The product of two numbers is 10000.If one number is 16 times the other numbers ,find the two numbers.​

Answers

Answer 1

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➯Question:

The product of two numbers is 10000. If one number is 16 times the other numbers ,find the two numbers.

Answer:

Both numbers are 25 and 400.

Step By Step Explanation:

Given that:

The product of two numbers is 10000.

One number is 16 times the other number.

To Find:

Both numbers?

Solution:

Let us consider that one number be n, in question it is stated that other number is 16 times the first number. Therefore, other number is 16n.

According to the Question :

[tex]\sf↦ Product ~of ~numbers = 10000\\\\↦ n × 16n = 10000\\\\↦ 16n² = 10000\\\\↦ n² = \sf \dfrac{10000}{16}\\\\↦ \sf n = \sqrt{\dfrac{10000}{16}}\\\\↦ \sf n = \sqrt{\dfrac{100\:\times\:100}{4\:\times\:4}}\\\\↦ \sf n = {\cancel{\dfrac{100}{4}}}\\\\➦\pmb{\underline{\boxed{\sf{\pink{n = 25}}}}}[/tex]

Hence,

1st number = n = 25

2nd number = 16n = 16 × 25 = 400

∴ Hence, both numbers are 25 and 400.

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Answer 2

Answer:

(25, 400) or (-25, - 400)

Step-by-step explanation:

Let the numbers be x and y.

We have:

y = 16xxy = 10000

Substitute y and solve for x:

x(16x) = 1000016x² = 10000x² = 10000/16x² = 625x = √625x = ± 25

Then y is:

y = ± 25*16 = ± 400

The numbers are:

25 and 400 or -25 and - 400

Related Questions

What is a linear system?

Answers

Answer:

Linear systems are systems of equations in which the variables are never multiplied with each other but only with constants and then summed up

What quadratic formula do I need to use to solve 3x(x+6)=-1

Answers

Answer:

[tex]\Large \boxed{x_1=\frac{9+\sqrt{51} }{3} \ \ ; \ \ x_2=\frac{9-\sqrt{51} }{3} }[/tex]

Step-by-step explanation:

[tex]\displaystyle \Large \boldsymbol{} 3x(x+6)=-10 \\\\3x^2+18x=-10 \\\\3x^2+18x+10=0 \\\\D=324-120=204 \\\\ x_{1;2}=\frac{18\pm2\sqrt{51} }{6} =\frac{9\pm\sqrt{51} }{3}[/tex]

Mike and Ken shared some stamps. \frac{1}{5} 5 1 ​ of Ken's stamps were \frac{1}{3} 3 1 ​ of Mike's stamps. If Mike gave Ken 24 stamps, Ken would have thrice as many stamps as Mike. Find the number of stamps each of them had in the beginning.

Answers

Answer:

Mike had 72 stamps

Ken had 120 stamps

Step-by-step explanation:

Given

[tex]M \to Mike[/tex]

[tex]K \to Ken[/tex]

[tex]\frac{1}{5} * K = \frac{1}{3} * M[/tex]

[tex]K + 24 = 3 * ( M - 24)[/tex]

Required

Find K and M

Make K the subject in: [tex]K + 24 = 3 * ( M - 24)[/tex]

[tex]K = 3 * ( M - 24) - 24[/tex]

Substitute [tex]K = 3 * ( M - 24) - 24[/tex] in [tex]\frac{1}{5} * K = \frac{1}{3} * M[/tex]

[tex]\frac{1}{5} * [3 * ( M - 24) - 24] = \frac{1}{3} * M[/tex]

Open brackets

[tex]\frac{1}{5} * [3M - 72 - 24] = \frac{1}{3} * M[/tex]

[tex]\frac{1}{5} * [3M -96] = \frac{1}{3} * M[/tex]

Multiply both sides by 15

[tex]3* [3M -96] = 5 * M[/tex]

[tex]9M -288 = 5M[/tex]

Collect like terms

[tex]9M -5M= 288[/tex]

[tex]4M= 288[/tex]

Divide both sides by 4

[tex]M= 72[/tex]

Substitute [tex]M= 72[/tex] in [tex]K = 3 * ( M - 24) - 24[/tex]

[tex]K = 3 * (72 - 24) - 24[/tex]

[tex]K = 3 * 48 - 24[/tex]

[tex]K = 120[/tex]

A train travels a distance of 60 km at uniform speed. If the speed of the train was reduced by 10 kmh-1, the time taken to travel the 60km will increase by 1/2h. Find the speed of the train at the beginning.

