Answer:
C. 10⁻³ rads
Explanation:
Here, we shall use Rayleigh's Criterion to find out the angular resolution of Cat's eye during day light. Rayleigh's Criterion is written as follows:
θ = λ/a
where,
θ = angular resolution of Cat's eye = ?
λ = wavelength = 500 nm = 5 x 10⁻⁷ m
a = slit width of eye = 0.5 mm = 5 x 10⁻⁴ m
Therefore,
θ = (5 x 10⁻⁷ m/5 x 10⁻⁴ m)
Therefore,
θ = 0.001
θ = Sin⁻¹(0.001)
θ = 0.001 rad = 1 x 10⁻³ rad
Hence, the correct answer is:
C. 10⁻³ rads
A book on a 2-meter high shelf has a mass of 0.4 kg. What is its potential energy?
Answer:
[tex]\boxed {\boxed {\sf 7.84 \ Joules}}[/tex]
Explanation:
The formula for potential energy is:
[tex]PE=m*g*h[/tex]
where m is the mass, g is the gravitational acceleration, and h is the height.
The mass of the book is 0.4 kilograms. The gravitational acceleration on Earth is 9.8 m/s². The height of the book is 2 meters.
[tex]m=0.4 \ kg \\g=9.8 \ m/s^2 \\h=2\ m[/tex]
Substitute the values into the formula.
[tex]PE=(0.4 \ kg)(9.8 \ m/s^2)(2 \ m)[/tex]
Multiply the first two numbers.
0.4 kg*9.8 m/s²= 3.92 kg*m/s²If we convert the units now, the problem will be much easier later on. 1 kg*m/s² is equal to 1 Newton. So, our answer of 3.92 kg*m/s² is equal to 3.92 N[tex]PE=(3.92 \ N )(2 \ m)[/tex]
Multiply.
3.92 N* 2 m=7.84 N*m1 Newton meter is equal to 1 Joule (this is why we converted the units). Our answer is equal to 7.84 Joules.[tex]PE=7.84 \ J[/tex]
Answer:
7.84 is your answer ok bye
What is the minimum energy (in MeV) that is required to break a nucleus of 12C (of mass 11.99671 u) into three nuclei of 4He (of mass 4.00151 u each)?
Answer:
the minimum energy that needed to break the nucleus is 1.12608 × 10^-12 J
Explanation:
The computation of the minimum energy that needed to break the nucleus is shown below:
The Change in mass is
= 11.99671 - 3 × 4.00151
= 0.00782
The Energy = mc^2
= (0.00782 × 1.6 × 10^{-27}) × (3 × 10^8)^2
= 1.12608 × 10^-12 J
Hence, the minimum energy that needed to break the nucleus is 1.12608 × 10^-12 J
The same is to be considered
Does lighting striking the earth considered the speed of light?
Answer:
i would tell you but im a hobbit
Explanation:
biden 2020
Witch is not true about longitudinal waves?
Answer:
light is a longitudinal wave.
Explanation:
lol
A car with a mass of 1.5 × 103 kilograms is traveling west at a velocity of 22 meters/second. It hits a stationary car with a mass of 9.0 × 102 kilograms. If the collision is inelastic, what is the final direction and approximate velocity of the two cars?
Answer:
A. 14 meters/second to the west
Explanation:
The collision is inelastic, which means that:
- only the total momentum is conserved (not the kinetic energy)
Answer:
14 meters/second to the west
Explanation:
That's the answer!
How much heat does 56 L of water need to absorb to raise its temperature from 350C to 740C?
Answer:
300 L of water
Explanation:
Two car's are racing! The winner of the race will always be be the vehicle with the greater...
(30points pls help ASAP) How many grams of sodium would there be in 70 g of NaCl?
27.52g grams of sodium would there be in 70 g of NaCl.
What is molecular mass ?The molecular mass gives the total mass of the molecule, it is the sum of masses of all the atoms present in a molecule. for example in Nacl, there is one atom of Na and one atom of Cl both makes NaCl. the sum of masses of Na and Cl gives the mass of the NaCL. Molecular mass is expressed in amu. 1 amu = Avogadro's number of atom or molecule.
The Molar mass is defined as the mass of a given substance divided by the amount of a substance. its unit is g/mol.
