:
photo
Explanation:
A 6.0 cm high object is placed 30.0 cm in front of a convex mirror. The radius of curvature of the mirror is 20.0 cm. How high is the image? Is it upright or inverted?
Photons — particles of light — stream toward the smooth pane of glass and bounce off it. The image of everything in front of the mirror is reflected backward, retracing the path it traveled to get there. Nothing is switching left to right or up-down. Instead, it's being inverted front to back.
When an object is placed in front of the convex mirror, the image is formed behind the mirror. The height of the image is 1.5 cm. The image is upright.
What is Convex mirror?Convex mirror is the spherical type of mirror. It has positive focal length. It forms the images by the virtual meeting of the rays coming from the object.
By the lens maker formula,
1/f = 1/u +1/v
where image distance is v, the object distance is 30 cm and the focal length of mirror, f = Radius of curvature /2
f = 20/2 = 10 cm
Substitute the values, we get the image distance as
1/10 = 1/-30 +1/v
v = 7.5 cm (on right of lens)
From the definition,
m = -image distance /object distance = image height / object height
-(7.5) /30 = hi / 6
hi = 1.5 cm
Thus, the height of the image is 1.5 cm. The image is upright.
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The valves in the heart open and close to move blood in between heart chambers. O a) three directions O b) two directions O c) four directions d) one direction
Hi,
The valves in the heart open and close to move blood in between heart chambers.
Answer:
d) one direction
A velocity selector is a device with an electric and magnetic field perpendicular to one another.
a. True
b. False
Answer:
a. True
Explanation:
It's commonly used in the bain bridge diagram determining positive rays
intial velocity is 45km/h, final velocity is 0, time taken is 3 seconds,calculate the retradation of the vehicle and distance travelled
Answer:
Acceleration=12.5/3m/s^2=4.17m/s^2
Explanation:
Initial velocity u = 45 km/h = 12.5 m/s; Final velocity v = 0 m/s; time t = 3 s, acceleration a.
[a=v-u/t] : a=0-12.5/3=-12/3m/s^2
(Retaradation=-(-12.5/3)=12.5/3.
Imagine two pairs of books. In the first pair, two books of mass m_1m 1 m, start subscript, 1, end subscript and m_2m 2 m, start subscript, 2, end subscript are separated by the distance rrr, resulting in a gravitational force F_1F 1 F, start subscript, 1, end subscript. In the second pair, two books of mass 2m_12m 1 2, m, start subscript, 1, end subscript and 4m_24m 2 4, m, start subscript, 2, end subscript are separated by the distance 2r2r2, r, resulting in a gravitational force of F_2F 2 F, start subscript, 2, end subscript. The relationship between these two forces can be written as F_2 = nF_1F 2 =nF 1 F, start subscript, 2, end subscript, equals, n, F, start subscript, 1, end subscript. In the expression F_2 = nF_1F 2 =nF 1 F, start subscript, 2, end subscript, equals, n, F, start subscript, 1, end subscript, what is the value of nnn?
The value of n in the relationship between F₁ and F₂, (F₂ = n·F₁), is n = 2
The reason for the above value is as follows;
The given parameters of the first pair of books are;
The masses of the books = m₁, and m₂
The distance between the two m₁ and m₂ = r
The gravitational force between the masses = F₁
The given parameters of the second pair of books are;
The masses of the books second pair = 2·m₁, and 4·m₂
The distance between the two masses in second pair = 2·r
The gravitational force between the masses in second pair = F₂
The relationship between the two forces is F₂ = n·F₁
The required parameter;
The value of n in F₂ = n·F₁
According to Newton's law of universal gravitation, we have;
[tex]\mathbf{F = G \times \dfrac{m_1 \times m_2}{r^2}}[/tex]
Therefore, we get;
[tex]F_1 = G \times \dfrac{m_1 \times m_2}{r^2}[/tex]
[tex]F_2 = G \times \dfrac{2\cdot m_1 \times 4 \cdot m_2}{(2 \cdot r)^2} = G \times \dfrac{8 \times m_1 \times m_2}{4 \times r^2} = 2 \times G \times \dfrac{ m_1 \times m_2}{r^2} = 2 \times F_1[/tex]
Therefore;
F₂ = 2·F₁
The value of n in F₂ = n·F₁ is n = 2
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two bodies A and B with some asses 20 kg and 30 kg respectively above the ground which have greater potential
Answer:
B has greater potential
Explanation:
We know;
Potential Energy (PE) = mgh
where, m=mass of body
g=acceleration due to gravity
h=height of body
From the formula,
PE is directly proportional to the mass of the body
so the body with greater mass has greater potential.
write the formula of Lever, Pulleys, wheel and axle and inclined plane.
Answer:
Lever => [tex]d_{e} = d_{r}[/tex]
Pulley => G = M x n (gravitational acceleration)
Wheel and axle => M.A = Radius of the wheel/radius of the axle = R/r
Inclined plane => It can be divided into two components: Fi = Fg * sinθ - parallel to inclined plane. Fn = Fg * cosθ - perpendicular one.
Electron A is fired horizontally with speed 1.00 Mm/s into a region where a vertical magnetic field exists. Electron B is fired along the same path with speed 2.00 Mm/s. (i) Which electron has a larger magnetic force exerted on it
B will have the greater force
Fc=MV2 /R=Fm
The A particle has less centipetal force and larger radius so larger curve