Answers

Answer:

Initial speed is 32 m/s

At uniform speed, acceleration is 0, (a = 0).

When speed reduced, (v - u) = 2.78 ms-¹, t = 1800 sec, s = 60 ,000 metres.

From first equation of motion:

[tex]{ \boxed{ \bf{v = u + at}}} \\ { \tt{(v - u) = at}}[/tex]

substitute:

[tex]{ \tt{2.78 = (a \times 1800)}} \\ { \tt{acceleration = 0.0015 \: {ms}^{ - 2} }}[/tex]

from second equation of motion:

[tex]{ \boxed{ \bf{s = ut + \frac{1}{2} a {t}^{2} }}}[/tex]

substitute:

[tex]{ \tt{60000 = 1800u + ( \frac{1}{2} \times 0.0015 \times {1800}^{2}) }} \\ { \tt{1800u = 57570}} \\ { \tt{u = 32 \: m {s}^{ - 1} }}[/tex]

need help with this!!!

Answers

Answer:

It's D I sure about it correspond means identical... The matching number

The difference between interior angle in centesimal measurement and sexagesimal measurement is 15° of a regular polygon. Find the number of sides of the polygon.​

Answers

Answer:

8

Step-by-step explanation:

x = centesimal angle (100 degrees in a right angle)

y = sexagesimal angle (90 degrees in a right angle)

x - y = 15

x×90/100 = y

x×9/10 = y

x - x×9/10 = 15

10x/10 - 9x/10 = 15

x/10 = 15

x = 150

y = 150×9/10 = 15×9 = 135

using centesimal system :

the sum of all external angles in a polygon is 400 degrees (a full circle).

one external angle is the complement of one internal angle to 200 degrees = 200-150=50 degrees.

to find the number of sides of the polygon we need to find the number of angles or corners. and that is how many external angles fit into the full circle.

n = 400/50 = 8

the polygon has 8 sides

The curve C has parametric equations x = t², y = (2 - t)^1/2, for 0 ≤ t ≤2.
Find d2y/dx2 in terms of t.
Can I have the full workings also please?

Answers

Answer:

y''=(4-3t)/[16 t^3 (2-t)^(3/2)]

Step-by-step explanation:

x = t², y = (2 - t)^1/2

dy/dx=dy/dt×dt/dx by chain rule

dy/dt=1/2 (2-t)^(1/2-1) × (-1)

dy/dt=-1/2 (2-t)^(-1/2)

dy/dt=-1/[2(2-t)^(1/2) ]

dx/dt=2t

dy/dx=-1/[2(2-t)^(1/2) ] × 1/[2t]

dy/dx=-1/[4t (2-t)^(1/2) ]

We need to find the second derivative now.

That is we calculate d/dt(dy/dx in terms of t) then divide by derivative of x in terms of t).

dy/dx=-1/[4t (2-t)^(1/2) ]

Let's find derivative of this with respect to t.

d/dt(dy/dx)=

[0[4t (2-t)^(1/2)]-(-1)(4(2-t)^(1/2)+-4t(1/2)(2-t)^(-1/2))]/ [4t (2-t)^(1/2) ]^2

Let's simplify

d/dt(dy/dx)=

[(4(2-t)^(1/2)+-4t(1/2)(2-t)^(-1/2))]/ [4t (2-t)^(1/2) ]^2

Continuing to simplify

Apply the power in the denominator

d/dt(dy/dx)=

[(4(2-t)^(1/2)+-4t(1/2)(2-t)^(-1/2))]/ [16t^2 (2-t) ]