Here I have direct method for the calculation of mass of particular atom in the molecule.
Molecular weight of the NaCl is,
(23+35.5)g=58.5g where 23= mass of Na and 35.5 mass Cl.
in this we can see that 58.5 g of Nacl contains 23 g of Na.
we can write 58.5 NaCl = 23g Na
therefore 70g of NaCl = (23÷58.5)×70 Na
70g of NaCl = 27.52g of Na
Hence 70g of NaCl contains 27.52g of sodium.
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According to the Law of the Conservation of Matter, if you dissolve 25 grams of sugar into 150 grams of water, the mixture should weigh how much?
the nitrogen group has 5 electrons true or false
Answer:
True
Nitrogen family elements consists of atoms having 5 electrons in their outer energy level.
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Hope it may helps you
The Sputnik 1 satellite orbited Earth
(mass = 5.98 x 1024 kg) in a circle of
radius 6.96 x 106 m. What was its
period of orbit in seconds?
[?] s
Answer:
5778.1931
Explanation:
Given that:
Mass (M) = 5.98 x 10^24 kg
Radius (r) = 6.96 x 10^6 m
Gravitational constant (G) = 6.67 * 10^-11
Using the relation:
T² / R³ = 4π² / GM
Where T = period of orbit
T = 2π√(R³ /GM)
T = 2π√((6.96 x 10^6)³) /(6.67 * 10^-11) * (5.98 x 10^24)
T = 2π√((3.37153 * 10^20) / (39.866 * 10^13))
T = 2π √845715.64
T = 2π * 919.62799
T = 5778.1931
The diagrams below show forces acting on a toy car as it moves to the right which diagram shows the toy car that will most likely accelerate to the right based on these conditions?
Answer:
Option 1.
Explanation:
To know which option is correct, let us calculate the net force in each case to know which will move to the right direction.
Option 1:
Force to the right (Fᵣ) = 8 N
Force to the left (Fₗ) = 6 N
Net force (Fₙ) =?
Fₙ = Fᵣ – Fₗ
Fₙ = 8 – 6
Fₙ = 2 N to the right
Option 2:
Force to the right (Fᵣ) = 8 N
Force to the left (Fₗ) = 10 N
Net force (Fₙ) =?
Fₙ = Fₗ – Fᵣ
Fₙ = 10 – 8
Fₙ = 2 N to the left
Option 3:
Force to the right (Fᵣ) = 10 N
Force to the left (Fₗ) = 10 N
Net force (Fₙ) =?
Fₙ = Fᵣ – Fₗ
Fₙ = 10 – 10
Fₙ = 0 (no movement)
Option 4:
Force to the right (Fᵣ) = 10 N
Force to the left (Fₗ) = 13 N
Net force (Fₙ) =?
Fₙ = Fₗ – Fᵣ
Fₙ = 13 – 10
Fₙ = 3 N to the left
From the illustrations made above, only option 1 has a net force toward the right direction. Therefore, only option 1 will have an acceleration towards the right direction.
Answer:
Option 1
Explanation:
What name is given to the rate at which velocity changes?
Answer mere
Answer:
Acceleration
Explanation:
As you take the stoppered part of the tube up the staircase you begin to see the water level drop around the 4th floor. As you continue up it does not continue up with you but stays at a constant level. What does that mean?
a. The pressure in the tubing is equal to the barometric pressure.
b. The tubing was unable to supply any more water to the tube for use.
c. The pressure outside the tube is higher that the water pressure inside the tube.
Answer:
a. The pressure in the tubing is equal to the barometric pressure.
Explanation:
Since in the question it is mentioned that the if you take the stoppert part of the tube than the level of warer would be fall approx 4th floor and if it is continued than it wont be continue but remains constant.
Now here first we do that the tube i.e. connected to the bucket should be taken up. In the first instance, the bucket supplies the water to the tube but it would not increased far away to the level of the barometric pressure
Hence, the correct option is a.
An unknown mass is hung from a very light spring with a spring constant of 13.6 N/m. Neglect the mass of the spring. If the period of oscillation of the mass-spring system is 3.35 s, then the unknown mass is:__________
Answer:
The unknown mass is 3.87 kg.
