The spiral grooves in a drill body are used to do all of the following except?

Solution :

The mass flow rate of the cooling water is determined from the energy balance equation. The enthalpies of the refrigerant at the initial and the final states were obtained from A-13 and A-12 for the given parameters.

Therefore by energy balance equation,

[tex]$\dot m_r h_{r1}=\dot m_w \Delta h_w +\dot m_r h_{r2} $[/tex]

[tex]$\dot m_w = \frac{\dot m(h_1-h_2)_r}{c \Delta T}$[/tex]

[tex]$\dot m_w = \frac{8(308.34-88.82)}{4.18 \times 10}$[/tex]

     = 42 kg / min

Answer:

Operating Pressure P = 793.716 mmHg

Y_Benzene y1 = 0.541

Explanation:

Given that;

liquid phase leaving the evaporator = 32.5 mole%

Equi Temp T = 99.0°C = 99 + 273.15 = 372.15 K

Now let 1 and 2 represent Benzene and Toluene respectively.

Antoine's Constant for these components are;

COMPONENETS        A                B                    C

Benzene 1             4.72583     1660.652        -1.461

Toluene  2            4.07827     1343.943         -53.773

Antoine's equation is expressed as;

Ps = 10^(A - (B/(T+C)))

Ps is in Bar and T is in Kelvin

so

P1s = 10^( 4.72583 - (1660.652/(372.15 - (-1.461)))) = 1.7617 Bar

P2s = 10^( 4.07827 - (1343.943/(372.15 - (-53.773)))) = 0.7195 Bar

now here, liquid leaving and vapor are both in equilibrium

composition of liquid leaving are;

X1 = 32.5%    = 0.325

X2 = 1 - X1 = 1 - 0.325 = 0.675

Now

Raoult's Law is expressed as;

p × y1=x1 × pis     for all components

So for Benzene ; p × y1=x1 × p1s   ------let this be equation 1

for Toluene ; p × y2=x2 × p2s   ------let this be equation 2

lets add equ 1 and 2

p × y1=x1 × p1s + p × y2=x2 × p2s

p(y1 + y2) = x1 × p1s + x2 × p2s

buy y1 + y2 = 1

therefore we substitute

p(1) = 0.325 × 1.7617 + 0.675 × 0.7195 = 1.0582 Bar

we know that 1 Bar = 750.062 mmHg

so p = 1.0582 × 750.062

p = 793.716 mmHg

Also from equation 1

p × y1=x1 × p1s

y1 = (x1 × p1s) / p

y1 = (0.325 × 1.7617) / 1.0582

y1 = 0.541

Therefore;

Operating Pressure P = 793.716 mmHg

Y_Benzene y1 = 0.541

Answer:

a

Explanation:

Waterjet cutting uses a very-small-diameter jet of water that exits the cutting nozzle at approximately the speed of sound. A water jet cutter, is oftentimes simply called a water jet is an industrial tool, like its name suggests, with the capabilities of cutting a different types of materials. Like its name suggests again, it uses water, although an extremely high-pressure jet of water to do the cutting. Other times, it uses a mixture of water and an abrasive substance to facilitate the cutting.

Answer:

I believe that cpu devices are not considered peripherals

Explanation:

From google: A peripheral or peripheral device is an ancillary device used to put information into and get information out of the computer.

Answer:

percentage yield = 63%

Explanation:

The yield efficiency or percentage yield measure the amount of products that are formed from a given amount of reactant. For a percentage yield of 100, all the reactants are completely converted to product. Mathematically, the percentage yield is given by:

[tex]percentage\ yield = \frac{Actual\ yield}{expected\ yield} \times 100\\Actual\ yield = 10.08kg\\Expected\ yield= 16.00kg\\\\\therefore percentage\ yield = \frac{10.08}{16.00} \times 100 = 63 \%[/tex]

Answer:

11.541 mol/min

Explanation:

temperature = 35°C

Total pressure = 1.5 * 1.013 * 10^5 = 151.95 kPa

note : partial pressure of water in mixture = saturation pressure of water at T = 35°c )

from steam table it is = 5.6291 Kpa

calculate the mole fraction of H[tex]_{2}o[/tex] ( YH[tex]_{2}o[/tex] )