Multiply by (2-t)^(1/2)/(2-t)^(1/2):

d/dt(dy/dx)=

[(4(2-t)+-4t(1/2)]/ [16t^2 (2-t)^(3/2)]

Distribute/multiply:

d/dt(dy/dx)=

[(8-4t+-2t)]/ [16t^2 (2-t)^(3/2)]

Combine like terms:

d/dt(dy/dx)=

[(8-6t)]/ [16t^2 (2-t)^(3/2)]

Reducing fraction by dividing top and bottom by 2:

d/dt(dy/dx)=

[(4-3t)]/ [8t^2 (2-t)^(3/2)]

Now finally the d^2 y/dx^2 in terms of t is

d/dt(dy/dx) ÷ dx/dt=

[(4-3t)]/ [8t^2 (2-t)^(3/2)] ÷ 2t

d/dt(dy/dx) ÷ dx/dt=

[(4-3t)]/ [8t^2 (2-t)^(3/2)] × 1/( 2t)

d/dt(dy/dx) ÷ dx/dt=

[(4-3t)]/ [16t^3 (2-t)^(3/2)]

Or!!!!!!

x = t², y = (2 - t)^1/2

Since t>0, then t=sqrt(x) or x^(1/2).

Make this substitution into the equation explicitly solved for y:

y = (2 - x^1/2)^1/2

Differentiate:

y' =(1/2) (2 - x^1/2)^(-1/2) × -1/2x^(-1/2)

y'=-1/4(2 - x^1/2)^(-1/2)x^(-1/2)

y'=-1/4(2x-x^3/2)^(-1/2)

Differentiate:

y''=1/8(2x-x^3/2)^(-3/2)×(2-3/2x^1/2)

y''=(2-3/2x^1/2)/[8 (2x-x^3/2)^(3/2)]

Replace x with t^2

y''=(2-3/2t)/[8 (2t^2-t^3)^(3/2)]

Multiply top and bottom by 2

y''=(4-3t)/[16 (2t^2-t^3)^(3/2)]

Factor out t^2 inside the 3/2 power factor:

y''=(4-3t)/[16 (t^2)^(3/2) (2-t)^(3/2)]

y''=(4-3t)/[16 t^3 (2-t)^(3/2)]

You are standing 186 feet away from the base of a building and your clinometer
measures 23° when it's looking at the top of the building. (This angle is the one between
the ground and the top of the building). Please calculate the height of the building.

Answers

9514 1404 393

Answer:

  about 79 ft

Step-by-step explanation:

The relevant trig relation is ...

  Tan = Opposite/Adjacent

In this scenario, the angle is 23°, the adjacent side is the distance to the building, and the opposite side is the building height. Then we have ...

  height = tan(23°)·(186 ft) ≈ 78.95 ft ≈ 79 ft

pls help. And can someone tell me how give brainliest so i can give it?

Answers

Answer:

n - 324 = 394

STEP BY STEP EXPLANATION

toán 9 nha mọi người

Answers

Answer:

Thamkhao

Step-by-step explanation:

A particle moves along a line with a velocity v(t)=t2−t−6, measured in meters per second. Find the total distance the particle travels from t=0 seconds to t=4 seconds.

Answers

The total distance the particle travels from t=0 seconds to t=4 seconds would be 11.33 meters.

Used the concept of integration that states,

In Maths, integration is a method of adding or summing up the parts to find the whole. It is a reverse process of differentiation, where we reduce the functions into parts.

Given that,

A particle moves along a line with a velocity v(t) = t² - t - 6, measured in meters per second.

Now the total distance the particle travels from t=0 seconds to t=4 seconds is,

D = ∫₀⁴ |(t² - t - 6)| dt

D =  ∫₀⁴ (t²) dt - ∫₀⁴ (t) dt -  ∫₀⁴ (6) dt

D = (t³/3)₀⁴ - (t²/2)₀⁴ - 6 (t)₀⁴

D =| (64/3) - (16/2) - 6 (4)|

D = | (64/3) - 8 - 24 |

D = | (64/3) - 32|

D = 11.33 meters

Therefore, the total distance is 11.33 meters.

