9514 1404 393
Answer:
$11,715.65
Step-by-step explanation:
The applicable formula is ...
FV = P(1 +r/n)^(nt)
where principal P earns interest at rate r compounded n times per year for t years.
FV = $9500(1 +0.042/12)^(12·5) = $9500(1.0035^60) ≈ $11,715.65
The account will hold $11,715.65 after 5 years.
A tour bus is traveling along a triangular path. The three straight lines form a right triangle. One leg of the triangle represents a distance of 8 miles. The other leg of the triangle is 4 miles shorter than the hypotenuse. What is the length of the hypotenuse of this triangle? Of the other leg?
Answer:
Hypotenuse=10 miles.
Short leg=6 miles.
Step-by-step explanation:
Set up triangle, leg 8 miles, hypotenuse x miles, short leg x-4 miles.Input into Pythagoras theorem.Simplify.Use the given degree of confidence and sample data to construct a confidence interval for the population mean μ. Assume that the population has a normal distribution. A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with s = 17.6 milligrams.
Required:
Construct a 95% confidence interval for the true mean cholesterol content of all such eggs.
Answer:
CI ≈ (173.8 < μ < 196.2)
Step-by-step explanation:
We are told that laboratory tested twelve chicken eggs. Thus;
n = 12
Mean; x¯ = 185 mg
S.D; s = 17.6 mg
DF = n - 1 = 12 - 1 = 11
We have a 95% confidence level. Thus; α = 0.05
Since n < 30, we will use t-sample test.
Thus, from t-table attached at 95% Confidence level and DF = 11, we have;
t = 2.201
Thus,formula for Confidence interval is;
CI = (x¯ - t(s/√n)) < μ < (x¯ + t(s/√n))
CI = (185 - 2.201(17.6/√12)) < μ < (185 + 2.201(17.6/√12))
CI = (185 - 11.1825) < μ < (185 + 11.1825)
CI = (173.8175 < μ < 196.1825)
CI ≈ (173.8 < μ < 196.2)
Find the numerical value of the area under the normal curve given the following information:
less than z = -0.06
enter your answer as a decimal (NOT percentage) and lead with a zero...for example: 0.1234
Answer:
.4761
I have a feeling that you are not quite getting the concept of these questions
a "Z" table "maps" a value (x-mu/sigma) to a number on a z-table chart
Your calculator has the function but the chart is simple for this questions
the numbers IN the chart represent "the percent UNDER THE NORMAL CURVE"
a z =0 is the MIDDLE so it is 50%
your questions is negative so it is to the left of the "middle"
all you have to do is find the z number on the chart and that is the answer to this question
Step-by-step explanation:
An expression is shown below:
6x2y − 3xy − 24xy2 + 12y2
Part A: Rewrite the expression by factoring out the greatest common factor. (4 points)
Part B: Factor the entire expression completely. Show the steps of your work. (6 points)
Given:
The given expression is:
[tex]6x^2y-3xy-24xy^2+12y^2[/tex]
To find:
Part A: The expression by factoring out the greatest common factor.
Part B: Factor the entire expression completely.
Solution:
Part A:
We have,
[tex]6x^2y-3xy-24xy^2+12y^2[/tex]
Taking out the highest common factor 3y, we get
[tex]=3y(2x^2-x-8xy+4y)[/tex]
Therefore, the required expression is [tex]3y(2x^2-x-8xy+4y)[/tex].
Part B:
From part A, we have,
[tex]3y(2x^2-x-8xy+4y)[/tex]
By grouping method, we get
[tex]=3y(x(2x-1)-4y(2x-1))[/tex]
[tex]=3y(x-4y)(2x-1)[/tex]
Therefore, the required factored form of the given expression is [tex]3y(x-4y)(2x-1)[/tex].
Please I need help :(
Answer:
A. x-2y-3z = 1/2
Step-by-step explanation:
yess.. if you take solve every equation then you will get same equation from all the equations
i need help!!! due by 12
Answer:
1. $11747.083
2. $29,253
3. $24222.04
4. $1542.23
Step-by-step explanation:
Message for explanation if you want.
