Answer:
Approximately [tex]0.253\; {\rm J \cdot g^{-1} \cdot K^{-1}}[/tex] assuming no heat exchange between the mixture and the surroundings.
Explanation:
Consider an object of specific heat capacity [tex]c[/tex] and mass [tex]m[/tex]. Increasing the temperature of this object by [tex]\Delta T[/tex] would require [tex]Q = c\, m \, \Delta T[/tex].
Look up the specific heat of water: [tex]c(\text{water}) = 4.182\; {\rm J \cdot g^{-1} \cdot K^{-1}}[/tex].
It is given that the mass of the water in this mixture is [tex]m(\text{water}) = 1.00 \times 10^{2}\; {\rm g}[/tex].
Temperature change of the water: [tex]\Delta T(\text{water}) = (45 - 35)\; {\rm K} = 10\; {\rm K}[/tex].
Thus, the water in this mixture would have absorbed :
[tex]\begin{aligned}Q &= c\, m\, \Delta T \\ &= 4.182\; {\rm J \cdot g^{-1}\cdot K^{-1}} \\ &\quad \times 1.00 \times 10^{2}\; {\rm g} \times 10\; {\rm K} \\ &= 4.182 \times 10^{3}\; {\rm J}\end{aligned}[/tex].
Thus, the energy that water absorbed was: [tex]Q(\text{water}) = 4.182 \times 10^{3}\; {\rm J}[/tex].
Assuming that there was no heat exchange between the mixture and its surroundings. The energy that the water in this mixture absorbed, [tex]Q(\text{water})[/tex], would be the opposite of the energy that the metal in this mixture released.
Thus: [tex]Q(\text{metal}) = -Q(\text{water}) = -4.182 \times 10^{3}\; {\rm J}[/tex] (negative because the metal in this mixture released energy rather than absorbing energy.)
Mass of the metal in this mixture: [tex]m(\text{metal}) = 3 \times 1.00 \times 10^{2}\; {\rm g} = 3.00 \times 10^{2}\; {\rm g}[/tex].
Temperature change of the metal in this mixture: [tex]\Delta T(\text{metal}) = (100 - 45)\; {\rm K} = 55\; {\rm K}[/tex].
Rearrange the equation [tex]Q = c\, m \, \Delta T[/tex] to obtain an expression for the specific heat capacity: [tex]c = Q / (m\, \Delta T)[/tex]. The (average) specific heat capacity of the metal pieces in this mixture would be:
[tex]\begin{aligned}c &= \frac{Q}{m\, \Delta T} \\ &= \frac{-4.182 \times 10^{3}\; {\rm J}}{3.00 \times 10^{2}\; {\rm g} \times (-55\; {\rm K})} \\ &\approx 0.253\; {\rm J \cdot g^{-1} \cdot K^{-1}}\end{aligned}[/tex].
How do the stomach and the small intestines work together to digest the food? (2 points)
The stomach breaks down the food and passes it to the small intestine to be digested further.
The stomach passes the digested food from the small intestine to the large intestine.
The small intestine turns the solid food into a liquid mixture and sends it to the stomach.
The stomach digests the food by using digestive juices made by the small intestine.
Answer:
A) The stomach breaks down the food and passes it to the small intestine to be digested further.
Explanation:
I am pretty sure it is the first option because there is no way the stuff you eat can be turned into a liquid, it wouldn't make sense for the stomach to pass the digested food from small intestine to large intestine, so it would have to be the first one. A out of all of the options makes more sense and the stomach has to pass the digested food somewhere.
I hope I helped you
Legolas shoots 333 arrows at once from his bow. He has 177177177 arrows.
How many times can Legolas shoot his bow before he needs more arrows?
Answer:
532063
Explanation:
If he's shooting 333 arrows per shot and has 177177177 arrows, you need to divide to find the number of arrows he can shoot total, ignoring the decimal since you can't shoot a partial arrow.