To learn more about integration visit:

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If the vertex of an isosceles triangle measures 46°, what is the measure of it’s base angles?

Answers

Answer:

67°

Step-by-step explanation:

let the base angle=x

x+x+46=180

2x=180-46=134

x=134/2=67

PLS HELP WILL GIVE BRAINLY!!
A triangle has sides that measure 4 units, 6 units, and 7.21 units. What is the area of a circle with a circumference that equals the perimeter of the triangle? Use 3.14 for π, and round your answer to the nearest whole number.

17 units2
24 units2
54 units2
94 units2

Answers

Answer:

24 units ²

Step-by-step explanation:

In this problem, we are given the circumference of a triangle (after finding the perimeter) and want to find the area of a circle with that circumference. Since the area of a circle is a function based on its radius, we can use the circumference to find the radius to find the area.

First, we can figure out the perimeter of the triangle, which is equal to the sum of its sides. The perimeter is 6+4+7.21 = 17.21 units.

Next, the circumference of a circle is equal to π * diameter = π * 2 * radius. Using 3.14 for π and r for radius, we get

3.14 * 2 * r = 17.21

6.28 * r = 17.21

divide both sides by 6.28 to isolate r

r ≈ 2.74

Furthermore, to find the area from the radius, we can use

area = πr². Plugging 2.74 in for r, we get

2.74² * 3.14 = area

≈23.6, rounding up to 24 units ²

The circumference is equal to the perimeter of the triangle. Then the area of the circle is 23.58 or 24 square units. Option B is correct.

What is a circle?

It is a locus of a point drawn equidistant from the center. The distance from the center to the circumference is called the radius of the circle.

A triangle has sides that measure 4 units, 6 units, and 7.21 units.

Then the perimeter of the triangle will be

Perimeter = 6 + 4 + 7.21

Perimeter = 17.21

The circumference is equal to the perimeter of the triangle. Then the radius will be

[tex]2\pi r = 17.21\\\\r = 2.74[/tex]

Then the area of the circle will be given as

[tex]\rm Area = \pi r^2 \\\\Area = \pi \times 2.74^2 \\\\Area = 23.58[/tex]

Thus, the area of the circle is 23.58 square units.

More about the circle link is given below.

https://brainly.com/question/11833983

what is the approximate shadow in feet of the tree in the figure below.​

Answers

Answer:

224 ft

Step-by-step explanation:

The tree makes a 90° angle with the ground, so we have a right triangle.

For the 32° angle, the height of the tree is the opposite leg. The length of the shadow on the ground is the adjacent leg.

The trig ratio that relates the opposite leg to the adjacent leg is the tangent.

Let the length of the shadow of the tree on the ground be x.

tan A = opp/adj

tan 32° = 140 ft/x

x = 140 ft/tan 32°

x = 224 ft

Answer: 224 ft

8. Colleen times her morning commute such that there is an equal likelihood that she will arrive early or late to work on any given day. If she always arrives either early or late, what is the probability that Colleen will arrive late to work no more than twice during a five-day workweek

Answers

Solution :

Case I :

If Collen is late on [tex]0[/tex] out of [tex]5[/tex] days.

[tex]$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} $[/tex]

[tex]$=\frac{1}{32}[/tex]

Case II :

When Collen is late on [tex]1[/tex] out of [tex]5[/tex] days.

[tex]$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times ^5C_1$[/tex]

[tex]$=\frac{1}{32} \times 5$[/tex]

[tex]$=\frac{5}{32}[/tex]

Case III :

When Collen was late on [tex]2[/tex] out of [tex]5[/tex] days.

[tex]$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times ^5C_2$[/tex]

[tex]$=\frac{1}{32} \times 10$[/tex]

[tex]$=\frac{5}{16}[/tex]

Therefore, the [tex]\text{probability}[/tex] that Collen will arrive late to work no more than [tex]\text{twice}[/tex] during a [tex]\text{five day workweek}[/tex] is :

[tex]$=\frac{1}{32} + \frac{5}{32} + \frac{5}{16} $[/tex]

[tex]$=\frac{1}{2}$[/tex]

Given a line segment that contains the points A,B, & C in order,if AB = 2x + 3, BC = 4x - 11, and AC = 28, find the length of segment AB.