Categorize the trigonometric functions as positive or negative.
Answer:
So, remember that:
cos(x) > 0 for -pi/2 < x < pi/2
cos(x) < 0 for pi/2 < x < (3/2)*pi
and
sin(x) > 0 for 0 < x < pi
sin(x) < 0 for -pi < x <0 or pi < x < 2pi
Also, we have the periodicty of the sine and cocine equations, such that:
sin(x) = sin(x + 2pi)
cos(x) = cos(x + 2pi)
Now let's solve the problem:
[tex]sin(\frac{13*\pi}{36} )[/tex]
here we have:
x = (13/36)π
This is larger than zero and smaller than π:
0 < (13/36)π < π
then:
[tex]sin(\frac{13*\pi}{36} )[/tex]
Is positive.
The next one is:
[tex]cos(\frac{7*\pi}{12} )[/tex]
Here we have x = (7/12)*pi
notice that:
7/12 > 1/2
Then:
(7/12)*π > (1/2)*π
Then:
[tex]cos(\frac{7*\pi}{12} )[/tex]
is negative.
next one:
[tex]sin(\frac{47*\pi}{36} )[/tex]
here:
x = (47/36)*π
here we have (47/36) > 1
then:
(47/36)*π > π
then:
[tex]sin(\frac{47*\pi}{36} )[/tex]
is negative.
the next one is:
[tex]cos(\frac{17*\pi}{10} )[/tex]
Here we have x = (17/10)*π
if we subtract 2*π (because of the periodicity) we get:
(17/10)*π - 2*π
(17/10)*π - (20/10)*π
(-3/10)*π
this is in the range where the cosine function is positive, thus:
[tex]cos(\frac{17*\pi}{10} )[/tex]
is positive.
the next one is:
[tex]tan(\frac{41*\pi}{36} ) = \frac{sin(\frac{41*\pi}{36} )}{cos(\frac{41*\pi}{36} )}[/tex]
here we have:
x = (41/36)*π
Notice that both functions, sine and cosine are negatives for that value, then we have the quotient of two negative values, so:
[tex]tan(\frac{41*\pi}{36} ) = \frac{sin(\frac{41*\pi}{36} )}{cos(\frac{41*\pi}{36} )}[/tex]
is positive.
The final one is:
[tex]tan(\frac{5*\pi}{9} ) = \frac{sin(\frac{5*\pi}{9} )}{cos(\frac{5*\pi}{9} )}[/tex]
Here:
x = (5/9)*π
The sin function is positive with this x value, while the cosine function is negative, thus:
[tex]tan(\frac{5*\pi}{9} ) = \frac{sin(\frac{5*\pi}{9} )}{cos(\frac{5*\pi}{9} )}[/tex]
Is negative.
Q:
To which axis is the line passing through A(4,3) and B(4,-2) parallel to?
Answer:
y-axis.
Step-by-step explanation:
The x coordinate of both points is 4, so it is parallel to they-axis.
Which rules of exponents will be used to evaluate the expression. Check all that apply.
[
1791
quotient of powers
product of powers
power of a power
power of a product
negative exponent
zero exponent
Answer:
product of power
Step-by-step explanation:
I think this will help you
scientist has two solutions, which she has labeled solution a and solution b. solution a is 60% salt and solution b is 85% salt. she wants to obtain 140 ounces of mixture that is 80% salt. How many ounces of each solution should she use?
Answer:
We have 60% salt and 85% salt solutions and we need 140 ounces of a solution that is 80% salt.
We set up 2 equations:
A) x + y = 140
B) .60x + .85y = .80 * 140
Multiply equation A) by -.60
A) -.60x -.60y = -84 then we add this to B)
B) .60x + .85y = 112
.25y = 28
y = 112 ounces of 85% salt
x = 28 ounces of 60% salt.
Double Check
112 * .85 = 95.2 AND 28 * .60 = 16.80
95.2 + 16.80 = 112
and 112/140 = 80 per cent!!