Explanation:
Given;
spring constant of the spring, k = 13.6 N/m
period of oscillation, T = 3.35 s
The period of oscillation of the mass-spring system is given by;
[tex]T = 2\pi \sqrt{\frac{m}{k} }[/tex]
where;
m is the mass attached to the spring
[tex]T = 2\pi \sqrt{\frac{m}{k} }\\\\\frac{T}{2\pi} = \sqrt{\frac{m}{k} }\\\\\frac{T^2}{4\pi^2}= \frac{m}{k}\\\\m = \frac{kT^2}{4\pi^2}\\\\m = \frac{(13.6)(3.35)^2}{4\pi^2}\\\\m = 3.87 \ kg[/tex]
Therefore, the unknown mass is 3.87 kg.
A wire 50.0 m long and 2.00 mm in diameter is connected to a source with a potential difference of 9.11 V, and the current is found to be 36.0 A. Find the resistivity of the material.
Answer:
ρ = 1.6*10⁻⁸ Ω/m.
Explanation:
Applying Ohm's Law to the wire, assuming that it can be treated as a pure resistance, the resistance of the wire can be obtained as follows:[tex]R = \frac{V}{I} = \frac{9.11V}{36.0A} = 0.253 \Omega (1)[/tex]
At the same time, we know that there exists a relationship between the resistance, the resistivity ρ, the length L and the area A of the wire, that is given for the following expression:[tex]R = \rho* \frac{L}{A} (2)[/tex]
The area of the circular section of the wire, can be expressed as a function of the diameter d, as follows:[tex]A = \frac{\pi*d^{2} }{4} = \frac{\pi*(0.002m)^{2}}{4} = \pi*10e-6 (3)[/tex]
Replacing the left side of (2) by (1), and (3) on the right side, we can solve for the resistivity ρ as follows:[tex]\rho = \frac{R*A}{L} = \frac{0.253\Omega*\pi*10e-6}{50.0m} = 1.6e-8 \Omega/m[/tex]
ρ = 1.6*10⁻⁸ Ω/mWhen Royce was 10 years old, he had a mass of
30 kg. By the time he was 16 years old, his mass
increased to 60 kg. How much larger is the
gravitational force between Royce and Earth at
age 16 compared to age 10?
Answer:
The gravitational force between Royce and Earth would be doubled at 16 years.
Explanation:
"Newton's law of universal gravitation states that gravitation force between two masses is proportional to the magnitude of their masses and inverse-squared of their distance".
Royce Scenario
At the age of 10 Royce's mass = 30kg
At the age of 16 Royce's mass = 60kg
From Newton's law of universal gravitation, an Increase in the mass of a body would amount to a corresponding increase in the gravitational force.
In the case of Royce, the mass double between the age of 10 and 16, so there would be an increase of the gravitation force by double.
The gravitational force at the age of 60 is doubled of the gravitational force at the age of 10. A complete solution is below.
Given:
At 10 years old,
Mass,
m = 30 kgnow,
→ [tex]Gravitational \ force (F_1) = \frac{GMm}{r^2}[/tex]
[tex]= mg[/tex]
or,
→ [tex]g = \frac{GM}{r^2}[/tex]
then,
Gravitational force = 30 g
Now,
At 16 years old,
Mass,
m = 60 kgNow,
→ [tex]\frac{F_1}{F_2} = \frac{30}{60}[/tex]
[tex]=\frac{1}{2}[/tex]
[tex]F_2 = 2F_1[/tex]
Thus the above response is right.
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ok who love lizard can we talk plz
Answer:
Meeee
Explanation:
N stands for _____________________, which is an SI unit of force.
Answer:
Newton
Explanation:
can a body have mass but no weight give reasion for your answer
Answer:
Hey buddy, here is your answer. Hope it helps you.
Explanation:
Yes, weight of a body is not constant, it varies with the value of acceleration due to gravity, g. Weight of a body is zero, when it is taken to the centre of the earth or in the interplanetary space, where g=0. Mass is the total matter in a body, while weight is the force by which the body is attracted.
Weight is never constant while mass is. So we can have weight zero but with some mass. This will happen when an object is at the centre of earth, as g=0 at centre of earth , so weight will be 0 while mass will always be constant everywhere
Answer:
yes a body can have mass but no wt at a centre of the earth
Explanation:
this is because acceleration due to gravity decreases as we go deep into earth and becomes 0 at the centre
In which type of collision is the kinetic energy of the system unchanged?