Answers

Answer:

15

Step-by-step explanation:

AB+BC=AC

2X+3+(4X-11)

6X-8=28

6x= 36

x=6

then ab= 2(6)+3

=15

bc= 4(6)-11

=13

ac=ab+bc

=15+13

=28

Zoe walks at a speed of 10 miles/h and jogs at a speed of 20 miles/h. She goes to the park to walk 2 miles on a Monday. How long will she take to walk 2 miles?

Answers

Answer:

12 minutes

Step-by-step explanation:

Given

[tex]s_1 = 10mi/h[/tex] --- walk speed

[tex]s_2 = 20mi/h[/tex] --- jog speed

[tex]d = 2\ miles[/tex] --- distance

Required

The time to walk the given distance

Time is calculated as:

[tex]Time = \frac{distance}{speed}[/tex]

In this case, the speed is the speed at which she walks.

So, we have:

[tex]Time = \frac{d}{s_1}[/tex]

Substitute known values

[tex]Time = \frac{2mi}{10mi/h}[/tex]

[tex]Time = 0.2hr[/tex]

Convert to minutes

[tex]Time = 0.2 * 60mins[/tex]

[tex]Time =12mins[/tex]

You're playing a game where you defend your village from an orc invasion. There are 3 characters (elf, hobbit, or human) and 5 defense tools (magic, sword, shield, slingshot, or umbrella) to pick from. If you randomly choose your character and tool, what is the probability that you wont be a hobbit or use an umbrella

Answers

Answer:

The probability that you won't be a hobbit=

[tex] \frac{2}{3} [/tex]

The probability that you won't choose an umbrella=

[tex] \frac{4}{5} [/tex]

Step-by-step explanation:

The characters are 3, minus the hobbit gives you 2. So the probability of that=

[tex] \frac{2}{3} [/tex]

The weapons are 5, minus the umbrella is 4. So the probability of that=

[tex] \frac{4}{5} [/tex]

(a + b)2 = 1a2 + 2ab + 1b2
(a + b)3 = 1a3 + 3a2b + 3ab2 + 1b3
How are binomial expansions related to Pascal’s triangle?

Answers

The Pascal triangle terms and binomial are related by the binomial theorem fomrula:

The row of the Pascal triangle is the same as

where n is the same as the row of the Pascal triangle.

For example,

.

is the same as the 2nd row of the Pascal triangle.

.

Also know the leading coefficient and last term degree will be the nth row of the Pascal triangle.

The first term, a will be 1 less than the previous terms and the second term, b will be 1 more than the previous terms. For example, look at

.

Another example is

.

The third row of Pascal Triangle

.

.

Pascal's triangle provides a systematic way to determine the coefficients of binomial expansions, making it a valuable tool in algebra and combinatorics.

Binomial expansions are directly related to Pascal's triangle.

Pascal's triangle is a triangular arrangement of numbers in which each number is the sum of the two numbers directly above it. The first and last numbers in each row of Pascal's triangle are always 1.

The coefficients of the terms in a binomial expansion correspond to the numbers in Pascal's triangle. Each row of Pascal's triangle represents the coefficients of the corresponding power of the binomial.

For example, in the expansion of (a + b)², the coefficients are 1, 2, and 1. These coefficients can be found in the third row of Pascal's triangle: 1, 2, 1. Similarly, in the expansion of (a + b)³, the coefficients are 1, 3, 3, and 1, which can be found in the fourth row of Pascal's triangle: 1, 3, 3, 1.

In summary, Pascal's triangle provides a systematic way to determine the coefficients of binomial expansions, making it a valuable tool in algebra and combinatorics.