= 5.6291 / 151.95

= 0.03704

calculate the mole fraction of air ( Yair )

 = 1 - mole fraction of water

= 1 - 0.03704 = 0.9629

Now to determine the molar flow rate of water vapor in the stream

lets assume N = Total molar flow rate

NH[tex]_{2}o[/tex] = molar flow rate of water

Nair = molar  flow rate of air = 300 moles /min

note : Yair * n = Nair

therefore n = 300 / 0.9629 = 311.541  moles /min

Molar flowrate of water

=  n -  Nair

= 311.541 - 300 = 11.541 mol/min

Answer:

hello your question is incomplete attached below is the complete question

answer :

a) attached below

b) 63.71°c

Explanation:

A) Given data

The system has ; mass ( M ) , specific heat capacity , and surface area

attached below is a detailed solution

B) Given data

power generated = 60w

weight of heat sink = 0.31 kg

temperature given = 100°c

temp in ambient air = 20°c

lets take

specific heat capacity = 918.18 J /kg-k

density = 2702 kg/m^2

attached below is the detailed solution

Answer:

1. 4/d and 1

2. Engineering tech with 3, Engineer with 1, and Scientist with 2

Explanation:

I'm pretty sure but tell me if im wrong

Answer:

please mark me as BRAINLIEST

Explanation:

There are so many software packages available to develop HTML. The software packages can be grouped into two main categories: text-based (or code-based) editors.

...

WYSIWYG editors

Macromedia Dreamweaver.

Microsoft FrontPage.

Adobe GoLive.

Answer:

the answer is airfoil

Explanation:

hope the answer helps

Answer:

It is called the airfoil

Explanation:

The answer is D. ( airfoil) because an airport is a place. Air raid is a attack in the air and that only leaves airfoil, so airfoil is the correct answer.(Hoped that helped)

The question is incomplete. We have to calculate :

a). the cutting force

b). volumetric metal removal rate, MRR

c). the horsepower required at the cut

d). if the power efficiency of the machine tool is 90%, determine the motor horsepower

Solution :

Given :

Cutting velocity (v) = 500 ft/min

                               = 500 x 12 in/min

                               = 6000 in/min

Feed , f = 0.025 in/rev

Depth of cut, d = 0.2 in

b). Volumetric material removal rate, MRR = v.f.d

                                                                      = 6000 x 0.025 x 0.2

                                                                      = 30 [tex]$in^3 / min$[/tex]

c). Horsepower required = MRR x unit horsepower

                                         = 30 x 1.6

                                         = 48 hp

a). Cutting force,

[tex]$F=\frac{power}{cuting \ velocity}$[/tex]

    [tex]$=\frac{48 \times 550}{500 /60}$[/tex]                (1 hp = 550 ft lbf /sec)

   = 3168 lbf

d). Machine HP required

  [tex]$=\frac{HP}{\eta}$[/tex]

 [tex]$=\frac{48}{0.9}$[/tex]

= 53.33 HP

Answer:

A cost is something you have to give up or sacrifice and a benefit is something that is gained or is helpful.

Explanation:

In a cost-benefit analysis of a system, an engineer is to simply look at the requirements for the system and determine the costs to build the system, both in financial value and energy value.  Additionally, the engineer needs to determine the benefits that would come from choosing a particular path of cost.  If the benefits outweigh the cost for the project, then the solution is accepted.  Else, the cost outweighs the benefit and the solution is rejected.

Answer:

Anything you want to do in Hootsuite can be found in the ___ Sidebar_____, with the main workspace in the ___center______

Sidebar; center

Explanation:

The main workspace of the Hootsuite is located in the center.  The sidebar is where the core access to the Hootsuite functionality, like Streams, Inbox, Planner, Analytics, Publisher, and the App Directory, is obtained.  Hootsuite is a media management platform for curating content, scheduling posts, managing team members, and measuring performances.