177177177/333=532063
A 85.0kg man and a 65, 0kg woman are riding a Ferris wheel with a radius of 20.0m. What is the Ferris wheels tangential velocity if the net centripetal force on the woman is 115N
Answer:
The Ferris wheel's tangential (linear) velocity if the net centripetal force on the woman is 115 N is 3.92 m/s.
Explanation:
Let's use Newton's 2nd Law to help solve this problem.
F = maThe force acting on the Ferris wheel is the centripetal force, given in the problem: [tex]F_c=115 \ \text{N}[/tex].
The mass "m" is the sum of the man and woman's masses: [tex]85+65= 150 \ \text{kg}[/tex].
The acceleration is the centripetal acceleration of the Ferris wheel: [tex]a_c=\displaystyle \frac{v^2}{r}[/tex].
Let's write an equation and solve for "v", the tangential (linear) acceleration.
[tex]\displaystyle 115=m(\frac{v^2}{r} )[/tex][tex]\displaystyle 115 = (85+65)(\frac{v^2}{20})[/tex][tex]\displaystyle 115=150(\frac{v^2}{20} )[/tex][tex].766667=\displaystyle(\frac{v^2}{20} )[/tex][tex]15.\overline{3}=v^2[/tex][tex]v=3.9158[/tex]The Ferris wheel's tangential velocity is 3.92 m/s.
A long conducting cylindrical pipe has a length L
The charge distribute on the inner surface with the radius r₁ will be zero,In the region r₁<r<r₂ will also zero. While on the outer surface with radius r₂ will be -q.
What is Gauss law?The total electric flux out of a closed surface is equal to the charge contained divided by the permittivity,
According to Gauss Law. the electric flux in a given area is calculated by multiplying the electric field by the area of the surface projected in a plane perpendicular to the field.
From the Gauss law, it is stated that the field inside the conductor is zero. Charge will lie only on the surface.
(a)The charge distribute on the inner surface with the radius r₁ will be zero.
(b) In the region r₁<r<r₂ will also zero.
(c)The outer surface with radius r₂ charge distribution will be -q.
Hence, the charge distribute on the inner surface with the radius r₁ will be zero,
To learn more about the Gauss law, refer to the link;
https://brainly.com/question/2854215
#SPJ1
Which set of terms is in the proper order, from left to right, for labeling the
reactants and products in this reaction?
H3PO4 + 3KOH + 3H20 + K3P04
A. Base, salt, water, acid
O B. Salt, acid, water, base
C. Acid, base, water, salt
O D. Base, acid, water, salt
Waldo gets stopped by the police.
Answer:
At least they found him.
Explanation:
Light does not pass through some materials. What do you think happens
to the energy of photons when photons strike a surface and are
absorbed? What indicators would tell you that the energy of the photons
?
has been transformed?
Answer:
When an electron is hit by a photon of light, it absorbs the quanta of energy the photon was carrying and moves to a higher energy state. One way of thinking about this higher energy state is to imagine that the electron is now moving faster, (it has just been "hit" by a rapidly moving photon)
A photon is a quantum of EM radiation. Its energy is given by E = hf and is related to the frequency f and wavelength λ of the radiation by. E=hf=hcλ(energy of a photon) E = h f = h c λ (energy of a photon) , where E is the energy of a single photon and c is the speed of light.
Which best ilustrates the way in which radiation transfers thermal energy?
Answer:
B) Warm radiates to Cool
Explanation:
Radiation transfers thermal energy without need for contact, where areas with higher thermal energy (hot) transfer energy to areas with lower thermal energy (cold)
A student rubs one side of an inflated balloon on her hair. This side of the balloon becomes positively charged. Explain this.
Answer:
Friction
Explanation:
Friction between two conductive objects creates static energy in this example making the hair stick up as if it is connected to the balloon. Hope this helps!
can someone help with the vocabulary of the relative age of rocks
Two 74.0-kg hockey players skating at 6.15 m/s collide and stick together.
If the angle between their initial directions was 90 ∘ , what is their speed after the collision?
If the angle between their initial directions was 90 ∘ , their speed after the collision will be 4.35 m/s.
What is inelastic collision?When two moving bodies after colliding stick to each other and move together is called the inelastic collision.