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without using tables or calculator, evaluate​

Answers

Question:- Find the value

[tex] \frac{ \sin(20 \degree) }{ \cos(70\degree) } + \frac{ \cos(35\degree) }{ \sin( 65\degree)} [/tex]

Answer->

[tex] \frac{ \sin(20 \degree) }{ \cos(70\degree) } + \frac{ \cos(35\degree) }{ \sin( 65\degree)} [/tex]

we know:-

[tex] \sin( \theta) = \cos(90 - \theta) \\ \\ \cos( \theta) = \sin(90 - \theta) [/tex]

So putting down the value

[tex] \frac{ \cos(90 - 20 \degree) }{ \cos(70\degree) } + \frac{ \sin(90 - 35\degree) }{ \sin( 65\degree)} [/tex]

[tex] \frac{ \cos(70\degree) }{ \cos(70\degree) } + \frac{ \sin(65\degree) }{ \sin( 65\degree)} [/tex]

[tex]\frac{\cancel{\cos(70\degree)}}{ \cancel{\cos(70\degree)}} + \frac{\cancel{\sin(65\degree)}}{\cancel{\sin( 65\degree)}} [/tex]

[tex] \frac{1}{1} + \frac{1}{1} \\ 1 + 1 = 2 \: \: ans[/tex]

If m


Please Help!!!!!!!!!!!!

Answers

Answer:

45 degrees

Step-by-step explanation:

the 2 angles are supplementary (add up to 180 degrees)

180-135=45

Out of the 14641 times Voldemort has brushed his teeth, only 5/11 of the time did he floss immediately beforehand. How many times total has Voldemort NOT flossed right before brushing his teeth?

Answers

In this question, we want to find a fraction of a value, which is found multiplying the fraction by the value.

Information:

Voldemort has brushed his teeth 14641 times.

5/11 of the time, he has flossed immediately beforehand.

[tex]1 - \frac{5}{11} = \frac{6}{11}[/tex] of the time, he has NOT flossed immediately beforehand.

How many times total has Voldemort NOT flossed right before brushing his teeth?

6/11 out of 14641, so:

6*14641/11 = 7986.

Thus, Voldemort has NOT flossed right before brushing his teeth 7986 times.

For another example with a fraction of a value, you can check https://brainly.com/question/5501130

Lord Voldemort did not floss his teeth 7986 times.

According to this question, we know the following two facts:

1) Lord Voldemort has brushed his teeth 14641 times.

2) He flossed his teeth beforehand only [tex]\frac{5}{11}[/tex] of the time.

There, he did not floss his teeth [tex]\frac{6}{11}[/tex] of the time and the total number of time that he did not floss is obtained by multiplicating the total number of times that he brushed his teeth and the rational number deducted at the beginning of the paragraph. That is to say:

[tex]x = \left(\frac{6}{11} \right)\cdot (14641)[/tex]

[tex]x = 7986[/tex]

Lord Voldemort did not floss his teeth 7986 times.

double a number plus 54 equals 8 times the number

Answers

2x+54=8x

So. The Answer is 7

(12, 9, 4) What is the area of the parallelogram shown below?

Answers

area of the parallelogram is: b x h

12 x 4 = 48 (d)

Tính : 2020^3-1/2020+2021

Answers

Answer:

2020³-1/4041

Step-by-step explanation:

The length of a rectangle is 10 m more than its breadth. If the perimeter of rectangle is 80 m, find the dimensions of the rectangle.

Answers

if you like my answer then please mark me as brainliest

Complete the equation to represent finding x, the greater integer. x(x – ) = 143 What is the greater integer?

Answers

Answer:

[tex]x * (x - 2) = 143[/tex]

Where [tex]x = 13[/tex]

Step-by-step explanation:

Given

[tex]x (x - \_) = 143[/tex]

Required

Complete the blank

The complete question implies that the product include 2 consecutive odd numbers.