Explanation:

for 40hz

since they are in series they will have the same amper

so R=30ohm

C=30F

for 50Hz

R=25

C=25

Solution :

Given :

m  = 2 kg

k = 8 N/m

C= 1 N-s/m

F(t) = 20 sin (4t)

[tex]$F_0= 20 \ N$[/tex]

ω = 4 rad/s

[tex]$\omega_n = \sqrt{\frac{k}{m}}$[/tex]

[tex]$\omega_n = \sqrt{\frac{8}{2}}$[/tex]

   = 2 rad/s

Therefore,

[tex]$\epsilon = \frac{C}{2 m \omega_n}$[/tex]

[tex]$\epsilon = \frac{1}{2 \times 2 \times 2}$[/tex]

 = [tex]$\frac{1}{8}$[/tex]

 = 0.125

So, r = [tex]$\frac{\omega}{\omega_n}$[/tex]

        = [tex]$\frac{4}{2}$[/tex]

        = 2

Steady state response is given by

[tex]$(A)=\frac{F_0 / k}{\sqrt{(1-r^r)^2+(2 \epsilon r)^r}}$[/tex]

[tex]$(A)=\frac{20 / 8}{\sqrt{(1-2^r)^2+(2 \times 0.125 \times 2)^r}}$[/tex]

  A = 0.82 m

Answer:

The first Machine Process is Turning.

Explanation:plz mark brainliest if i am right

Answer:

I believe its turning.

Answer:

Most cylinder wear occurs at the top of ring travel.

Answer:

how many people were asked though

Explanation:

Answer:

B) An increase in pressure can lower the boiling point of a liquid and change the temperature at which it turns to a gas.

Explanation:

B) An increase in pressure can lower the boiling point of a liquid and change the temperature at which it turns to a gas.

The basic principle which influences how all HVACR systems work is that an increase in pressure can increase the boiling point of a liquid, the temperature at which the liquid turns to a gas. Thus, the correct option for this question is C.

An HVACR system may be defined as a type of system that is significantly designed in order to achieve the environmental requirements of the comfort of occupants and a process. These systems are used in different types of buildings such as industrial, commercial, residential, and institutional buildings.

Heating, air conditioning, and refrigeration mechanics and installers, often called HVAC technicians, work on heating, ventilation, cooling, and refrigeration systems that control the temperature and air quality in buildings.

If you're interested in becoming qualified to install heating and cooling systems and you want to know more about the HVAC-R industry, read on for professional definitions and training options.

Therefore, the correct option for this question is C.

To learn more about the HVACR system, refer to the link:

https://brainly.com/question/29996270

#SPJ2

Answer:

I think 7

Explanation:

Here are seven-steps for an effective problem-solving process.

1.Identify the issues. Be clear about what the problem is. ...

2.Understand everyone's interests. ...

3.List the possible solutions (options) ...

4.Evaluate the options. ...

5.Select an option or options. ...

6.Document the agreement(s). ...

7.Agree on contingencies, monitoring, and evaluation.

Answer:

2Θ = 81.34⁰

Explanation:

We have the plane = 113

The material = fcc platinum

Lambda L, = 0.1542

n = 1

Lambda = 2dsinΘ --------(1)

d = a/√h²+k²+l² -------(2)

We have been given the atomic radius to be

R = 0.1387nm

For FCC we have

a = 2R√2

= 2x0.1387x√2

= 0.3923nm

From the second equation

d111 = 0.3923nm/√1²+1²+3²

= 0.3923/√11

= 0.1183nm

From the first equation

0.1542 = 2x0.1183nmSinΘ

0.1542 = 0.2366sinΘ

SinΘ = 0.1542/0.2366

= 0.6517

Θ = Sin-1(0.6517)

= 40.67

2Θ = 81.34⁰

Explanation:

There are 8.35 pounds in a gallon of water. Water weighs 1 gram per cubic centimeter or 1 000 kilogram per cubic meter, i.e. density of water is equal to 1 000 kg/m³; at 25°C (77°F or 298.15K) at standard atmospheric pressure.