In inelastic collision , momentum is remains conserved.
Initial momentum =Final momentum
m₁u₁ +m₂u₂ = (m₁ +m₂ )v
where, u₁ and u₂ represents initial velocities of two hockey players and v₁ and v₂ shows the final velocities.
m₁ =m₂ =m and u₁ = u₂ =u
Substitute the values from the question, we get
2mu = 2mv
u =v
u = v x cos (θ/2)
u = 6.15 cos(90/2)
u = v = 4.35 m/s
Thus, the speed after collision is 4.35 m/s.
Learn more about inelastic collision.
https://brainly.com/question/14521843
#SPJ1
Bacteria vary somewhat in size, but a diameter of 2.9 μm is not unusual.
A) What would be the volume (in cubic centimeters) of such a bacterium, assuming that it is spherical?
B) What would be the surface area (in square millimeters) of such a bacterium, assuming that it is spherical?
Answer:
a) 6.4 x 10^-12 cm^3
b) 17 x 10^-6 mm^2
Explanation
a). The shape is assumed to be spherical The volume = volume of a sphere = \frac{4}{3} \pi r^3
3
4
πr
3
V = \frac{4}{3}*3.142* 1.15^3
3
4
∗3.142∗1.15
3
= 6.3715 μm^3
1 μm^3 = 10^-12 cm^3
6.3715 μm^3 = 6.3715 x 10^-12 cm^3
==> 6.4 x 10^-12 cm^3
Answer:
See below
Explanation:
Volume of a sphere = 4/3 pi r^3
we are given diameter r = 1/2 dia = 1.45 u-meter = 1.45 x 10^-4 cm
4/3 pi (1.45 x 10^-4)^3 = 1.277 x 10^-11 cm^3 = VOLUME
1.45 u-meter = .00145 mm
Surface area = 4 pi r^2 = 4 pi (1.45 x 10^-3 ) ^2 = 2.64 x 10^-5 mm^2
The physical property that determines that how easily heat and electricity pass through a material is?
A. conductivity
B. density
C. weight
D. hardness
Answer: Hello! I'm Jungkook. Here is your answer.....
A. conductivity
Explanation:
Hope this helps! Anneyong/Bye!
xoxoKookie
If the trend changed toward traditional (pre-World War II) families, how would that affect women’s rights?
If the trend changed toward traditional (pre-World War II) families, the women’s rights are employment in manufacturing sector.
What is World war?
The war between two countries to take over each other's kingdom using weapons to kill each other.
Before the world war, the army needs armor, weapons, guns and tanks. Their manufacturing is only possible with many workers to work for long hours. If the men are not enough, then women are given opportunities to work with them.
Thus, the women’s rights are employment in manufacturing sector when trend changed traditional families.
Learn more about world war.
https://brainly.com/question/1449762
#SPJ1
In what order do the stages of the birth process occur? delivery of the placenta, dilation and thinning of the cervix, delivery of the fetus uterine contractions, delivery of the placenta, delivery of the fetus delivery of the fetus, delivery of the placenta, delivery of the cervix dilation and thinning of the cervix, delivery of the fetus, delivery of the placenta
The stages of the baby birth are Dilation, strong contractions, and delivery of the baby and the placenta.
What are the stage of the birth process ?Dilation, intense contractions, and delivery of the baby and placenta are the phases of a baby's birth.
The stages of the birth process are as follows;
1. The first stage includes the latent phase, in which cervical dilation begins (3 to 5 cm) along with mild contractions, and the active phase, in which strong contractions occur along with complete or nearly complete dilation.
2. The second stage is fetus expulsion or delivery, in which the cervix is fully dilated, and the baby is born.
3. The third stage is placenta delivery or expulsion, which occurs as the placenta is delivered.
4. Dilation, intense contractions, and delivery of the baby and placenta are the phases of labor and delivery.
Hence,the stages of the baby birth are Dilation, strong contractions, and delivery of the baby and the placenta.