Two numbers whose products equal 143 are: 11 and 13

i.e. [tex]11 * 13 = 143[/tex]

So, we have:

[tex]x * (x - \_) = 13 * 11[/tex]

By comparison, we have:

[tex]x = 13[/tex]

[tex]x - \_ = 11[/tex]

Collect like terms

[tex]\_ = x - 11[/tex]

Substitute 13 for x

[tex]\_ = 13 - 11[/tex]

[tex]\_ = 2[/tex]

So, the complete equation is:

[tex]x * (x - 2) = 143[/tex]

Where [tex]x = 13[/tex]

Answer:

2

and

13

Step-by-step explanation:

Got it right on edge.

multiply
12/18×10/18
lesson name fraction.
find me out this question for answer​

Answers

Here you go
Hope it’s helps

A line with slope 3 intersects a line with slope 5 at the point (10, 15). What is the distance between the x-intercepts of these two lines?​

Answers

Answer:

2

y = 3x-15

y=5x-35

x1=5

x2=7

distance between = 7-5 = 2

Step-by-step explanation:

Solve for m g=4cm-3cm

Answers

Answer:

g/c =m

Step-by-step explanation:

g=4cm-3cm

Combine like terms

g = 1cm

g =cm

Divide by c

g/c = cm/c

g/c =m

Other Questions
find the missing angles pls answer quickly before 3:30 need help asap pls ! As part of an experimental study on neuropeptides and their effect on emotions, Hilda administers a certain chemical to a group of teenagers, which has been chosen as the sample. The effects of this chemical include a feeling of elation and a need for affiliation. The group of teenagers considered for research exhibits a need to socialize more with the people on campus. Which of the following is the group of teenagers likely to have been given?-Oxytocin-Ghrelin-Lutein-Melanin 3/7 x 4/7 what is the answer Independent PracticeWhich model is most appropriate for the set of points?(2, 5), (1, 1), (0, 3), (1, 1), (2, 5)A.exponentialB.linearC.quadratic el Conde de Montecristo What group of archaebacteria is both thermophilic and acidophilic?PyrogensMethanogensThermoacidophilesHalophiles What are the effects of global warming? 36. It was a beautiful day. _______ sun shone brightly in _____ sky. A. a / a. B. a / the. C. the / the. D. the / a 37. My mother goes to church in ______ morning. A. x. B. every. C. the D. a 38. I saw .. man going into the office. I dont know who man was. A. a / the. B. an / the. C. the / a. D. X / X 39. . moon is full tonight. A. a. B. an. C. the. . D. X 40. She cant play . piano but she can play violin. A. a / a. . B. a / the. C. the / the. D. X / X 41 It was not until 2000 that I .................... him. A. teach B. teaching. C. to teach D. taught 42. It .................... until his father came that he ate something. A. was B. were. C. was not. D. were not 43. It was not until I .................... to new school that my mother bought me a new bike. A. go. B. . went. C. am going. D. will go 44. It was not until .................... that I met her. A. next week. B. last week. C. week. D. the week 45. It was not until he came ................................ she left. A. Since. B. till. C. that. D. as On the Navajo Reservation, a random sample of 210 permanent dwellings in the Fort Defiance region showed that 69 were traditional Navajo hogans. In the Indian Wells region, a random sample of 162 permanent dwellings showed that 22 were traditional hogans. Let p1 be the population proportion of all traditional hogans in the Fort Defiance region, and let p2 be the population proportion of all traditional hogans in the Indian Wells region.Required:a. Find a 99% confidence interval for p 1 - P2. b. Examine the confidence interval and comment on its meaning. Does it include numbers that are all positive? please helpppppp I will give brainlist The basic economic problem of scarcityQuestion 1 options:A) does not apply to the wealthy in society.B) is a problem only in developing economies.C) has always existed and will continue to exist.D) will eventually disappear as technology continues to advance. which of the specific classification is the specific organism found please answer urgently you dont need to explain it i am having troubles solving this 4(x+3)=x+42 can i get some help please. Which best describes the United States' response to Nazi killing of European Jews?a.The United States did very little to help the Jews until late in the war and with limited action after the war.b.The United States willingly accepted most of the Jewish refugees.c.The United States insisted that all nations change their immigration laws to help protect Jewish refugees from extermination.d.There was very little prejudice or discrimination against Jewish people in the United States in the 1940's. i will give brainliest please help geometry work coordinates Which of the following is a benefit of using email to communicate at work ? a ) You can express yourself in limited number of characters Ob ) You don't have to worry about using proper grammar. c) You always get a response right away. d ) You can reach a large audience with one communication .