Answer:

Decreases

Explanation:

The Entropy change for a reversible process is;

ΔS = nRIn(V_b/V_a)

Now, applying this formula to an isothermal expansion in an irreversible process, it will have same initial and final states as we got for the reversible expansion process. Now, due to the fact that entropy is a state function, the change in entropy of the system will be the same as we got for the equation in reversible process and is given by the same formula.

In both the reversible and irreversible process, the surroundings of which they differ by the entropy there are usually at a constant temperature, T in a way that we have the change jn entropy relationship as;

ΔS_sur = −Q/T

Where;

- the negative sign is used since the heat transferred to the surroundings is equal in magnitude and opposite in sign to the heat, Q, transferred to the system.

Thus, it is clear that the change in the entropy decreases due to the negative sign.

Answer: It will be saved $81 per year.

Explanation: A car without the tires, that gets 35mpg and is driven 15,000 miles per year, will have a fuel cost of:

1 gal ---- 35 miles

x gal ---- 15,000 miles

x = [tex]\frac{15,000}{35}[/tex]

x = 428.57 gal

Per year, 1 gal costs $3.5, then:

cost = 428.57*3.5

cost = 1500

The car with the tires, improve the efficiency in nearly 2mpg, i.e.:

efficiency = 35 + 2 = 37mpg

1 gal ----- 37 miles

y gal ----- 15,000 miles

y = [tex]\frac{15000}{37}[/tex]

y = 405.40 gal

Per year:

cost = 405.40*3.5

cost = 1419

The difference in costs is:

d = 1500 - 1419

d = 81

With lowest rolling resistance tires, a car will save, per year, $81.

Answer:

A reactor is a piece of equipment in which the feedstock is converted to the desired product. Reactors are chosen such that they meet the requirements imposed by the reaction mechanisms, rate expressions, and the required production capacity. Other parameters that must be determined to choose the correct type of reactor are reaction heat, reaction rate constant, heat transfer coefficient, and reactor size. Reactors that are free of the effect of the macro-kinetic properties are classified as: batch isothermal perfectly stirred reactor, batch adiabatic perfectly stirred reactor, semi-batch perfectly stirred reactor, continuous isothermal perfectly stirred reactor flow reactor, continuous adiabatic perfectly stirred flow reactor, continuous isothermal plug flow reactor, and continuous adiabatic plug flow reactor.

Answer:

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Answer:

a method of connecting polyphrase circuits in which one end of each phase line is connected to a common neutral point that may be connected to the earth as protection against lightning or to a wire to which all the other neutral points of the system are connected

Explanation:

Answer:

El tiempo que tarda la barca en llegar a la orilla es 40 s.

Explanation:

Debido a que el río se mueve en dirección perpendicular a la barca, ésta se va a mover de manera diagonal, cuya velocidad ([tex]v_{b_{d}}[/tex]) viene dada por:

[tex]|v_{b_{d}}| = \sqrt{v_{r}^{2} + v_{b}^{2}} = \sqrt{(4)^{2} + (3)^{2}} = 5 m/s[/tex]

Por lo tanto, el módulo del vector velocidad diagonal es 5 m/s, y su dirección es:

[tex]tan(\alpha) = \frac{v_{r}}{v_{b}} = \frac{4}{3}[/tex]

Entonces, α es:

[tex] \alpha = arctan(\frac{4}{3}) = 53.13 ^{\circ} [/tex]    

Ahora, debemos encontrar la distancia de la longitud diagonal que recorre la barca:

[tex] cos(\alpha) = \frac{a}{d_{d}} [/tex]

[tex] d_{d} = \frac{a}{cos(\alpha)} = \frac{120 m}{cos(53.13)} = 200.0 m [/tex]

Finalmente, el tiempo que le tomaría a la barca recorrer 200 m sería:

[tex]v_{b_{d}} = \frac{d_{d}}{t}[/tex]

[tex] t = \frac{200 m}{5 m/s} = 40 s [/tex]

Por lo tanto, el tiempo que tarda la barca en llegar a la orilla es 40 s.

Espero que te sea de utilidad!