Source: http://www.1728.org/mixture.htm
Step-by-step explanation:
i need help ON THIS PLS
Answer:
No, because the ratio of pay to hours is not the same for each pair of value.
Why is the value of -9 is not-3
Answer:
Because it's a negative.
Step-by-step explanation:
The value of a positive number is still a positive number.
PLEASE ANSWER
Triangle ABC is similar to triangle DEF. find the length of median CP
A. 12
B. 16
C. 24
D.48
12/16 = (3x-12)/(2x+8)
16(3x-12)=12(2x+8)
48x-192=24x+96
48x-24x=192+96
24x=288
X=288/24
X=12
3x-12
=(12x3)-12
=36-12
=24
C is the answer
Hope this helps!
Answer:
48
Step-by-step explanation:
2x+8=3x-12(ABCP ~FDQE)
2x-3x= -8-12
-x= -20
x=20
now,
CP=3x-12
3*20-12
48
what is the value of sum of 18 and 3 time the difference of 9 and 5 divided by 2 is subtracted from 30 ?
if u give right answer i will mark u as a brainlist
Answer:
12
Step-by-step explanation:
(18+3)=21
(9-5)=4
4x21=84
84/2=42
42-30=12
Answer:
12
Step-by-step explanation:
((18+3)x(9-5))/2-30
=((21)x(4))/2-30
=(84)/2-30
=42-30
=12
can somebody help with this please
Answer:
"D"
Step-by-step explanation:
just add the two functions
5x^2 - 8x^2 = -3x^2 etc
Which of the following numbers has the greatest value?
89 3/4
66 1/2
55 2/3
74 1/4
106 5/6
Answer:
106 5/6
Step-by-step explanation:
55 < 66 < 74 < 89 < 106
the fractions are irrelevant because the whole numbers are all different
The greatest of the numbers will be 106 5/6 since 106 is greater than the rest of the integers present in the mixed fractions.
Finding greatest value in a sequenceThe greatest value is the highest value in a given set of number.
Given the following numbers
89 3/4
66 1/2
55 2/3
74 1/4
106 5/6
The greatest of the numbers will be 106 5/6 since 106 is greater than the rest of the integers present in the mixed fractions.
Learn more on mixed fractions here: https://brainly.com/question/414559
#SPJ6
I need help with just 1 and 2
1. I think in Brooklyn, Manhattan, and the other different cities in New Jersey, the rents are overpriced.
2. Some factors are if it looks nice, there are no bugs or rodents, and if it's not a rip off.
**I can't answer the second part bcuz i don't see the tables.
A normal distribution has a mean of 15 and a standard deviation of 2. Find the value that corresponds to the 75th
percentile. Round your answer to two decimal places.
N
0.00
0.01
0.02
0.03
0.04
0.05
0.06
0.07
0.08
0.09
0.5
0.6915
0.6950
0.6985
0.7019
0.7054
0.7088
0.7123
0.7157
0.7190
0.7224
0.6 0.7257
0.7291
0.7324
0.7357
0.7389 0.7422
0.7454
0.7486
0.7517
0.7549
0.7 0.7580
0.7611
0.76420.7673
0.7704
0.7734
0.7764
0.7794
0.7823
0.7852
0.8
0.7881
0.7910
0.7939
0.7967
0.7995
0.8023
0.8051
0.8078
0.8106
0.8133
A physical trainer decides to collect data to see if people are actually weight changing weight during the shelter in place. He believes there will not be a meaningful change in weight due to the shelter in place order. He randomly chooses a sample of 30 of his clients. From each client, he records their weight before the shelter in place order, and again 10 days after the order. A summary of the data is below.
The trainer claims, "on average, there is no difference in my clients' weights before and after the shelter in place order." Select the pair of hypotheses that are appropriate for testing this claim.
H0: µd = 0
H1: µd < 0 (claim)
H0: µd = 0 (claim)
H1: µd ≠ 0
H0: µd ≠ 0 (claim)
H1: µd = 0
H0: µd = 0 (claim)
H1: µd > 0
H0: µd = 0
H1: µd > 0 (claim)
H0: µd = 0
H1: µd ≠ 0 (claim)
H0: µd = 0 (claim)
H1: µd < 0
H0: µd ≠ 0
H1: µd = 0 (claim)
b) Select the choice that best describes the nature and direction of a hypothesis test for this claim.
This is a right-tail t-test for µd.
This is a right-tail z-test for µd.
This is a two-tail t-test for µd.
This is a two-tail z-test for µd.
This is a left-tail t-test for µd.
This is a left-tail z-test for µd.
c) Find the standardized test statistic for this hypothesis test. Round your answer to 2 decimal places.
d) Find the P-value for this hypothesis test. Round your answer to 4 decimal places.
e) Using your previous calculations, select the correct decision for this hypothesis test.
Fail to reject the alternative hypothesis.
Reject the alternative hypothesis.
Fail to reject the claim.
Reject the claim.
Fail to reject the null hypothesis.
Reject the null hypothesis.
f) Consider the following statements related to the trainer's claim. Interpret your decision in the context of the problem (ignoring the claim) and interpret them in the context of the claim.
Answer:
H0: µd = 0 (claim)
H1: µd ≠ 0
This is a two-tail t-test for µd
Step-by-step explanation:
This is a paired (dependent) sample test, with its hypothesis is written as :
H0: µd = 0
H1: µd ≠ 0
From the equality sign used in the hypothesis declaration, a not equal to ≠ sign in the alternative hypothesis is used for a two tailed t test
The data isn't attached, however bce the test statistic cannot be obtained. However, the test statistic formular for a paired sample is given as :
T = dbar / (Sd/√n)
dbar = mean of the difference ; Sd = standard deviation of the difference.
Tuition. The tuition at a community college increased from $2,500 to $2,650 per semester. What was the percent of increase in the tuition?
Answer:
6 percent increase
Step-by-step explanation:
2650 divided by 2500 gives you 1.06 which means if 2500 is 100 percent 2650 would be 106 percent so the answer is a 6 percent increase
Answer:
6%
Step-by-step explanation:
another way of doing this type of calculation is...
NEW-OLD = 2650-2500 = 150 = .06 = 6%
OLD 2500 2500
welp I am getting graded for this
Answer:
it is summer how do y'all still have school,like don't they give y'all a break
someone help me pls i need to pass summer school
Answer:
A
Step-by-step explanation:
The be the inverse function the domain {4,5,6,7} becomes the range and the range {14,12,10,8} becomes the domain
14 → 4
12 →5
10 →6
8 →7
A stick 1 meter long casts a shadow 1.3 meters long. A building casts a shadow 25 meters long. How tall is the building (to 2 decimal places)
Answer: 19.23 meters
Step-by-step explanation:
1/1.3 = x/25
(1) (25) / 1.3
= 19.23 meters
Find the length of the missing sides
Answer:
f = 10
g = 2 sqrt(3)
h = 20
Step-by-step explanation:
The short leg is opposite the smaller angle so it is f
The longer leg is opposite the larger angle so it is g
The hypotenuse is opposite the right angle so it is 20
We know f = x
g = x sqrt(3)
h = 2x = 20
2x = 20 so x = 10
f = 10
g = 2 sqrt(3)
h = 20
The answer the the question pictured
Answer:
x-1/2x-3
Step-by-step explanation:
be happy bro this is your perfect answer
What is the length of de?
Answer: length of DE = 18
Step-by-step explanation:
Since the angles of these two triangles are the same, we can assume that they are similar triangles. To solve for a missing side of a triangle that is similar, you can set up a proportion:
[tex]\frac{27}{15}=\frac{x}{10}[/tex]
To solve for x (the missing length), you would do:
27 × 10 ÷ 15 = 18
You can set up the proportion in any way between the two triangles as long as the two sides correspond to each other. For example, you could have also used the following proportion to solve for x:
[tex]\frac{x}{27} =\frac{10}{15}[/tex]
When you solve for x using this proportion, you would get the same value for x:
10 × 27 ÷ 15 = 18
5 times a certain number plus 6 has the same value as two times the same number minus 3 what is the number
Let the number be x
ATQ
[tex]\\ \sf\longmapsto 5x+6=2x-3[/tex]
[tex]\\ \sf\longmapsto 5x-2x=-3-6[/tex]
[tex]\\ \sf\longmapsto 3x=-9[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{-9}{3}[/tex]
[tex]\\ \sf\longmapsto x=-3[/tex]
solve x^3-7x^2+7x+15
Step-by-step explanation:
\underline{\textsf{Given:}}
Given:
\mathsf{Polynomial\;is\;x^3+7x^2+7x-15}Polynomialisx
3
+7x
2
+7x−15
\underline{\textsf{To find:}}
To find:
\mathsf{Factors\;of\;x^3+7x^2+7x-15}Factorsofx
3
+7x
2
+7x−15
\underline{\textsf{Solution:}}
Solution:
\textsf{Factor theorem:}Factor theorem:
\boxed{\mathsf{(x-a)\;is\;a\;factor\;P(x)\;\iff\;P(a)=0}}
(x−a)isafactorP(x)⟺P(a)=0
\mathsf{Let\;P(x)=x^3+7x^2+7x-15}LetP(x)=x
3
+7x
2
+7x−15
\mathsf{Sum\;of\;the\;coefficients=1+7+7-15=0}Sumofthecoefficients=1+7+7−15=0
\therefore\mathsf{(x-1)\;is\;a\;factor\;of\;P(x)}∴(x−1)isafactorofP(x)
\mathsf{When\;x=-3}Whenx=−3
\mathsf{P(-3)=(-3)^3+7(-3)^2+7(-3)-15}P(−3)=(−3)
3
+7(−3)
2
+7(−3)−15
\mathsf{P(-3)=-27+63-21-15}P(−3)=−27+63−21−15
\mathsf{P(-3)=63-63}P(−3)=63−63
\mathsf{P(-3)=0}P(−3)=0
\therefore\mathsf{(x+3)\;is\;a\;factor}∴(x+3)isafactor
\mathsf{When\;x=-5}Whenx=−5
\mathsf{P(-5)=(-5)^3+7(-5)^2+7(-5)-15}P(−5)=(−5)
3
+7(−5)
2
+7(−5)−15
\mathsf{P(-5)=-125+175-35-15}P(−5)=−125+175−35−15
\mathsf{P(-5)=175-175}P(−5)=175−175
\mathsf{P(-5)=0}P(−5)=0
\therefore\mathsf{(x+5)\;is\;a\;factor}∴(x+5)isafactor
\underline{\textsf{Answer:}}
Answer:
\mathsf{x^3+7x^2+7x-15=(x-1)(x+3)(x+5)}x
3
+7x
2
+7x−15=(x−1)(x+3)(x+5)
\underline{\textsf{Find more:}}
Find more:
A health club sold ten memberships in one week for total of $3000. If male memberships cost $300 and female memberships cost $300, then how many male memberships and how female memberships were sold?
Answer:
Step-by-step explanation:
The reason you haven't gotten an answer to this is because in its current formatting, there is no answer. Here's what I mean:
The first equation is going to be concerning the NUMBER of memberships sold, where m is male and f is female. The total number of memberships was 10:
m + f = 10
Now for the money equation. The total amount of money made from that number of memberships was 3000, where male memberships cost $300 and so do the female memberships, giving us an equation of
300m + 300f = 3000
Go back to the first equation and solve for either m or f. I solved for m in terms of f:
m = 10 - f and sub that into the second equation for m to get:
300(10 - f) + 300f = 3000 and
3000 - 300f + 300f = 3000. Here is where you find the problem. The -300f and the 300f cancel each other out, leaving you with the fact that
3000 = 3000 which it does, but it doesn't give us any viable answer.
I would have to say that since we can't do math on this, that the most credible answer you'll find is that the same number of male and female memberships were sold because 5 male memberships cost $1500 (5 memberships at $300 a piece is $1500) and 5 female memberships also cost $1500.
1500 + 1500 = 3000
how to solve this trig
Hi there!
To find the Trigonometric Equation, we have to isolate sin, cos, tan, etc. We are also given the interval [0,2π).
First Question
What we have to do is to isolate cos first.
[tex] \displaystyle \large{ cos \theta = - \frac{1}{2} }[/tex]
Then find the reference angle. As we know cos(π/3) equals 1/2. Therefore π/3 is our reference angle.
Since we know that cos is negative in Q2 and Q3. We will be using π + (ref. angle) for Q3. and π - (ref. angle) for Q2.
Find Q2
[tex] \displaystyle \large{ \pi - \frac{ \pi}{3} = \frac{3 \pi}{3} - \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{2 \pi}{3} }[/tex]
Find Q3
[tex] \displaystyle \large{ \pi + \frac{ \pi}{3} = \frac{3 \pi}{3} + \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{4 \pi}{3} }[/tex]
Both values are apart of the interval. Hence,
[tex] \displaystyle \large \boxed{ \theta = \frac{2 \pi}{3} , \frac{4 \pi}{3} }[/tex]
Second Question
Isolate sin(4 theta).
[tex] \displaystyle \large{sin 4 \theta = - \frac{1}{ \sqrt{2} } }[/tex]
Rationalize the denominator.
[tex] \displaystyle \large{sin4 \theta = - \frac{ \sqrt{2} }{2} }[/tex]
The problem here is 4 beside theta. What we are going to do is to expand the interval.
[tex] \displaystyle \large{0 \leqslant \theta < 2 \pi}[/tex]
Multiply whole by 4.
[tex] \displaystyle \large{0 \times 4 \leqslant \theta \times 4 < 2 \pi \times 4} \\ \displaystyle \large \boxed{0 \leqslant 4 \theta < 8 \pi}[/tex]
Then find the reference angle.
We know that sin(π/4) = √2/2. Hence π/4 is our reference angle.
sin is negative in Q3 and Q4. We use π + (ref. angle) for Q3 and 2π - (ref. angle for Q4.)
Find Q3
[tex] \displaystyle \large{ \pi + \frac{ \pi}{4} = \frac{ 4 \pi}{4} + \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{5 \pi}{4} }[/tex]
Find Q4
[tex] \displaystyle \large{2 \pi - \frac{ \pi}{4} = \frac{8 \pi}{4} - \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{7 \pi}{4} }[/tex]
Both values are in [0,2π). However, we exceed our interval to < 8π.
We will be using these following:-
[tex] \displaystyle \large{ \theta + 2 \pi k = \theta \: \: \: \: \: \sf{(k \: \: is \: \: integer)}}[/tex]
Hence:-
For Q3
[tex] \displaystyle \large{ \frac{5 \pi}{4} + 2 \pi = \frac{13 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 4\pi = \frac{21 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 6\pi = \frac{29 \pi}{4} }[/tex]
We cannot use any further k-values (or k cannot be 4 or higher) because it'd be +8π and not in the interval.
For Q4
[tex] \displaystyle \large{ \frac{ 7 \pi}{4} + 2 \pi = \frac{15 \pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 4 \pi = \frac{23\pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 6 \pi = \frac{31 \pi}{4} }[/tex]
Therefore:-
[tex] \displaystyle \large{4 \theta = \frac{5 \pi}{4} , \frac{7 \pi}{4} , \frac{13\pi}{4} , \frac{21\pi}{4} , \frac{29\pi}{4}, \frac{15 \pi}{4} , \frac{23\pi}{4} , \frac{31\pi}{4} }[/tex]
Then we divide all these values by 4.
[tex] \displaystyle \large \boxed{\theta = \frac{5 \pi}{16} , \frac{7 \pi}{16} , \frac{13\pi}{16} , \frac{21\pi}{16} , \frac{29\pi}{16}, \frac{15 \pi}{16} , \frac{23\pi}{16} , \frac{31\pi}{16} }[/tex]
Let me know if you have any questions!