To learn more about the stage of the birth process refer:
https://brainly.com/question/12352717
#SPJ1
Answer:
the answer is -dilation and thinning of the cervix, delivery of the fetus, delivery of the placenta
Explanation:
i took a quiz and got it right
Which of the following is an example of a chemical change?
a
Boiling water
b
Burning paper
c
Dissolving sugar in water
d
Melting gold
b. burning paper
hope it helps
QUESTION 4 A ball is dropped from a height. If it takes 0.2 s to cross the last 6 m before hitting the ground, find the approximate height from which it is dropped.
Answer:
S = V t + 1/2 g t^2 where the ball has a speed of V and falls for .2 sec
6 = V t + 4.9 * .04 = V * .2 + .2
V = (6 - .2) / .2 = 29 m/s speed entering area
T = V / g = 29 / 9.8
T = 2.96 sec time to reach speed V
H = 1/2 g t^2 time to fall a distance H
H = 4.9 * 2.96^2 = 42.9 m height from which ball was dropped
Check using first equation:
S = 29 * .2 + 4.9 + .2^2 = 6 m
Given the information in the velocity vs. time graph, what is the displacement of the object after 1 second?
In the velocity vs. time graph, the displacement of the object after 1 second is 3 m.
What is displacement?The displacement of an object is the change in position of the object.
From the graph, the displacement of the object after 1 second is calculated as follows;
x = vt
where;
v is velocity = 3 m/st is time = 1 secondx = 3 x 1 = 3 m
Thus, in the velocity vs. time graph, the displacement of the object after 1 second is 3 m.
Learn more about displacement here: https://brainly.com/question/2109763
#SPJ1
A ball of mass 0.4kg is dropped from a height of 30m. Determine the potential energy on impact to the ground
A 20.0 kg trunk is pushed across the floor of a moving van by a horizontal force. If the coefficient of kinetic friction between the trunk and the floor is 0.255, what is the magnitude of the frictional force opposing the applied force?
The magnitude of the frictional force opposing the applied force is 50 N.
What is the frictional force?The friction is caused due to the relative motion between two uneven contacting surfaces.
Given is the mass of trunk m = 20kg, kinetic coefficient of friction μ = 0.255.
The normal force acting on the trunk N = mg
N = 20 kg x 9.81m /s²
N = 196.2 Newton
The friction force is
f =μN
f = 0.255 x 196.2
f =50.031 N
Thus, the magnitude of the frictional force opposing the applied force is approximately 50N.
Learn more about frictional force.
https://brainly.com/question/1714663
#SPJ1
someone help me answer this.
Bug Walking on Pivoted Ring A ring of radius R and mass my lies on its side on a frictionless table. It is pivoted to the table at its rim. A bug of mass my walks on the ring with constant speed v relative to the ring, starting at the pivot, when the ring is initially at rest. Take k to point out of the page. top view frictionless table ring bug Pluot Point (a) What is the angular velocity of the ring when the bug is halfway around? Express you answer in terms of some or all of the following: mi, m2, u, R and k. (b) What is the angular velocity of the ring when the bug is back at the pivot? Express you answer in terms of some or all of the following: mı, m2, v, R and k.
The angular velocity of the ring when the bug is halfway around and the angular velocity of the ring when the bug is back at the pivot is [m₂v / {(2m₁ +m₂)R}].
What is angular velocity?The velocity of a particle when moving in the circular path.
Let speed of the bug with respect to ground is u.
Speed of bag with respect to ring will be
v = u - (- Rω) =
Then, u = v- Rω...............(1)
Angular momentum of ring and bug will remain conserved.
Initial momentum: L ring + Lbug =0
Final momentum: -2m₁ R²ω + m₂uR =0...............(2)
Using equation (1) and (2), the angular velocity expression will be
ω =[m₂v / {(2m₁ +m₂)R}] in positive z direction
Thus, the angular velocity of the ring when the bug is halfway around and the angular velocity of the ring when the bug is back at the pivot is [m₂v / {(2m₁ +m₂)R}].
Learn more about angular velocity.
https://brainly.com/question/17592191
#SPJ1
(See picture) may I have help!!?
PLE HELP
What is the best description of temperature?
Temperature is the same thing as heat.
Temperature measures the number of Kelvins in a substance.
Temperature is the measurement of kinetic energy (movement of molecules).
Temperature only measures an increase in heat energy.
any form of stored energy is described as
Determine the net force required to accelerate a 2,160 kg truck from 0 to 27 m/s in 10 s
∑F=m.a = m.(Δv/Δt)
∑F=2.16 x (27-0/10)
∑F=5.832 N
5. For the following pairs of masses, which one has the largest gravitational attraction between masses? Which one has the smallest gravitational attraction between masses? Explain.
Answer:
MOST : E LEAST : D
Explanation:
Grav attraction = G m1 m1 / r^2
G and 'r' are the same for all of the pictures, so the one picture with the biggest mass has the MOST attraction and the one with the least mass has the least attraction.
The pair with the largest gravitational attraction is the Earth and the Moon.
The pair with the smallest gravitational attraction is the Earth and a grain of sand.
The gravitational force between two masses is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. In other words, the more massive the objects, the stronger the gravitational force between them. The closer the objects are, the stronger the gravitational force between them.
The Earth and the Moon are the most massive objects in the pair. The Earth has a mass of about 5.972 × 10²⁴ kg, and the Moon has a mass of about 7.34 × 10²² kg. The distance between the Earth and the Moon is about 384,400 km.
The grain of sand is much less massive than the Earth or the Moon. The mass of a grain of sand is about 10⁻⁶ kg. The distance between the Earth and a grain of sand is much greater than the distance between the Earth and the Moon.
Therefore, the gravitational attraction between the Earth and the Moon is much stronger than the gravitational attraction between the Earth and a grain of sand.
Here is a table of the gravitational attractions for each pair of masses:
Pair of masses Gravitational attraction
Earth and Moon 1.98 × 10²⁰ N
Earth and a grain of sand 1.0 × 10⁻¹⁷ N
To learn more about gravitational attraction, here
https://brainly.com/question/29326667
#SPJ2
Find the velocity using the d/t graph below
Answer:
-10/3
Explanation:
the slope of the graph is negative, the velocity is slowing. so we know the positive answers are not correct. next we just need to figure out how much of a slope the line has. it's down 10 and over 3... soo
-10/3 looks good .. the format for the fraction is rise / run . in this case rise is negative, but other wise it's the same.
A car accelerates uniformly in a straight line from rest at the rate of 2.3 m/s2. What is the speed of the car after it has traveled 55 m?
Answer:
The speed is =15.91ms−1. The time is =6.92s
Explanation:
How many times is the motion of the object stopped?
Answer:
4
Explanation:
We can say the motion of the object is stopped when its velocity is 0. That means we just have to check how many times the line of the graph intersects the x-axis. Hence, we can say that the object of the motion is stopped 4 times.
A (1.28×10-5 C) charge is moving at (5.63×107 m/s) perpendicular to a magnetic field
of (8.91×10-4 T). What is the magnitude of the magnetic force on the charge?
A. 6.42×10 -1 N
B. 5.02×10 4 N
C. 7.21×10 2 N
D. 1.14×10 -8 N
Hello!
We can use the following equation for magnetic force on a moving particle:
[tex]F_B = qv \times B[/tex]
[tex]F_B[/tex] = Magnetic Force (? N)
q = Charge of particle (1.28 × 10⁻⁵C)
v =velocity of particle (5.63× 10⁷m/s)
B = Strength of magnetic field (8.91 × 10⁻⁴T)
This is a cross-product, so the magnetic force depends on the SINE of the angle between the particle's velocity vector and the magnetic field vector.
Since the charge is moving PERPENDICULAR to the field, the angle between the velocity and magnetic field is 90°. The sine of 90° = 1, so we can simplify the equation to:
[tex]F_B = qvB(1) = qvB\\[/tex]
Plug in the values and solve.
[tex]F_B = (1.28*10^{-5})(5.63*10^7)(8.91*10^{-4}) = \boxed{\text{A. } 0.6421 N}[/tex]