A. Perfectly inelastic
O B. Elastic
C. No type of collision
D. Inelastic
B.) Elastic
Took the test and this is the answer
HURRY
An ultrasound tech is trying to identify an object, but the screen of the machine is broken. Which statement best describes this situation?
The generated sound wave will not be able to reflect off of the object.
The sound wave will not be generated, so there will be no echoes received.
The echoes will be made but will not be able to be received by the machine.
The machine will not be able to process the received echoes into images.
Answer:
It’s b
Explanation:
Everyone else is wrong and I tried this and got it right
Answer:
the answer is b or "The sound wave will not be generated, so there will be no echoes received."
Explanation:
On an alien planet, a simple pendulum of length 0.300 m has oscillation frequency 0.709 Hz. Find the period of the pendulum. Find the acceleration due to gravity on this planet's surface. What must be the length of a simple pendulum if its oscillation frequency is to be equal to that of an air-track glider of mass 0.450 kg attached to a spring of force constant 9.75 N/m?
Answer:
1.41s
5.95m/s
0.2746m
Explanation:
The time period
T = 1/f
= 1/0.709s
= 1.41 seconds
We have
T = 2π√l/g
T² = 4π²l/g
g = 4π²l/T²
g = 4x3.14²x0.300/1.41²
g = 5.95m/s² this is the acceleration due to gravity.
Then the time period of the glide
T2 = 2π√m/k
Length of pendulum = l
Time period T
T2 = 2π√l/g
Then T1 = T2
2π√m/k = 2π√l/g
M/k = l/g
L = g.m/k
L = 5.95x0.450/9.75
L = 0.2746
This must be the length of the simple pendulum
What's the name for how you see the world through your perception
in cognitive theory.
Answer:
Perception: Perception is a cognitive process that allows people to take in information through their senses (sensation) and then utilize this information to respond and interact with the world. Thought: Thought is an essential part of every cognitive process.
I hope it helped
Picture question please answer do in 5 mins
Answer:
Can't see anything, please share clearly
What is responsible for keeping an object at rest or maintaining an object's
constant velocity?
Answer:
Inertia
Explanation:
Inertia is a force which keeps stationary objects at rest and moving objects in motion at constant velocity.
A student rides a bicycle in a circle at a constant speed and constant radius. A force diagram for the student-bicycle system is
shown in the figure above. The value for each force is shown in the figure. What is the acceleration of the student-bicycle system?
m
А
0
2
B
0.2"
C) 5
D
25"
Solution:
The gravitational force that acts on the bicycle system is
[tex]$F_{g} = 500 \ N$[/tex]
Now the force, that is the gravitational force is related to mass of the system and the acceleration due to gravity of the system, 'm' and 'g' respectively.
Therefore, we can write
[tex]$F_g=mg$[/tex]
500 = m x 10 (since , g = 10 m/s-s)
∴ m = 50 kg
Now the net vertical force acting on the student bicycle system is 0. And the vertical acceleration of system is also 0. The total horizontal force acts to the right of the system. So by Newton's 2nd law of motion, we can write
[tex]$F_f = ma$[/tex]
[tex]$a=\frac{F_f}{m}$[/tex]
[tex]$=\frac{250}{50}$[/tex]
Therefore [tex]$a= 5 \ m/s^2$[/tex]
Hence (C) is correct option.
A metal block of density 900kgm^-3 weighs 60N in air, find its weight when it is immersed in paraffin wax of density 800kgm^-3
A projectile is fired horizontally from a height of 78.4 m at a speed of 300 m/sec. How far did it travel horizontally before hitting the ground?
Answer:
Explanation:
Using the formula for calculating range expressed as;
R = U√2H/g
U is the speed = 300m/s
H is the maximum height = 78.4m
g is the acceleration due to gravity = 9.8m/s²
Substitute into the fromula;
R = 300√2(78.4)/9.8
R = 300 √(16)
R = 300*4
R = 1200m
Hence the projectile travelled 1200m before hitting the ground
Help please an observer at the North Pole sees the moon phase shown below. What Moon phase will be observed approximately one week later?
Answer:
it should be a new moon
Explanation:
